what is the minimum probability of receiving the franchise that sporthotel will accept and still believe it is wise to build the hotel? (hint: what probability will give npv)

The probability of exactly one successes in five trials  is 0.20

From the question, we have the following parameters that can be used in our computation:

The probability is calculated as

P(x) = nCx * p^x * (1 - p)^(n -x)

Where

n = 5

p = 5%

x = 1

Substitute the known values in the above equation, so, we have the following representation

P(1) = 5C1 * (5%)^1 * (1 - 5%)^(5 -1)

Evaluate

P(1) = 0.20

HEnce, the probability value is 0.20

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The measure of angle FED is 5x + 1°.

Let's use the angle DFE to solve for the measure of angle FED. We know that angle DFE measures (8x - 20)°. Since the diagonals of a rhombus bisect each other, we can use the fact that angle DFE is divided into two equal parts by diagonal DE.

Each of these two equal parts has measure (1/2)(8x - 20)° = 4x - 10°. Let's denote the measure of angle CDE as "y". Since angles DCE and CDE are complementary (they add up to 90°), we know that angle CDE has measure (90 - y)°.

Now, we can use the fact that the diagonals of a rhombus are perpendicular bisectors of each other. This means that angle CFD (which has measure (5x + 1)°) is equal to angle CDE (which has measure (90 - y)°).

Setting these two expressions equal to each other, we get:

5x + 1 = 90 - y

Solving for y, we get:

y = 89 - 5x

Now we can use the fact that angles DCE and CDE are complementary to find the measure of angle FED. Angle FED is equal to (90 - y)°, which is:

(90 - (89 - 5x))° = 5x + 1°

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Answer:

To find out how many minutes Valeria would practice in 4 weeks, we need to first find out how many minutes she practices per week.

Divide the total number of minutes she practices by the number of weeks she practices:

910 minutes ÷ 5 weeks = 182 minutes per week

Valeria practices 182 minutes per week.

To find out how many minutes she would practice in 4 weeks, we can multiply the minutes per week by the number of weeks:

182 minutes/week x 4 weeks = 728 minutes in 4 weeks

Valeria would practice 728 minutes in 4 weeks.

Answer:

replace

y

with

0

and solve for

x

.

Step-by-step explanation:

x=-1/3,2

Note that the equation of the line perpendicular to the tangent to the curve y = x³ − 3x+1 is y = (-1/9)x + 7/3.

To find the  equation of the line perpendicular to the tangent of the curve at  the point (2, 3):


Get the slop of the tangent at that point.

To do this, we take  derivative of the function y = x³ - 3x + 1 and evaluating it at x = 2:

y' = 3x² - 3

y '(2) = 3 (2) ² -  3 = 9

So the slope of  (2, 3) =  9.

Since   the line we are looking for is  perpendicular to this tangent, its slope will be the  negative reciprocal of 9, which is -1/ 9.

Next,  use the point-slope form of a line to write the equation of the line

y - 3 = (-1/9) ( x - 2)

⇒ y = (-1/9)x  + 7/3

So the  equation of the lie perpendicular to the tangent to the curve at the point (2,3) is y = (-1/9)x + 7/3.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Find equation to the line perpendicular to the tangent to the curve y=x³−3x+1 , at the point (2,3)

.

We first calculate D⁴:

D⁴ = |1⁴ 0 0 |

|0 2⁴ 0 |

|0 0 4⁴|

Substituting into the formula, we get:

A⁴ =

Question 1:

To find the eigenvalues and eigenvectors of matrix A, we solve the characteristic equation:

|A - λI| = 0

where I is the identity matrix and λ is the eigenvalue.

Substituting A, we get:

|1-λ 1 3 |

|1 5-λ 1 | = 0

|3 1 1-λ|

Expanding the determinant, we get:

(1-λ) [(5-λ)(1-λ) - 1] - (1)[(1)(1-λ) - (3)(1)] + (3)[(1)(1) - (5-λ)(3)] = 0

Simplifying, we get:

-λ³ + 7λ² - 14λ + 8 = 0

This equation can be factored as:

-(λ-1)(λ-2)(λ-4) = 0

Therefore, the eigenvalues of A are λ1 = 1, λ2 = 2, and λ3 = 4.

To find the eigenvectors, we solve the equation (A-λI)x = 0 for each eigenvalue.

For λ1 = 1, we get:

|0 1 3 | |x1| |0|

|1 4 1 | |x2| = |0|

|3 1 -0 | |x3| |0|

Simplifying, we get the system of equations:

x2 + 3x3 = 0

x1 + 4x2 + x3 = 0

3x1 + x2 = 0

Solving this system, we get:

x1 = -3x3

x2 = x3

x3 = x3

So, the eigenvector corresponding to λ1 = 1 is:

v1 = (-3, 1, 1)

Similarly, for λ2 = 2, we get:

v2 = (-1, 1, -1)

And for λ3 = 4, we get:

v3 = (1, 1, -3)

Therefore, the eigenvalues of A are 1, 2, and 4, and the corresponding eigenvectors are (-3, 1, 1), (-1, 1, -1), and (1, 1, -3).

Question 2:

To find the matrix P that transforms A to diagonal form, we need to find the eigenvectors of A and use them as columns of P. That is:

P = [v1 v2 v3]

where v1, v2, and v3 are the eigenvectors of A.

From Question 1, we have:

v1 = (-3, 1, 1)

v2 = (-1, 1, -1)

v3 = (1, 1, -3)

So, the matrix P is:

P = |-3 -1 1|

| 1 1 1|

| 1 -1 -3|

To calculate A⁴, we use the formula:

Aⁿ = PDⁿP⁻¹

where Dⁿ is the diagonal matrix with the eigenvalues raised to the nth power.

So, we first calculate D⁴:

D⁴ = |1⁴ 0 0 |

|0 2⁴ 0 |

|0 0 4⁴|

Substituting into the formula, we get:

A⁴ =

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The final amount after 20 years, compounded quarterly is $6,353.98.

The final amount after 5 years, compounded continuously, is  $1,145.10.

we can use the formula for compound interest:

[tex]A = P(1 + r/n)^(^n^\times^t^)[/tex]

where A is the final amount,

P is the principal (starting amount),

r is the annual interest rate, t is the time in years, and n is the number of times compounded per year.

Plugging in the given values, we get:

[tex]A = 3750(1 + 0.035/4)^(^4^\times^2^0^)[/tex]

A = $6,353.98

Therefore, the final amount after 20 years, compounded quarterly, is approximately $6,353.98.

P= $1,000; r=2.8%, t= 5yrs compounded continuously ​

For the second problem, we can use the formula for continuous compounding:

[tex]A = Pe^(^r^t^)[/tex]

[tex]A = 1000e^(^0^.^0^2^8^\times^5^)[/tex]

A = $1,145.10

Therefore, the final amount after 5 years, compounded continuously, is  $1,145.10.

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The actual length and width of the kitchen in the scale drawing is: 22.5 ft x 17.5 ft

A scale drawing is defined as an enlargement of an object. An enlargement changes the size of an object by multiplying each of the lengths by a scale factor to make it larger or smaller. The scale of a drawing is usually stated as a ratio.

Now, the scale factor of the given drawing is seen as 2 in : 5 ft

From the drawing the dimensions of the kitchen are:

9" x 7"

Thus:

True length = (9 * 5)/2 = 22.5 ft

True width = (7 * 5)/2 = 17.5 ft

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Arun is going to invest $7,700 and leave it in an account for 20 years. Assuming theinterest is compounded continuously, what interest rate, to the nearest hundredth ofa percent, would be required in order for Arun to endend up with $13,100?

So first you do 13,100 minus 7700 equals 5400. Now you have 5400 you want to divide it by 20 which equals 270. So over the course of 20 years it went up to 13100. Which means every year it had to go up by $270 but that’s not a percent so… we have to divide 13100 by 5400 which equals 2.43 (Hope this helps)

To find the sum of all left leaves in a binary tree, Python programming language is used and code is written in Phyton.

Here's the Python code to find the sum of all left leaves in a binary tree:

Class TreeNode:

def __init__(self, x):

self.val = x

self. left = none

self.right = None

def sum_of_left_leaves(root):

If not root:

return 0

# If the left child of the root node is a leaf node, add its value to the total

If root. left is root.left.left and not root. left.right :

returns root. left.val + sum_of_left_leaves(root.right)

# Recursively go left and right subtrees and add their left leaves to the sum

returns sum_of_left_leaves(root. left) + sum_of_left_leaves(root. right)

This code first checks to see if the root node is None. If so, return 0 as there are no leaves left to add.

Then check if the left child of the root node is a leaf node. If so, add that value to the total and recursively traverse only the correct subtree.

If the left child of the root node is not a leaf node, recursively traverse the left and right subtrees and add the left leaves of both subtrees to the total.

Finally, it returns the sum of the leaves on the left side of the entire binary tree.

To utilize this work, make a double tree utilizing the TreeNode lesson and call the sum_of_left_leaves to work, passing the root of the twofold tree as a contention. 

Here is an example of using the function:

# build a binary tree

root = tree node (3)

root. left = tree node (9)

root. right = tree node (20)

root. right.left = TreeNode(15)

root. right.right = TreeNode(7)

# compute the sum of the leaves on the left

sum = sum_of_left_leaves(root)

# print result

print(sum) # output:

twenty-four 

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The initial mortality rate in 1998 per 100,000 people is :

88.8 deaths

To find the initial mortality rate in 1998, you'll need to use the given relation :

M = 88.8(0.9418)^t, where M is the number of deaths per 100,000 people, and t is the number of years since 1998.

Identify the value of t for 1998. Since 1998 is the starting year, t = 0.

Substitute the value of t into the equation. M = 88.8(0.9418)^0

Calculate M. Since any number raised to the power of 0 is 1, the equation becomes M = 88.8(1), which simplifies to M = 88.8.

So, the initial mortality rate in 1998 is 88.8 deaths per 100,000 people.

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Answer:

The expression that represents how much money Monique will make this week is:

12h + 20

Where 12h represents the money she earns as a lifeguard (h hours at $12 per hour) and 20 represents the money she earns for dog sitting.

Answer:

Step-by-step explanation :

I suggest you ask an expert

Answer: Y = 45x + 140

Step-by-step explanation:

which equation represents the length of the completed tunnel based on the number of days since tbm was introduced? the answer is y = 45x + 140

If Charlotte will take out the garbage for 15 weeks,  Charlotte will earn 327.67 dollars on the 15th week.

To find how much Charlotte will earn on the 15th week, we can use the formula for the sum of a geometric series:

Sₙ = a(1 - rⁿ) / (1 - r)

where Sₙ is the sum of the first n terms of the series, a is the first term, r is the common ratio, and n is the number of terms.

In this case, a = 1 cent, r = 2 (since each week Charlotte earns twice as much as she did the week before), and n = 15. Substituting these values into the formula gives:

S₁₅ = 1(1 - 2¹⁵) / (1 - 2)

S₁₅ = (1 - 32768) / (-1)

S₁₅ = 32767 cents

Therefore, Charlotte will earn 327.67 dollars on the 15th week.

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For Daniel's four-day business trip, the total fixed costs for the car rental from car rental agency is equals the $153.2.

We have, Daniel plans to rent a car for an upcoming four-day business trip.

Flat fee charges for rent a car from car rental agency = $29 per day

Charges for driven = $0.12 per mile

Total distance travelled by him on first day = 140 miles

Cost of driven charges on first day = 140× 0.12 = $16.8

Total distance travelled by him on secon day = 15 miles

Cost of driven charges on first day = 15× 0.12 = $1.8

Total distance travelled by him on third day = 15 miles

Cost of driven charges on first day = 15× 0.12 = $1.8

Total distance travelled by him on fourth day = 140 miles

Cost of driven charges on first day = 140 × 0.12 = $16.8

Total cost of driven charges on four-day business trip = $16.8 + $16.8 + $1.8 + $1.8

= $37.2

Now, total fixed cost for rent a car are calculated by sum of driven charges and flat fee for rent = $37.2 + 4×$29

= $153.2

Hence required value is $153.2.

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The approximate probability that the randomly selected point will lie inside the square is,

≈ 13.3%

Since, Area of square with side of 5 mm is:

A = a² = (5 mm)² = 25 mm²

Now, Find total area of the figure:

A(total) = A(trapezoid) + A(triangle)

A(total) = (b₁ + b₂)h/2 + bh/2

A(total) = (14 + 18)(17 - 12)/2 + 18 x 12/2

           = 80 + 108 = 188

Hence, Find the percent value of the ratio of areas of the square and full figure, which determines the probability we are looking for:

= 25/188  x 100%

= 13.2978723404 %

≈ 13.3%

Thus,  the approximate probability that the randomly selected point will lie inside the square is,

≈ 13.3%

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Answer:

5 units

Step-by-step explanation:

To determine the distance between the points (-3, -2) and (0, 2), we can use the distance formula.

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Distance Formula}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where:\\ \phantom{ww}$\bullet$ $d$ is the distance between two points. \\\phantom{ww}$\bullet$ $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]

Let (x₁, y₁) = (-3, -2)

Let (x₂, y₂) = (0, 2)

Substitute the values into the formula and solve for d:

[tex]\begin{aligned}\implies d&=\sqrt{(0-(-3))^2+(2-(-2))^2}\\&=\sqrt{(0+3)^2+(2+2)^2}\\&=\sqrt{(3)^2+(4)^2}\\&=\sqrt{9+16}\\&=\sqrt{25}\\&=5\; \rm units \end{aligned}[/tex]

Therefore, the distance between the given points (-3, -2) and (0, 2) is 5 units.

Answer:is 5

Step-by-step explanation: cuz I read other answer

The function is not differentiable at two points, C=1 and C=2, making the answer (d) two.

The given function involves four absolute value terms. To determine the points where the function is not differentiable, we need to check where the absolute value terms change their behavior.

The term |2c| is differentiable everywhere since it always yields a non-negative value, irrespective of the value of c.

The term |2C-2| changes its behavior at C=1, where it changes from decreasing to increasing. The function is not differentiable at C=1. The term |2x-3| is differentiable everywhere.

The term |2C-4| changes its behavior at C=2, where it changes from decreasing to increasing. The function is not differentiable at C=2.

The function is not differentiable at the points where the absolute value terms change from decreasing to increasing or vice versa, which results in a sharp corner or a cusp in the graph of the function.

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A. The domain is N and the image is the set of all natural numbers that are products of two natural numbers

B. The image is all values of y in Q such that (1 - 2x)/3 is defined.

C. we note that y² + 1 is always odd, so the image is the set of all odd natural numbers greater than or equal to 2.

What is function?

In mathematics, a function is a relationship between two sets of elements, called the domain and the range, such that each element in the domain is associated with a unique element in the range.

(a) R is a function because for each x in N, there exists a unique y in N such that xy. The domain is N and the image is the set of all natural numbers that are products of two natural numbers.

(b) R is a function because for each x in Q, there exists a unique y in Q such that 2x+3y=1. To find the domain, we solve for x in terms of y: 2x = 1 - 3y, x = (1 - 3y)/2. The domain is all values of y in Q such that (1 - 3y)/2 is defined. Simplifying, we get y ≠ 1/3. Therefore, the domain is Q - {1/3}. To find the image, we solve for y in terms of x: 3y = 1 - 2x, y = (1 - 2x)/3. The image is all values of y in Q such that (1 - 2x)/3 is defined. Therefore, the image is Q.

(c) R is a function because for each x in N, there exists a unique y in N such that y²+1=x. To find the domain, we solve for x in terms of y: y² = x - 1, y = ±√(x - 1). Since we are given that x and y are natural numbers, the domain is the set of all natural numbers greater than or equal to 2. To find the image, we note that y² + 1 is always odd, so the image is the set of all odd natural numbers greater than or equal to 2.

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To determine the value of "r" between age and salary, we would need to conduct a statistical analysis, such as a correlation coefficient calculation. Without this information, it is impossible to determine the direction or strength of the relationship between age and salary.

Similarly, without the results of a regression analysis, it is not possible to determine the value of R², which represents the proportion of variance in the dependent variable (salary) that can be explained by the independent variable (age). Once this value is known, we can use the rubric to determine the strength of the predictor.

However, based on the rubrics provided, if the correlation coefficient (r) is close to -1 or 1, the relationship between age and salary would be considered very strong, either negatively or positively correlated. If the coefficient is closer to 0, the correlation would be considered weak or somewhat weak.

Similarly, R² measures the proportion of variance in the dependent variable (salary) that is explained by the independent variable (age). A value of 1 would indicate a perfect predictor, while a value of 0 would indicate no relationship between the variables. Values between 0 and 1 would indicate varying degrees of predictive power.

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a) To calculate the probability that the sample proportion of defective cups from Supplier A is less than 10%, we need to find the probability that the sample proportion is less than 0.10. Thus, we need to find P(p < 0.10).

We can use the central limit theorem to approximate the distribution of the sample proportion as a normal distribution, with mean μ = 0.08 and standard deviation [tex]σ = \sqrt{0.08 (\frac{1-0.08)}{200} )}= 0.024[/tex]. Then, we can standardize the distribution and use a standard normal table or calculator to find the probability:

[tex]P (p < 0.10)=P(\frac{p-u}{σ} < \frac{0.10-0.08}{0.024} = P(z < 0.83)=0.7977[/tex]

Therefore, the probability that the sample proportion of defective cups from Supplier A is less than 10% is approximately 0.7977.

b) To calculate the probability that the sample proportion of defective cups from Supplier A is at least 5%, we need to find the probability that the sample proportion is greater than or equal to 0.05. Thus, we need to find P(p≥ 0.05).

Using the same approach as in part (a), we can find that                                                             P(p < 0.05)=-0.0207. Therefore, P(p ≥ 0.05) = 1 - P(p< 0.05) =0.9793.

Therefore, the probability that the sample proportion of defective cups from Supplier A is at least 5% is approximately 0.9793.

c) To calculate the probability that the sample proportion of defective cups from Supplier A is between 5% and 10%, we need to find the probability that 0.05 ≤ p < 0.10. We can use the same approach as in part (a) to find that P(p < 0.05) = 0.0207 and P(p < 0.10) = 0.7977. Therefore, P(0.05 ≤ p < 0.10) = P(p < 0.10) - P(p < 0.05) = 0.7770.

Therefore, the probability that the sample proportion of defective cups from Supplier A is between 5% and 10% is approximately 0.7770.

d) To calculate the probability that the sample proportion of defective cups from Supplier A is exactly 8%, we need to find P(p = 0.08). Since the sample proportion is a discrete random variable, we can use the binomial distribution to find the probability:

[tex]P(p=0.08)=(200 choose 16) (0.080)^{16} (1-0.08)^{184} = 0.1567[/tex]

Therefore, the probability that the sample proportion of defective cups from Supplier A is exactly 8% is approximately 0.1567.

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Answer:

First, we need to calculate the total exemptions for Kareem, his wife, and their child:

Total exemptions = 3 x 4,050 = 12,150

Next, we subtract the standard deduction and exemptions from their adjusted gross income to find their taxable income:

Taxable income = 92,600 - 12,600 - 12,150 = 67,850

Therefore, the correct answer is (B) 67,850.

Step-by-step explanation:

Branliest please

Answer: x=67    x=70    x=61

Step-by-step explanation:

see image for explanaton

The value of the arbitrary constant is approximately -1.08.

To determine the value of the arbitrary constant of the antiderivative of F(x) = x^2 * ln(x) given the initial value x = 7.15 and y = 2.21, follow these steps:

Step 1: Find the antiderivative of F(x) = x^2 * ln(x).
The antiderivative can be found using integration by parts. Let u = ln(x) and dv = x^2 * dx.
Then, du = (1/x) * dx and v = (x^3)/3.

Using integration by parts formula: ∫u dv = u * v - ∫v du

∫(x^2 * ln(x)) dx = (x^3 * ln(x))/3 - ∫(x^3 * (1/x)) dx/3

Now integrate the second term:
= (x^3 * ln(x))/3 - (1/3) * ∫x^2 dx
= (x^3 * ln(x))/3 - (1/3) * (x^3/3)

Step 2: Add the arbitrary constant 'C' to the antiderivative.
y(x) = (x^3 * ln(x))/3 - (x^3/9) + C

Step 3: Use the initial values x = 7.15 and y = 2.21 to find the value of 'C'.
2.21 = (7.15^3 * ln(7.15))/3 - (7.15^3/9) + C

Step 4: Solve for 'C'.
C ≈ -1.08 (rounded to 2 decimal places)

The value of the arbitrary constant is approximately -1.08.

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If a candy bar cost 95 cents, then I'll cost 3.8$ to buy the four candy's

To Find How much will it cost to buy 4 candy bars which comes in price of 95 cents per candy bar so therefore calculation will be:

One candy bar cost  = 95 cent

We will use multiplication to multiply the cost of each candy.

4 candy bar costs  = 4 x  price of one candy

4 candy bar costs  = 4 x  95 cents

4 candy bar costs  = 380 cents

After that we get:

100 cents = 1 $

Now we will divide:

4 candy bar costs  = 380/100$

4 candy bar costs  = 3.8 $

Therefore, If a candy bar is 95 cents, it will cost me 3.8$ to purchase the four candies together.

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The general solution to the differential equation is:

y(t) = y_h(t) + y_p(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t)) - (1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

We have the differential equation:

d^2y/dt^2 + 4 dy/dt + 13y = e^(2t)cos(t)

The characteristic equation is:

r^2 + 4r + 13 = 0

Using the quadratic formula, we get:

r = (-4 ± sqrt(4^2 - 4(13)))/(2) = -2 ± 3i

So the general solution to the homogeneous equation is:

y_h(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t))

To find a particular solution to the non-homogeneous equation, we can use the method of undetermined coefficients. Since e^(2t)cos(t) is of the form:

e^(at)cos(bt)

We guess a particular solution of the form:

y_p(t) = A e^(2t)cos(t) + B e^(2t)sin(t)

Taking the first and second derivatives, we get:

y'_p(t) = 2A e^(2t)cos(t) - A e^(2t)sin(t) + 2B e^(2t)sin(t) + B e^(2t)cos(t)

y''_p(t) = 4A e^(2t)cos(t) - 4A e^(2t)sin(t) + 4B e^(2t)sin(t) + 4B e^(2t)cos(t) + 2A e^(2t)sin(t) + 2B e^(2t)cos(t)

Substituting these back into the original equation, we get:

(4A + 2B) e^(2t)cos(t) + (4B - 2A) e^(2t)sin(t) + 13(A e^(2t)cos(t) + B e^(2t)sin(t)) = e^(2t)cos(t)

We can equate coefficients of like terms on both sides to get a system of equations:

4A + 2B + 13A = 1

4B - 2A + 13B = 0

Solving for A and B, we get:

A = -1/170

B = 3/170

So a particular solution to the non-homogeneous equation is:

y_p(t) = (-1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

Therefore, the general solution to the differential equation is:

y(t) = y_h(t) + y_p(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t)) - (1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

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By using the formula for variance

[tex]varX= m*(n*(m-1)/m^n)(1 - n(m-1)/(m^n-1))[/tex]

To compute varX:

we first need to find the expected value of X, denoted as E(X).

We can approach this by using the linearity of expectation, which states that the expected value of the sum of random variables is equal to the sum of their individual expected values.

Let's define a random variable Xi as the number of bins with exactly one ball. Then, we have:

[tex]X = X1 + X2 + ... + Xm[/tex]

where m is the total number of bins.

By the definition of Xi, we know that Xi can only take on values between 0 and 1, since a bin can either have exactly one ball (Xi = 1) or not (Xi = 0).

To find E(Xi), we can use the probability of Xi being 1. The probability that a specific bin has exactly one ball is given by:

[tex]P(Xi = 1) = (n choose 1) * ((m-1) choose (n-1)) / (m choose n)[/tex]

The first term (n choose 1) represents the number of ways to choose one ball out of n balls to put into the bin. The second term ((m-1) choose (n-1)) represents the number of ways to choose (n-1) balls out of the remaining (m-1) bins. Dividing by (m choose n) gives us the probability that exactly one bin has one ball.

Therefore, we have:

E(Xi) = P(Xi = 1) * 1 + P(Xi = 0) * 0
     = P(Xi = 1)=[tex](n choose 1) * ((m-1) choose (n-1)) / (m choose n)[/tex]
Using the linearity of expectation, we can find E(X) as:

E(X) = E(X1) + E(X2) + ... + E(Xm)
    = [tex]m * (n choose 1) * ((m-1) choose (n-1)) / (m choose n)[/tex]

Now, to find varX, we need to find the variance of Xi and use the formula for variance of a sum of random variables.

The variance of Xi can be found as:

Var(Xi) = E(Xi^2) - (E(Xi))^2

Since Xi can only take on values 0 or 1, we have:

E(Xi^2) =[tex]0^2 * P(Xi = 0) + 1^2 * P(Xi = 1) = P(Xi = 1)[/tex]

Therefore, we have:

Var(Xi) = P(Xi = 1) - (E(Xi))^2
      = [tex]m*(n*(m-1)/m^n) + m*(m-1)(n(m-1)/m^n)^2 - (mn(m-1)/m^n)^2[/tex]

Using the formula for variance of a sum of random variables, we have:

varX = Var(X1 + X2 + ... + Xm)
    = Var(X1) + Var(X2) + ... + Var(Xm)      (since Xi's are independent)
    = [tex]m*(n*(m-1)/m^n)(1 - n(m-1)/(m^n-1))[/tex]

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The additional fact would prove that quadrilateral WXYZ is a parallelogram is M∠Y ≅ m∠W . The option D is correct.

To prove that quadrilateral WXYZ is a parallelogram, we need to show that both pairs of opposite sides are parallel.

Option A, which states that XY=YZ, does not provide information about the parallelism of the sides, and it is not sufficient to prove that WXYZ is a parallelogram. Option B, which states that the sum of angles X and Y is 180 degrees, suggests that WXYZ may be a straight line, but it does not necessarily mean that the opposite sides are parallel.

Option C, which states that YZ=WX, suggests that the opposite sides may be equal in length, but again, it does not necessarily mean that they are parallel. Option D, which states that angle Y is congruent to angle W, provides information about the opposite angles of the quadrilateral, and this is enough to prove that the opposite sides are parallel. This is because in a parallelogram, opposite angles are congruent, and therefore, the fact that M∠Y ≅ m∠W proves that WXYZ is a parallelogram. Option D is the correct answer as it provides sufficient information to prove that WXYZ is a parallelogram.

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In the triangle, the values are:

PART A: AC = 9 units

PART B: Sin A = 1/√2

Trigonometry deals with the relationship between the ratios of the sides of a right-angled triangle with its angles.

Check the attached image for the sketch of triangle ABC.

From the sketch:

AC = √(AB² - BC²)       (Pythagoras theorem)

AC = √(162 - 81)

AC = √(81)

AC = 9 units

PART B:

Sin A = BC/AB (opposite/hypotenuse)

Sin A = 9/(9√2)

Sin A = 1/√2

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