Answers
First, let's see that we can extract the concentration of OH- because Ba(OH)2 is a base. Let's see the dissociation of this base:
[tex]Ba(OH)_2\to Ba^{2+}+2OH^-,[/tex]You can realize that we have 2 moles of OH-. The next step is to multiply this number of moles by the concentration (0.050 M):
[tex]\lbrack OH^-\rbrack=2\cdot0.050=0.1.[/tex]Remember that the formula of pOH is -log ( [OH-] ):
[tex]\text{pOH}=-\log (0.1)=1.[/tex]And with this result, we can find pH, using the formula:
[tex]pH+\text{pOH}=14[/tex]And we're going to obtain:
[tex]\begin{gathered} pH=14-\text{pOH}, \\ pH=14-1, \\ pH=13. \end{gathered}[/tex]The pH of the solution would be 13, so the answer is (2).
Related Questions
Convert 3.00 caws to screeches8.00 caw = 6.00 chirps0.85 chirps = 1.0 song2.00 song = 2.0 screechRound your answer to 2 significant figures
Answers
Answer:
2.6 screeches.
Explanation:
We have to solve this problem step-by-step. The key is to state a rule of three based on the given information.
We want to convert 3.00 caws to screeches, but first, we have to convert it from caws to chirps. 8.00 caw equals 6.00 chirps:
[tex]3.00\text{ caws}\cdot\frac{6.00\text{ chirps}}{8.00\text{ caw}}=2.25\text{ chirps.}[/tex]3.00 caws equals 2.25 chirps. Now, let's convert from chirps to songs using the given information. 0.85 chirps equals 1.0 song:
[tex]2.25\text{ chirps}\cdot\frac{1.0\text{ song}}{0.85\text{ chirps}}=2.6\text{ songs.}[/tex]3.00 caws equals 2.6 songs. Finally, we convert 2.6 songs to screeches. 2.00 songs equals 2.0 screeches:
[tex]2.6\text{ songs}\cdot\frac{2.0\text{ screeches}}{2.00\text{ songs}}=2.6\text{ screeches.}[/tex]The answer would be that 3.00 caws equal 2.6 screeches.
3. How many moles of bleach are in each trial if you use 5.00 mL of a 6.00% (m/m) solution? Use the density you found in Question 2.
Trial Mass (grams) Density
1 0.448 1.12g/ml
2 0.450 1.125g/ml
3 0.437 1.093g/ml
4 0.442 1.105g/ml
Average 1.111
Answers
Based on the percentage composition of the bleach solution, The number of moles of NaOCl in the bleach solution is 0.00447 moles.
What is the mass of bleach present in the given volume of bleach?The mass of bleach present in the given volume of bleach solution is determined from the formula given below as follows;
Mass = volume * densityVolume of solution = 5.00 mL
The density of solution = 1.111 g/mL
Mass of bleach solution = 5.0 * 1.111
Mass of bleach solution = 5.555 g
The active compound in bleach is NaOCl
Mass of NaOCl in the bleach solution = percentage concentration * mass of solutionMass of NaOCl in the bleach solution = 6.00% * 5.555 g
Mass of NaOCl in the bleach solution = 0.333 g
Molar mass of NaOCl = 74.5 g/mol
Moles of NaOCl in the bleach solution = 0.333 / 74.5
Moles of NaOCl in the bleach solution = 0.00447 moles
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What does a buffer do?A. It prevents a salt from forming in solution.B. It resists a change in pH when H* or OH is added to a solution.C. It prevents an acid or base from being neutralized.D. It prevents an acid-base reaction from happening.
Answers
INFORMATION:
We have the next options:
A. It prevents a salt from forming in solution.
B. It resists a change in pH when H* or OH is added to a solution.
C. It prevents an acid or base from being neutralized.
D. It prevents an acid-base reaction from happening.
And we must select the one that describes what a buffer do
STEP BY STEP EXPLANATION:
A buffer is a mixture of a weak acid and its conjugate base or a mixture of a weak base and its conjugate acid.
A buffer resists change in pH by accepting hydrogen ions when acids are added to the solution and donating hydrogen ions when bases are added.
Knowing that, we can state that a buffer resists a change in pH when strong acid (H+) or strong base (OH-) is added to a solution.
ANSWER:
B. It resists a change in pH when H* or OH is added to a solution.
Assume that a scientist is measuring mass in an experiment, The balance she is using is not set at zero so it always measures mass a little too high. What type of error does this cause in the data? Select one:A. Random errorB. observer errorC. SystematicD. None of these
Answers
Answer:
[tex]C\text{ : Systematic}[/tex]Explanation:
Here, we want to get the type of error associated with the experiment
From what we have in the question, we can see that the error is due to the measuring apparatus. Thus, we can identify a zero error
Zero errors are a type of systematic error
Thus, the correct answer choice here is that there would be a systematic error in the data
using the balance equation LiOH + KCl arrow LiCl + KOHI actually produced 6 grams of lithium chloride and began thisw reaction with 20 grams of lithium hydroxide. What is my percent yield?
Answers
Answer:
Percent yield = 16.95%.
Explanation:
Let's write the balanced equation:
[tex]LiOH+KCl\rightarrow LiCl+KOH.[/tex]We want to know the theoretical yield of lithium chloride (LiCl), we want to know how much we will produce of this compound from 20 g of lithium hydroxide; so the first step is to convert 20 g of lithium hydroxide (LiOH) to moles using its molar which is 23.9 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will look like this:
[tex]20\text{ g LiOH}\cdot\frac{1\text{ mol LiOH}}{23.9\text{ g LiOH}}=0.837\text{ moles LiOH.}[/tex]You can see in the chemical equation that 1 mol of LiOH reacted produces 1 mol of LiCl, so the molar ratio between them is 1:1, which means that 0.837 moles of LiOH reacted produces 0.837 moles of LiCl.
The next step is to convert 0.837 moles of LiCl to grams using its molar mass which is 42.3 g/mol:
[tex]0.837\text{ moles LiCl}\cdot\frac{42.3\text{ g LiCl}}{1\text{ mol LiCl}}=35.4\text{ g LiCl.}[/tex]35.4 g LiCl would be our theoretical yield. 6 grams of LiCl that are being produced is the actual yield, so to calculate the percent yield, we use the following formula:
[tex]\%\text{ yield =}\frac{actual\text{ yield}}{theoretical\text{ yield}}\cdot100\%[/tex]And finally, we replace the given data on it:
[tex]\%\text{ yield=}\frac{6\text{ g}}{35.4\text{ g}}\cdot100\%=16.95\%.[/tex]The percent yield is 16.95%.
Diethyl ether is made from ethanol according to thefollowing reaction:2C₂H5OH()Ethanol(C₂H5)₂O(l) + H₂O(l)DiethyletherIn an experiment, 517 g of ethanol gave 391 g ofdiethyl ether. What was the percent yield in thisexperiment?
Answers
Answer:
94.4 %.
Explanation:
First, let's see the chemical equation:
[tex]2C_2H_5OH\text{ \lparen ethanol\rparen}\rightarrow(C_2H_5)_2O\text{ \lparen diethyl ether\rparen}+H_2O\text{ \lparen water\rparen}.[/tex]Now, let's calculate the number of moles of ethanol of 517 g of ethanol using its molar mass, which is 46 g/mol, like this:
[tex]517\text{ g ethanol}\cdot\frac{1\text{ mol ethanol}}{46\text{ g ethanol}}=11.2\text{ moles ethanol.}[/tex]Now, let's see how many moles of diethyl ether can be produced by 11.2 moles of ethanol. You can see in the chemical equation that 2 moles of ethanol reacted produces 1 mol of diethyl ether:
[tex]11.2\text{ moles ethanol}\cdot\frac{1\text{ mol diethyl ether}}{2\text{ moles ethanol}}=5.6\text{ moles diethyl ether.}[/tex]Now, let's convert 5.6 moles of diethyl ether to grams using the molar mass of diethyl ether which is 74 g/mol:
[tex]5.6\text{ moles diethyl ether}\cdot\frac{74\text{ g diethyl ether}}{1\text{ mol diethyl ether}}=414.4\text{ g diethyl ether.}[/tex]414 g of diethyl ether would be the theoretical yield.
The final step is to calculate the percent yield using the following formula:
[tex]percent\text{ yield=}\frac{actual\text{ yield}}{theoretical\text{ yield}}\cdot100\%.[/tex]The actual yield of diethyl ether is the given value of the experiment, which is 391 g. If we replace the data that we have, we obtain:
[tex]\begin{gathered} percent\text{ yield=}\frac{391\text{ g}}{414\text{ g}}\cdot100\%, \\ percent\text{ yield=94.4}\%. \end{gathered}[/tex]The percent yield of this experiment is 94.4 %.
8. What is the smallest element on the periodic table?
Answers
HELIUM
Explanations;The smallest element in the periodic table can be categorized based on the value of its atomic radius.
In the periodic table, the atomic radius of elements increases as we move down the table and decreases as we move from left to right.
The increment of the radius from top to bottom is mainly due to the increase in the atomic number due to the increase in the electron shells.
Since the Helium element has the smallest atomic radius, we can categorize it as the smallest element in the periodic table.
In conclusion, the smallest element if categorized based on the atomic radius will be HELIUM
Guven the following equation 4Fe+3O2=2Fe2O3 how many moles of Feare needed to react with 1.00 moles od O2
Answers
Answer: 1.3 moles Fe
Explanation:
I think you do this by unitary method that is
3 moles O2 react with 4 moles Fe
∴ 1 mole O2 react with 4/3 = 1.3 moles Fe
Ammonium perchlorate NH4ClO4 is a powerful solid rocket fuel, used in the Space Shuttle boosters. It decomposes into nitrogen N2 gas, chlorine Cl2 gas, oxygen O2 gas and water vapor, releasing a great deal of energy. Calculate the moles of nitrogen produced by the reaction of 0.090mol of ammonium perchlorate. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answers
First step is to set up the equation and also properly balance it:
2 NH4ClO4 -> N2 + Cl2 + 4 H2O + 2 O2
Now the reaction is properly balanced, so we can focus on what the question is giving and asking. The question gave us 0.090 moles of NH4ClO4 and wants to know how many moles can we make of Nitrogen gas from this, so forget all the other compounds and only look at these 2 molecules. So what is the molar ratio between these 2? 2:1 of molar ratio, because if you look at the equation you will see that with 2 moles of ammonium perchlorate I will have 1 mol of Nitrogen gas, now we can do the following calculation:
2 NH4ClO4 = 1 N2
0.090 NH4ClO4 = x N2
x = 0.045 moles of N2 will be produced
I have a question about my teachers notes. Where does 28g come from?
Answers
Answer
The 28g from the first equation of N2 is the mass of N2 per 1 mole.
If you look at the periodic table, you will see that Nitrogen has a molar mass of 14 u, since it is 2 nitrogen atoms, you say 14 x 2 = 28 g/mol.
Your teacher wanted to convert the mass of N2 to moles, that is why the mass is divided by 28 g (which is per 1 mole).
Just choose one, I’m sorry I wasn’t able to crop it out
Answers
Remember that compounds with OH refer to alcohols and end with OL
The nomenclature depends on the number of carbons in the molecule.
Here, we have two molecules of carbon, so we put at the beginning ETH
And then
you complete with suffix OL. So the answer will be Ethanol
how much of a 400 Gram sample of rubidium-87 would remain after 1 half life
Answers
Answer:
200 g.
Explanation:
What is given?
Initial quantity (N₀) = 400 g.
Half-life of rubidium-87 = 4.8 x 10¹⁰ years.
Step-by-step solution:
Let's see the formula to calculate the quantity remaining:
[tex]N(t)=N_0\cdot(\frac{1}{2})^{t\text{ /t}_{\frac{1}{2}}}.{}[/tex]Where N₀ is the initial quantity, t is the time, and t (1/2) is the half-life of the substance, in this case, Rb-87. Based on this, our formula will be:
[tex]N(t)=400\cdot(\frac{1}{2})^{\text{t/\lparen4.8}\cdot10^{10})}[/tex]If we want to find the amount of Rb-87 after 1 half-life, our t would be equal to 4.8 x 10¹⁰ years, so replacing this value in the formula we obtain:
[tex]\begin{gathered} N(4.8\cdot10^{10})=400\cdot(\frac{1}{2})^{4.8\cdot10^{10}\text{/4.8}\cdot10^{10}}, \\ N(4.8\cdot10^{10})=400\cdot(\frac{1}{2})^1, \\ N(4.8\cdot10^{10})=400\cdot(\frac{1}{2}), \\ N(4.8\cdot10^{10})=200\text{ g.} \end{gathered}[/tex]The answer is that after 1 half-life of a 400 g sample of Rb-87, the remaining quantity is 200 g.
According to the following reaction: ___ C6H6(g) + ___ O2(g)→___ CO2(g) + ___ H2O(g)a. If 2.45 liters of benzene are consumed in this reaction, how many liters of water vapor can be formed, if thereaction occurs at 1.25 atm and 25°C?
Answers
Answer:
7.33L of water vapor can be formed.
Explanation:
1st) It is necessary to balance the chemical reaction:
[tex]2C_6H_6+15O_2\rightarrow12CO_2+6H_2O[/tex]From the balanced reaction we know that with 2 moles of benzene (C6H6), 6 moles of water vapor can be formed.
2nd) We need to convert the 2.45 liters of benzene to moles, using the Gas Law formula:
[tex]\begin{gathered} P*V=n*R*T \\ 1.25atm*2.45L=n*0.082\frac{atm*L}{mol*K}*298K \\ 3.06atm*L=n*24.44\frac{atm*L}{mol} \\ \frac{3.06atm*L}{24.44\frac{atm*L}{mol}}=n \\ 0.125mol=n \end{gathered}[/tex]Now we know that 0.125 moles of benzene were consumed.
3rd) From the stoichiometry of the reaction and the 0.125 moles, we can calculate the moles of water vapor that can be formed:
[tex]\begin{gathered} 2molesC_6H_6-6molesH_2O \\ 0.125molesC_6H_6-x=\frac{0.125molesC_6H_6*6molesH_2O}{2molesC_6H_6} \\ x=0.375molesH_2O \end{gathered}[/tex]0.375 moles of water vapor are formed.
4th) Finally, we can use the Gas Law formula again, to calculate the liters of water vapor that can be formed:
[tex]\begin{gathered} P*V=n*R*T \\ 1.25atm*V=0.375mol*0.082*\frac{atmL}{molK}*298K \\ 1.25atm*V=9.16atm*L \\ V=\frac{9.16atm*L}{1.25atm} \\ V=7.33L \end{gathered}[/tex]So, 7.33L of water vapor can be formed.
2. Hydrogen chloride (HCI (g)) decomposes in hydrogen gas and chlorine gas. The equilibrium constant, K, is 3.2 x 10^-34 at 25°C. Calculate the equilibrium concentrations of all entities if 2.00 mol HCl(9) is initially placed in a closed 1.00-L vessel. All the entities are in gaseous form. HCl H2 + Cl2
Answers
The chemical equation:
[tex]2\text{HCl}\to H_2+Cl_2.[/tex]And the concentrations of hydrogen chloride:
[tex]M_{HCl}=\frac{2\text{ mol HCl}}{1\text{ L}}=2M_{HCl}.[/tex]We do an ICE chart:
[tex]K=\frac{x^2}{(2-2x)}=3.2\cdot10^{-34}[/tex]Doing the calculations in a software, we obtain that x is:
[tex]x=\pm2.5982\cdot10^{-17}.[/tex]Using the positive result, we obtain that:
[tex]\lbrack HCl\rbrack^2=2-2x=2-2(2.5982\cdot10^{-17})\text{.}[/tex][tex]\lbrack HCl\rbrack=\sqrt[]{2}\approx1.41\text{ M}[/tex][tex]\lbrack H_2\rbrack=\lbrack Cl_2\rbrack=x=2.5982\cdot10^{-17}.[/tex]These results is tellinig us that the direction of the equilibrium in the reaction goes like this:
[tex]K=\frac{\lbrack HCl\rbrack^2}{\lbrack H_2\rbrack\lbrack Cl_2\rbrack}=\frac{2}{(\text{2}.5982\cdot10^{-17})^2}\approx2.963\cdot10^{33}.[/tex]When K > 0, the direction goes to the right: to the products.
1. If 22.5L of nitrogen at 745 mm Hg are compressed to 725 minHg. What is the new volume?od SestD001 20v bu par 1.0
Answers
Step 1 - Understanding how pressure and volume are related
There are three main variables that can modify the state of a gas: pressure, volume and temperature.
When one of these variables is kept constant, the remaining two become proportional to each other. Suppose temperature is kept constant. In this case, pressure and volume become proportional.
I.e., if we increase the pressure, we also increase the volume. We can state it mathematically as follows:
[tex]p_1V_1=p_2V_2[/tex]We can use this equation to solve this exercise.
Step 2 - Calculating the new volume
According to the exercise:
[tex]\begin{gathered} V_1=22.5L \\ \\ p_1=745mmHg \\ \\ p_2=725mmHg \\ \\ V_2=? \end{gathered}[/tex]Setting these values in the equation given in step 1:
[tex]\begin{gathered} 22.5\times745=725\times V_2 \\ \\ V_2=\frac{22.5\times745}{725}=23.1L \end{gathered}[/tex]Answer: 23.1L
Instead of using a pH meter, suggest an appropriate indicator other than phenolphthalein that could be used to find the equivalence point of this reaction.
Answers
An indicator that we can use to find the equivalence of a reaction is methyl orange which is a colorant and acts changing from red to yellow-orange color and its range of pH is 3.1 and 4.4, which shows its color in an acidic (weak) medium.
Which is true Boyles Law of gases?Group of answer choicesthe volume is directly proportional to pressurethe temperature and volume is directly proportionalthe amount and temperature is held constant.none are true.
Answers
Boyle's law applies to ideal gases and assumes that temperature and moles are constant and relate volume to pressure. It tells us that at constant temperature volume is inversely proportional to pressure.
That is to say that when the pressure increases the volume decreases and if the pressure decreases the volume increases.
Therefore, of the given options the third is true.
Answer: the amount and temperature are held constant.
Which of the following atoms are likely to form an ionic bond?
Answers
Explanation:
Ionic bonds are more likely to produce between a metal and a nonmetal atom.
According to this, Na (sodium) is a metal from group 1 and Cl (chlorine) is a nonmetal from group 17 in the periodic table. Both form an ionic bond in NaCl (sodium chloride) molecule.
Answer: D. Sodium (metal) and Chlorine (nonmetal)
(ii) State two practical uses of microwaves. [2]
Answers
=To cook food as it cause water and fat molecules to vibrate, which makes the substances hot.
=Mobile phones use microwaves, as they can be generated by a small antenna.
=Wifi also uses microwaves.
=Fixed traffic speed cameras.
=For radar, which is used by aircraft, ships and weather forecasters.
write any two you like.
Which word does not belong with the others? (a) alkane(b) paraffin (c) saturated (d) ethane(e) ethylene(f) pentane
Answers
Ethylene. Option E is correct.
Explanations:Alkanes are organic compounds that consists of hydrogen and carbon atoms. The general formula for alkanes is CnH2n+2.
Alkanes, also known as paraffins are series of saturated hydrocarbons such as the methane, ethane, pentane, etc.. The alkane compounds alwas end with the suffix
-ane
From the explanation above,you can see that the following words are used alkane, paraffin, saturated, ethane and pentane. Hence the word that does not obelong with others is ethylene since it is not an alkane compound
If you review Data Table 2, you will notice that it took fewer drops of 0.1 M NaOH to neutralize the acid in Reaction 3 (20 drops of 0.05 M HCl) as it did to neutralize the acid in Reaction 1 (20 drops of 0.1 M HCl). Explain why the smaller amount of NaOH was required to neutralize the acid in Reaction 3.
Answers
The question requires us to compare two neutralization reactions between NaOH and HCl, given the concentrantio of HCl and the amount of NaOH used, and explain why a smaller amount of NaOH was used for one of the reactions.
From the table, we can gather the following information regarding reactions 1 and 3:
Reaction 1: 20 drops of 0.1 M HCl + 42 drops of NaOH
Reaction 3: 20 drops of 0.05 M HCl + 43 drops of NaOH
Just comparing the concentrantion of HCl used in each reaction, we can see that for Reaction 3, a less concentrated HCl solution was used, although the volume of solution was the same in both cases.
Remember that the amount of a compund, in moles, can be calculated multiplying the solution concentration (in mol/L, for example) by its volume (in L), therefore if we are using the same volume but different concentrations, there will be a different amount of HCl for reaction 1 and 3 (smaller for 3 because the concentration is smaller).
Since we are talking about a neutralization reaction and the same 0.1 M NaOH solution was used for both reaction 1 and reaction 3, we should expect that a smaller amount of NaOH should be used for reaction 3 because the effective amount of HCl in the reaction was smaller. Therefore, we could answer the question "why the smaller amount of NaOH was required to neutralize the acid in Reaction 3" by comparing the concentration of HCl solutions - a smaller concentration in reaction 3 leads to a smaller amount of NaOH necessary to neutralize it.
On the other hand, the observations presented in table 2 say otherwise: more volume of NaOH was counted for reaction 3 compared to reaction 1.
To explain this, we could consider that an experimental error occured (for example, the wrong number of drops was counted for reaction 1, or the final point of the reaction - when it turns "pinkish" - was not the same for all reactions).
I am a gaz element in the 5th family who am I?
Answers
Explanation:
The 5th family may refer to the 15 group of the periodic table or V-A.
It is composed by N, P, As, Sb, Bi and Mc.
The only gas in that "column" is nitrogen.
Answer: N (nitrogen)
what is the initial volume, in milliliters, needed to prepare each of the following diluted solution?350 mL of 3.0 %(m/v) HCl from 15.0 % (m/v) HCl Express your answer to two significant figures and include the appropriate units.
Answers
ANSWER
The initial volume of the solution is 70mL
EXPLANATION
Given that;
The initial concentration of the solution is 15.0% m/v
The final volume of the solution is 350mL
The final concentration of the solution is 3.0% m/v
Follow the steps below to find the initial volume of the solution.
Step 1; Apply the dilution formula
[tex]\text{ C1 V1 = C2 V2}[/tex]Substitute the given data into the above formula
[tex]\begin{gathered} \text{ }\frac{15}{100}\text{ }\times\text{ V1 = }\frac{3}{100}\times\text{ 350} \\ \text{ 0.15 }\times\text{ V1 = 0.03 }\times\text{ 350} \\ \text{ 0.15 V1 = 10.5} \\ \text{ Divide both sides by 0.15} \\ \text{ V1 = }\frac{\text{ 10.5}}{\text{ 0.15}} \\ \text{ V1 = 70mL} \end{gathered}[/tex]Therefore, the initial volume of the solution is 70mL
Find Δ E° for the reaction below if the process is carried out at a constant pressure of 1.00 atm and Δ V (the volume change) = -24.5 L. (1 L ∙ atm = 101 J) 2 CO(g) + O2 (g) → 2 CO2(g)ΔH° = -566. kJ
Answers
2 CO (g) + O₂ (g) → 2 CO₂ (g)
The given conditions are:
ΔH° = -566. kJ
Pressure = constant = 1.00 atm
ΔV = -24.5 L
ΔE° = ?
To solve this problem we will use this formula:
ΔH = ΔE° + PΔV
That's the formula that describes our process since it is a reaction at constant pressure.
ΔH = ΔE° + PΔV
ΔE° = ΔH - PΔV
ΔE° = (-566. kJ) - 1.00 atm * (-24.5 L)
ΔE° = - 566. kJ + 24.5 atm*L
ΔE° = - 566. kJ + 24.5 atm*L * 101 J/ (1 atm*L)
ΔE° = - 566. kJ + 2475 J
ΔE° = - 566. kJ + 2475 J * (1 kJ/1000 J)
ΔE° = - 566. kJ + 2.475 KJ
ΔE° = - 563.5 kJ
If 2.09 g of CuNO3 is dissolved in water to make 0.700 M solution, what is the volume of the solution in milliliters? Volume: ____________ mL
Answers
To solve this problem, proceed as follows: Use the molecular weight to convert the mass to moles, then, use the molarity to find the number of liters and finally convert this to mililiters (the molecular weight of CuNO3 is 125.55g/mol):
[tex]2.09g\cdot\frac{mol}{125.55g}\cdot\frac{lt}{0.700mol}\cdot\frac{1000ml}{lt}=23.78ml[/tex]According to this, the volume of the solution is 23.78ml.
Which type of motion in the figure below best represents the movement of gas particles
Answers
Gas particles move in different directions because they collition everytime. Thus, the correct motion is motion 1.
What is the frequency of light having a wavelength of 415nm?
Answers
In order to answer this question, we might use the formula in which we have frequency, wavelenght and the speed of light. This formula in order to find frequency will be written as it follows:
f = c/λ
where:
c = speed of light, which is 2.998*10^8 m/s
λ = wavelenght, which is 415 nm or 400*10^-9 meters
f = 2.998*10^8/400*10^-9
f = 7.49*10^14 Hz
Calculate the molecular mass of Pb(ClO2)4. Remember to include units
Answers
So,
To find the molecular mass of this compound, we multiply the mass of each element by the number of atoms of each element in the compound and then sum all these values.
First, remember:
The molar mass of Pb is 207.2g/mol
The molar mass of Cl is 35.45g/mol
The molar mass of O is 16g/mol
This is:
Now, if we sum:
The molecular mass of Pb(ClO2)4 is 477g.
Draw the electron-dot diagram for these two elements. Use the circle tool to draw your dots. Consult the periodic table to obtain the correct number of valence electrons.
Answers
The electron dot structure contains the symbol that is used for the element as well as the dots that show its valence electrons as shown for calcium and silicon in the images attached.
What is electron-dot diagram?The term electron-dot diagram is the kind of diagram that shows the symbol of the element as well as the number of electrons that can be found in the outermost shell of the element.
In effect, there are two things that we could say that leads to the formation of the electron dot diagram and they are;
1) The symbol that shows the element
2) The number of valence electrons that surround the atom often shown as dots around the symbol of the element.
In the images that have been attached to the question as we have it, we have shown the dot electrons structures for both the calcium atom and the silicon atom.
The calcium atom has the symbol Ca while the silicon atom has the symbol Si.
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what are amines and amidines
Answers
Answer
Amines are organic compounds that contain nitrogen atoms with a lone pair. Basically, they are derived from ammonia (NH3) in which one or more hydrogen atoms are replaced by an alkyl or aryl group, and so they are known as alkylamines and arylamines respectively. The functional group of amine is R-NH2
Amidines are related to amides by replacing the C(O) group in the formula of an amide with C(NH), hence the functional group of amidines is R-C(NH)NH2.
The diagram below is the general formula for primary, secondary, and tertiary amines: