Answer:
y=5/4x-5
Step-by-step explanation:
y-y1=m(x-x1)
y-0=5/4(x-4)
y=5/4(x-4)
y=5/4x-20/4
y=5/4x-5
Research workshop: Generating Research questions and evaluating sources.
Take notes for two sources
Take notes on your second source
Based on the information, the best research question that Juan should choose will be "How does playing a team sport affect a child's development?"
A research question simply means a question that a researcher wants to answer. It should be noted that choosing a research question is an important element in research.
From the complete question, it should be noted that since Juan is writing a paper about children who play team sports, and he has different research questions, he should choose the one that conveys the research appropriately.
In this case, the best option will be "How does playing a team sport affect a child's development?"
Learn more about research questions on:
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Wheel Fun offers rentals of paddle boats that can be enjoyed by 2 or 3 riders. The price for renting a paddle boat is $15 for each hour. Customers must also pay a $20 deposit on the rental. Write an equation that can be used to determine the price, y for renting a paddle boat for x, hours?
Answer:
15+20=35+15 And then add an additional plus 15 for each hour
Step-by-step explanation:
x squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
Answer:
[tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
Step-by-step explanation:
I'm assuming the system is [tex]\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.[/tex]:
[tex]x^2+y^2=2[/tex]
[tex]x^2+(2x^2-3)^2=2[/tex]
[tex]x^2+(4x^4-12x^2+9)=2[/tex]
[tex]x^2+4x^4-12x^2+9=2[/tex]
[tex]4x^4-11x^2+9=2[/tex]
[tex]4x^4-11x^2+7=0[/tex]
[tex]x^4-11x^2+28=0[/tex]
[tex](x^2-7)(x^2-4)=0[/tex]
[tex](4x^2-7)(x^2-1)=0[/tex]
[tex]4x^2-7=0[/tex]
[tex]4x^2=7[/tex]
[tex]x^2=\frac{7}{4}[/tex]
[tex]x=\pm\sqrt{\frac{7}{4}}[/tex]
[tex]x^2-1=0[/tex]
[tex]x^2=1[/tex]
[tex]x=\pm1[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm\sqrt{\frac{7}{4}})^2-3[/tex]
[tex]y=2({\frac{7}{4}})-3[/tex]
[tex]y=\frac{7}{2}-3[/tex]
[tex]y=\frac{1}{2}[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm1)^2-3[/tex]
[tex]y=2(1)-3[/tex]
[tex]y=2-3[/tex]
[tex]y=-1[/tex]
Therefore, [tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
At a local movie theatre, sodas cost$4.50 and bags of popcorn cost &1.50. Kirk buys three times as many bags of popcorn as sodas and pays a total of $36. Write a system of equations and solve it using any method to determine how many of each item Kirk bought.
Answer:
this might help
Step-by-step explanation:
this might be kinda similar
Chickens and rabbits
In the yard were chickens and rabbits. Together they had 18 heads and 56 legs. How many chickens and how many rabbits were in the yard?
Correct answer:
chickens: 8
rabbits: 10
Step-by-step explanation:
a+b=18
2a+4b=56
a=8
b=10
a+b = 18
2•a+4•b=56
a+b = 18
2a+4b = 56
a = 8
b = 10
1 1/5- 1/3
AS FRACTION
Answer:
-2/15
this should work
Step-by-step explanation:
Answer:
13/15
Step-by-step explanation:
1 1/5 - 1/3 =
= 1 + 1/5 - 1/3
= 5/5 + 1/5 - 1/3
= 6/5 - 1/3
= 18/15 - 5/15
= 13/15
Question
Bill needs to mow his yard which has the dimensions in the shape below. What is the area of yard he needs to mow?
Note: Round your answer to one decimal place.
12 m
5 m
15 m
Answer:
Step-by-step explanation:
imagine you chop off a right triangle from the left side
now you have a rectangle and a right triangle
the rectangle
height 5
width 12
5 x 12 = 60
triangle
height 5
width 3
3 x 5 = 15
15 / 2 = 7.5
60 + 7.5 = 67.5 m^2
Answer: 67.5 m^2
Step-by-step explanation:
To find out the area of the yard, we split the shape up into a triangle and rectangle. The area of the triangle is,
A = 1 × b × h/2 = 1 × 3 × 5/2 = 7.5 m^2.
And the area of the rectangle is,
A = 12 × 5 = 60 m^2.
We then add the area of the triangle and the area of the rectangle.
A = 7.5 + 60 =67.5 m^2
Rounded to one decimal place, the area of the yard is 67.5 square meters.
For n = 10 and 1 = 0.59, what is P(X = 8)?
P(X = 8) =
(Round to four decimal places as needed.)
nCx⋅px⋅(1−p)n−x
llllllllllllllllllllllllllllllllllllll
What does Point P on the number line represent? (Use the hyphen for negative numbers, such as −9)
Number line from negative 8 to positive 10 in increments of 1 is shown. Only the even numbers are labeled. A point labeled P is placed at the third tick mark to the left of 0.
(5 points)
Answer:
P = -3, each line in the negative direction is 1 number
so you would have -1, -2, -3 , -4, etc.
P is on the -3 line.
See attached picture.
Step-by-step explanation:
The radioactive compound 14CO2 may be used as a tracer to study metabolism in plants. Suppose that a compound isolated from a plant exhibited 28, 32, 27, 39 and 40 counts of radioactive decays per minute. A blank sample used to measure the background counts of the radiation counter gave 28,21, 28 and 20 counts per minute. It appears that the isolated compound gives more counts than those from background. Can we be 95% confident that the compound is indeed radioactive?
Using the t-distribution, it is found that since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.
At the null hypothesis, it is tested if isolated compounds do not give more counts than those from background, that is:
[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]
At the alternative hypothesis, it is tested if the give more counts, that is:
[tex]H_1: \mu_1 - \mu_2 > 0[/tex]
Using a calculator, the mean and the standard deviation for each sample are given by:
[tex]\mu_1 = 33.2, s_1 = 6.058[/tex]
[tex]\mu_2 = 24.25, s_2 = 4.35[/tex]
Considering the sample sizes of 5 and 4, respectively, the standard errors are given by:
[tex]s_1 = \frac{6.058}{\sqrt{5}} = 2.71[/tex]
[tex]s_2 = \frac{4.35}{\sqrt{4}} = 2.175[/tex]
For the distribution of differences, the mean and standard error are given by:
[tex]\overline{x} = \mu_1 - \mu_2 = 33.2 - 24.25 = 8.95[/tex]
[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{2.71^2 + 2.175^2} = 3.4749[/tex]
The standard error was found from the standard deviation for each sample, hence, the t-distribution is used.
The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis, hence:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
[tex]t = \frac{8.95 - 0}{3.4749}[/tex]
[tex]t = 2.58[/tex]
The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with 5 + 4 - 2 = 7 df and a 0.05 significance level is of [tex]t^{\ast} = 1.895[/tex]
Since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.
A similar problem is given at brainly.com/question/24826023
please helppppppppppppp ASAP. please ensure to use step by step explanation. thanks.
I'll do the first two parts to get you started.
=====================================================
Part (i)
We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.
Let's say we go for a = 1 and b = 2
[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]
Now let's swap the values. We'll try a = 2 and b = 1
[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]
We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.
The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,
[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]
It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.
Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.
=====================================================
Part (ii)
Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.
a = 1b = 2c = 3Then,
[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]
Next, we can say:
[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]
Let's compare the two outputs:
[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]
They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).
In general, the operation is not associative in R.
Little help? Ill give 5 stars and brainly (If correct)
Answer:
C
Step-by-step explanation:
Slope is rise over run. Pick two points and then count the rise and run. The rise in this case is one and the run is 2 and one over 2 is 1/2
[tex]Hiya![/tex]
Sokka is here to help!
ANSWER:[tex]C.[/tex]
Because, All you need to do is.. Find the slope of proportional graph, by y and x, Which the line is [tex]\frac{4}{2}[/tex].
[tex]And, \frac{4}{2} =\frac{1}{2} .[/tex]
Hopefully, this helps you!!
[tex]Sokka[/tex]
HELP ASAP Match each division expression to its quotient.
Answer:
2=-12.2/(-6.1
-2=16/(-8)
-3= -2 2/5/4/5
3= 3 3/7 / 1 1/7
Step-by-step explanation:
The constraints of a problem are listed below. What are the vertices of the feasible region?
x+3y<=6
4x+6y>=9
x>=0
y>=0
The vertices of the feasible region of the constraints is (0,2.5)
How to determine the vertices?The constraints are given as:
x + 3y ≤ 6
4x + 6y ≥ 9
x ≥ 0, y ≥ 0
Express the inequalities as equations
x + 3y = 6
4x + 6y = 9
Make x the subject in x + 3y = 6
x = 6 - 3y
Substitute x = 6 - 3y in 4x + 6y = 9
4(6 - 3y) + 6y = 9
Expand
24 - 12y + 6y = 9
Evaluate the like terms
-6y = -15
Divide by 6
y = 2.5
Substitute y = 2.5 in x = 6 - 3y
x = 6 - 3 * 2.5
Evaluate
x = -1.5
So, we have:
(x,y) = (-1.5, 2.5)
Recall that: x ≥ 0, y ≥ 0
This means that the feasible region must have positive coordinates or zero
So, we set x = 0
(x,y) = (0, 2.5)
Hence, the vertices of the feasible region of the constraints is (0,2.5)
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#SPJ1
(2+√3)+(4-√3)
[tex] [/tex]
Explanation :
________________________________
Given:
(2+√3)+(4-√3)
To Find:
Evaluate the expression
Solution:
⇨Step 1:
Remove the parentheses
(2+√3)+(4-√3)
When there is + or no sign in front of an expression in parentheses, the expression remains the same
= 2 + √3+ 4-√3
⇨Step 2:
Cancel the opposite terms √3 and -√3
"Two numbers are opposites if they have the same absolute value but different signs"
= 2 + 4
⇨Step 3:
Add the numbers
= 6
Hence (2+√3)+(4-√3) = 6.
Given that f(x) = ax – 5 and f(4) = 15, determine the value of a.
Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
The given function is:
f(x) = ax - 5
If f(4) = 15, then x = 4
Substitute x = 4 into f(x) = ax - 5
f(4) = a(4) - 5
15 = 4a - 5
Solve for a by adding 5 to both sides
15 + 5 = 4a - 5 + 5
20 = 4a
Divide both sides by 4
4a/4 = 20/4
a = 5
Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
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Pls help stuck on it
Answer:
4,-1
Step-by-step explanation:
Please like!♥
Help help help help math math
Answer:
Yes, it is a function
Step-by-step explanation:
Each x value in the domain has its own output, and it does not have more than 1
what is the percent change of
30 to 90?
what is what is the percent change of 30 to 90?
Answer:
200% increase
Step-by-step explanation:
Select the interval where g(2) < 0.
(graphed on khan academy)
Answer:
the number 0 Originally called finding the vertical asymptote.
Troy is buying a car that costs $15,000. He
plans to get a 5-year loan to pay for it. He
can get a loan for $15,000 or he can pay
$3,000 from his savings and get a loan
for the rest. The savings account pays 2%
simple interest per year. The simple interest
rate for the loan is 0.5% per year.
a. How much interest over a 5-year
Answer:
300/75
Step-by-step explanation:
Cost of the Car = $15,000
a) Rate of interest received on savings(r) = 2%
Amount in savings account(p) =$3000
Time period(t) = 5 years
simple intrest.
Interest received on savings account = $300
b) Rate of interest on loan = 0.5%
IF P= 15000
intrest.
Difference between the interest = $75
c) Taking loan of the whole amount that is of $15,000 is more reasonable because though the interest is more but Troy will receive interest($300) from his savings account as well. But if he withdraws $3000 from savings and takes the loan for the rest of the amount, he would have no earnings.
A bag with 6 marbles has 2 blue marbles, 1 red marble, and 3 yellow marbles. A marble is chosen from the bag at random. What is the probability that it
is not blue?
There are 2 blue marbles out of 6 total marbles.
6-2 = 4 marbles are not blue.
Probability of not being blue = 4/6 which reduces to 2/3
Answer: 2/3
The cost of providing water bottles at a high school football game is $35 for the rental of the coolers and $0.50 per bottle
The cost function is an illustration of a linear function
The equation of the cost function is C(x) = 35 + 0.5x
The given parameters are:
[tex]Rentals = 35[/tex] -- the cost of renting a cooler
[tex]Rate = 0.5[/tex] --- the rate per bottle
Assume the number of bottles in a cooler is x.
The cost function for the bottles in a cooler would be:
[tex]C(x) = Rentals + Rate \times x[/tex]
So, we have:
[tex]C(x) = 35 + 0.5\times x[/tex]
Evaluate the products
[tex]C(x) = 35 + 0.5x[/tex]
Hence, the equation is [tex]C(x) = 35 + 0.5x[/tex]
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Can anyone help with this?
What is 10% of 75? Use the double number line below to label your work and answer.
Answer: the answer is 7.5
Step-by-step explanation:
I don’t understand this please help
Answer:
i think BC = 8.5
Step-by-step explanation:
19-(2+6.5+2)
19-10.5
8.5
Find the area of the figure.
7cm
8cm
11cm
Area is ___ square cm?
Answer:
616cm³
Step-by-step explanation:
you just need to multiply those numbers
7 x 8 x 11= 616
[tex]\text{Perimeter of the triangle,}\\\\ 2s = 7 + 8 +11 =26}\\\\\\\implies s = \dfrac{26}2 = 13\\\\\\\text{Apply Heron's formula to find the area of the triangle,}\\\\A = \sqrt{s(s-8)(s-7)(s-11)}\\\\\implies A = \sqrt{13(13-8)(13-7)(13-11)}\\\\\implies A = \sqrt{780} \\\\\implies A = 27.93~~ \text{cm}^2[/tex]
What are the coordinates of the point (-4, 2) after a translation 2 units left and 2 units up?
A (-2, 0)
B (-6,0)
C (-2, 4)
D (-6, 4)
Answer:
the answer you're looking for is D. when you move to the left the -4 becomes -6 and when you move up 2 becomes 4.
Evaluate 4x^2 y^-3 for x=3 and y=-2
Answer:
36 and -1/8
Step-by-step explanation:
x^2 = 3^2 = 9 * 4 = 36
y^-3 = (-2)^-3 = -1/8
Answer:
-4.5.
Step-by-step explanation:
4x^2 y^-3
= 4x^2 / y^3
When x = 3 and y = -2
it is 4(3)^2 / (-2)^3
= 36 / -8
= -4.5.
Evaluate the expression when c=4. c^4 + 6
Answer:
262
Step-by-step explanation:
4x4x4x4+6
256+6
262
From a hot-air balloon, Guadalupe measures a 31^{\circ} ∘ angle of depression to a landmark that’s 316 feet away, measuring horizontally. What’s the balloon’s vertical distance above the ground?
Check the picture below.