What is the light speed formula?

Answers

Answer 1

If ' c ' is the speed of light, then the formula for it is . . .

c = 299,792,458 meters per second


Related Questions

True or False? 13. All living things are made of cells 14. All cells have DNA within their nucleus 15. The cell is the basic unit of life in all organisms 16. All cells in a living thing are similar in structure or function 17. Cells must develop from other cells

Answers

Answer:

1: True

2: False

3: True

4: False

5: True

A 12 V automobile battery is connected to an electric starter motor. The current
through the motor is 250 A.
a) How much power does the motor dissipate?
b) How much energy does the battery deliver to the motor during the 26 s period?

PLEASE HELP QUICK

Answers

Answer: [tex]3000\ W,\ 78,000\ J[/tex]

Explanation:

Given

The voltage of the battery is [tex]V=12\ V[/tex]

Current through the battery is [tex]I=250\ A[/tex]

(a) Power is the product of voltage and current

Power dissipates is given by

[tex]P=VI\\P=12\times 250\\P=3000\ W[/tex]

(b) Energy delivered

[tex]E=P\times t[/tex]

[tex]E=3000\times 26\\E=78,000\ J[/tex]

180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?

Answers

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N O C. 75 N O D. 150 N ​

Answers

Answer:

150N

Explanation:

To find the force applied remember that force equals to Mass multiply by the Acceleration.

F=Ma

=30*5

=150N

Answer:

150N

Explanation:

F = m*a = 30 * 5 = 150 N

how to prepare a trading stock account​

Answers

Answer:

Opening stock details of raw material, semi-finished goods and finished goods.

Closing stock details of raw material, semi-finished goods, and finished goods.

Total purchases of goods fewer Purchase Returns.

Total sales of goods fewer Sales Returns.

During a football game player A (mass 120kg velocity 5.5m/s [L]) tackles and grabs player B (mass 105kg velocity 7.9m/s [R]). What is the final speed of the two players immediately after the collision?

Answers

Answer:

6.62m/s

Explanation:

Given data

M1= 120kg

U1= 5.5m/s

M2= 105kg

U2= 7.9m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

120*5.5+ 105*7.9= (120+105)*V

660+ 829.5= (225)*V

1489.5= (225)*V

Divide both sides by 225

V= 1489.5/225

V= 6.62m/s

Hence the common velocity is 6.62m/s

The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​

Answers

Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

who is known as the father of India​

Answers

Answer:

the answer is

Mahatma Gandhi

Answer:

Mahatma Gandhi

hope it helps.

the path of the earth around the sun is called​

Answers

Answer:

Orbit.

Explanation:

An orbit is a regular, repeating path that one object in space takes around another one, it's an imaginary path of the Earth around the Sun.

How are both electromagnetic and mechanical waves used when people communicate with each other?

Answers

Unlike mechanical waves, which require matter, electromagnetic waves can travel through empty space, as well as through liquids, solids, and gases. There are many similarities between light waves and mechanical waves. They can both be measured by their amplitude, wavelength, and frequency.

Imagine that you are observing the region of space where a cloud of gas and dust is beginning to collapse inward to form a star (the object that initially forms in this process is called a protostar). Will the atoms in the collapsing cloud move away from one another, move closer to one another, or stay at the same locations? 2) What physical interaction, or force, causes the atoms to behave as you described they would in Question 1?

Answers

Answer:

1. The atoms in the collapsing cloud would move closer to one another.

2. Gravity

Explanation:

1. This is because there is a force of attraction between the atoms of the collapsing cloud. Thus, the atoms in the collapsing cloud would move closer to one another.

2. This is because gravity is the force of attraction between masses. Now, the collapsing cloud of dust contains mass of atoms, and as the atoms come together due to gravity, they form a larger mass which develops into a star.

(a) The atoms in the collapsing cloud would move closer to one another.

(b)  Due to the force of interaction between masses that is gravity

What is force of attraction?

(a) The atoms will come closer

This is because there is a force of attraction between the atoms of the collapsing cloud. Thus, the atoms in the collapsing cloud would move closer to one another.

(b) Due to the gravitational attraction

This is because gravity is the force of attraction between masses. Now, the collapsing cloud of dust contains mass of atoms, and as the atoms come together due to gravity, they form a larger mass which develops into a star.

Hence

(a) The atoms in the collapsing cloud would move closer to one another.

(b)  Due to the force of interaction between masses that is gravity

To know more about force of attraction follow

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A 16.2-g bullet with an initial speed of 850 m/s embeds itself in a 40.0-kg block, which is attached to a horizontal spring with a force constant of 1000 N/m. What is the maximum compression of the spring

Answers

The maximum compression in the spring is 0.06883 meters.

Given to us,

mass of bullet, [tex]m= 16.2\ grams[/tex]

velocity of bullet, [tex]v= 850\ meter/second[/tex]

mass of the block, [tex]m_2= 40\ kilograms[/tex]

velocity of block, [tex]v_2= 0\ meter/second[/tex]

spring constant, [tex]k = 1000\ Newton/meter[/tex]

Combined mass after collision,

[tex]\begin{aligned}M&= m_1+m_2\\&= 40.0162\ Kilograms\end{aligned}[/tex]

Using the momentum conservation equation, to find out final velocity of the system(bullet and block combined)

[tex]m_1v_1+m_2v_2= MV\\[/tex]

[tex]0.0162\times 850+40\times 0 = 40.0162\times V\\V= 0.3441 meter/sec[/tex]

Now using the Conservation of Energy (Kinetic energy of the system will be equal to potential energy in the spring), to find out the displacement of the spring [tex](x)[/tex]

[tex]\frac{1}{2}kx^2 = \frac{1}{2}MV^2\\\\\frac{1}{2}\times 1000\times x^2= \frac{1}{2} \times40.0162\times0.3441^2\\\\x^2= 0.004738\\\\x= 0.06883\ meters[/tex]

Hence, the maximum compression in the spring is 0.06883 meters.

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describe an experiment to show that air support burning​

Answers

Take a small burning candle. ... After few minutes the candle is extinguished. As the supply of air is stopped due to glass jar the burning of candle is also stopped. This experiment proves that air supports burning.

Part
An object with a charge of 3.53 pc experiences a force of 0.0147 N when it moves at right angles to a magnetic field traveling at 2342 m/s. Find the strength of the
magnetic field

Answers

Answer:

4.05 000 the about id

Explanation:

d. The mass of the boy is the same in all places because mass does not depend
on gravity.
True or False
(Science)

Answers

Explanation:

Remember, even if you weigh less because of a change in gravity's force on your body, your body's mass is still the same. As your body grows, you will have more mass, which also means you will weigh more. That's because when you're on the earth, the amount of gravity that pulls on you stays the same.Thank you for marking me Brainlist ☺️

Answer:

true . it depends tho weight depends on gravity .

You have a Coke bottle with an air cavity
that is 0.220 m deep. You add water to
the bottle, shortening the column, so
that when you blow across the top, it
plays a 528 Hz fundamental. How tall is
the water column in the bottle?

Answers

Answer: 0.0576

Explanation:

The equation for fundamental frequency for closed pipes is as follows:

f(1) = v/4L

In which v is the speed of sound (343 m/s) and L is the length of the pipe. Therefore:

528 = 343/4L

x = 0.1624

This is not the answer as you still need to subtract it from the original length.

0.220 - 0.1624 = 0.0576

an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration

Answers

Answer:  130 meters

===================================================

Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

would have to be about 130 meters

¿Con qué cualidad del sonido está relacionada la Amplitud de onda?

Answers

Answer:

Amplitud (dinámica)

Explanation:

La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.

PLEASE HURRY I GIVE BRAINLIST and extra points !!!!!!

1 What happens to the energy from the light when the material changes?

2 What happens to the energy from the light when the material does not change?

Answers

Answer:

2 stays the same 1 it will go bad or go good depends on which material you use

The bean of light is incident from a light source is: i.covergent
ii.divergent
iii.parallel
iv.both i and ii​

Answers

Answer:

I think the answer is II.divergent

because parralel beams are convergent to the light source

and in the question it says incident from the light source

Answer:

The correct answer is (i) Convergent.

George is studying a mechanical wave. He counts thirty crests of the wave pass through a point in 10 seconds.

If What is the frequency of this wave?
Select one:

2 Hz.

20 Hz.

3 Hz.

30 Hz.

Answers

Answer:

Option C

Explanation:

Frequency determines the number of waves that pass through any defined point in a given time period.

Frequency of 1 hertz means that one wave travels through a given point in one second.

By the above definition, we can say

Frequency

[tex]= \frac{30}{10} \\=3[/tex]

Hence, option C is correct

A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN. The elongation of the rod is delta = 1.40 mm and its diameter becomes df = 19.9837 mm. Determine the modulus of elasticity (E) and the modulus of elasticity in shear (G). Assume the material does not yield.

Answers

Answer:

a) the modulus of elasticity (E) is 68.22 GPa

b) the modulus of elasticity in shear is 25.28 GPa

Explanation:

Given the data in the question;

First we determine the cross-sectional area A of the road;

A = π/4 × d²

given that; diameter d = 20 mm

we substitute

A = π/4 × ( 20 mm )²

A = π/4 × 400 mm

A = 314.159 mm²

Next, we find, the normal stress of the rod σ

σ = P / A

given that load p = 50 kN = 50,000 Newton

we substitute

σ = 50,000 N / 314.159 mm²

σ = 159.155 N/mm²

σ = 159.155 Mpa

Next, is the normal strain ε

ε = δ / L

given that; change in length δ = 1.40 mm and Length of rod L = 600 mm

we substitute

ε = 1.40 mm / 600 mm

ε = 0.002333

Now, we find the modulus of elasticity;

we know that;

σ = Eε

modulus of elasticity E = σ / ε

we substitute

E = 159.155 Mpa / 0.002333

E = 68219.031 MPa

E = ( 68219.031 / 1000 ) GPa

E = 68.22 GPa

Therefore, the modulus of elasticity (E) is 68.22 GPa

b)

we know that the Poisson's ratio v is;

v = -(ε[tex]_{lat[/tex] / ε )

v = - (((d[tex]_f[/tex] - d)/d) / ε )

where d[tex]_f[/tex]  is the final diameter of the rod ( 19.9837  mm ) and ε[tex]_{lat[/tex] is the lateral strain

so we substitute

v = - ((( 19.9837 - 20 ) / 20 ) / 0.002333  )

v = - (( -0.0163 / 20 ) / 0.002333  )

v = - ( - 0.000815 / 0.002333 )

v = - ( - 0.3493 )

v = 0.3493

So, our shear modulus will be;

G = E / 2( 1 + v )

we substitute

G = 68.22 GPa / 2( 1 + 0.3493  )

G = 68.22 GPa / 2( 1.3493  )

G = 68.22 GPa / 2.6986

G = 25.28 GPa

Therefore, the modulus of elasticity in shear is 25.28 GPa

How does competition affect population size? Use the terms carrying capacity and limiting factor with your example.

Answers

Limiting factors are resources or other factors in the environment that can lower the population growth rate. Competition for resources like food and space cause the growth rate to stop increasing, so the population levels off. This flat upper line on a growth curve is the carrying capacity.

Answer:

they can eat all of the food and kill off the population

Explanation:

if the competition eats all of the food there's no food for the population and they will die off.

a solid cubic centimeter of platinum weighs 21.5 N. if this cube of platinum is placed under water, what volume of water is displaced? what weight of water is displaced? (Hints: 1 cm3 of water has a mass of 1 gram; 1 gram weighs 0.0098 N; density of platinum = 21.5 g/cm3.)

Answers

Answer:

Mp =Pp g    where p = density of solid Platinum

Wp  = Mp Pp g     weight of mass M

Volume displaced is 1 cm^3

Weight of water = .0098 N   since 1 cm^3 displaced

Or Ww = 1 cm^3 * .001 kg / cm^3 * 9.8 N/kg = .0098 N

HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!​

Answers

work done =force /area

=500/50

power =work done * time taken

During a hard drive crash the read/write head scrapes against the disk with a coefficient of kinetic friction of µk and normal force of N. Assume that just before the head crash the disk is rotating at ω0 rad/s, and the distance of the head from the disk axis is r. You can ignore any friction at the bearing (rotational axis of the disk). Assume that the disk is uniform, and has radius R and mass M. What is the angular acceleration associated with the torque from the crashed disk head?

Answers

Answer:

 α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]

Explanation:

For this exercise we use Newton's equation for rotational motion

           ∑ τ = I α

the troque is

           α = Fr .r

the moment of inertia of a cylinder is

           I = ½ m r²

we substitute

         fr r = (½ m r²) α

the expression friction is

         fr = μ N

we substitute

         μ N r = ½ m r² α

       

         α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]

Calculer la grandeur Terre = G x mterre/r2terre
Justifier alors pourquoi le poids d'un corps dépend de l'astre sur lequel il se trouve

Effectuer le même calcul pour la Lune.
Données :
MTerre = 5,97 x 1024 kg
Terre = 6,38 x 106m
mLune = 7,35 x 1022 kg
"Lune = 1,74 x 106 m

Answers

Answer:  La valeur du poids dépend de la pesanteur et de la masse. ... La masse est une grandeur positive liée à la quantité de matière contenue dans un objet. ... qui correspond à la force d'attraction exercée par l'astre sur lequel il se trouve (et qui ... 1 kg n'aura pas le même poids à la surface de la Lune ou à la surface de la Terre.

Explanation:

Yellow light (600 nm) passes through a
diffraction grating with d = 2.35 x 10-6 m.
What is the angular separation between
the second (m = 2) and third (m = 3)
maximum?

Answers

Answer:

19.284

Explanation:

The answer is right on Accellus.

why do trucks need a runaway ramp

Answers

Answer:

in case they lose control going downhill.

Explanation:

which is why they usually have a steep incline and are quite long. You see them used typically when the trucks brakes fail.

50 POINTS !!!

Three particles of mass 8 kg, 3 kg, and 7 kg are connected by rigid rods of
negligible mass lying along the y axis and are placed at 5 m, -2 m, and -6 m,
respectively as in the figure. The system rotates about the x axis with an angular
speed of 1.65 rad/s.

a) Find the moment of inertia about the x axis. Consider the
masses to be point particles.

b) Find the total rotational energy.

c) Find the linear speed of the top particle of mass 8 kg in the figure.

Answers

Answer:

a) I = 464 kg m²,  b)  K = 631 .6 J, c)  v = 8.25 m / s

Explanation:

a) the moment of inertia of point particles is

          I = ∑ m_i r_i²

in this case

          I = 8 5² + 3 (-2) ² + 7 (-6) ²

          I = 464 kg m²

b) The kinetic energy is

          K = ½ I w²

          K = ½ 464 1.65²

          K = 631 .6 J

c) linear and angular velocity are related

          v = w r

          v = 1.65 5

          v = 8.25 m / s

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