What is the distance from A(-3, 6) to B(4, -3)?

\/~~32

\/~~-32

\/~~10

\/~~130

Answers

Answer 1

Answer:

D)  √130

The distance of the given points

AB = √130

Step-by-step explanation:

Explanation:-

Given points are A(-3,6) and B( 4,-3)

The distance formula

   AB = [tex]\sqrt{x_{2}-x_{1})^{2} +(y_{2} -y_{1} )^{2} }[/tex]

 AB = [tex]\sqrt{(4-(-3))^{2} +(-3-6)^{2}[/tex]

 AB = [tex]\sqrt{(7)^{2} +(-9)^{2} }[/tex]

AB = [tex]\sqrt{49+81}[/tex]

AB = √130


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50 divided by 40 equals 1.25! So the car is going 1.25 mph

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Answer:

x=130 I believe

Step-by-step explanation:

28+8+14+x=180

50+x=180

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Answers

You find the intersection point of the two lines, which is (3, -2).

It is what the question meant when it asked for "solution".

These two lines are y = mx + c, which is another form of linear equations with two variables you are likely familiar with

x+y=20

x-y=10

Hope this clears up your confusion.

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Answers

Answer: -46

Step-by-step explanation:

Consecutive means next in order.

Sum means answer to an addition problem.

-45 + -46 = -91

-46 is smaller (farther away from zero) than -45

Ty uses 20 ft of fence to divide into 4 equal parts all in one row. Each aware part is 2 feet long. What is the area of the garden?

Answers

Answer:

10

Step-by-step explanation:

20 divided by 4 = 5 and times it from there

What is the slope in the equation:
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Answers

Answer: the slope is 3/4.

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Answer:

the slope is 3/4

Step-by-step explanation:

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y = slopex + y intercept

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Find The Area of this
Triangle
5 cm
13 cm
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Answers

the correct answer is 30cm

Luke and nabila are playing squash Luke wins twice as many games as nabila they play 18 games how many do each win

Answers

Answer:

Luke = 12 games

Naliba = 6 games

Step-by-step explanation:

Luke and naliba are playing squash

Luke wins twice as many games as naliba

They play a total of 18 games

Luke= 2x

naliba = x

2x +x= 18

3x= 18

x= 18/3

x= 6

Luke= 2(6)

= 12

naliba= 6

Hence luke wins 12 games and naliba wins 6 games

PLZ ANSWER FAST!!!!! Mr. Miller took a poll of which students in his class have gone to a water park. If 7/9 of his class have visited a water park for a total of 21 students, then how many total students are in Mr. Miller's class?

Answers

Answer:

29 students

Step-by-step explanation:

divide by 7 to get 1/9 then multiply by 9 to get total.

Answer:

27

Step-by-step explanation:

Let x be the total number of students. So, turning the words of the problem into an equation, we get:

7/9x = 21,

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how can i solve this

tan2x/(tan4x-tan2x)​

Answers

the answer is yes i did this before so hope that helps

Answer: = cos 4x

[tex]\frac{tan2x}{tan4x-tan2x}\\\\=\frac{tan2x}{\frac{2tan2x}{1-tan^{2}2x }-tan2x }\\\\=\frac{tan2x(1-tan^{2}2x) }{2tan2x-tan2x(1-tan^{2}2x) }\\\\=\frac{tan2x(1-tan^{2}2x) }{tan2x(2-1+tan^{2}2x) }\\\\=\frac{1-tan^{2}2x }{1+tan^{2}2x } \\\\=\frac{1-\frac{sin^{2}2x }{cos^{2}2x } }{1+\frac{sin^{2}2x }{cos^{2}2x } }\\\\=\frac{cos^{2}2x-sin^{2}2x }{cos^{2}2x+sin^{2}2x } \\\\=\frac{cos4x}{1}\\\\=cos4x[/tex]

Step-by-step explanation:

The problem of the Week!

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

Help ASAP!!!
Which of the following statements are true for the transformation of the pre image to the Image? Choose all that apply. There is more than one correct answer. Write the answer as just the
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Answer:

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Step-by-step explanation:

Brandon Brandon Drew the two congruent squares shown he divided one square into 2 congruent triangular parts he divided the other square into 2 congruent rectangular parts

Answers

Incomplete question: Options

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

(b) Each triangular part has an area that is greater than the area of each rectangular part.

(c) Each triangular part and each rectangular part represents 1/4 the area of one square

(d) Each rectangular part has an area that is greater than the area of each triangular part.

See attachment for squares

Answer:

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

Step-by-step explanation:

Given

See attachment

Required

Which statement is true

Before the division, the area of both squares is:

[tex]Area = l * w[/tex]

After the division:

The area of the triangle is:

[tex]Area = \frac{1}{2} * base * height[/tex]

[tex]A_1 = \frac{1}{2} * l * w[/tex]

Substitute Area for l * w

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[tex]Area = length * width[/tex]

The length of the rectangle is now half the length of the original square.

So, we have:

[tex]A_2 = \frac{1}{2} l * w[/tex]

Substitute Area for l * w

[tex]A_2 = \frac{1}{2} *Area[/tex]

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Victoria buys a two-gallon bottle of juice for $48.64. What is the unit rate of the cost of the juice per fluid ounce? I need this asap

Answers

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

The perimeter of parallelogram LMNO

Is calculated using the formula

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Answer:

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Step-by-step explanation:

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Answers

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Recall that the center of dilation is point J. On the logo, identify one or two line segments: that contain the center of dilation that do not contain the center of dilation that lie on a line that passes through the center of dilation Record the names of the line segments you identified and the category they belong to. What differences do you notice in the way these categories of line segments are mapped from the preimage to the image?

PLATO

Answers

Answer:

HA , LJ , and IK contain the center of dilation. Line segments that contain the center of dilation in the preimage also contain the center of dilation in the image. GF , HI , and KL do not contain the center of dilation. Line segments that do not contain the center of dilation in the pre image are mapped onto distinct lines parallel to the original, corresponding line segment. HL does not contain the center of dilation either but it does lie on a line that passes through the center of dilation. Line segments that lie on lines passing through the center of dilation in the preimage lie on the same lines in the image.

Step-by-step explanation:

Plato’s Answer

Answer:

Step-by-step explanation:

HA , LJ , and IK contain the center of dilation. Line segments that contain the center of dilation in the preimage also contain the center of dilation in the image. GF , HI , and KL do not contain the center of dilation. Line segments that do not contain the center of dilation in the pre image are mapped onto distinct lines parallel to the original, corresponding line segment. HL does not contain the center of dilation either but it does lie on a line that passes through the center of dilation. Line segments that lie on lines passing through the center of dilation in the preimage lie on the same lines in the image.

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