What is the molecule shown below?
A. 2,3-methylpentane
B. 3-propylbutane
C. Heptane
D. 2-butylpropane

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

Identify variables

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

Step 2: Identify Conversions

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃

Answer:

use grahamns law to get the answer

Answer:

The pH of the solution is basic

Explanation:

as one of the characteristics of the base is to increase the OH concentration in a solution so if the solution has low concentration of OH this means that the solution is basic

Answer:

im solving now

Explanation:

Answer:

2. 181.25 K.

3. 0.04 atm.

Explanation:

2. Determination of the temperature.

Number of mole (n) = 2.1 moles

Pressure (P) = 1.25 atm

Volume (V) = 25 L

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =?

The temperature can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

1.25 × 25 = 2.1 × 0.0821 × T

31.25 = 0.17241 × T

Divide both side by 0.17241

T = 31.25 / 0.17241

T = 181.25 K

Thus, the temperature is 181.25 K.

3. Determination of the pressure.

Number of mole (n) = 10 moles

Volume (V) = 5000 L

Temperature (T) = –10 °C = –10 °C + 273 = 263 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

The pressure can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 5000 = 10 × 0.0821 × 263

P × 5000 = 215.923

Divide both side by 5000

P = 215.923 / 5000

P = 0.04 atm

Thus, the pressure is 0.04 atm

Answer:

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Explanation:

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Answer:

A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion.

Explanation:

Answer:

nooooo it is not equal to it

The molar mass of the unknown nonelectrolyte compound is

Using the formula;

∆T = K m i

Where;

K = freezing point depression constant

m = molality of the solution

i = Van't Hoft factor

Note that i = 1 since the compound is a nonelectrolyte.

To find molality;

Number of moles = 0.520 g/Molar mass

Let the molar mass of the unknown compound be MM

Number of moles = 0.520 g/MM

Number of kilograms of solvent = 4.12 g/1000 = 0.00412 Kg

Molality = 0.520 g/MM * 1/0.00412 Kg

Freezing point depression is 4.20 °C

To find the molar mass of the compound;

4.20 °C = 3.90 °C/m *  0.520 g/MM * 1/0.00412 Kg

4.20  = 492.23/MM

MM = 492.23/4.20

MM = 117.19 g/mol

Learn more; https://brainly.com/question/14762341

[tex]mass \: of \: the \: car \: = 1250 \: kg \\ \\ velocity \: of \: the \: car \: is \: = 2.3m/s \\ \\ formula \: to calculate \: momentum \: \\ \\ \: \: \: \: p = mv \: \: \: (m = mass \: and \: v = velocity) \\ \\ momentum \: = 1250 \times 2.3 = 2875m/s[/tex]

Answer:

All ionic compounds with alkali metals are soluble.

Explanation:

Certain elements always form soluble substances. Most of those elements are alkali metals/group 1 metals.

Answer:

Both Arrhenius Base and Bronsted Lowry Base

Both Arrhenius Acid and Bronsted Lowry Acid

Arrhenius Acid Only

Arrhenius Base Only

Bronsted Lowry Acid Only

Bronsted Lowry Base Only

Explanation:

Answer:

this is a required answer. look it once.

Answer:

Examples of physical change include changes in the size or shape of matter. Changes of state—for example, from solid to liquid or from liquid to gas—are also physical changes. Some of the processes that cause physical changes include cutting, bending, dissolving, freezing, boiling, and melting.

Explanation:

Answer:

22

Explanation:

3x4+  5x2

Answer:

the answer is 1.1grams is the currect ans

According to the law of conservation of mass, 1.1 grams of calcium carbonate are formed  if 2.2 grams of CaO are used for this reaction.

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.If 56 g CaO gives 46.2 g calcium carbonate then  2.2 g CaO will give 2.2×46.2/56=1.1 g.

Learn more about law of conservation of mass, here:

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Answer:

As the world changes, plants and animals change with it. Aside from a few living fossils, the species we see today are very different from species that lived in the past. Thus, the fossil record can be used to show that organisms changed to meet new conditions. This is the result of evolution of species over time.

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Explanation:

Answer:

Metilaminas

Explanation:

Las metilaminas a menudo están presentes en los tejidos corporales de organismos marinos como crustáceos, moluscos y en todos los peces marinos como N-óxido de trimetilamina, donde actúan para estabilizar la proteína que se desestabiliza por la presión y también se cree que actúa como un depresor del punto de congelación. en peces polares

Las metilaminas tienen olor a pescado podrido, basura o huevos podridos, de modo que una acumulación de metilamina en el cuerpo da como resultado la liberación de un olor a pescado en la amplitud, el sudor y la orina de un individuo

Answer:

Explanation:

Ultimately, milk can be described as both. The actual description depends on the individual and/or company involved. For example, in many places milk if extracted from cows, bottled, and delivered to the end consumer. In this case, milk would be considered as natural because nothing has been done to change its nutritional composition. This changes when companies begin to pasteurise and homogenize the milk so that it has a longer shelf life and create different variations. The milk in this case no longer has the same nutritional composition and has been altered, and is therefore considered as processed.

Answer:

Amoeba since it can come together as a multicellular with other amoebas, but still act as one giant living cell.

Explanation: i read in a book that red-slime molds can do that. hope it wasn't too far too late recent.

Answer: The volume of stock solution needed is 62.5 mL

Explanation:

A solution consists of solute and solvent. A solute is defined as the component that is present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

To calculate the volume of stock solution needed, the formula used is:

[tex]C_1V_1=C_2V_2[/tex]             ....(1)

where,

[tex]C_1\text{ and }V_1[/tex] are the concentration and volume of stock solution.

[tex]C_2\text{ and }V_2[/tex] are the concentration and volume of diluted solution.

We are given:

[tex]C_1=3.00M\\V_1=?mL\\C_2=1.25M\\V_2=150mL[/tex]

Putting values in equation 1, we get:

[tex]3.00\times V_1=1.25\times 150\\\\V_1=\frac{1.25\times 150}{3.00}\\\\V_1=62.5mL[/tex]

Hence, the volume of stock solution needed is 62.5 mL

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Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

Answer:

To produce a solution that frees at -50°C we need 1668.5 g of ethylene glycol

Explanation:

Formula for freezing point depression is:

Freezing T° of pure solvent - Freezing T° of solution = Kf . m . i

Our solute is the ethylene glycol, then water is our solvent.

As ethylene glycol is a non ionic compound, i = 1 (Van't Hoff factor, numbers of ions dissolved)

Kf = Cryoscopic constant. For water is 1.86 °C/m

We replace data:

0°C - (-50°C) = 1.86 °C/m . m . 1

To determine grams of ethylene glycol needed, we need to find m (molality)

50°C / 1.86 m/°C = m → 26.8 mol/kg

As this moles of solute are contained in 1kg, definetely we need 26.8 moles of ethylene glycol.

To find the answer, we convert moles to mass:

26.8 mol . 62.07g / mol = 1668.5 g

Answer:

is your answe b?

Explanation:

Im really asking

Answer:

it may also become impure,I think.