Answer:
pH = 4.6
Explanation:
As hydrochloric acid (HCl) is a strong acid, the molar concentration of H⁺ species is the same as the molar concentration of the HCl solution. In other words:
[H⁺] = 2.51x10⁻⁵ MWith the information above in mind we can calculate the pH:
pH = -log[H⁺]pH = -log(2.51x10⁻⁵ M)pH = 4.6A sample of dry gas is found to occupy 3.650 L at 22.0°C and 740.0 mmHg. How many moles of gas are present?
will mark brainliest
Answer:
0.147
Explanation
PV/RT
One method of increasing the chances of particles colliding during a reaction is to...
1)decrease temperature
2) decrease concentration
3)increasing concentration
4)use a catalyst
Answer:
3
Explanation:
Increasing concentration
To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.20 g Pb
They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
How many moles of Oxygen atoms are contained in 45.9 mol CO2?
Answer:
Explanation:
10 moles of oxygen atoms.\ \textbf{b)} 91.8 moles of oxygen at
What answer is it and how ? please help !!!!!! ill mark brainlyest if right
Answer:
The answer is B
Brainliest please!
What is the initial and final mass of the zinc and copper?
Answer:the final mass of copper is 3.84 g. There was an increase in mass of 1.84 g from the initial mass of 2.0 g.
Explanation:
help me with questions 6,11,15,16 and 17 please
ayúdame con las preguntas 6,11,15,16 y 17 por favor
Compute the number of electrons that each lead atom donates, on average, to a bulk piece of lead metal. Room temperature data for lead: The conductivity of lead is 4.90 × 104 1/(Ω·m) The electron mobility of lead is 2.3 cm2/(V·s) The mass density of lead is 11.4 g/cm3 The atomic weight of lead is 207 g/mol
Answer:
4 electrons/atom
Explanation:
The conductivity of the lead σ = neμ where n = electron density, e = electron charge = 1.602 × 10⁻¹⁹ C and μ = electron mobility of lead = 2.3 cm²/(V·s) = 2.3 × 10⁻⁴ m²/(V.s)
Making n subject of the formula, we have
n = σ/eμ
Since σ = 4.90 × 10⁶ (Ω·m)⁻¹
Substituting the values of the variables into the equation, we have
n = σ/eμ
n = 4.90 × 10⁶ (Ω·m)⁻¹/(1.602 × 10⁻¹⁹ C × 2.3 × 10⁻⁴ m²/(V.s))
n = 4.90 × 10⁶ (Ω·m)⁻¹/(3.6846 × 10⁻²³ Cm²/(V.s))
n = 1.33 × 10²⁹ electrons/m³
We now find the number of moles of lead present in 1 m³ of lead.
So n' = ρ/M where ρ = density of lead = 11.4 g/cm³ = 11.4 g/cm³ × 10⁶ cm³/m³ = 11.4 × 10⁶ g/m³ and M = atomic weight of lead = 207 g/mol
So, n' = ρ/M
N = 11.4 × 10⁶ g/m³/207 g/mol
n' = 0.0551 × 10⁶ mol/m³
n' = 5.51 × 10⁴ mol/m³
Since n' = N/N' where N = number of atoms of lead in 1 m³ of lead and N = Avogadro's constant = 6.022 × 10²³ mol⁻¹
N = n'N' = 5.51 × 10⁴ mol/m³ × 6.022 × 10²³ mol⁻¹
N = 33.18 × 10²⁷ atoms/m³
N = 3.318 × 10²⁸ atoms/m³
So, the number of electron per atom is N" = n/N
= 1.33 × 10²⁹ electrons/m³ ÷ 3.318 × 10²⁸ atoms/m³
= 0.4 × 10¹ electrons/atom
= 4 electrons/atom
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
Answer:
The answer is "2%"
Explanation:
Equation:
[tex]HNO_2\ (aq) \leftrightharpoons H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\ K_a = 4.0\times \ 10^{-4}[/tex]
[tex]H^{+}=?[/tex]
Formula:
[tex]Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}[/tex]
Let
[tex][H^{+}] = [NO_2^{-}] = x[/tex] at equilibrium
[tex]x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \ M\\\\[/tex]
therefore,
[tex][H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M[/tex]
Calculating the % ionization:
[tex]= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\[/tex]
The approximate percent ionization of HNO₂ in a 1.0 M HNO₂ (aq) solution is 2%.
How we calculate the % ionization?% ionization of any compound will be calculated as follow:
% ionization = ([ion]/[acid or base]) ₓ 100
Given chemical reaction with ICE table will be represented as:
HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)
initial 1 0 0
change -x +x +x
equilibrium 1-x x x
Equilibrium constant will be represented as:
Ka = [H⁺][NO₂⁻] / [HNO₂]
Acid dissociation constant for HNO₂ = 4×10⁻⁴
Putting all values in the above equation, we get
4×10⁻⁴ = x² / 1-x
Value of changeable quantity is very less, so we neglect from the concentration of HNO₂.
4×10⁻⁴ = x²
x = 2 × 10⁻²
So, the concentration of H⁺ ion = 2 × 10⁻²M
Now we put all these values in the % ionization equation, we get
% ionization = (0.02/1) × 100 = 2%
Hence , % ionization is 2%.
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Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4
Answer:
2.35x10²³ molecules of C2Cl4 are present
Explanation:
To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:
Moles C2Cl4:
73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4
Molecules:
0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =
2.35x10²³ molecules of C2Cl4 are presentSuppose you needed to explain the concept of the mole to a junior high school student. What would you tell them?
Answer:
Explanation:
duehgjvcujhyeq bvckjfdsaeb gjdksghUIBGREQWMNHGTRE BAGTFEQA
What is [H⁺] in a 0.330 M solution of acrylic acid, CH₂CHCOOH (Ka = 3.16 × 10⁻⁵)?
Answer:
[H⁺] = 3.23x10⁻³ M
Explanation:
For a weak monoprotic acid, such as acrylic acid, we can calculate [H⁺] using the following formula if the solution concentration is significantly higher than the Ka:
[H⁺] = √(C * Ka)Where C is the weak acid concentration.
We input the data:
[H⁺] = [tex]\sqrt{0.330 M * 3.16x10^{-5}}[/tex]And solve for [H⁺]:
[H⁺] = 3.23x10⁻³ MWhich of the compounds shown are structural
isomers of this compound? Check all that apply.
A
B
С
D
Answer:
A & C
Explanation:
The next one is A Edge 2022
The compound which are the structural isomers of the given compound is compound A & C.
What are structural isomers?Structural isomers are those isomers in which which are having the same molecular formula but different structural structures.
Compound A: A is the structural isomer of the given compound as they both have same number of carbon and hydrogen atoms present in that.Compound B: B is not the structural isomer of the given ompound as they have not equal number of carbon and hydrogen atoms in it.Compound C: C is the structural isomer of the given compound as they both have same number of carbon and hydrogen atoms present in that.Compound D: D is not the structural isomer of the given ompound as they have not equal number of carbon and hydrogen atoms in it.Hence A & C are the structural isomers of given compound.
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determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount
Answer:
9 moles of NaNO3 is obtained
Explanation:
The balanced chemical reaction equation for the reaction is;
Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3
Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.
1 mole of Al(NO3)3 yields 3 moles of NaNO3
4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3
Also,
3 moles of NaCl yields 3 moles of NaNO3
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3
Hence, NaCl is the limiting reactant and 9 moles of NaNO3 is obtained.
9 moles of NaNO₃ is obtained.
Balanced chemical reaction:
[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]
From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.
1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃
4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃
Also,
3 moles of NaCl yields 3 moles of NaNO₃
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃
Hence, NaCl is the limiting reactant and 9 moles of NaNO₃ is obtained.
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What is the percent yield of a reaction producing 26g Iridium V Sulfate from 30g Lithium Sulfate and 30g Iridium V Carbonate?
A cylindrical rod of copper (E = 110 GPa) having a yield strength of 240 MPa is to be subjected
to a load of 6660 N. If the length of the rod is 380 mm, what must be the diameter to allow an
elongation of 0.50 mm?
Answer:
required diameter is 7.65 mm
Explanation:
Given the data in the question;
F = 6660 N
l₀ = 380 mm = 0.38 m
E = 110 GPa = 110 × 10⁹ N/m²
Δl = 0.50 mm = 0.0005 m
So, lets assume the deformation is elastic;
d₀ = √( [4l₀F] / [πEΔl] )
we substitute
d₀ = √( [4 × 0.38 × 6660] / [π × (110 × 10⁹) × 0.0005]] )
d₀ = √( 10123.2 / 172787595.947 )
d₀ = √( 5.85875 × 10⁻⁵ )
d₀ = 0.007654 m
d₀ = ( 0.007654 × 1000 )mm
d₀ = 7.65 mm
Therefore, required diameter is 7.65 mm
A helium-filled balloon contains 0.16 mol He at 101 kPa and a temperature of 23°C. What is
the volume of the gas in the balloon?
V = 3.9 L
Explanation:
Given:
T = 23°C + 273 = 296K
n = 0.16 mol He
P = 101 kPa = 0.997 atm
R = universal gas constant = 0.08205 L-atm/mol-K
V = ?
Using the ideal gas law,
PV = nRT
V = nRT/P
= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)
= 3.9 L
What are the substances that interact to form new substances in a chemical reaction called?
A. Reactants
B. Products
C. Chemicals
D. Substances
Answer:
A. Reactants
Explanation:
A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.
According to the kinetic molecular theory which substances are made of particles ?
Answer:
The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.
Explanation:
Kinetic molecular theory explains the properties of solids, liquids and gases. As per this theory, matter is made of particles.
What is kinetic theory?
Kinetic molecular theory explains the properties of different states of matter. According to this theory matter is made up of particles. But the theory is mostly applies for gases.
According to kinetic theory of gases, gaseous substances consists of tiny spherical particles which are located apart from each other and hence no intermolecular force acts between them. They are in random motion and gains kinetic energy.
The kinetic energy of particles are temperature dependant and it increase as temperature rises. The collision between the particles and the particle and wall of the container in which they are will be elastic collision.
These concepts are applicable only for ideal gases. An less applicable for other states of matter.
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Which best describes the total mass of substances before and after a
combustion reaction?
A. The mass is the same because atoms are not created or
destroyed.
B. The mass is greater after the reaction because the number of
atoms increases.
C. The mass is the same because the molecules do not change.
D. The mass is less after the reaction because gases are produced.
Answer:
B. The mass is greater after the reaction because the number of
atoms increases.
What is the mass, in grams, of a piece of aluminum if its temperature changes from 25.0 ºC to 31.5 ºC when it absorbs 42.2 joules of energy? The specific heat for aluminum is 0.89J/gºC
Answer:
m = 7.29 grams
Explanation:
Given that,
Initial temperature, T₁ = 25ºC
Final temperature, T₂ = 31.5ºC
The specific heat of the metal is 0.89 J/gºC.
We know that the heat released due to the change in temperature is given by :
[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g[/tex]
So, the mass of the piece is equal to 7.29 grams.
PLEASE HELP!! NO LINKS PLEASE REAL ANSWER!!!!!
What will be volume of 20.0 g of CH4 gas at a pressure of 0.950 atm and temperature of 21.0 oc?Question 1 options:
A. 21.8 L
B. 31.8 L
C. 2.27 L
D. 4.27 L
hydrogen chloride, hydrogen nitrate (v), sodium chloride, sodium hydroxide. Name a substance known as common salt
Answer:
C: Sodium chloride
Explanation:
Common salt is gotten when sodium atoms reacts with chlorine atoms in an exothermic reaction to form an ionic substance known as sodium chloride with the chemical formula NaCl.
Equation is;
2Na + Cl2 = 2NaCl
Looking at the options, the correct one is Sodium chloride.
can someone answer this
what is the percent composition of calcium fluoride
Answer:
78.07
Explanation:
them seperatly is
Calcium Ca 51.333%
Fluorine F 48.667%
Read about reverse osmosis and multistage flash distillation .Then identify at least three advantages and three
disadvantages for each process
Answer:
Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob
Explanation:
Osmosis is movement of solvent (like water) through semi permeable membrane (like living cell) into solution of higher solute concentration.Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.
Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.
Multistage flash distillation refers to desalination water distilling seawater, by flashing water portions in steams in various stages of concurrent heat exchangers.Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.
Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.
2+4 help please i will fail 6th grade
Answer:
6
Explanation:
lol
A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?
Answer:
What is
the volume of the balloon when the temperature is 310K?
A certain reaction has an activation energy of 51.02 kJ/mol. At what Kelvin temperature will the reaction proceed 4.50 times faster than it did at 365 K
Answer:
[tex]T_2=400.73K[/tex]
Explanation:
From the question we are told that:
Activation energy [tex]E_a= 51.02 kJ/mol.=>51.02*10^3J/mol[/tex]
Reaction Ratio [tex]\triangle K=4.50[/tex]
Initial Temperature [tex]T_1=365K[/tex]
Generally the equation for Final Temperature [tex]T_2[/tex] is mathematically given by
[tex]log \triangle K=\frac{E_a}{2.303R}*(\frac{T_2-T_1}{T_1T_2})[/tex]
Where
[tex]R=Gas constant[/tex]
[tex]R =8.3143[/tex]
Therefore
[tex]log 4.50=\frac{51.2*10^3}{2.303*8.31432}*(\frac{T_2-365}{365*T_2})[/tex]
[tex]log 4.50=7.328*\frac{T_2-365}{T_2}[/tex]
[tex]0.0892=\frac{T_2-365}{T_2}[/tex]
[tex]0.0892T_2=T_2-365[/tex]
[tex]365=T_2-0.0892T_2[/tex]
[tex]365=0.91T_2[/tex]
[tex]T_2=\frac{365}{0.91}[/tex]
[tex]T_2=400.73K[/tex]
What is the IUPAC name for the following compound?
a. benzenecarbonitrile
b. benzenecyanide
c. phenylcyanide
d. cyanophenyl
Answer:
Option a. Benzenecarbonitrile
Explanation:
You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.
As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.
This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.
phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.
Hope this helps