what is the descender order of f(x)=5x2+4x-11

Answer:

0

x

16

-5

5.5

Step-by-step explanation:

Answer:

The polar bear weighs 525kg

Step-by-step explanation:

C = Polar Bear

D = Baby Elephant

____________________________

(1)  C + D = 700 kg

(2)  C = 3D

________________________________

C = 700 - D

700 - D = 3D

700 = 4D

________________________________

525 + 175 = 700

Then we get our answer, the polar bear weighs 525kg, and the baby elephant weighs 175kg.

Hope this helps you :)

Answer:

1.870828693387

Step-by-step explanation:

Standard Deviation, σ: 1.870828693387

Count, N:4

Sum, Σx: 12

Mean, μ: 3

Variance, σ2:  3.5

Steps

σ2 = Σ(xi - μ)2

N  =   (6 - 3)2 + ... + (1 - 3)2

4 = 14

4  = 3.5

σ = √3.5

= 1.870828693387

Answer:

B 18.79

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

my school

Step-by-step explanation:

block me from sieng the image

Answer:

answer: Hi = 15

Step-by-step explanation:

the larger shape is the same as the smaller shape just flipped over and bigger of course so to find this out you have to take 2 simular angles and find out what multiplied by the small angle will get the big angle so I see angles gh and ba are simular I try 4.5 ÷ 1.5 = 3 so 3 is how much the shape is being multiplied by so bc is simular to hi so I do 5 x 3 = 15 and theres are answer 15 is the length of hi hope this helps you!

Answer:

y=1/3x+2

Step-by-step explanation:

Step-by-step explanation:

the mean is simply

8+9+3+9+3+8+4+4=48

48/8=6

mean= 6

the median is simply

3,3,4,4,8,8,9,9

4+8=12÷2=6

median=6

the mode is simply(I'm not sure of this answer)

3,4,8,9

the range is

9-3= 6

Answer:

What?

Step-by-step explanation:

G8ve me more info and Ill answer again

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

[tex]\huge\mathcal\pink{Answer}[/tex]

radius r = 10 m

volume V = 4188.7902 m3

surface area A = 1256.63706 m2

circumference C = 62.8318531 m

In Terms of Pi π

volume V = 1333.33333 π m3

surface area A = 400 π m2

circumference C = 20 π m

Step-by-step explanation:

In a cylinder

We know that

[tex] \boxed { \sf \: volume = \pi {r}^{2} h} \\ \rm \rightharpoonup \: \frac{22}{7} \times {5}^{2} \times 12 \\ \rm \rightharpoonup \: \frac{22}{7} \times 25 \times 12 \\ \rm \rightharpoonup \: \frac{6600}{7} \\ \rm \rightharpoonup \: 942.8cm {}^{3} [/tex]

Answer:

approx. 943 cm^3

Step-by-step explanation:

π × 5^2 x 12 = approx. 943 cm^3

Answer:

89^2π

Step-by-step explanation:

Using the formulas

A=4πR2

D=2r

Solving for A

A=πD2=π·89^2≈24884.55541

Answer: 5 is your answer hope this helped

plz make brainly

Step-by-step explanation:

Answer:

i its 3 or 4

Step-by-step explanation:

Answer:

336 cm²

Step-by-step explanation:

rectangle area:

b×h = 24×7,5=180 cm²

" " = 6,5×24=156 cm²

total area: 180+156=336 cm²

Answer:

I searched it up and took a screenshot

Step-by-step explanation:

Here they are:

Btw the 1st one is for 6x + 2y = 12 and the second one is for 5x + 2y = 8​.

Hope this helps! : )

Answer:

just do 400 times 400 witch is 1600

Step-by-step explanation:

Answer:

x=-1

Step-by-step explanation:

Answer:

10x = 2x -8

-2x -2x

8x = -8

divide by 8

x = -1

Answer:

c≈5.2

Step-by-step explanation:

c=a2+b2=1.412+52≈5.19501

Answer:

12

Step-by-step explanation:

Answer:

x=28

Step-by-step explanation:

4(x-5)=92

4x-20=92

add 20 to both sides

4x=112

divide 4 on both sides

x=28

Answer:

The value of x is 28

Step-by-step explanation:

4(x - 5) = 92

4x - 20 = 92

4x = 92 + 20

4x = 112

x = 112 ÷ 4

x = 28

Thus, The value of x is 28

-TheUnknownScientist

Answer:

B

Step-by-step explanation:

B...............................

mark me the brainliest plzzzzzzzz

The statement about rectangles and rhombuses that is always true is that both figures are quadrilaterals.

A quadrilateral is a closed, two-dimensional shape which has four straight sides.

In other word, a quadrilateral is a plane figure that has four sides or edges, and also has four corners or vertices.

Quadrilateral has four sides.

Rhombuses and rectangles have four sides. Therefore, they are both quadrilaterals.

learn more on quadrilateral here: https://brainly.com/question/10388790

Answer:

33

Step-by-step explanation:

Answer:

∠ G ≈ 8.3°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan G = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{HI}{GI}[/tex] = [tex]\frac{1.1}{7.5}[/tex] , then

∠ G = [tex]tan^{-1}[/tex] ([tex]\frac{1.1}{7.5}[/tex] ) ≈ 8.3° ( to the nearest tenth )

Answer:

{x,y} = {-5,-2}

Step-by-step explanation:

Answer:

C. Multiply 1st equation by 3, then add together

Step-by-step explanation:

X+y=10

3(x+y)=3(10)multiply by 3

3x+3y=30 add to following equation

2x-3y=6

5x=36

Answer:

21.908

Step-by-step explanation: