What is the solution to the inequality 7<=-3x-4

Answer:

8.033

Step-by-step explanation:

Answer:

hio

Step-by-step explanation:

hi

As early as 4,000 years ago, but the first recorded use of a zero-like symbol dates to sometime around the third century B.C. in ancient Babylon.

Given that, the ancient Babylonians were writing fractions in 1800 BCE.

In Mathematics, fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

In fact, at first, fractions weren't even thought of as numbers in their own right at all, just a way of comparing whole numbers with each other.

The word fraction actually comes from the Latin "fractio" which means to break. To understand how fractions have developed into the form we recognize, we'll have to step back even further in time to discover what the first number systems were like.

From as early as 1800 BC, the Egyptians were writing fractions. Their number system was a base 10 idea (a little bit like ours now) so they had separate symbols for 1, 10, 100, 1000, 10000, 100000 and 1000000.

Hence, as early as 4,000 years ago, but the first recorded use of a zero-like symbol dates to sometime around the third century B.C. in ancient Babylon.

To learn more about the fraction visit:

brainly.com/question/1301963.

#SPJ2

Answer:

Exact form: 157/20

Decimal Form: 7.85

Mixed Number Form: 7/17/20

Step-by-step explanation:

Answer:

A) None of the above

Step-by-step explanation

it's distributive property

Answer:

a) 2260 cm³

b) 3390 grams

Step-by-step explanation:

3.

a)The radius of the solid cylinder = 6cm

The height of the cylinder is =20 cm

The volume = π*r²*h

The volume = 3.14 * 6²*20 =2260 cm³

b) Density of the material = 1.5 g/cm³

  Volume of the cylinder = 2261 cm³

  Mass of the cylinder = Density * Volume

  Mass of the cylinder = 1.5 * 2261 = 3390 grams

Answer:

so what is the question?

Answer:

x=5

Both are vertical lines and parallel to each other.

Answer:

the answer is there should be another digit in the quotient

Answer:

No, because there should be another digit in the quotient

Answer:

66 2/3

Step-by-step explanation:

(2/3)(100) = 66 2/3

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Question reads....}[/tex]

[tex]\large\textbf{What percent is equivalent to }\rm{\bf \dfrac{2}{3}}\large\textbf{ ?}[/tex]

[tex]\huge\textbf{Let's simplify the current fraction}\\\huge\textbf{to find the overall result to this question.}[/tex]

[tex]\mathbf{\dfrac{2}{3}}[/tex]

[tex]\mathbf{= 2\div3}[/tex]

[tex]\mathbf{= 0.66666667}[/tex]

[tex]\mathbf{= 0.66666667 \times 100}[/tex]

[tex]\mathbf{= 66.6666667\%}[/tex]

[tex]\mathbf{\approx 66.67\%}[/tex]

[tex]\huge\textbf{Let's do process of elimination to find}\\\huge\textbf{the fraction that is equivalent to yours.}[/tex]

[tex]\huge\textsf{Option A.}[/tex]

[tex]\mathbf{66 \dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+1}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 +1}{3}}[/tex]

[tex]\mathbf{= \dfrac{199}{3}}[/tex]

[tex]\mathbf{= 199\div3}[/tex]

[tex]\mathbf{= 66.3333333}[/tex]

[tex]\mathbf{= 66.3333333 \times100}[/tex]

[tex]\mathbf{= 6,633.33333\%}[/tex]

[tex]\mathbf{\approx 6,633.33\%}[/tex]

[tex]\huge\textsf{This eliminates Option A. as your result.}[/tex]

[tex]\huge\textsf{Option B.}[/tex]

[tex]\mathbf{66 \dfrac{3}{5}}[/tex]

[tex]\mathbf{= \dfrac{66\times5 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{330 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{333}{5}}[/tex]

[tex]\mathbf{= 333\div5}[/tex]

[tex]\mathbf{= 66.6}[/tex]

[tex]\mathbf{= 66.6 \times 100}[/tex]

[tex]\mathbf{= 6,660}[/tex]

[tex]\mathbf{\approx 6,660\%}[/tex]

[tex]\huge\textsf{This eliminates Option B. as your result.}[/tex]

[tex]\huge\textsf{Option C.}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+2}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 + 2}{3}}[/tex]

[tex]\mathbf{= \dfrac{200}{3}}[/tex]

[tex]\mathbf{= 200\div3}[/tex]

[tex]\mathbf{= 66.6666667}[/tex]

[tex]\mathbf{= 66.6666667\times100}[/tex]

[tex]\mathbf{= 6,666.66667}[/tex]

[tex]\mathbf{\approx 6,666.67\%}[/tex]

[tex]\huge\textsf{This eliminates Option C. as your result.}[/tex]

[tex]\huge\textsf{Option D.}[/tex]

[tex]\mathbf{66\dfrac{7}{10}}[/tex]

[tex]\mathbf{= \dfrac{66\times10 +7}{10}}[/tex]

[tex]\mathbf{= \dfrac{660 + 7}{10}}[/tex]

[tex]\mathbf{= \dfrac{667}{10}}[/tex]

[tex]\mathbf{= 667\div10}[/tex]

[tex]\mathbf{= 6.67}[/tex]

[tex]\mathbf{= 6.67\times100}[/tex]

[tex]\mathbf{= 6,670}[/tex]

[tex]\mathbf{\approx 6,670\%}[/tex]

[tex]\huge\textsf{This eliminates Option D. as your result.}[/tex]

[tex]\huge\textbf{It seems like none of the above matches }\\\huge\textbf{the original fraction, so we will use the}\\\huge\textbf{that is close to the original answer.}[/tex]

[tex]\huge\textbf{The closest answer was:}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\huge\textbf{Therefore the answer MIGHT be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ C. \ 66 \dfrac{2}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

 [tex]y= -\frac{1}{3}x -6[/tex]

Step-by-step explanation:

Using the slope formula, you can form this equation! The slope of any equation would replace the m, and the y intercept would replace b!

I added in the slope formula at the bottom, just in case, so you'll see what I mean!

I hope this helps, and I explained enough! Have a great day c:

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A right turn represents a clockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by -i.

A left turn represents a counterclockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by i.

The attached table shows the desired values and expressions.

Step-by-step explanation:

[tex]\boxed{\begin{array}{c|c|c} \underline{Intial -d} & \underline {Left-turn} & \underline{Right-turn} \\ -1 & -i & i \\ 1 & i & -i \\ i & -1 & 1\\ -i & 1 & -1 \\ d & di & -di \end{array}}[/tex]

Answer:

5

Step-by-step explanation:

Answer:

Less Than :)

Step-by-step explanation:

Answer:

2a^2 b^3(3a^2 b^3 - 4ab^2 + 6)

Answer:

x>-17.2

Step-by-step explanation:

Simplify both sides of the inequality

-0.5x-3.1< 5.5

Add 3.1 to both sides

-0.5x< 8.6

Divided both sides by -0.5

x>-17.2

Hope this helped! :)

Answer:

Step-by-step explanation:

4x^3 + 7x^3 - 5x + 9x + 3 + 11 = 11x^3 + 4x + 14

Answer:

The dimensions that will maximize the enclosed area of the pen is 250 ft by 250 ft

Step-by-step explanation:

we have the perimeter as 1000

So the sum of the lengths will be

1000/2 = 500

The dimensions that will maximize these pens will be such that they will have equal values

Mathematically, that will be 500/2 = 250 by 250

Answer:

280

Step-by-step explanation:

Month 1: 100 + 30 = 150

Month 2: +30

Month 3: +30

Month 4: +30

Month 5: +30

Month 6: +30

Total: 280

Hope this helps!

Answer:

$280

Step-by-step explanation:

For this problem, we simply need to take the initial cost of membership and add that to the reoccurring cost from a time period, in this case, 6 months.  So let's make an equation to represent this.

The initial cost is $100

The per month cost is $30

Total cost after 6 months = Inital cost + Per Month Cost * 6 months

Total cost = $100 + $30 * 6

Total cost = $100 + $180

Total cost = $280

Thus, a member will spend $280 after 6 months on the membership.

Cheers.

Answer:

y = 4/5x

Step-by-step explanation:

Her ya go!

Answer:

Two complex (imaginary) solutions.

Step-by-step explanation:

To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.

The discriminant formula for a quadratic in standard form is:

[tex]\Delta=b^2-4ac[/tex]

We have:

[tex]3x^2+7x+5[/tex]

Hence, a=3; b=7; and c=5.

Substitute the values into our formula and evaluate. Therefore:

[tex]\Delta=(7)^2-4(3)(5) \\ =49-60\\=-11[/tex]

Hence, the result is a negative value.

If:

Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

Answer:

See steps below

Step-by-step explanation:

WS ⊥ MH , HS = SM ......... Given

<HSW = <MSW = 90  .....  From WS ⊥ MH

Triangle HWS = Triangle WMS .... SAS  theorem

<M = <H  .... based on triangle congruency, and angle opposed to equal side WS

Answer:

The instantaneous rate of change as x approaches 3 is 18.

Step-by-step explanation:

From Differential Calculus and Geometry we remember that instantaneous rate of change of the function is represented by a tangent line, whose slope is determined by the first derivative of the curve. Let [tex]f(x) = 3\cdot x^{2}[/tex], the instantaneous rate of change of the function when x approaches 3 is deducted from the definition of derivative:

[tex]f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex] (1)

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x^{2}+2\cdot x\cdot h +h^{2})-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot x^{2}+6\cdot x\cdot h+3\cdot h^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{6\cdot x\cdot h +3\cdot h^{2}}{h}[/tex]

[tex]f'(x) = \lim _{h\to 0} (6\cdot x+3\cdot h)[/tex]

[tex]f'(x) = 6\cdot x \cdot \lim_{h\to 0} 1 + 3\cdot \lim_{h\to 0} h[/tex]

[tex]f'(x) = 6\cdot x[/tex] (2)

If we know that [tex]x = 3[/tex], then the instantaneous rate of change as x approaches 3 is:

[tex]f'(3) = 6\cdot (3)[/tex]

[tex]f'(3) = 18[/tex]

The instantaneous rate of change as x approaches 3 is 18.

Answer:

a. 50 - 4h < 32

Step-by-step explanation:

The question is "When will the temperature be below 32F?" so it can't be less than or equal to (≤), it has to be less than (<).

If the temperature is decreasing every hour you have to decrease 4 for each hour.

hope that helps!

Answer:

[tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 52[/tex]

Step-by-step explanation:

Given

[tex]Sequence: 12, 16, 20, 24[/tex]

Solving (a): Write a formula

The above sequence shows an arithmetic progression

Hence:

The formula can be calculated using:

[tex]T_n = a + (n - 1) d[/tex]

In this case:

[tex]a = First\ Term = 12[/tex]

Difference (d) is difference of 2 successive terms

So:

[tex]d = 16 - 12 = 20 - 16 = 24 - 20[/tex]

[tex]d = 4[/tex]

Substitute 4 for d and 12 for a in [tex]T_n = a + (n - 1) d[/tex]

[tex]T_n = 12 + (n - 1) * 4[/tex]

Open Bracket

[tex]T_n = 12 + 4n - 4[/tex]

Collect Like Terms

[tex]T_n = 12 - 4+ 4n[/tex]

[tex]T_n = 8+ 4n[/tex]

Hence, the explicit formula is: [tex]T_n = 8+ 4n[/tex]

Solving (b): 11th term

This implies that n = 11

Substitute 11 for n in: [tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 8+ 4 * 11[/tex]

[tex]T_{11} = 8+ 44[/tex]

[tex]T_{11} = 52[/tex]

Answer:

A) The explicit formula for the sequence is [tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex].

B) The 11th term of the sequence is 62.

Step-by-step explanation:

A) Let [tex]f(0) = 12[/tex], we notice that sequence observes an arithmetic progression, in which there is a difference of 4 between two consecutive elements. The formula for arithmetic progression is:

[tex]f(n) = f(0) +r\cdot n[/tex] (1)

Where:

[tex]f(0)[/tex] - First value of the sequence, dimensionless.

[tex]r[/tex] - Arithmetic increase rate, dimensionless.

[tex]n[/tex] - Term of the value in the sequence, dimensionless.

If we know that [tex]f(0) = 12[/tex] and [tex]r = 4[/tex], then the explicit formula for the sequence is:

[tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex]

B) If we know that [tex]f(n) = 12+4\cdot n[/tex] and [tex]n = 10[/tex], the 11th term of the sequence is:

[tex]f(10) = 12+4\cdot (10)[/tex]

[tex]f(10) = 62[/tex]

The 11th term of the sequence is 62.

Answer:

he will fill 6 pitchers

Step-by-step explanation:

4.8÷0.8=6

Answer:

The anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Step-by-step explanation:

Given the function

[tex]\:f\left(x\right)=10x^4\:+\:12.5[/tex]

Taking the anti-derivative of f(x)

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:[/tex]

[tex]\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx[/tex]

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

Solving

[tex]\int 10x^4dx[/tex]

[tex]\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx[/tex]

[tex]=10\cdot \int \:x^4dx[/tex]

[tex]\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]

[tex]=2x^5[/tex]

similarly,

[tex]\int 12.5dx[/tex]

[tex]\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax[/tex]

[tex]=12.5x[/tex]

so substituting these values

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

                                [tex]=2x^5+12.5x[/tex]

                               [tex]=2x^5+12.5x+C[/tex]   ∵ Add constant to the solution

Therefore, the anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Answer:

1.2

Step-by-step explanation:

0.3 * 4

= 3 * 0.1  * 4

= 3 * 4 * 0.1

= 12 * 0.1

= 1.2

Answer:

Is this in a different language?

Step-by-step explanation:ok:)