Answer:
D. Tetrahedral
Explanation:
the reason is because four electron pairs are distributed.
Consider preparing ammonia gas by the following reaction:
N2(g) + 3H2(g) ===> 2NH3(g)
If you have 28.02 g of N2 and excess H2, how many grams of NH3(g) can be produced.
6.06g
14.01g
34.08 g
68.16 g
28.02g
Answer:
34.08g
Explanation:
(Take the atomic mass of N=14.0, H=1.0)
no. of moles = mass / molar mass
no. of moles of N2 used = 28.02 / (14x2)
= 1 mol
Since H2 is in excess and N2 is the limiting reagent, the no. of moles of NH3 produced depends on the no. of moles of N2 used.
From the equation, the mole ratio of N2:NH3 = 1: 2,
which means one mole of N2 produces 2 moles of NH3.
From the ratio, we can deduce the no. of moles of NH3 produced = 1 x 2 =2moles.
Mass = no. of moles x molar mass
Mass of NH3 produced = 2 x (14.0+1.0x3)
= 34g
≈34.08g (this happens because the atomic mass I took is only corrected to 1 decimal place, but in the end, this is only a very small error in the decimals. Make sure you take a look if the question provides the atomic mass:) )
What is measured by the reaction rate? the probability that a reaction will occur the speed at which products form the time required for a reaction to go to completion
Answer: the speed at which products form
Explanation:
Rate of a reaction is defined as the speed at which a chemical reaction proceeds. It is often expressed in terms of the concentration of a reactant that is consumed in a unit time or the concentration of a product that is formed in a unit of time.
For a general reaction :[tex]A\rightarrow B[/tex]
[tex]Rate=-\frac{d[A]}{dt}[/tex]
or [tex]Rate=+\frac{d[B]}{dt}[/tex]
where d[A] = change in concentration of reactant A
d[B] = change in concentration of product B
dt = time interval
How many Liters of 18 M H2SO4 are needed to make 0.5 L of 1.5 M H2SO4
Answer:
0.04 L
Explanation:
The following data were obtained from the question:
Concentration of stock solution (C1) = 18M
Volume of stock solution needed (V1) =?
Concentration of diluted solution (C2) = 1.5M
Volume of diluted solution (V2) = 0.5L
The volume of the stock solution needed can be obtain by using the dilution formula.
This is illustrated below:
C1V1 = C2V2
18 x V1 = 1.5 x 0.5
Divide both side by 18
V1 = (1.5 x 0.5)/18
V1 = 0.04L
Therefore, the volume of the stock solution needed is 0.04L.
Which lifestyle is most likely to lead to infertility in a male ?
A man who works as a mechanic
A man who works as a computer programmer and sits at desk magority of the day
A semi professional athlete
A man who works for a company’s that applies pesticides to lawns
Answer:
The second on, A man who works as a computer programmer and sits at desk magority of the day.
Explanation:
Answer:
Explanation:
The only answer I can think as being possible is the last one. Pesticides are chemicals that go after unwanted animal life. They do not know that they should not attack human beings.
Infertility could very well be one of the side effects of a pesticide. There are others as well. Some pesticides go after the central nervous system (think mice and rats) and those are dangerous to use and to leave around.
The others all involve occupations that either require authentic abilities or mental astuteness. Neither should affect a man's ability to reproduce.
Which phrase describes an irregular galaxy?
O has a round shape
O contains many young stars
O has arms that extend from the center
O is larger than other types of galaxies
Answer: The answer would be B. contains many young stars.
Explanation:
There is very little new star formation in Irregular galaxies. Irregular galaxies have no particular shape and are smaller than other types of galaxies.
The irregular galaxy possess many young stars.
Irregular galaxyThey are the most unusual of galaxies.
They do not fit into either the elliptical or spiral galaxy categories.
They do not possess nice spiral arm, however, they do possess dark patches of dust and gas.
The irregular galaxies do not possess definite shape.
They comprise of several young stars as the extent of the formation of stars in irregular galaxies in brisk. They also do comprise old stars.
Thus, the correct statement is contains many young stars.
Find more information about irregular galaxies here:
https://brainly.com/question/1241789
SERE
What type of energy is the sum of an object's potential and kinetic energy?
mechanical energy
electromagnetic energy
chemical energy
thermal enemy
Answer:
Mechanical energy
Answer:
Mechanical Energy
Explanation:
The mechanical energy is the sum of the objects potential energy (energy the object possess due to its position) and its kinetic energy (energy the object possess due to its motion). Adding this two energies together, gives the total mechanical energy.
How many grams of NO are produced from 15.8 g of H2O
Answer:
26.33 g of NO.
Explanation:
We'll begin by writing the balanced equation to produce NO from H2O. This is given below:
5N2 + 6H2O —> 4NH3 + 6NO
Next, we shall determine the mass of H2O that reacted and the mass of NO produced from the balanced equation. This is illustrated below:
Molar mass of H2O = (2x1) + 16 = 18 g/mol
Mass of H2O from the balanced equation = 6 x 18 = 108 g
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO from the balanced equation = 6 x 30 = 180 g
From the balanced equation above,
108 g of H2O reacted to produce 180 g of NO.
Finally, we shall determine the mass of NO produced by the reaction of 15.8 g of H2O.
This is illustrated below:
From the balanced equation above,
108 g of H2O reacted to produce 180 g of NO.
Therefore, 15.8 g of H2O will react to produce = (15.8 x 180)/108 = 26.33 g of NO.
Therefore, 26.33 g of NO were obtained from the reaction.
procedure to find out if the penny is real copper with copper wire
Answer:
Four ways to test a copper penny are given below:-
Explanation:
Firstly, take a quick look only at the color of the penny. Zinc pennies may appear patchy, irregular whereas copper-gold coins may seem more probable to be orange or even chocolate. Secondly, drop your penny on the floor and hear the noise it's making. The copper penny would have a "started to ring" sound in this situation, whereas the zinc penny should "clunk." Third, you can weigh the centimeter. You'll need an accurate scale weighing in grams. The penny of copper will weigh 3.11 grams while the penny of zinc weighs 2.5 grams. In the end, look at the date. If your penny was taken out of circulation before 1982, 95 percent copper and 5 percent zinc will be made. Beginning in 1982, pennies had just 2.5 percent copper and 97.5 percent zinc in them. Pennies from any of the two formulations made in 1982 may be produced.
Consider preparing ammonia gas by the following reaction:
N2(g) + 3H2(g)
===>
2NH3(g)
If you have 28.02 g of N2 and excess H2, how many grams of NH3(g) can be produced.
6.06 g
14.01 g
34.08 g
68.16 g
28.02 g
Answer:
34.08 g
Explanation:
Take the atomic mass of N=14.0, H=1.0/
no. of moles=mmass/molar mass
no. of moles of N2 used = 28.02 / (14x2)
=1.0007mol
From the equation, the mole ratio of N2 : NH3 = 1: 2,
so one mole of N2 produces 2 moles of NH3.
Using this ratio, we can deduce that the no. of moles of NH3 = 1.0007x2
= 2.001428mol
mass = no. of moles x molar mass
Hence,
mass of NH3 produced = 2.001428 x (14+1x3)
= 34.03
≈C
1. Give IUPAC for the following compound
Answer:
Ethane
Explanation:
The correct name for molecule I is
Molecule I
I
|
CH3-CH-CH3
a. Iodopropane
b. 2-iodylpropane
c. 2-iodopropane
D. Propyliodine
14. The correct name for molecule III is
Molecule III
F
|
C= CH
——-
a. 2-Fluoroeth 1-yne
b. Fluoroethyne
C. Fluoroethene
D. Methylfluorine
16. Synthetic chlorinated hydrocarbons such as dioxins and furans are usually greater pollution hazard then natural organic substances because synthetic hydrocarbons are
a. More volatile
b. Less water soluble
C. Less Biodegradable
D. More chemically reactive
Question 17.
Sources of pollutants
1. High temperature combustion
2. Pulp and paper industry
3. Pesticides
4. Sour gas plants
Match each source of pollutant as numbered above with its pollutant as listed below. Use each number only once
17. Dioxins/furans
18. SO2(g)
19. Nox(g)
20. Phosphates
Answer:
c). 2-iodopropane
14) C). Fluoroethene
16) D). More chemically reactive
17) 1). High temperature combustion - Dioxins/furans
2). Pulp and paper industry - SO2(g)
3). Pesticides - Phosphates
4). Sour gas plants - Nox(g)
Explanation:
The correct name for molecule I would be '2-iodopropane' where the number 2 reflects the position of iodine. There are three carbons and 8 hydrogen atoms which reflect that it is an alkane compound. In the given carbon chain. In this chain of three carbons, iodine is present on the second carbon. Therefore, option C is the correct answer.
14). The appropriate name for molecule III exemplifies Fluoroethene as it consists of two carbons due to which it belongs to the 'ethane' group and it bears the prefix 'fluoro as it belongs to fluorine group and the suffix '-ene' due to double bond.
16). Synthetic hydrocarbons are 'more chemically reactive' and therefore, it generates greenhouse gases and leads to climate change, global warming, depletion of the ozone layer, etc.
17). 1). Dioxins are generated as a result of high-temperature combustion processes like commercial waste incineration or burning of fuels.
2). Pulp and paper industry releases various gases like nitrogen oxide, sulfur dioxide SO2(g), carbon dioxide, etc.
3). Phosphate is the pollutant released from pesticides that badly affects the fertility of the soil.
4). Nox(g) nitrogen oxide released by sour gas plants and coal-fired emissions is a major contributor to increased greenhouses gases and global warming.
1. A 10.0 g sample of propane, C3H8, was combusted in a constant-volume bomb
calorimeter. The total heat capacity of the bomb calorimeter and water was 8.0
kJ/°C. The molar heat of combustion of propane is -2 222 KJ/mol. If the starting
temperature of the water was 20 °C, what will be the final temperature of the
bomb calorimeter?
Answer:
The final temperature of the bomb calorimeter is 82.98°C
Explanation:
The given information are;
The mass of the propane sample = 10.0 g
The heat capacity of the bomb calorimeter = 8.0 kJ/°C
The molar heat of combustion of propane is -2,222 kJ/mol.
The starting (initial) temperature of the water, T₁ = 20°C
The final temperature of the bomb calorimeter = T₂
The molar mas of propane = 44.1 g/mol
The number of moles, n, of propane present in 10.0 g of propane is found as follows;
[tex]Number \ of \ moles \ of \ propane, \ n = \dfrac{Mass \ of \ propane}{Molar mass \ of \ propane} = \dfrac{10}{44.1} = 0.227 \ moles[/tex]Which gives;
The heat, Δh, released from the combustion of 10.0 g of propane = 0.227 × -2222 kJ/mol
Δh = -503.85 kJ/mol
Heat gained by the calorimeter = Heat released from the combustion of 10.0 g of propane = 503.85 kJ/mol
Change in heat, Δh[tex]_c[/tex] in the calorimeter = Heat capacity × Temperature change
Δh[tex]_c[/tex] = m × C
503.85 kJ/mol = 8.0 kJ/°C × (T₂ - 20°C)
T₂ = -503.85 kJ/mol/(8.0 kJ/°C) + 20°C = 82.98°C
The final temperature of the bomb calorimeter = 82.98°C