Answer:
n = 2
Step-by-step explanation:
Given
5( [tex]\frac{n-1}{10}[/tex] ) = [tex]\frac{1}{2}[/tex] ← distribute parenthesis on left side
[tex]\frac{n-1}{2}[/tex] = [tex]\frac{1}{2}[/tex]
Since denominators are both 2 then equate numerators
n - 1 = 1 ( add 1 to both sides )
n = 2
The length of ZX is 2 units. What is the perimeter of triangle XYZ? 5 + + 2 units 5 + 3 units 5 + + 2 units 10 + 2 units
Answer:
B) 5 + 3√5 units
Step-by-step explanation:
The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?
A) 5 +√3 + 2 √5 units
B) 5 + 3√5 units
C) 5 + √6 + 2√5 units
D) 10 + 2√5 units
From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).
The distance between two point
[tex]O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
The lengths of the sides of the triangle are:
[tex]|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit[/tex]
The perimeter of the triangle is the sum of all the sides, i.e.
Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5
Answer:
B
Step-by-step explanation:
For every 2 males birds in a birdcage, there are 5 females. What is the ratio of
males to females? *
Answer:
2:5
Step-by-step explanation:
The structure of a ratio is x:y.
So all you have to do is place the former as the first digit and the latter as the second and separate them by a colon.
Brad walked a total of 24 kilometers by making 6 trips to school. After 21 trips to school, how many kilometers will Brad have walked in total? Solve using unit rates.
Answer:
84 km... Mark me as BRAINLIEST
Step-by-step explanation:
Refer to the pic...
Hope it helped you!
Step-by-step explanation:
Since it takes 6 trips to cover 24 km -
1 trip = 24/6
Therefore 1 trip is -
4 km
Now, the distance for 21 trips is -
21*4 = 84
Therefore, Brad has walked -
84 km
HOPE YOU FIND THIS HELPFUL
Please answer this in two minutes
Answer:
[tex] s = 14.1 [/tex]
Step-by-step explanation:
Given:
<S = 31°
SQ = r = 9
SR = q = 21
s = ?
To find s, use the Law of Cosines:
s² = r² + q² - 2rs*cos(S)
[tex] s^2 = 9^2 + 21^2 - 2*9*21*cos(31) [/tex]
[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]
[tex] s^2 = 522 - 324.02 [/tex]
[tex] s^2 = 197.98 [/tex]
[tex] s = 14.1 [/tex] (nearest tenth)
HELP!! PLEASEE!
The graph f(x)=e^x-1+5 is shown below. g(x) is a transformation of f(x). How would you write the equation for the function g(x)?
Answer:
A
Step-by-step explanation:
The blue graph, g(x), is shifted down 8 units.
So the answer is f(x)-8 which is A
Answer: C. g(x) = eˣ⁻¹ - 3
Step-by-step explanation:
g(x) is a vertical shift 8 units down (-8) from f(x)
f(x) = eˣ⁻¹ + 5
g(x) = (eˣ⁻¹ + 5) - 8
= eˣ⁻¹ - 3
Determine the equation for a line perpendicular to y=1/3+4 and has an x-intercept of 2.
Answer:
y = -3x + 6
Step-by-step explanation:
Any line perpendicular to
y = (1/3)x + 4
has a slope of -1/(1/3) = -3
and equation
y = -3x + b .................(1)
If the line has an x intercept of 2 at (0,2), then
0 = -3(2) + b
solving
b = 6
By substituting b=6 into (1), the line required
y = -3x + 6
Answer:
y = -3x + 2
Step-by-step explanation:
y= [tex]\frac{1}{3}x +4[/tex]
Slope [tex]m_{1}=\frac{1}{3}[/tex]
slope of the perpendicular line [tex]m_{2}[/tex] = [tex]\frac{-1}{m_{1}}[/tex] = [tex]\frac{-1}{\frac{1}{3}}=-1*\frac{3}{1}=-3\\[/tex]
b= 2
Slope intercept form of required line: y = mx + b
y = -3x + 2
which of the following is the Pythagorean theorem
Answer:
[tex]a^2+b^2=c^2[/tex]
Step-by-step explanation:
The Pythagorean Theorem is used to find a missing side length in a right triangle, and the formula [tex]a^2+b^2=c^2[/tex] is used to find the missing side, assuming a and b are legs, while c is the hypotenuse.
Answer:
in a right triangle, the sum of the squares of the leg lengths is equal to the square of the hypotenuse length
If f ( x) = 4x
2 and g( x) = 5x , what is
g( f (2x)) ?
Answer: 40x
First, let's find f(2x)
[tex]f(2x)=4(2x)=8x[/tex]
Using this, let's find g(f(2x)):
[tex]g(f(2x))=g(8x)=5(8x)=40x[/tex]
That's the answer. Let me know if you need any clarifications, thanks!
Answer:
80x²
Step-by-step explanation:
f(x) = 4x², g(x) = 5x
f(2x) = 4(2x)² = 16x²
g(f(2x)) = 5(16x²) = 80x²
32 is an example of A. an algebraic equation B. a numerical expression C. a numerical equation D. an algebraic expression Reset
ayuda plis nosé donde estoy q Brainli es este
ayuda
Answer:
hmm I'm not sure but i think it's B. a numerical expression
Sowwy if this didn't help :c
WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched. Graphon the coordinate plane.
Answer:
[tex]h=64t-4.9t^{2}[/tex]
Please refer to the attached graph.
Step-by-step explanation:
Given that
Initial velocity of rocket = 64 and is launched vertically.
To find:
Quadratic equation in time to represent the height of rocket in feet.
Solution:
Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.
Initial velocity, u = 64 feet/s
The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.
Formula for distance traveled is given as:
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here Let us represent s by 'h'
a = -g = 9.8 m/[tex]s^2[/tex]
Let us put the known values in the formula:
[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]
It is a quadratic equation, the equation represents the graph of a parabola.
Please refer to the attached graph.
Value of height is 0 at 0 second and ~13 seconds
Which choice shows the coordinates of B' if the trapezoid is reflected across the x-axis? On a coordinate plane, trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1). (–7, 2) (2, –7) (7, –2) (–2, 7)
Answer:
(7, -2)
Step-by-step explanation:
The trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1).
Transformation of a point is the change in location from an original position to a new position. If a shape is transformed, all its points are also transformed. A transformation can either be a rotation, translation, reflection or dilation.
If a point O(x,y) is reflected across the y axis, the new coordinate of the point is at O'(x, -y), i.e. the x coordinate does not change, but the y coordinate is negated.
Since in trapezoid ABCD, the coordinate of point B is (7, 2). The trapezoid is reflected across the x-axis, therefore the new coordinate of B' is at (7, -2)
Answer:c
Step-by-step explanation:
I took the test
need help adding and subtracting functions
Answer:
Step-by-step explanation:
[x/2-2/1] × [2x^2 + x -3]
we can solve this very simply by multiplication
(05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2). What is the length of Side RT of the polygon? 4 unit 6 units 7 units 11 units
Answer: 11 units
Step-by-step explanation:
Given: On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2).
To find : length of Side RT of the polygon.
Using distance formula to find distance between (a,b) and (c,d):
[tex]d=\sqrt{(d-b)^2+(c-a)^2}[/tex]
Length of RT = [tex]\sqrt{(2-2)^2+(5-(-6))^2}[/tex]
[tex]\\\\=\sqrt{0+(5+6)^2}\\\\= \sqrt{11^2}\\\\=11[/tex]
hence, the length of RT = 11 units.
Answer:
the answer is 11 units
Step-by-step explanation:
solve for x, if a solution is extraneous identify in the final answer. thx :)
Answer:
x = 6 and x = 11.
Step-by-step explanation:
sqrt(x - 2) + 8 = x
sqrt(x - 2) = x - 8
(sqrt(x - 2))^2 = (x - 8)^2
x - 2 = x^2 - 16x + 64
x^2 - 16x + 64 = x - 2
x^2 - 17x + 66 = 0
We can use the discriminant to find whether there are solutions to the equation.
b^2 - 4ac; where a = 1, b = -17, and c = 66.
(-17)^2 - 4 * 1 * 66
= 289 - 264
= 25
Since the discriminant is positive, we know there are two valid solutions to the equation.
x^2 - 17x + 66 = 0
(x - 6)(x - 11) = 0
The solutions are when x - 6 = 0 and x - 11 = 0.
x - 6 = 0
x = 6
x - 11 = 0
x = 11
Hope this helps!
Answer:
x=11 solution
x=6 extraneous
Step-by-step explanation:
sqrt( x-2) + 8 = x
Subtract x from each side
sqrt(x-2) = x-8
Square each side
(sqrt(x-2))^2 = (x-8) ^2
x-2 = x^2 -8x-8x+64
x-2 = x^2 -16x+64
Subtract ( x-2) from each side
0 = x^2 -17x +66
Factor
0 = (x-6) ( x-11)
Using the zero product property
x=6 x=11
Checking the solutions
x=6
sqrt( 6-2) + 8 = 6
sqrt(4) +8 = 6
2 +8 = 6
False not a solution
x=11
sqrt( 11-2) + 8 = 11
sqrt(9) +8 =11
3 +8 = 11
solution
Solve.
y=x - 7
5+2y=7
Answer:
[tex]\huge\boxed{x=8;\ y=1\to(8;\ 1)}[/tex]
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}y=x-7&(1)\\5+2y=7&(2)\end{array}\right\\\\\text{Substitute (1) to (2) and solve for x:}\\\\5+2(x-7)=7\qquad\text{use the distributive property}\\\\5+(2)(x)+(2)(-7)=7\\\\5+2x-14=7\\\\2x+(5-14)=7\\\\2x-9=7\qquad\text{add 9 to both sides}\\\\2x-9+9=7+9\\\\2x=16\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{16}{2}\\\\\boxed{x=8}[/tex]
[tex]\text{Substitute it to (1):}\\\\y=8-7\\\\\boxed{y=1}[/tex]
Answer:
(8, 1).
Step-by-step explanation:
y = x - 7
5 + 2y = 7
5 + 2(y) = 7
5 + 2(x - 7) = 7
5 + 2x - 14 = 7
Subtract 5 from both sides
2x - 14 = 2
Add 14 to both sides
2x = 16
Divide both sides by 2
x = 8
Since x = 8...
y = x - 7
y = 8 - 7
y = 1.
To check our work...
5 + 2y = 7
5 + 2 * 1 = 7
5 + 2 = 7
7 = 7
Since it works out, your answer is (8, 1).
Hope this helps!
What the correct answer now fast
Answer:
y = 12.9
Step-by-step explanation:
To find the value of the side y, simply apply the law of cosines.
y^2 = (14)^2 + (9)^2 - 2(14)(9)cos(64)
y^2 = 196 + 81 - 110.47
y^2 = 166.53
y = 12.9
Therefore, your solution should be y = 12.9
Cheers.
A candle burns at a constant rate of 2.5cm/h. The candle is 15cm tall when it is first lit. Let "t" represent the time is it burning in hours and let "h" represent the height of the candle in centimetres.
Answer:
The initial height of the candle is H = 15cm
The rate at which the candle burns is 2.5 cm per hour
Then after one hour, the height of the candle is:
h = 15cm - 2.5cm = 12.5cm
after two hours is:
h = 15cm - 2*2.5cm = 10cm
then, after t hours, the height of the candle is:
h = 15cm - (2.5cm/h)*t
now, the domain of h (or the range of the function) is:
h ∈ [0cm, 15cm]
when t = 0, h(0h) = 15cm
and the maximum value of t will be such that the candle is totally consumed:
h(t) = 0 = 15 - 2.5*t
t = 15/2.5 = 6
Then the domain of the function is:
t ∈ [0h, 6h]
how do i find x?
is the formula
"the sum of exterior angles=360°" false for concaved polygons?
Answer:
To find x you need to divide polygon into trianglesThe formula : "the sum of exterior angles=360°" is false for concaved polygonsStep-by-step explanation:
α = 180° - 135° = 45°
β = 180° - 120° = 60°
γ = 180° - 60° = 120°
δ = 180° - x
ε = 180° - 80° = 100°
If we divide the pentagon into five triangles then:
5•180° = α + β + γ + δ + ε + 4x
900° = 45° + 60° + 120° + x + 100° + 4x
900° = 325° + 5x
5x = 575°
x = 115°
60° + 120° + 135° + 80° + 115° = 510° ≠ 360°
Paul has four paper strips of the same length. He glues two of them together with a 4 cm overlap, and the new strip is 36 cm long. He wants to make a 30 cm long strip with the other two strips. How long should the overlap be?
Answer:
10 cm overlap required to make a 30 cm long strip.
Step-by-step explanation:
Given:
Four paper strips of the same length.
Two of them glued together with a 4 cm overlap to make a new strip which is 36 cm long.
To find:
Overlap required to make a strip which is 30 cm long = ?
Solution:
First of all, let us understand the concept of overlap.
Please refer to the attached image.
Let length of each strip be [tex]x[/tex] cm.
Given that there is 4 cm overlap resulting in new strip of length 36 cm.
The overlapping length is counted only once as clear from the figure attached.
So, Let us try to find the equation:
[tex]x +(x-4) = 36\\\Rightarrow 2x=40\\\Rightarrow x = 20\ cm[/tex]
i.e. each strip length is 20 cm.
Now, let us assume, an overlap of 'y' cm is to be made to make a new strip of 30 cm.
The equation will be:
[tex](20-y)+20 =30\\\Rightarrow y = 40-30\\\Rightarrow y = 10\ cm[/tex]
Answer the problem below
Answer:
D. 4z^3
Step-by-step explanation:
First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3
Hope this helps, if you want me to explain more, feel free to ask questions.
Have a good day! :)
Answer:
4 z^3
Step-by-step explanation:
( 64 z^9) ^ 1/3
Rewriting 64 as 4^3
( 4^3 z^9) ^ 1/3
We know that ( ab) ^c = a^c * b^c
4^3 ^ 1/3 z^9 ^ 1/3
We know that a^ b^c = a^ ( b*c)
4^(3 * 1/3) z^ (9 * 1/3)
4 ^ ( 1) z^ ( 3)
4 z^3
In Central City, Elm Street and Maple Street are parallel to one another. Oak Street crosses both Elm Street and Maple Street as shown.
Answer:
a. (True) Since ∠6 and ∠8 are vertical angles, they are congruent.
b. (False) ∠1 and ∠2 are supplementary but 65 + 125 ≠ 190.
c. True
d. True
e. True
Answer:
The answer is Freddy Kruger
Step-by-step explanation:
Elm Street, duh
can someone help....
Answer:
-7 is no, -2 is no, 7 is no, and 10 is yes
Step-by-step explanation:
-5+9*(-7)>58
-5+-63>58
-68>58
-5+9*(-2)>58
-5+-18>58
-23>58
-5+9*(7)>58
-5+63>58
58>58
-5+9*(10)>58
-5+90>58
85>58
so the only one that is a solution is v=10, hope this helps
Answer: No, No, No, Yes
Step-by-step explanation:
Solve the equation for "v":
-5 + 9v > 58
9v > 63
v > 7
Check the options to see if they make a true statement:
-7 > 7 False
-2 > 7 False
7 > 7 False
10 > 7 TRUE!
Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem?
Answer:
The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR
Step-by-step explanation:
Given DF/PR = FE/RQ = 3/2
The Side Side Side, SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar
Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.
If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.
Answer:
D: DE/PQ = 3/2
Step-by-step explanation:
Did it on edge 2020
vertical stretch of the graph f(x)= x² by a factor of 5
PLEASE HELP!!
Answer:
f(x) = 5x^2
Step-by-step explanation:
A vertical stretch is in the y direction
y = Cf(x) C > 1 stretches it in the y-direction
f(x) = 5x^2
An item is selling for $7,000. This item gets a discount and it is now $4,900. What percentage was the discount?
Answer:
30%Step-by-step explanation:
Discount =$7000-$4900
Discount% =
[tex] \frac{2100}{7000} \times 100 \\ = \frac{210000}{7000 } \\ = \frac{210}{7} = 30[/tex]
In one U.S. city, the taxi cost is $3 plus $0.60 per mile. If you are traveling from the airport, there is an additional charge of $5.50 for tolls. How far can you travel from the airport by taxi for $26.50?
the airport by taxi for $26.50?
Answer:
30 milesStep-by-step explanation:
How far can you travel from the airport by taxi for $26.50 ?($26.5 - $3 - $5.50) : $0.6/m =
= $18 : 0.6$/m
= 30 miles
The sales tax on clothing in Nebraska is 5.5%. Calculate how much tax you need to pay on a shirt if it costs $18.20 before tax. Round your answer to the nearest cent. ( pls answer asap and thanks ) will give BRANLIEST
Answer:
$1.00
Step-by-step explanation:
The tax rate in Nebraska = 5.5%
Cost of the shirt before tax = $18.20
Therefore:
Tax to be paid = 5.5% of $18.20
[tex]=0.055 \times \$18.20\\=\$1.00 $(correct to the nearest cent)[/tex]
The amount you need to pay as tax is $1.00.
plzzz hellpppppp...........
Answer:
Bearing of R from S = S 45° E or 135°
The bearing of R from Q
= S 66.42° w or 246.42°
Step-by-step explanation:
Distance between R and S
RS²= RP²+PS²
RS²= 15²+15²
RS²=225+225
RS= √450
RS= 21.21
Angle at S
21.21= 15/sins
Sin s= 15/21.21
S= sin^-1 15/21.21.
S= 45°
90+45= 135°
Bearing of R from S = S 45° E or 135°
Distance between R and Q
RQ²= PQ²+PR²
RQ²= 35²+15²
RQ²=1225+225
RQ= √1450
RQ= 38.08
RQ= 15/sinQ
SinQ= 15/38.08
SinQ= 0.40
Q=23.58°
90-23.58 = 66.42°
66.42+180= 246.42°
The bearing of R from Q
= S 66.42° w or 246.42°
area perimeter for grade 4
Answer:
what is the questions.
Find side AC and round your answer to the nearest hundredth, help please.
Answer:
Step-by-step explanation:
Side AC is the side opposite the reference angle of 70 degrees while side BC is the side adjacent to the reference angle. AB is the hypotenuse since it is across from (or opposite) the right angle. The trig ratio that uses the sides opposite from and adjacent to the reference angle is the tangent. Setting up to solve for AC:
[tex]tan(70)=\frac{?}{3}[/tex] and
3tan(70) = ? so
? = 8.24