Answer:
associative property of addition
Step-by-step explanation:
There are various properties of mathematics.
One of these is called the associative property of addition, which states that for three numbers a, b, and c:
(a + b) + c = a + (b + c)
Basically, this means that given an addition statement, no matter if we change the order of how we solve it (solving a + b first or solving b + c first), we will still obtain the same result.
Therefore, here, it's clearly a representation of the associative property of addition, and that's the answer.
~ an aesthetics lover
Suppose you were given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). What is the value of a?
Answer:
Hope it helps..........The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). Hence, the value of x is 7.5.
What is a function?Function is a type of relation, or rule, that maps one input to specific single output.
The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2).
here x = 2
Substitute in the function;
F(x)=x^4-2x^3+3x^2 - ax+3
F(2) = 2^4-2(2)^3+3(2)^2 - a(2) +3
F(2) = 16 - 16 + 12 - 2a +3
F(2) = 15 - 2a
15 - 2a = 0
15 = 2a
a = 7.5
Hence, the value of x is 7.5
Learn more about function here:
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A triangular plot of land has one side along a straight road measuring 147147 feet. A second side makes a 2323degrees° angle with the road, and the third side makes a 2222degrees° angle with the road. How long are the other two sides?
Answer:
81.23 ft and 77.88 ft long
Step-by-step explanation:
The sum of the internal angles of a triangle is 180 degrees, the missing angle is:
[tex]a+b+c=180\\a+23+22=180\\a=135^o[/tex]
According to the Law of Sines:
[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}= \frac{C}{sin(c)}[/tex]
Let A be the side that is 147 feet long, the length of the other two sides are:
[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}\\B=\frac{sin(23)*147}{sin(135)}\\B=81.23\ ft\\\\\frac{A}{sin(a)}= \frac{C}{sin(c)}\\C=\frac{sin(22)*147}{sin(135)}\\C=77.88\ ft[/tex]
The other two sides are 81.23 ft and 77.88 ft long
Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!
Step-by-step explanation:
(-3x-2/x) multiply by (-15x+12/x)
Which of the following relations is a function?
A{(3,-1), (2, 3), (3, 4), (1,7)}
B{(1, 2), (2, 3), (3, 4), (4, 5)}.
C{(3, 0), (4, -3), (6, 7), (4,4)}
D{(1, 2), (1, 3), (2, 8), (3, 9)}
Answer:
B
Step-by-step explanation:
A is not a function because the same x value is repeated twice with different y values. The same goes for C and D so the answer is C.
Answer:
B.
Step-by-step explanation:
Well a relation is a set of points and a function is a relation where every x value corresponds to only 1 y value.
So lets see which x values in these relations have only 1 y value.
A. Well a isn’t a function because the number 3 which is a x value had two y values which are -1 and 4.
B. This relation is a function because there are no similar x values.
C. This is not a function because the x value 4 has two y values which are 4 and -3.
D. This is not a function because the number 1 has 2 and 3 as y values.
which of the following equations is equal to 2x^2+8 A. (2x-4i)(x-2i) B. (2x+4i)(x+2i) C. (2x-2i)(x+6i) D. (2x-4i)(x+2i)
Answer:
(2x-4i) (x+2i)
Step-by-step explanation:
2x^2+8
Factor out 2
2 ( x^2+4)
Writing as the difference of squares a^2 -b^2 = (a-b) (a+b)
2 ( x^2 -(2i)^2)
2 ( x-2i) (x+2i)
Multiplying the 2 into the first term
(2x-4i) (x+2i)
Which proportion would convert 18 ounces into pounds?
Answer:
16 ounces = 1 pound
Step-by-step explanation:
You would just do 18/16 = 1.125 pounds. There are always 16 ounces in a pound, so it always works like this
A random sample has been taken from a normal distribution. The output from a software package follows:
variable N Men SE Mean StDev Variance Sum
X ? ? 1.58 6.11 ? 751.40
a) Fill in the missing quantities.
b) Find a 95% CI on the popular mean.
Answer:
a) variable = X
N = 15
Mean = 50.0933
SE Mean = 1.58
StDev = 6.11
Variance = 37.3321
Sum = 751.40
b) 95% Confidence interval = (46.997, 53.190) = (47.00, 53.19)
Step-by-step explanation:
variable = X
N = ?
Mean = ?
SE Mean = 1.58
StDev = 6.11
Variance = ?
Sum = 751.40
To fill in the missing quantities, we need to use some of their formulas.
For N, the number of variables
SE = Standard Error of the mean = σₓ = (σ/√N)
σₓ = Standard Error of the mean = 1.58
σ = standard deviation of the sample = 6.11
N = sample size = ?
1.58 = (6.11/√N)
√N = (6.11/1.58) = 3.8671
N = 3.8671² = 14.954374299 = 15 to the nearest whole number.
For the Mean
Mean = (Sum of variables)/(Number of variables)
Mean = ?
Sum of variables = 751.40
Number of variables = N = 15
Mean = (751.40/15) = 50.0933333333 = 50.093
For Variance
Variance = (Standard deviation)² = (6.11)² = 37.3321
b) To compute the confidence interval.
idence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample mean) ± (Margin of error)
Sample Mean = 50.0933
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the mean)
Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample size is large enough for the sample properties to approximate the population properties.
To find the critical value from the z-tables,
z at 95% confidence level = 1.960 (from the z-distribution tables)
Standard error of the mean = σₓ = (σ/√N)
Already calculated to be 1.58
95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]
CI = 50.0933 ± (1.960 × 1.58)
CI = 50.0933 ± 3.0968
95% CI = (46.9965, 53.1901)
95% Confidence interval = (46.997, 53.190) = (47.00, 53.19)
Hope this Helps!!!
Consider the statement, "Confidence intervals are underutilized" and explain what the implications might be of using or not using confidence intervals.
Answer:
Step-by-step explanation:
Confidence intervals have been underutilized prior to this time.
The implications of not using confidence intervals include:
- The under-representation or over-representation of research results that amounts from the use of a single figure to represent a statistic.
- In Market Research analysis, neglecting the use of confidence intervals will increase the risk of your portfolio.
Implications/Importance of using confidence intervals include:
- Calculation of confidence interval gives additional information about the likely values of the statistic you are estimating.
- In the presentation and comprehension of results, confidence intervals give more accuracy from the data or metrics captured.
- Given a sample mean, confidence intervals show the likely range of values of the population mean.
2. A ski lodge offers two weekend packages. Package A provides 2 nights and 3 meals for $280. Package B provides 2 nights and 5 meals for $320. Write and solve a system of equations to find the costs per night and per meal. (Assume the cost per night and cost per meal are the same for both packages.) Use n to represent the cost per night and m to represent the cost of each meal. (8 points) Step 1: The equation representing package A is given. Complete the system of equations by writing an equation to represent package B. (1 point) Package A: 2n + 3m = 280 Package B: ___________________ Step 2: Select a method for solving the system. Which method did you choose? Why? (2 points) Step 3: Solve the system of equations to find the costs per night and per meal. Show your work.(3 points) Step 4: Explain the meaning of the solutions for m and n. (2 points: 1 point each)
Answer:
see below
Step-by-step explanation:
Package A
2n + 3m = 280
Package B
2n + 5m = 320
Using elimination to eliminate n since the coefficient is the same
Subtracting the A equation from the B equation
2n + 5m = 320
-2n - 3m = -280
------------------------
2m = 40
Divide by 2
2m/2 = 40/2
m = 20
Now finding n
2n+3m = 280
2n +3(20) = 280
2n+60 = 280
Subtract 60 from each side
2n +60-60= 280-60
2n = 220
Divide by 2
2n/2 = 220/2
n = 110
The cost per night is 110 and the cost per meal is 20
50 pts If You Get IT RIGHT!!!
Kellianne lined up the interior angles of the triangle along line p below. Triangle A B C. Angle A, B, and C are on line p. Which statements are true for line p? Check all that apply.
Answer:
angles a and b are lined up
The sets L and B are given below.
L= (-2, 2, 8)
B= (-2, 1, 2, 4, 8)
Find the intersection of L and B.
Find the union of L and B.
Write your answers using set notation (in roster form).
[tex]L= (-2, 2, 8) \\
B= (-2, 1, 2, 4, 8) \\ L \: n \: B \: = \: ( - 2, 2, 8) \\ L \: u \: B = ( - 2, 2, 1, 4, 8)[/tex]
WILL GIVE BRAINLIEST! NEED QUICK HELP ASAP! Photo added! least common denominator x^3/x^2+4x+4 and -9/x^2+5x+6
The denominator( s ) we are given are [tex]x^2 + 4x + 4[/tex], and . The first thing we want to do is factor the expressions, to make this easier -
[tex]x^2 + 4x + 4[/tex]
This expression is a perfect square, as ( x )^2 = x^2, ( 2 )^2 = 4, 2 * ( x ) * ( 2 ) = 4x. Thus, the simplified expression should be the following -
[tex]( x + 2 )^2[/tex]
The other expression is, on the other hand, not a perfect square so we must break this expression into groups and attempt factorization -
[tex]x^2 + 5x + 6,\\\left(x^2+2x\right)+\left(3x+6\right),\\x\left(x+2\right)+3\left(x+2\right),\\\left(x+2\right)\left(x+3\right)\\\\Factored Expression = \left(x+2\right)\left(x+3\right)[/tex]
Combining ( x + 2 )^2 and ( x + 2 )( x + 3 ), the expression that contains factors of each is ( x + 2 )^2 * ( x + 3 ), or in other words the LCM.
Solution = [tex]\left(x+2\right)^2\left(x+3\right)[/tex]
the construction of creating the perpendicular bisector of PQ is started below. How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?
Answer: It will not create a perpendicular bisector.
Explanation:
If the compass is the same setting as the first arc and drawn from point B, the points of intersection of the arcs will pass through the midpoint of AB (thus creating a perpendicular bisector).
If you change the setting of the compass and draw an arc from point B, the points of intersection of the arcs will still create a perpendicular line but will not pass through the midpoint of AB (creating a perpendicular line but not a perpendicular bisector).
A perpendicular bisector divides a line segment into two equal segments.
If the compass setting is changed, the line will not be bisected.
To bisect a line, the positioning of the compass must be done as follows:
Place the compass at the endpoint of the line segment, then draw an arcRepeat the above process for the other endpoint of the line segment.Trace the point of intersection of the two arcs, to the line that is being bisected.The above points are what is being done in the given construction.
Any step or setting other than that, would not create a perpendicular bisector.
Hence, if the compass setting is changed, the perpendicular bisector of the line would not be drawn.
Read more about perpendicular bisection at:
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Martin had 24 5 pounds of grapes left. Which expression shows the pounds of grapes Martin has if he doubles his current amount?
Answer:
x=2*2 4/5
Step-by-step explanation:
: Martin had 2 4/5 pounds of grapes left.
So x=2*2 4/5
x=2* 14/5
x=28/5
x=5 3/5
The expression shows the pounds of grapes Martin has if he doubles his current amount of grapes. x=2*2 4/5
A contractor is setting up new accounts for the local cable company. She earns $75 for each customer account she sets up. Which expression models this situation, and how much will she profit if she sets up 8 customers? (The variable c represents the number of customers.) Question 4 options: A) c – 75; $9.78 B) 75c; $600 C) c + 75; $600 D) 75/c; $9.78
Answer:
B
Step-by-step explanation:
The contractor gets $75 for every single customer she sets up. Okay, so if she sets up 1 customer, she gets $75, if she sets up 2, she gets $150 and so on.
This is a multiplication expression since multiplication is just repeated addition, which is what is happening in this case, where the contractor gets $75 added to her account every time she sets another person up.
At this point you can just eliminate the other answer options except for B, so it is B.
But to double check... if you multiply 75 by 8, you would get $600, which is B.
Answer:
d
Step-by-step explanation:
75/c; $9.78
At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men nor teachers. Find the number of women teachers attending the lecture
Answer:
20 teachers
Step-by-step explanation:
Because if you take 100 and minus it by 29, 23, 4 and 24 you get 20.
What is the standard form for 80000 + 200+ 2
Answer:
80202
Step-by-step explanation:
Simply add according to number value:
200 - 2 goes into hundreds place
2 - 2 goes into ones place
80000 - 8 goes into ten-thousands place
PLS HELP-- The total area of the rectangular prism shown is a. 30 sq ft b. 50 sq ft c. 62 sq ft
Answer:
c (62)
Step-by-step explanation:
17. Which of the following trigonometric functions can be described as a reciprocal trig function?
O A. sin(e)
O B. sin-1(0)
O C. arctan(e)
O D. sec(0)
Answer:
Step-by-step explanation:
Reciprocal trig functions are opposite or mirror of the normal trig functions. The normal trig functions are as follows:
Sine = opposite side/hypotenuse
Cosine = adjacent side/hypotenuse
Tangent = opposite side/adjacent side
The reciprocals of the above trig ratios would be
Cosecant = hypotenuse/opposite side
Secant = hypotenuse/adjacent side
Cotangent = adjacent side/opposite side
Therefore, looking at the given options, the trigonometric function that can be described as a reciprocal trig function is
D. sec(0)
The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown population mean. If a random sample of 27 text messages is taken and results in a sample mean of 29 characters, find a 95% confidence interval for the population mean. Round your answers to two decimal places.
Answer:
29+/-2.26
= (26.74, 31.26) characters
Therefore the 95% confidence interval (a,b) = (26.74, 31.26) characters
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 29 characters
Standard deviation r = 6 characters
Number of samples n = 27
Confidence level = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
29+/-1.96(6/√27)
29+/-1.96(1.154700538379)
29+/-2.263213055223
29+/-2.26
= (26.74, 31.26) characters
Therefore the 95% confidence interval (a,b) = (26.74, 31.26) characters
SCCoast, an Internet provider in the Southeast, developed the following frequency distribution on the age of Internet users. Find the mean and the standard deviation. (Round squared deviations to nearest whole number and final answer to 2 decimal places.)
Answer:
Mean: 40.17 years.
Standard deviation: 10.97 years.
Step-by-step explanation:
The frequency distribution is in the attached image.
We can calculate the mean adding the multiplication of midpoints of each class and frequency, and dividing by the sample size.
The midpoints of a class is calculated as the average of the bounds of the class.
Then, the mean can be written as:
[tex]E(X)=\dfrac{1}{N}\sum f_iX_i\\\\\\E(X)=\dfrac{1}{60}(3\cdot15+7\cdot25+18\cdot35+20\cdot45+12\cdot 55)=\dfrac{45+175+630+900+660}{60}\\\\\\E(X)=\dfrac{2,410}{60}=40.17[/tex]
The standard deviation can be calculated as:
[tex]s=\sqrt{\dfrac{1}{N-1}\sum f_i(X_i-E(X))^2}\\\\\\s=\sqrt{\dfrac{1}{59}[3(15-40.17)^2+7(25-40.17)^2+18(35-40.17)^2+20(45-40.17)^2+12(55-40.17)^2]}[/tex]
[tex]\\\\\\s=\sqrt{\dfrac{1}{59}( 1,900.59 + 1,610.90 + 481.12 + 466.58 + 2,639.15 )}\\\\\\s=\sqrt{\dfrac{ 7,098.33 }{59}}=\sqrt{120}=10.97[/tex]
A 37 bag sample had a mean of 421 grams. Assume the population standard deviation is known to be 29. A level of significance of 0.05 will be used. State the null and alternative hypothesis.
Answer: [tex]H_0:\mu=421[/tex]
[tex]H_a : \mu\neq421[/tex]
Step-by-step explanation:
A null hypothesis is a type of hypothesis that is used in statistics that assumes there is no difference between particular characteristics of a population wheres the alternative hypothesis shows that there is a difference.Given: A 37 bag sample had a mean of 421 grams.
Let [tex]\mu[/tex] be the population mean.
Then, the null hypothesis would be:
[tex]H_0:\mu=421[/tex]
whereas the alternative hypothesis would be:
[tex]H_a : \mu\neq421[/tex]
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a that makes the following probability statements true.
a. P(X <= a) =0.95
b. P(X < a)= 0.49
c. P(X >= a)= 0.85
d. P(X >a )= 0.89
e. P(1.83 <= x <=a)= 0.31
Answer:
(a) The value of a is 53.35.
(b) The value of a is 38.17.
(c) The value of a is 26.95.
(d) The value of a is 25.63.
(e) The value of a is 12.06.
Step-by-step explanation:
The probability density function of X is:
[tex]f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}[/tex]
Here, 22 < X < 55.
(a)
Compute the value of a as follows:
[tex]P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35[/tex]
Thus, the value of a is 53.35.
(b)
Compute the value of a as follows:
[tex]P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17[/tex]
Thus, the value of a is 38.17.
(c)
Compute the value of a as follows:
[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95[/tex]
Thus, the value of a is 26.95.
(d)
Compute the value of a as follows:
[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63[/tex]
Thus, the value of a is 25.63.
(e)
Compute the value of a as follows:
[tex]P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06[/tex]
Thus, the value of a is 12.06.
A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66degreesF.Construct a 99%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body temperature?
Answer:
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body temperature is correct.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 104 - 1 = 103
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.624
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.
The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body temperature is correct.
PLEASE HELP I GIVE BRAINLIEST AND 25 POINTS JUST ANSWER GOOD!!! ATTACHED IS SEQUENCES QUESTION. ONLY ONE QUESTION PLEASEEE I NEED IT IN 5 MINUTES PLEASEEE
Answer:
First box: 6
Second box: 10
Third box: 14
Step-by-step explanation:
The rule is to add the same number to each box. I tried adding different numbers, and I stopped at 4. 2 + 4 is 6, 6+4 is 10, 10+4 is 14, and 14+4 is 18. Therefore, you fill in the numbers accordingly.
Hope this helps!
~gloriouspurpose~
The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.8, 15.6, 15.1, 15.2, 15.1, 15.5, 15.9, 15.5. Construct a 97.5% confidence interval for the mean amount of juice in all such bottles. Assume an approximate Normal distribution.
Answer:
The required 97.5% confidence interval is
[tex]\text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\\text {CI} = 15.5 \pm 2.8412\cdot \frac{0.31}{\sqrt{8} } \\\\\text {CI} = 15.5 \pm 2.8412\cdot 0.1096\\\\\text {CI} = 15.5 \pm 0.311\\\\\text {CI} = 15.5 - 0.311, \: 15.5 + 0.311\\\\\text {CI} = (15.19, \: 15.81)\\\\[/tex]
Therefore, we are 97.5% confident that the actual mean amount of juice in all such bottles is within the range of 15.19 to 15.81 ounces
.
Step-by-step explanation:
The amounts (in ounces) of juice in eight randomly selected juice bottles are:
15.8, 15.6, 15.1, 15.2, 15.1, 15.5, 15.9, 15.5
Let us first compute the mean and standard deviation of the given data.
Using Excel,
=AVERAGE(number1, number2,....)
The mean is found to be
[tex]\bar{x} = 15.5[/tex]
=STDEV(number1, number2,....)
The standard deviation is found to be
[tex]s = 0.31[/tex]
The confidence interval for the mean amount of juice in all such bottles is given by
[tex]$ \text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $\\\\[/tex]
Where [tex]\bar{x}[/tex] is the sample mean, n is the samplesize, s is the sample standard deviation and [tex]t_{\alpha/2}[/tex] is the t-score corresponding to a 97.5% confidence level.
The t-score corresponding to a 97.5% confidence level is
Significance level = α = 1 - 0.975 = 0.025/2 = 0.0125
Degree of freedom = n - 1 = 8 - 1 = 7
From the t-table at α = 0.0125 and DoF = 7
t-score = 2.8412
So the required 97.5% confidence interval is
[tex]\text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\\text {CI} = 15.5 \pm 2.8412\cdot \frac{0.31}{\sqrt{8} } \\\\\text {CI} = 15.5 \pm 2.8412\cdot 0.1096\\\\\text {CI} = 15.5 \pm 0.311\\\\\text {CI} = 15.5 - 0.311, \: 15.5 + 0.311\\\\\text {CI} = (15.19, \: 15.81)\\\\[/tex]
Therefore, we are 97.5% confident that the actual mean amount of juice in all such bottles is within the range of 15.19 to 15.81 ounces.
2.
On a spinner numbered 1-9, what is the probability of spinning a multiple of 3?
0
1/2
1/3
2/3
Answer:
1/3
Step-by-step explanation:
the multiples of three is three, six, and nine
which is 3/9 bc the total is 9
hope this helps
solve the proportion for y 11/8=y/13
Answer:
We can use the cross products property.
11/8 = y / 13
8y = 11 * 13
y = 11 * 13 / 8 = 17.875
Answer:
y=17.875
Step-by-step explanation:
[tex]\frac{11}{8} = \frac{y}{13}[/tex]
11(13)=8y
143=8y
y=17.875
Can Someone help me!!! I need this ASAP! What number? Increased by 130% is 69? FYI: the answer is less than 69
Answer:
Hey there!
There are a few ways you could solve this problem, but the easiest would to be writing an equation.
You could say-
2.3x=69
Divide by 2.3
x=30
Hope this helps :)
Answer:
30
Step-by-step explanation:
the answer is 30 bc increasing something by 130% is multiplying it by 2.3 so technically you have to divide 69 by 2.3 which equals to 30
The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown. f(x) = 4(x2 + 12x) + 10 (twelve-halves) squared = 36 What is the function written in vertex form?
Answer:
[tex]f(x)=4(x+6)^2-134[/tex]
Step-by-step explanation:
We are required to write the function[tex]f(x) = 4x^2 + 48x + 10[/tex] in vertex form.
First, bring the constant to the left-hand side.
[tex]f(x) -10= 4x^2 + 48x[/tex]
Factorize the right hand side.
[tex]f(x) -10= 4(x^2 + 12x)[/tex]
Take note of the factored term(4) and write it in the form below.
[tex]f(x) -10+4\Box= 4(x^2 + 12x+\Box)[/tex]
[tex]\Box = (\frac{\text{Coefficient of x}}{2} )^2\\\\\text{Coefficient of x}=12\\\\\Box = (\frac{12}{2} )^2 =6^2=36[/tex]
Substitute 36 for the boxes.
[tex]f(x) -10+4\boxed{36}= 4(x^2 + 12x+\boxed{36})[/tex]
[tex]f(x) -10+144= 4(x^2 + 12x+6^2)[/tex]
[tex]f(x) +134= 4(x+6)^2\\f(x)=4(x+6)^2-134[/tex]
The function written in vertex form is [tex]f(x)=4(x+6)^2-134[/tex]
Answer:
C
Step-by-step explanation:
I just finished the unit test on Edge. and got a 100% and I selected "c" as my answer.