What is the average speed between 5 seconds and 15 seconds?

Answer:

The gravitational attraction between Earth and a 2,500 kg car is 24,592.49 N.

Explanation:

The law of universal gravitation, or simply the law of gravity, establishes the force with which two bodies attract each other simply because they have mass. This law was developed by Sir Isaac Newton.

This law describes the gravitational interaction between massive bodies, and establishes a proportional relationship of the gravitational force with the mass of the bodies.

The Universal Law of Gravitation states that all objects attract each other with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This means that any two bodies attract each other with a greater or lesser force depending on their mass is greater or less, and according to the distance between them.

The fundamental formula of the Law of Universal Gravitation is as follows:

[tex]F=\frac{G*m1*m2}{d^{2} }[/tex]

Where:

In this case:

Replacing:

[tex]F=\frac{6.673484*10^{-11}\frac{N*m^{2} }{kg^{2} } *6*10^{24} kg*2,500 kg}{(6.38*10^{6} m)^{2} }[/tex]

Solving you get:

F= 24,592.49 N

The gravitational attraction between Earth and a 2,500 kg car is 24,592.49 N.

Answer:

3.  When energy is used, it can transform to new types but can never disappear.

Explanation: it can transform into heat, light, ect and will never disapear unlessed turned of.

Answer:

the current flowing in the circuit is 0.1 A.

Explanation:

Given;

potential difference, V = 12 V

resistance of the circuit, R = 120 ohms

The current flowing in the circuit is calculated as;

V = IR

I = V/R

where;

I is the current flowing in the circuit

I = 12 / 120

I = 0.1 A

Therefore, the current flowing in the circuit is 0.1 A.

Answer:

450pounds

Explanation:

Answer:

Solubility

Explanation:

Material becomes soluble in solvent and disappears.

The physical property of the material is Serena most likely observing is solubility.

Explanation:

Solubility is defined as the property of a substance to get dissolve in another substance. A small amount of substance is termed as solute and a substance in a larger amount is called a solvent.

Intermolecular interaction of solute particles with solvent particles results in the dissolving of a solute in the solvent.

Conductivity is the property of the substance to conduct heat, electric current, or sound through them.

magnetism is a physical phenomenon that arises due to the motion of electric current through a conductor resulting in the production of a magnetic field.

Density is a measure of the mass of a substance present in the unit volume of the substance.

So, when Serena observed the disappearance of a material into a beaker filled with liquid she is observing the property of solubility of that material.

Learn more about solubility here:

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Answer:

 a = 1600 m / s²

Explanation:

For this exercise we use the kinematics relations,

         v² = v₀² + 2 a x

where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m

         a = [tex]\frac{v^2}{2x}[/tex]

let's calculate

         a = [tex]\frac{80^2}{2 \ 2}[/tex]

         a = 1600 m / s²

Answer:

False

Explanation:

Think of the electric potential in terms of potential energy. If you imagine a place with high elevation (A) and another one at sea level (B), a ball will roll from high potential to low potential (A-->B).

Everything in our universe wants to reach a lower state of energy if no external force is acted upon it. Every object tends to slow down (friction), a radioactive element dissipates energy (an unstable element releases energy to get to a stable state), water in the clouds comes down to the ground (rain experiencing difference in potential energy).

Electric potential is exactly the same, you just can't see it! It flows from higher voltage (which is a synonym for electric potential) to lower voltage.

Explanation:

Given parameters:

Force  = 500N

Acceleration  =

Unknown:

Weight can be used to this problem = ?

Solution:

Weight is the vertical force on a body;

       Weight  = mass x acceleration

So from this we can find the mass and then convert to the second wealth.

Answer:

Explanation:

Joule effect and Joule's law are any of several different physical effects discovered or characterized by English physicist James Prescott Joule.

"Joule's first law" (Joule heating), a physical law expressing the relationship between the heat generated and current flowing through a conductor.

Joule's second law states that the internal energy of an ideal gas is independent of its volume and pressure, depending only on its temperature.

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

Answer:

The answer is A)  

I hope this helps.

Explanation:

Answer:

heyyyyyyy

Explanation:

Explanation:

Answer:

The first one is true.

Explanation:

Here it is

Answer:

true

Explanation:

I think true because I think

Answer:

In the explanation

Explanation:

After erosion and eruptions which is a primary occuration for sediments, this will create heat and tough pressure leading the sediment to be extremely stable and Hard.

Answer:

0J

Explanation:

The kinetic energy would be zero. An object just released from rest will have no kinetic energy but the potential energy will be maximum.

Kinetic energy is the energy due to the motion of a body

Potential energy is the energy due to the position of a body.

Therefore, the kinetic energy is zero

Answer:

The technology was also widely employed in fighter aircraft during the 1960s. It is also used in air traffic control systems to pick out aircraft from clutter. Pulse-Doppler RADAR is also the basis of synthetic aperture RADAR that is commonly used in RADAR astronomy, remote sensing, and mapping.

Answer:

im soo sad brainly wouldnt let me in the account that asked this question now i have to start everything over

Explanation:

Answer:

c. 15.4 s

Explanation:

Given the following data;

Mass, m = 50kg

Force, F = 130N

Initial velocity, u = 20m/s

Final velocity, v = 60m/s

To find the time;

First of all, we would solve for acceleration using the formula below;

Force = mass * acceleration

130 = 50*acceleration

Acceleration = 130/50

Acceleration = 2.6m/s²

Now, we would use the first equation of motion to find the time.

V = U + at

60 = 20 + 2.6t

2.6t = 60 - 20

2.6t = 40

t = 40/2.6

Time, t = 15.39 ≈ 15.4 seconds.

The time taken will be 15.4 seconds approximately. The correct answer is option c

NEWTON SECOND LAW

Newton's second law state that, the rate of change of momentum is proportional to the force applied.

Given that  a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s. The given parameters are;

from Newton's second law,

Ft = m(v - u)

Substitute all the parameters into the formula

130t = 50 (60 - 20)

130t = 50 x 40

130t = 2000

t = 2000/130

t = 15.38 seconds

Therefore, the time taken will be 15.4 seconds approximately. The correct answer is option c

Learn more about Newton's law here: https://brainly.com/question/25545050

As we know that,

[tex]\boxed{ \sf \: {v}^{2} - {u}^{2} = 2as }[/tex]

According to the question,

0² - u² = 2(20)(121)

0 - u² = 4840

-u² = 4840

-u = √4840

u = -69.5 m/s

The initial velocity of the stone is -69.5 m/S.

Answer:

Yes

Explanation:

Answer:

Simple answer: Yes

Explanation:

Even if you touch an item with a stick you re still doing work to it, most of the time something sitting on a table not being disturbed is having work done to it. Everything has the force of gravity working on it to essentially keep the items from floating away so workis being done to it.

Work done can be something so small (e.g) a pencil sitting on a table) or as big as an earthquake or kicking a ball through a window and smashing the glass.

Answer:

true

Explanation:

Answer:

a) The time it takes the ball to reach maximum height is approximately 3.06 seconds

b) The distance of the ball from the home plate once it is at the top is approximately 38.78 m

c) No

d) The height of the ball when it is at the top is approximately 45.92 m

e) The time it takes the ball to travel 100 m horizontally is 5 seconds

F) The height of the ball when it is 100 m away from the home plate is 27.5 m

G) The height of the ball above the ground when it 100 m away from the home plate, is 27.5 m

The height of the ball above the wall at 100 m from home plate is 3.5 m

Explanation:

The given parameters for the motion of the ball are;

The upward (vertical) velocity of the ball, [tex]u_y[/tex] = 30 m/s

The across (horizontal) velocity of the ball, uₓ = 20 m/s

The distance from the home plate to the outfield fence = 100 m

The height of the outfield fence = 24 m

a) The time, '[tex]t_{mh}[/tex]', it takes the ball to reach maximum height is by the following kinematic equation of motion;

[tex]v_y[/tex] = [tex]u_y[/tex] - g·t

Where;

[tex]u_y[/tex] = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

At maximum height, we have;

[tex]v_y[/tex] = 0 m/s, t = [tex]t_{mh}[/tex]

∴ 0 m/s = [tex]u_y[/tex] - g·[tex]t_{mh}[/tex]

[tex]u_y[/tex] = g·[tex]t_{mh}[/tex]

[tex]t_{mh}[/tex] = [tex]u_y[/tex]/g

∴ [tex]t_{mh}[/tex] = [tex]u_y[/tex]/g = (30 m/s)/(9.8 m/s²) = 150/49 s ≈ 3.06 seconds

The time it takes the ball to reach maximum height, [tex]t_{mh}[/tex] ≈ 3.06 seconds

b) The horizontal distance travelled by the ball, when it is at maximum height, [tex]x_{mh}[/tex], is given as follows;

[tex]x_{mh}[/tex] = uₓ × [tex]t_{mh}[/tex] = 20 m/s × 150/49 s

[tex]x_{mh}[/tex] = 20 m/s × 150/49 s = 3000/49 m

[tex]x_{mh}[/tex] = 3000/49 m

The distance of the ball from the home plate, 'd', once it is at the top (maximum height), is given as follows;

d = 100 m - [tex]x_{mh}[/tex]

∴ d = 100 m - 3000/49 m = 1900/49 m ≈ 38.78 m

The distance of the ball from the home plate once it is at the top = d ≈ 38.78 m

c) The ball is yet to reach the fence when it gets to the top

The ball has approximately 38.78 meters to reach the fence

d) The height of the ball, [tex]h_{max}[/tex], when it is at the top is given by the following kinematic equation

[tex]h_{max}[/tex] = [tex]u_y[/tex]²/(2·g)

Where;

[tex]u_y[/tex] = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ [tex]h_{max}[/tex] = (30 m/s)²/(2×9.8 m/s²) = 2,250/49 m ≈ 45.92 m

The height of the ball when it is at the top, [tex]h_{max}[/tex] ≈ 45.92 m

e) The time, t₁₀₀, it will take the ball to get 100 m from home plate is found from the following relationship;

Velocity, u = Distance, x/(time, t)

∴ Time = Distance/(Velocity)

t = x/v

The given distance is the horizontal distance, therefore, we use the horizontal component of the velocity as follows;

v = Horizontal velocity of the softball = uₓ = 20 m/s

x = The given horizontal distance travelled by the ball = 100 m

t₁₀₀ = The time it takes the ball to travel 100 m horizontally

∴ t₁₀₀ = x/(uₓ) = 100 m/(20 m/s) = 5 s

The time it takes the ball to travel 100 m horizontally, t₁₀₀ = 5 seconds

F) The height of the ball above ground when it is 100 m away from the home plate is given as follows;

When the ball is 100 m from the home plate, the time, t₁₀₀ = 5 seconds

The height of the ball at 100m, [tex]h_{t_{(100 \, m)}}[/tex], is given according to the kinematic equation of motion for vertical height reached by an object as follows;

h = [tex]u_y[/tex]·t - 1/2·g·t²

∴ [tex]h_{t_{(100 \, m)}}[/tex] =  [tex]u_y[/tex]·t₁₀₀ - 1/2·g·t₁₀₀²

Plugging in the known values gives;

[tex]h_{t_{(100 \, m)}}[/tex] =  30 m/s × 5 s  - 1/2 × 9.8 m/s × (5 s)² = 27.5 m

The height of the ball when it is 100 m away from the home plate, [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m.

G) The height of the ball above the ground when it 100 m away from the home plate, is  [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m

The height of the ball above the wall at 100 m from the home plate = The height of the ball when it is 100 m away from the home plate - The height of the wall at 100 m away from the home plate

∴ The height of the ball above the wall at 100 m from home plate = 27.5 m - 24 m = 3.5 m.

The rings around the planets such as Saturn, Uranus, and Neptune are formed because of the collision of moons, asteroids, or comets that got too close to the planets. Only those travels toward the sun which got enough energy to escape from the planet's gravity.

A ring system can be described as a disc or ring, orbiting an astronomical object, that is made up of solid material such as dust and moonlets, and is a component of satellite systems around giant planets. A ring system around a planet is also called a planetary ring system.

The planetary rings in the Solar System are those around Saturn, but the other three giant planets also have ring systems. The ring systems may also be found around minor planets, moons, and brown dwarfs.

The maximum size of a ring particle can be determined by the specific strength of the material it is composed of, its density, and tidal force at its altitude.

Learn more about planetary rings, here:

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Answer:

what is the question.

Explanation:

Answer:

B. When the average speed of particles is the same throughout the liquid