What is the frequency of a wave traveling at 10 m/s with a wavelength of 2 m?

Answers

Answer 1

Answer:

5 Hz

Explanation:

Given:

Wave velocity ( v ) = 10 m / sec

wavelength ( λ ) = 2 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 10 / 2 Hz

= > f = 5 Hz

Hence, frequency of sound is 5 Hz.


Related Questions

A thermometer has a scale which starts at -10 Celcius and ends at 110 Celcius. What is the value of the lower fixed point and of the upper fixed point of the scale?

Answers

Explanation:

The Kelvin, Celsius, and Fahrenheit scales are the three temperature scales that are most widely used. In most physical experiments the Celsius scale is used to take common measurements, but the Kelvin scale is used for most calculations.

If you have a spaceship that can go 20% of the speed of light, how long would it take to travel 200 light-years?

Answers

Answer:

1498962290

Explanation:

To understand the photoelectric effect physiciests should view light as having what type of properties?

Answers

Answer:

Particle

Explanation:

To understand photoelectric effect the physicists has to view light as a particle and not wave. The wave nature of the light could not explain the phenomenon of photoelectric effect.

Photoelectric effect is emission of electrons from a material when electromagnetic radiation(Light) is incident on it. These emitted electrons are called photoelectrons.

The explain this effect Einstein proposed that beam of light is can not be a wave propagating through space, but a swarm of discrete energy packets, called as photons.

In the center of the Milky Way galaxy is a
A

Answers

The answer is the Galactic Center I think

Answer:

a super massive blackhole

You are a drop of water going through the water cycle. Where doyou go?How do you get there? What processes do you go through?Include at least three phases of the water .

Answers

Answer:

If I were a drop of water and present in the ocean or any other aquatic system I should have moved in the water cycle as due to heats the water of the aquatic system such as the ocean becomes hot and evaporated turning into vapour, a gaseous phase of water.

Then vapour colloids with cooler air, and become cooler and convert into drops of water again which is called condensation. Drops of water again get back to the earth surface it can be in the form of rain, snow (ice form of water) termed as precipitation.

The three phases of the water cycle are

---> evaporation ---- > condensation -----> precipitation----

Which of the following football players have the same momentum?
Ted: mass = 60 kg, velocity = 2.0 m/s
Todd: mass = 80 kg, velocity = 1.7 m/s
Tom: mass = 90 kg, velocity = 1.5 m/s
Tim: mass = 100 kg, velocity = 1.2 m/s
a. Ted and Todd
b. Todd and Tim
c. Ted and Tim
d. None of the above.

Answers

Answer: Ted and Tim

Explanation:

The football players Ted and Tim have the same momentum, which is 120 kg m/s. Hence, option C is correct.

What is momentum?

The momentum is the result of a particle's velocity and mass. Force and motion, meaning it has both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on a particle equals the time rate of increase of momentum.

The impulse, which is the product of the force and the intervals (the impulse), is equal to the difference in momentum, according to Newton's 2nd law, if a steady force operates on a particle for a specific amount of time. On the other hand, a particle's momentum is the amount of time needed for a consistent action to fight it to rest.

As per the given information in the question,

The momentum of Ted is,

p = 60 × 2 = 120 kg m/s

The momentum for Todd is,

p = 80 × 1.7 = 136 kg m/s.

The momentum of Tom is,

p = 90 × 1.5 = 135 kg m/s and,

The momentum for Tim is,

p = 100 × 1.2

p = 120 kg m/s.  

After comparing the momentum of all the players, Ted and Tim have similar momentum.

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A laser beam travels from a telescope on Earth to a Moon and then back to the Based on this information , how far is the Moon Earth? PLEASE HELP?

A. 384,000,000

B. 58.600, 000m;

C. 1, 536, 000, 000m

D. 117, 000, 000m

Answers

Answer is d hope this helps

Two forces each of magnitude 25N acts in opposite direction at the opposite end of a circular ring. If the diameter at the ring is 65cm. Calculate the magnitude of the couple acting on the ring​.

Answers

Answer:

The magnitude of the couple is 16.25 Nm.

Explanation:

A couple is a force that always produce a turning effect of objects on which it is applied. It has applications in doors, taps, revolving doors etc. Couple is a two equal but opposite force applied on an object.

couple = force x length

From the given question, the couple acting on the ring can be determined as;

couple = 25 x 0.65

           = 16.25 Nm

The magnitude of the couple is 16.25 Nm.

A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?
120N
N8'0
ON

Answers

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

The force acting on the box is equal to 120N. Therefore, option (A) is correct.

What is Newton's second law of motion?

According to Newton's 2nd law of motion, The force acting on an object is equal to mass times the acceleration of that object.

This law tells that the acceleration of a moving body depends upon two variables in which one is the mass of the object which is constant while the other is the force acting on that object. The acceleration of an object increases as the mass of the object is less.

The mathematical equation of the second law of motion can be written as:

F = ma

Given, the mass of the box, m = 10 Kg

The acceleration of the box, a = 12m/s²

We can find the force acting on the box by putting the values a and m:

Force acting on the box, F = 10 ×12 = 120 N

Therefore, the force acting on the box is equal to 120 newtons.

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How are light waves produced

Answers

Answer:

Electromagnetic waves are created by oscillating charges (which radiate whenever accelerated) and have the same frequency as the oscillation. Since the electric and magnetic fields in most electromagnetic waves are perpendicular to the direction in which the wave moves, it is ordinarily a transverse wave

Explanation:

Answer:

Electromagnetic waves are created by oscillating charges (which radiate whenever accelerated) and have the same frequency as the oscillation. Since the electric and magnetic fields in most electromagnetic waves are perpendicular to the direction in which the wave moves, it is ordinarily a transverse wave

Explanation:


Moby lifted Tim off the ground a distance of 2 meters using a force of 2N. How much work did Moby do?

Answers

Answer:

4 J

Explanation:

As I guess,

From the equation,

work done = force × distance travelled

                   =  2        ×    2

                   = 4 J

There are no conversions since all are given in the standard form.

Which change would create light?
A. An electron in an atom jumping from a lower energy state to a higher one.
B. Two electrons from the same atom colliding
C. An electron in an atom jumping from a higher energy state to a lower one.
D. Two electrons from two different atoms colliding.

Answers

Answer:

Im not 100% sure but i think the answer is A. An electron in an atom jumping from a lower energy state to a higher one.

Explanation:

lmk if its wrong

If a force of 10 N acts on an object and an additional force of 6 N acts on the object in
the same direction. What will be the net force be on the object?
4N
60 N
6N
16 N

Answers

Answer:

D

Explanation:

For this kind of problem, forces add. F = F1 + F2

F1 = 6 N

F2 = 10 N

F = 6N + 10N

F = 16N

The period of a wave is 20 ms (milliseconds) and its wavelength is 4 cm. Calculate:

a) The frequency of the wave

b) The velocity of the wave. ​

Answers

Answer:

A. 50 Hz

B. 2 m/s

Explanation:

We'll begin by converting 20 ms to s. This can be obtained as follow:

1000 ms = 1 s

Therefore,

20 ms = 20 ms × 1 s / 1000 ms

20 ms = 0.02 s

Next, we shall convert the value of the wavelength (i.e 4cm) to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

4 cm = 4 cm × 1 m / 100 cm

4 cm = 0.04 m

A. Determination of the frequency.

Period (T) = 0.02 s

Frequency (f) =?

f = 1 / T

f = 1 / 0.02

f = 50 Hz

Therefore, the frequency of the wave is 50 Hz

B. Determination of the velocity.

Wavelength (λ) = 0.04 m

Frequency (f) = 50 Hz

Velocity (v) =?

v = λf

V = 0.04 × 50

v = 2 m/s

Therefore, the velocity of the wave is 2 m/s

A radio wave has a frequency of 3,000,000 Hz and a wavelength of 100m. What is the speed?

Answers

Answer:

300,000,000

Explanation:

Use the speed formula

Speed= wavelength x frequency

A beam of light from a laser pen passed through the air and then through a glass plate. Which diagram accurately models this phenomenon? Use evidence and scientific reasoning to defend your claim.

Answers

Explanation:

the second diagram depicts the phenomenon which is refraction and this stems from light moving from a medium to another......and in this case light moves from a less dense medium to a denser medium hence is refracted away from the normal(the straight line between the medium of air and glass)

PLS GIVE BRAINLY

Diagram B shows the refraction event and this is from light to medium, in this case, the light travels from a slightly narrower area to a compact area and is, therefore, further away from the normal (vertical line between the air and glass).

When a ray of light travels from a central location?

When a ray of light travels from a dense area to a rare place, it bends away from normal.

How do you calculate the refractive index?

Refractive index is also equal to the velocity of light c of a given wavelength in empty space divided by its velocity v in a substance, or n = c/v.

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A baseball player catches a 200 gram baseball which is moving
horizontally at a speed of 42.1 m/s. Determine the force which she must
apply to the baseball if her mitt recoils a horizontal distance of 29.2 cm.
A.) 177 N
B.) 0.57 N
C.) 607 N
D.) 57290 N

Please help solve

Answers

Did you get the answer?  I need it

Kevin bikes to the pizza place for lunch. He rides 1 km east, 3 km north, 4 km west, and finally 3 km south. What was his displacement?

Answers

Answer:

3km

Explanation:

To get the displacement, we will make use of the expression;

[tex]D = \sqrt{(\sum d_x)^2+(\sum d_y)^2}[/tex]

Taking the sum of the distances along the x;

dx = 1km - 4km

dx = -3km

Taking the sum of the distances along the y axis

dy = 3km - 3km

dy = 0km

Substitute into the formula above;

[tex]R = \sqrt{(-3)^2+(0)^2}\\R = \sqrt{9} \\R = 3km\\[/tex]

Hence his displacement is 3km

A young girl is on a swing that completes 35.0 cycles in 25 seconds. What are her frequency and period?

Answers

The first question has the answer to your problem! I found the answer key!


A bowling ball rolled with a force of 20 N accelerates at a rate of 5 m/sec2, a second ball rolled with the same force accelerates 10 m/sec2. What are the
combined masses of the two balls?

Answers

Answer:

sorry I need points

Explanation:

IM SO SORRY

What would be the Elastic Potential Energy (EPE) stored in a spring with a constant k = 200 N/m that is pulled to stretch 0.45m?

2,025 J
2,025 J

90 J
90 J

40.50 J
40.50 J

20.25 J

Answers

Answer:

During the summer, oxygen is supplied by surface winds. M/NPT 16 to 26 0.14 to 0.45 m 1/ 77.80 $ 28 Phone: 418 81-1 Fax: 418 81-2882 SZ5-2025 SZ22-200 SZ2-250 SZ24-00 12.5 x 60 12.5 x 60 12.5 x 60 8 x 10 10 x 15 10 x 20 15 x HI-950 can take measures between 0.1 C to 999.9 C/ F. K, J & T-type: The HI-9551

(Hope this is what you're asking for)

Hope this helps Have a good day

A 0.017 g coin sliding to the right at 0.255 m/s makes an elastic head-on collision with a 0.040 g coin that is initially at rest. After the collision, the 0.017 g coin moves to the left at 0.108 m/s. Find the final velocity of the other coin.

Answers

Answer:

[tex]\approx 0.154\:\mathrm{m/s}[/tex]

Explanation:

In all collisions, whether elastic or inelastic, momentum must be conserved. Therefore, we can write an equation using the conservation of momentum:

[tex]m_{c1}v_{c1,i}+m_{c2}v_{c2,i}=m_{c1}v_{c1,f}+m_{c2}v_{c2,f}[/tex]

Solving for [tex]v_{2c,f}[/tex]:

[tex]0.000017\cdot 0.255+0.000040\cdot0=0.000017\cdot (-0.108)+0.000040\cdot v_{c2,f},\\v_{c2,f}\approx \boxed{0.154\:\mathrm{m/s}}[/tex]

*Notes:

-It's important to convert g to kg, as kg is the SI unit of mass

-The negative sign in a velocity measure represents direction

-Since the velocity we solved for is positive, it implies that the direction is to the right

An observer notices that 12 waves pass by in 4 seconds. What is the frequency of these waves? 0.33 Hz 16 Hz 48 Hz 3 Hz

Answers

Answer:

Frequency = 3 Hz

Explanation:

Frequency is a measure of Hertz. Recall that Hertz is the unit expressing cycles/second, where one second is the denominator of the fraction for simplicity. If there are 12 waves every four seconds, and one wave represents one cycle, dividing 12 waves by 4 seconds will give the answer of 3 waves (or cycles) per one second.

The frequency of these waves is 3 Hz. The correct option is D.

What is a frequency?

Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is a fundamental property of waves and is directly related to the energy and wavelength of the wave. The higher the frequency of a wave, the more energy it carries and the shorter its wavelength.

The formula for frequency (f) is:

f = 1 / T

where f is the frequency in Hertz (Hz) and T is the period of the wave in seconds (s). The period is the time it takes for one complete cycle or oscillation of the wave to occur.

Here in the Question,

The frequency of the waves can be calculated using the formula:

frequency = number of waves/time

In this case, the number of waves is 12 and the time is 4 seconds. Substituting these values into the formula, we get:

frequency = 12 waves / 4 seconds = 3 Hz

Therefore, the frequency of these waves is 3 Hz.

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Tara kain tayo gaize ulam natin sardinas tara kain gaize?
A.heat
B.sun
C.earth
D.warm

Please answer it please​

Answers

Answer:

Heat.

Explanation:

Pyramids were built for religious purposes. The Egyptians were one of the first civilizations to believe in an afterlife. They believed that a second self called the ka lived within every human being. When the physical body expired, the ka enjoyed eternal life

what is 2 plus 2 and 1 plus 1​

Answers

Answer: 6

Explanation:

Have an awesome amazing day

Answer:

2 plus 2 = 4 AND 1 plus 1 = 2

Explanation:

I guess combine both equations if your detailed instructions allow.

Who can help me do some 8th grade Science if so i will mark you the brainliest and also no links

Answers

Answer:

yes I help what is the question

4.- Una vagoneta de 1000 kg de peso parte del reposo en el punto 1 y desciende, sin rozamiento, por la vía indicada en la figura. A) Calcular la fuerza que la vía ejerce sobre la vagoneta en el punto 2, donde el radio de curvatura es de 6 m. B) Determinar el mínimo valor del radio de curvatura en el punto 3 para salvar dicho punto

Answers

Answer:

A) 49,050 N

B) 16 m

Explanation:

Question:

El dibujo de la pregunta se obtiene de un documento titulado "TRABAJO DIVERSO Y ENERGÍA" que se encuentra en línea y se presenta aquí.

La masa dada del vagón, m = 1,000 kg

La altura del punto en el que descansa el vagón, punto 1, h₁ = 12 m

A) El radio en el punto 2, el punto más bajo, R = 6 m

La fuerza, 'N', que la vía ejerce sobre el vagón en el punto 1 viene dada por la siguiente relación;

N = El peso del vagón + La fuerza de movimiento del vagón

∴ N = m × g + m × a

Dónde;

g = La aceleración debida a la gravedad ≈ 9,81 m / s²

a = La aceleración del vagón

Observamos que para el movimiento circular, la fuerza de movimiento del vagón, m × a = La fuerza centrípeta que actúa sobre el vagón = m × v² / R

∴ m × a = m × v² / R

Dónde;

v² = La velocidad del vagón en el punto 2 = 2 · g · h₁

Por lo tanto;

N = m × g + m × a = m × g + m × v² / R = m × g + m × 2 · g · h₁ / R

∴ N = 1000 × 9,81 + 1000 × 2 × 9,81 × 12/6 = 49,050

La fuerza que ejerce el vagón en el punto 2, N = 49,050 N

B) En el punto 3, tenemos;

N = m · g - m · a₃

La fuerza centrípeta en el punto 3, m · a₃ = m · v₃² / R₃

∴ La altura en el punto 3, h₃ = 4 m

El cuadrado de la velocidad en el punto 3, v₃² = 2 · g · (h₁ - h₃)

Para que el vagón esté seguro en el punto 3, la fuerza de la vía sobre el vagón, N = 0 para que el vagón permanezca en la vía actuando

Por lo tanto;

N = m · g - m · a₃ = 0

m · g = m · a₃ = m · v₃² / R₃ = m · (2 ​​· g · (h₁ - h₃)) / R₃

∴ R₃ = (2 · g · (h₁ - h₃)) / g = (2 · (h₁ - h₃)) = 2 × (12 - 4) = 16

El radio de curvatura en el punto 3 para que el punto sea seguro es R₃ = 16 m.

______ is a chemical reaction between an acid and a base that forms a salt and water. Group of answer choices Neutralization Dissociation Titration Ionization

Answers

Answer:

neutralization

Explanation:

this is because

acid + base ---> salt + water


Why would African Americans like the song "Respect"?
A. It represented African Americans and their struggle for equality.
B. It represented African Americans and their success in achieving
equality.
C. It represented African Americans and their fight for African
independence.
D. It represented African Americans and their struggle to end slavery.

Answers

B. It represented African Americans and their struggle for equality.Answer:

Explanation:

An astronaut weighs 200 N on the Moon where gravity is 1.62 m/s/s. Find his weight on Earth. HELP PLEASE FAST

Answers

Answer:

the weight of the astronaut on Earth is 1209.88 N

Explanation:

Given;

weight of the astronaut, W = 200 N

acceleration due to gravity on moon, g = 1.62 m/s²

Apply Newton's second law of motion to determine the mass of the astronaut;

F = ma = mg

m = F/g

m = 200 / 1.62

m = 123.457 kg

The weight of the astronaut on Earth is calculated as follows;

F = mg

where;

g is acceleration due to gravity on Earth = 9.8 m/s²

F = 123.457 x 9.8

F = 1209.88 N

Therefore, the weight of the astronaut on Earth is 1209.88 N

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