What is the density of an unknown compound in g/ml if 1.28 pounds of the compound has a volume of 4.50L

Answers

Answer 1
First, we need to convert the mass of the compound from pounds to grams:
1.28 pounds * 453.59 grams/pound = 580.61 grams

Next, we can use the formula for density:
Density = Mass / Volume

Density = 580.61 grams / 4.50 L

Density = 128.91 g/L

Therefore, the density of the unknown compound is 128.91 g/L or 0.12891 g/mL (since there are 1000 mL in 1 L).

Related Questions

2 NaN3 → 2 Na + 3 N
Given 9.98 grams of N2, how many moles of NaN3 are produced?​

Answers

0.238 moles of NaN₃ are produced from 9.98 grams of N₂.

What is the moles of NaN₃ produced?​

The moles of he mass of NaN₃ produced

The balanced equation for the reaction is:

2 NaN₃ → 2 Na + 3 N₂

The molar ratio between NaN₃ and N₂ is 2:3, which means that for every 2 moles of NaN₃, 3 moles of N₂ are produced.

The mole ratio is used to determine how many moles of NaN₃ are produced from 9.98 grams of N₂.

First, we need to convert the mass of N₂ to moles:

moles of N₂ = mass of N2 / molar mass of N₂

moles of N₂ = 9.98 g / 28.02 g/mol

moles of N₂ = 0.356 mol

moles of NaN₃ = (2/3) * moles of N₂

moles of NaN₃ = (2/3) * 0.356 mol

moles of NaN₃ = 0.238 mol

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