What is the likelihood that you can pick a number that is less than 15 from a jar with papers labeled from 1 to 12
we have that
the numbers less than 15 are
1, 2,3,4,5,6,7,8,9,10,11,12
so
the probability is equal to
12/12=1
that means
the probability is 100% (certain)
Jack just took out a $3,000 loan for a new snowmobile. The simple interest rate on his loan is 40% per year after 4 months how much interest will be charged ?
The amount of interest that wil be charged after 4 months is $400
Here, we want to calculate the amount of interest that will be charged.
To get this, we simply use the simple interest formula
Mathematically;
[tex]\begin{gathered} \text{simple interest = }\frac{p\text{ }\times\text{ r}\times t}{100} \\ \\ \text{where P is the amount borrowed which is 3,000} \\ \\ r\text{ is the interest rate which is 40\%} \\ \\ t\text{ is the time which is 4 months; we express this as 4/12 = 1/3} \\ \\ \text{Substituting these values, we have;} \\ \\ \text{simple interest = }\frac{3000\text{ }\times40\text{ }\times\frac{1}{3}}{100\text{ }}\text{ = }\frac{1000\text{ }\times\text{ 40}}{100}\text{ = 400} \end{gathered}[/tex]I need help finding the five-number summary of the given numbers
We are given the following numbers
3 8 8 4 2 9 8 7 9 5 9 3 2 5 2 9 8 7 7 9
to calculate the five number summary, it means that we should calculate the following numbers:
- minimum
- percentile 25
- median (or percentile 50)
- quantile 75
- maximum
So, we should first sort this numbers from least to greatest, so it is easier to identify this five numbers. Once sorted we get the following numbers:
2 2 2 3 3 4 5 5 7 7 7 8 8 8 8 9 9 9 9 9
From this arrangement, we can see that the least number (or minimum) is 2 and the greatest number (or maximum) is 9.
Now we need to identify the percentiles 25, 50 and 75.
To calculate this numbers, we must first count the number of data points we have. Once we do so, we get that we have 20 elements.
Now, the term percentile 50 means that we are finding a point such that 50% of the data (the half) is on both sides of the number.
So, since we have 20 data points, we must find a number that splits the data in a way such that 10 points are less than or equal to the number and 10 points are greater than or equal to the number.
So, first, we count 10 numbers from left to right. The 10th number in the sorted sequence is 7, and the 11th number is also 7. So, the number that we are looking for is the average of this two numbers. So we get
[tex]\frac{7+7}{2}=7[/tex]So the percentile 50 is 7.
Now, we need to find the percentile 25 and percentile 75.
The percentile 25 is the number such that 25% of the data is less than or equal to this number.
Note that since we have 20 data points. The 25% of 20 is 5. That is, we should find a number such data 5 data points is on the left of the number and 15 numbers are on the right of the number. If we count 5 numbers, we get the number 3. The 6th number is 4. So, the number we are looking for should be inbetween 3 and 4. ONe way to find this number is to take a weighted average of this numbers. Since we are looking for the percentile 25, we will give a weight of 0.25 to 3 and 0.75 to 4. Then the percentile 25 would be
[tex]0.25\cdot3+0.75\cdot4\text{ =3.75}[/tex]In the same manner, to find the percentile 75, we first identify the 15th and 16th numbers. In this case, the 15th number is 8 and the 16th number is 9. Since we want the percentile 75, we give a weight of 0.75 to 8 and a weight of 0.25 to 9. Then we get
[tex]0.75\cdot8+0.25\cdot9\text{ = 8.25}[/tex]Then, the percentile 75 is 8.25.
Then, the five summary of the data is
- minimum : 2
- percentile 25 : 3.75
- median (or percentile 50): 7
- quantile 75: 8.25
- maximum: 9
As the connected complexity of mathematical concepts evolve, your mathematical knowledge evolves as well. Previous knowledge provides the necessary skills to acquire new learning. . Rewrite each the following expressions using the properties of exponents. b. xyz 3 - 2/3 C. 20-27 x 5y? d. 27Solve B.
Simplify the equation.
[tex]\begin{gathered} \frac{x^{-3}(x^2)^{-2}y^3z}{xy^{-4}z^4}=x^{-3+2\cdot(-2)-1}y^{3+4}z^{1-4} \\ =x^{-3-4-1}y^7z^{-3} \\ =x^{-8}y^7z^{-3} \\ =\frac{y^7}{x^8z^3} \end{gathered}[/tex]Label the image correctly (some of the choices are wrong) : True False 4-3-6-4Increasing DecreasingSlope is =Slope is equal to = (make sure you simplify)True or False the line passes through the origin ?
To solve the exercise, you can take the two points highlighted on the graph and use the slope formula
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{ Where} \\ (x_1,y_1),(x_2,y_2)\text{ are two points }through\text{ which the line passes and} \\ m\text{ is the slope of the line} \end{gathered}[/tex]So, if you take
[tex]\begin{gathered} (x_1,y_1)=(-4,2) \\ (x_2,y_2)=(4,-4) \end{gathered}[/tex]the slope of the line will be
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-4-2}{4-(-4)} \\ m=\frac{-6}{4+4} \\ m=\frac{-6}{8} \\ \text{ Simplifying} \\ m=\frac{2\cdot-3}{2\cdot4} \\ m=\frac{-3}{4} \end{gathered}[/tex]Now, with the point slope equation you can write the equation of the line in its slope-intercept form
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Where }(x_1,y_1)\text{ is one point through which the line passes} \end{gathered}[/tex]So, if you take the point (-4,2) you have
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2=\frac{-3}{4}(x-(-4)) \\ y-2=\frac{-3}{4}(x+4) \\ y-2=\frac{-3}{4}x-\frac{3}{4}\cdot4 \\ y-2=\frac{-3}{4}x-3 \\ \text{ Add 2 on both sides the equation} \\ y-2+2=\frac{-3}{4}x-3+2 \\ y=\frac{-3}{4}x-1 \end{gathered}[/tex]Then, the equation of the line in its slope-intercept form is
[tex]y=-\frac{3}{4}x-1[/tex]And to find out if the line passes through the origin, plug x = 0 into the equation found
[tex]\begin{gathered} y=-\frac{3}{4}x-1 \\ y=-\frac{3}{4}(0)-1 \\ y=0-1 \\ y=-1 \end{gathered}[/tex]That means that the line passes through the point (0, -1) and not through the point (0,0). Therefore, the line does not pass through the origin, and the answer is False.
Finally, since the slope of the line is negative, then the line is decreasing.
A baseball team holds a pizza night at the Ballpark. The table below shows the pieces for different numbers of pizzas.which set of ordered pairs could be added to this table?
Let's find the linear function which represents the table:
[tex]\begin{gathered} y=mx+b \\ for \\ x=2,y=4 \\ 4=2m+b_{\text{ }}(1) \\ ---- \\ for \\ x=10,y=20 \\ 20=10m+b_{\text{ }}(2) \\ (2)-(1) \\ 16=8m \\ m=\frac{16}{8}=2 \\ ---- \\ 4=2(2)+b \\ b=4-4=0 \end{gathered}[/tex]So:
[tex]y(x)=2x[/tex]For:
[tex]\begin{gathered} x=3 \\ y(3)=2(3)=6 \\ ----- \\ x=7 \\ y\mleft(7\mright)=2\mleft(7\mright)=14 \\ ----- \\ x=9 \\ y(9)=2(9)=18 \end{gathered}[/tex]Answer:
(3,6)
(7,14)
(2,18)
Mia earned some money doing odd jobs last summer and put it in a savings account that earns 11% interest, compounded annually. After 10 years, there is $800.00 in the account. How much did Mia earn doing odd jobs?
ANSWER
$281.69
EXPLANATION
Let the amount of money she earned doing odd jobs be P.
She put it in a savings account that earned 11% compound interest for 10 years, yielding $800.
To find out how much she earned (put in the account), we have to use the Compound interest formula:
[tex]A=P(1+r)^t[/tex]where A = amount earned (Principal + interest)
P = Principal (amount saved)
r = interest rate
t = amount of years
Therefore, from the question:
A = $800
P = P
r = 11% = 0.11
t = 10 years
Therefore, we have that:
[tex]\begin{gathered} 800=P(1+0.11)^{10}=P(1.11)^{10} \\ 800\text{ = P }\cdot\text{ 2.84} \\ P\text{ = }\frac{800}{2.84} \\ P\text{ = \$}281.69 \end{gathered}[/tex]That is the amount that she earned doing odd jobs.
find the coordinates of the point equidistant from (4,-6) and the origin, as well as on the line 2x-y=9
We have to find the coordinates of the point equidistant from (4,-6) and the origin, as well as on the line 2x-y=9.
We can graph the line and the points to have an idea of the problem:
We can write the distance from our point (x,y) to the point (4,-6) as:
[tex]D_1=\sqrt[]{(x-4)^2+(y+6)^2}[/tex]If we replace y with the value of the equation we get:
[tex]2x-y=9\longrightarrow y=2x-9[/tex][tex]D_1=\sqrt[]{(x-4)^2+(2x-9+6)^2}=\sqrt[]{(x-4)^2+(2x-3)^2}[/tex]For the distance of our point (x,y) to the origin (0,0) we get:
[tex]\begin{gathered} D_2=\sqrt[]{(x-0)^2+(y-0)^2} \\ D_2=\sqrt[]{x^2+(2x-9)^2} \end{gathered}[/tex]If the point is equidistant to both points, both distances are equal, so we can write:
[tex]\begin{gathered} D_1=D_2 \\ \sqrt[]{(x-4)^2+(2x-3)^2}=\sqrt[]{x^2+(2x-9)^2} \\ (x-4)^2+(2x-3)^2=x^2+(2x-9)^2 \\ (x^2-8x+16)+(4x^2-12x+9)^2=x^2+(4x^2-36x+81) \\ 5x^2-20x+25=5x^2-36x+81 \\ 5x^2-5x^2-20x+36x=81-25 \\ 16x=56 \\ x=\frac{56}{16} \\ x=3.5 \end{gathered}[/tex]We know the x-coordinate (x=3.5), so we can now calculate the y-coordinate as:
[tex]y=2x-9=2\cdot3.5-9=7-9=-2[/tex]Then, the coordinates for the equidistant point is (3.5, -2)
We can graph this as:
Answer: Coordinates of the point (x,y)=(3.5,-2)
For an elementary algebra course the total course points are calculated by adding points earned on homework, quizzes and tests. If the total scores of tests is worth 1/3 and the final exam is worth 1/4, what fraction of the course points comes from homework and quizzes?
STEP-BY-STEP EXPLANATION:
As you can see from the question provided, you were told that the total course points are calculated from the points gotten from homework, quizzes, and tests.
Based on the questions, we have the following information.
The total scores of the test = 1/3
The final exam worth = 1/4
Let the quizzes score be x
Let the homework score be y
Recall that, the final exam score will determine the total points earned in a course
Therefore, we have
Final score = quizzes score + tests scores + homework score
Given: points A(5, 1), B(5,5), C(1,3), Q(-6,-5) and R(-4,-5). What coordinates for S would prove AABC~AQRS (T.G.7)(2 point) B с QR O A. (-4,-3) O B. (-5,-8) O C. (-3,-5) o D. (-5,-3)
Given:
A(5, 1), B(5, 5), C(1, 3)
Q(-6, 5), R(-4, -5), S(__, __)
To find the coordinates of S that would prove that ABC is similar to QRS, we have:
First Find the distance betweem AB and the distance between QR using the distance formula below:
[tex]\begin{gathered} D=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \end{gathered}[/tex]Distance between AB:
[tex]\begin{gathered} AB=\sqrt[]{(5-5)^2+(5-1)^2} \\ \\ AB=\sqrt[]{0+16} \\ \\ AB\text{ = 4} \end{gathered}[/tex]Distance between QR:
[tex]\begin{gathered} QR=\sqrt[]{(-4--6)^2+(-5-}-5)^2 \\ \\ QR=\sqrt[]{(-4+6)^2+(-5+5)^2} \\ \\ QR\text{ = }\sqrt[]{(2)^2+(0)^2} \\ \\ QR=\sqrt[]{4} \\ \\ QR\text{ = 2} \end{gathered}[/tex]Since ABC is similar to QRS, we have:
AB ~ QR
AB = 4
QR = 2
The scale factor is:
[tex]\frac{AB}{QR}=\frac{4}{2}=2[/tex]Since the scale factor is 2, Let's find the coordinates of S:
Find the distance between BC and AC .
Thus, we have:
The coordinates of S that would prove that ABC is similar to QRS is:
(-3, -5)
Choice C is correct
ANSWER:
C. (-3 -5)
please help and explain I have no idea what e and in meanssimplify this
Given
[tex](e^{2-\sqrt{3}})^{2+\sqrt{3}}[/tex]To simplify.
Explanation:
It is given that,
[tex](e^{2-\sqrt{3}})^{2+\sqrt{3}}[/tex]Since
[tex](a^x)^y=a^{xy}[/tex]That implies,
[tex]\begin{gathered} (e^{2-\sqrt{3}})^{2+\sqrt{3}}=e^{(2-\sqrt{3})(2+\sqrt{3})} \\ =e^{4-3} \\ =e^1 \\ =e \end{gathered}[/tex]Hence, the answer is e.
convert the equation into vertex form, then solve the equation x^2 + 6x + 8 = 0
The Vertex form of a Quadratic function is:
[tex]f(x)=a\mleft(x-h\mright)^2+k[/tex]Where the vertex of the paraboola is:
[tex](h,k)[/tex]Given the following Quadratic equation:
[tex]x^2+6x+8=0[/tex]You need to convert it into Vertex form by completing the square. The steps are shown below:
- Identify the coefficient of the term with the variable "x". In this case, this is:
[tex]b=6[/tex]- Divide it by 2 and square it:
[tex](\frac{b}{2})^2=(\frac{6}{2})^2=3^2[/tex]- Add and subtract the number obtained (in the right side of the equation):
[tex]x^2+6x+8+3^2-3^2=0[/tex]- Order it and express it as a square of a binomial, you get:
[tex]\begin{gathered} (x^2+6x+3^2)+8-3^2=0 \\ (x+3)^2-1=0 \end{gathered}[/tex]- Add 1 to both sides of the equation:
[tex]\begin{gathered} (x+3)^2-1+1=0+1 \\ (x+3)^2=1 \end{gathered}[/tex]To solve the equation you must take the square root of both sides of the equation:
[tex]\begin{gathered} \sqrt[]{(x+3)^2}=\pm\sqrt[]{1} \\ \\ x+3=\pm1 \end{gathered}[/tex]Finally, subtract 3 from both sides of the equation:
[tex]\begin{gathered} x+3-3=\pm1-3 \\ \\ x=-3\pm1 \\ \\ x_1=-3+1=-2 \\ x_2=-3-1=-4 \end{gathered}[/tex]The answer is:
- Vertex form:
[tex](x+3)^2=1[/tex]- Solutions:
[tex]\begin{gathered} x_1=-2 \\ x_2=-4 \end{gathered}[/tex]Check all of the values that have three significant figures. A. 0.690B. 356C. 5.03D. 1408
we have the following:
0.690, has 3 significant figures
356,
1.Noah has a coupon for 30% off at his favorite clothing store. He uses it to buy a hoodieand a part of jeans.Noah paid $28 for the jeans after using the coupon.If the regular price of an item is x dollars and the item is 30% off, how wouldyou find the new price?
Step 01:
coupon = 30% off
Step 02:
which of the following are like terms with 17 select all that apply A.-4y B.10x C. 8 d. .257
The first step that anna made is that she subtracted 12x from both sides.
Determine the shaded area.The shaded area is(Type an integer or decimal rounded to the nearest hundredth
The shaded area is equal to the area of the circle substracted fromt he area of the trapezoid:
[tex]A=A_T-A_C[/tex]Area of a trapezoid:
[tex]A_T=\frac{(a+b)}{2}\cdot h[/tex]a is long base
b is short base
h is height
Area of a circle:
[tex]A_C=\pi\cdot r^2[/tex]The given trapezoid has a height equal to 2 times the radius of the circle in it. Then, the area of the shaded area is:
[tex]A=\frac{(a+b)}{2}\cdot2r-\pi\cdot r^2[/tex]a=13in
b=9in
r=3in
[tex]\begin{gathered} A=\frac{(13in+9in)}{2}\cdot2(3in)-\pi\cdot(3in)^2 \\ \\ A=\frac{(22in)}{2}\cdot6in-9\pi in^2 \\ \\ A=66in^2-9\pi in^2 \\ \\ A\approx37.73in^2 \end{gathered}[/tex]Assi Science Test Scores 6 2 8 9 7 2 5 5 5 8 8 8 8 9 8. 2. 2. 2. 6 6 9 9 9 0 0 0 2 2 5 5 5 Key: 812 means 82 1. How many students scored 78? (1 point) 1 student O2 students 3 students 4 students
The stem and leaf plot is a way to plot data, allowing people to do a fast counting of a set of data.
As said in the key, 8|2 means 82, then to find how many people scored 78, we need to look for the "7" row and count how many "8" are there.
In the "7", which is the second row, there are 4 "8".
That means that 4 students scored 78.
The following illustration is a Venn diagram. Which of the following numbers can be placed in the shaded area of the diagram? F --3/7G 25/5H -9.25J-3
From the diagram,
Whole numbers are the real numbers which include zero and all the positive integers. It does not include fractional numbers or negative integers.
Integers are whole numbers, but they also include negative numbers.
Therefore,
The intersection of both whole numbers and integers are all whole numbers.
Hence,
[tex]\frac{25}{5}\text{ = 5 is both integer and whole number}[/tex]The final answer is 25/5 G
Kerri made 27 of 40 shots. What percentage of shots did she make?
40 represent 100%
27 represent x
x is the percentage of shots
x can be calculated in the next way
[tex]x=\frac{27\cdot100}{40}=67.5[/tex]the answer is 67.5 %
I need help on showing work but it can’t be substitution! :(
(x - 5)^2 = 81
x^2 - 10x + 25 = 81
x^2 - 10x -56 = 0
The equation of bhaskara is
[tex]x=\frac{-b\text{ }\pm\sqrt[]{b^2-4ac}}{2a}[/tex]In this case, we have, a = 1, b = -10 and c = -56
Therefore:
[tex]x_+=\frac{10\text{ +}\sqrt[]{100+4\cdot56}}{2}=14_{},x_-=\text{ }\frac{10-\sqrt[]{100+4\cdot56}}{2}=\text{ -4}[/tex]Prescription for Marilyn JonesPiroxicam 20 milligrams (mg) capsules: take 1 capsule 2 times a dayGlucotrol 2.5 milligrams (mg) tablets: take 1 tablet every morningIsoniazid 100 milligrams (mg) tablets: take 1 tablet 3 times a dayHow many tablets should the pharmacy give Marilyn to fill the Isoniazid for 45 days?
Let:
a = tablets per day
x = Number of days
y = Total tablets
so:
[tex]\begin{gathered} y=ax \\ where \\ a=3 \\ x=45 \\ so\colon \\ y=3\cdot45 \\ y=135 \end{gathered}[/tex]Answer:
135 tablets
Look at the point P on the number line.Which number lines have a point that is equal to pointP? Check all that apply.р
In the given Number line the differece between each interval is 10
and the Point P is at -40
Since,
In the graph
A)
the first is -60, then it will be -50 So,
The point P is at -50
Thus the the number line have the same point
B) In the given number line the first point is -60
then -50, -40 and then -30
So, the point is at -30
This number line is not equal to the given number line
C) In the given number line the first point is at -60
and there are three interval so, the the three interval have the values 20
So, the second point will be -40
and the third will be -20
So, the point is at -40
The number line is equal to given number line
D) In the given number line, the interval are divided by 4 parts so
the each interval of the 15 units
the first is at -60
second is at -45
and the point is at -45
So, The number line is not equal to the given number line
The admission fee at an amusement park is 1.5 dollars for children and 4 dollars for adults. On a certain day, 282 people entered the park, and the admission fees collected totaled 748 dollars. How many children and how many adults were admitted? Your answer is number of children equals number of adults equals Submit Question M
We have to calculate the number of children (C) and the number of adults (A) that were admitted.
The number of people, that is the sum of the children and the adults, is 282. Then, we can write:
[tex]C+A=282[/tex]The ticket collection was $748, where each children pay $1.5 and each adult pays $4. Then, we can write:
[tex]1.5\cdot C+4\cdot A=748[/tex]Now, we have a system of 2 equations with 2 unknowns. We can solve it by substitution, using:
[tex]A=282-C[/tex][tex]\begin{gathered} 1.5C+4A=748 \\ 1.5C+4\cdot(282-C)=748 \\ 1.5C+4\cdot282-4\cdot C=748 \\ -2.5C+1128=748 \\ -2.5C=748-1128 \\ -2.5C=-380 \\ C=\frac{-380}{-2.5} \\ C=152 \end{gathered}[/tex]Now that we know the number of children C, we can calculate the number of adults A as:
[tex]A=282-C=282-152=130[/tex]Answer:
Number of children = 152
Numbre of adults = 130
Which of the following is the graph of y 2x+2?
hello, to solve this question, we need to look the function:
[tex]y\text{ }\ge\text{ }\frac{1}{3}x\text{ +2}[/tex]So, let's see the graphics:
remember: for this question, only values equal to or greater than y are of interest
We can solve by attempts:
when x = 0:
[tex]\begin{gathered} y\text{ }\ge\text{ }\frac{1}{3}\cdot0\text{+2} \\ y\ge2 \end{gathered}[/tex]At this moment, we can discard two options: A and C.
Why? Because when x = 0, just interest for us y>= 2.
when x = 1:
[tex]\begin{gathered} y\text{ }\ge\text{ }\frac{1}{3}\cdot1\text{+2} \\ y\text{ }\ge2.33 \end{gathered}[/tex]when x = 2:
[tex]\begin{gathered} y\text{ }\ge\text{ }\frac{1}{3}\cdot2\text{+2} \\ y\ge2.66 \end{gathered}[/tex]As we have the sign "greater than or equal to", we can conclude that it is a closed representation, so the line must be continuous.
Right answer: B.
Find the real numbers that satisfy the equation below. Express your answer in set-builder notation
We will have the following:
The values that satisfy the expression are:
[tex]x\ge0[/tex]sin 300 and cos 30º = 5 ° 2 2. ✓
Given:-
[tex]sin30=\frac{1}{2},cos30=\frac{\sqrt{3}}{2}[/tex]To find the given data is true or false.
So the value of,
[tex]sin30=\frac{1}{2}[/tex]Also the value of,
[tex]cos30=\frac{\sqrt{3}}{2}[/tex]Also the table is,
So the answer is true.
Jacob earns $15 per hour. He has saved $200 and is planning to buy a dresser that costs $500 Which of these represent the number of hours' pay, x, that Jacob must save to be able to purchase the dresser? Choose ALL that are correct. A 2 > 20 B x < 20 0 15x > 300 D 15x + 200 > 500 E 15x + 200 < 500
Problem
Jacob earns $15 per hour. He has saved $200 and is planning to buy a dresser that costs $500 Which of these represent the number of hours' pay, x, that Jacob must save to be able to purchase the dresser?
Solution
15x +200 >500
And that expression is equivalent to :
15 x > 500-200
15 x >300
consider the function f(x)=‐2/3x-24
Step 1
Find the inverse function
[tex]undefined[/tex]sketch the graph-2x+3y= -1
Given the equation:
[tex]-2x+3y=-1[/tex]The given equation represents a line
To graph the line, we need two points lying on the line
We will substitute with two values for x and find the corresponding values of y
So, when x = 5
[tex]\begin{gathered} -2\cdot5+3y=-1 \\ -10+3y=-1 \\ 3y=10-1=9 \\ y=\frac{9}{3}=3 \end{gathered}[/tex]And when x = -4
[tex]\begin{gathered} -2\cdot-4+3y=-1 \\ 8+3y=-1 \\ 3y=-1-8=-9 \\ y=-\frac{9}{3}=-3 \end{gathered}[/tex]So, the line passes through the points (5, 3) and (-4, -3)
We will draw the line segment connecting the points then extend it from both sides
The graph of the equation will be as shown in the following picture
Consider the line y=4/7x-7Find the equation of the line that is perpendicular to this line and passes through the point (7,2)Find the equation of the line that is parallel to this line and passes through the pint (7,2)What is the equation of the perpendicular line :What is the equation of the parallel line:
The general equation of line with slope m is express as :
y = mx + b
The given equation of line : y = 4/7x - 7
On comparing with the general form of line we get m = 4/7
Two lines are said to be perpendicular if the products of thier slope is (-1)
Let the slope of perpendicular line is n
So,
[tex]\begin{gathered} mn=(-1) \\ \frac{4}{7}n=(-1) \\ n=(-1)\times\frac{7}{4} \\ n=(-\frac{7}{4}) \end{gathered}[/tex]So, the slope of perpendicular line is (-7/4)
The line is passing through (7,2)
Substitute them in the general equation of line:
y - 2 = (-7/4)(x-7)
So, equation of line is :
[tex]y-2=(\frac{-7}{4})(x-7)[/tex]
Please help me I don’t understand this concept on number 4
This is an example of property tax. This is because he is paying a tax for a property he owns, which is his house.
So the correct answer is option H. Property