What is the strength of Ammonium lauryl sulfate?

Answer:

hydrogen ions which is H+

Answer: An acid is a solution with more H+ ions than OH- ions. An acid is any compound that yields hydrogen ions (H+) or hydronium ions (H3O+) when dissolved in water.

Explanation:

Answer:

Decantation

Explanation:

Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.

Moles of Oxygen produced : 4.5 moles

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

The reaction coefficient shows the mole ratio of the reactants and products

Reaction

2KCIO₃ → 2KCl + 30₂

moles of KCIO₃ = 3

From equation, mol ratio of KCIO₃ : O₂ = 2 : 3, so mol O₂ :

[tex]\tt mol~O_2=\dfrac{3}{2}\times 3=4.5[/tex]

Answer: 1.414 mol Cl-  

Explanation:

First, let's find the moles of BeCl2.

1.79 M = 1.79 mol/L

395 mL = 0.395 L , since 1L = 1000 mL

Using stoichiometry,

1.79 mol/L *0.395 L = about 0.707 mol BeCl2

Now, we have 0.707 mol of BeCl2, but we are trying to find moles of Cl-

There are two chloride ions in each molecule of BeCl2, so there will be twice as many moles as well.

0.707 mol BeCl * (2 mol Cl- / 1 mol BeCl) = 1.414 mol Cl-  

Hope this helps!

Answer:

No

Explanation:

There are vaccines, to prevent it, made by Dr. Fauci, but no cure

Answer:?

?Explanation:

Answer:

The correct answer is B

Explanation:

Educere

aluminium + copper oxide → aluminium oxide + copper. Hence, option B is correct.

A word equation represents a chemical reaction using the names of the substances involved.

aluminium + copper oxide → aluminium oxide + copper correctly shows the word equation for the reaction of aluminium and copper oxide yielding aluminum oxide and copper.

Hence, option B is correct.

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Answer:

a

Explanation:

The number of grains of rice in the 40 mL sample : 880 grains

Given

from recorded data:

mass of 20 grains rice = 0.4 g

mass beaker = 29.5 g

mass beaker+rice=47.1 g

mass only rice = 17.5 g

Required

the number of grains of rice

Solution

Maybe if we use a digital scale with high resolution accuracy we can get the mass of 1 grain of rice

But we still use existing data

To determine the mass of rice in the beaker, we just need to find the difference between the mass of the beaker + rice - beaker, or we can set the scale to zero before we add rice to the beaker.

If we look at this difference, the mass of the rice in the beaker should be :

47.1-29.5 = 17.6 g

Since the data shows that 20 grains of rice mass 0.4 g, so 17.6 g of rice contains:

[tex]\tt 17.6~g\times \dfrac{20~grains}{0.4~g}=880~grains[/tex]

Answer:Yes I am very good at acid

Explanation:

Answer: I say  B

Explanation:

Answer:

0.45881381335

Explanation:

divide 45 by the molar mass of H2SO4

45/98.079

Answer:

0.45

Explanation:

divise

Answer:Beta

Explanation:

I watched the video and I got it wrong, the right answer was beta. I can’t explain why because I’ve already forgotten lol

Digestive tract have digestive enzymes which are not able to break beta linkages as  humans do not have enzymes which breakdown beta linkages.

It consists of the gastrointestinal tract along with the accessory organs which are present in digestion process . It involves the breakdown of complex food into smaller components which can be easily assimilated and absorbed by the body.

The digestion process has 3 phases: cephalic phase , gastric phase and intestinal phase.Cephalic phase begins with secretion of gastric juices from gastric glands in response to sight and smell of food.It involves chewing and chemical breakdown of food by the action of digestive enzymes ,saliva in the mouth contain enzymes like lipase and amylase which are secreted by the salivary and serous glands present on the tongue.

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Answer:

Mass = 135.66 ×10⁻²¹ g

Explanation:

Given data:

Number of molecules of CuSO₄= 5.119×10²

Mass of CuSO₄= ?

Solution:

The given problem will solve by using Avogadro number.

1 mole contain 6.022×10²³ molecules

5.119×10² molecules ×1 mol / 6.022×10²³ molecules

0.85×10⁻²¹ mol

Mass in grams:

Mass = number of moles × molar mass

Mass = 0.85×10⁻²¹ mol × 159.6 g/mol

Mass = 135.66 ×10⁻²¹ g

Answer:

false

Explanation:

because elements never exist in nature as single isotopes they are always combined

Answer:

FALSE

Explanation:

in the cases of three elements (tellurium, indium, and rhenium) the most abundant isotope found in nature is actually one (or two) extremely long-lived radioisotope(s) of the element, despite these elements having one or more stable isotopes.

its me again this is how you find the answer. note: i dont have the periodic table to see the exact atomic mass to find the molar mass however this is the answer:

so the actual formula is Mg(OH) with a 2 as a subscript because there are 2 Mg. so with Mg(OH)2 the Molar mass is 58.32g/mol. 58.32 g/mol x 7.1x1024 = 4.1x1026g

Answer:

292.1 kg = 292 100 g

Explanation:

n = m/Mm

Mm(Cu) = 63.5

m = n * Mm

m = 4.6 * 63.5

m = 292.1 kg

Answer:

2B, 1A, 3D, 4C, because of the definitions, they match.

Answer:

1.4 mol

Explanation:

that my i got i was doing for it

Explanation:

34.31+35.45(2)=

27.31+70.90=

95.21g/mol

Answer:

Ovary

Explanation:

The ovaries are organs that lie to the upper right and left of the uterus. They produce, store, and release eggs into the fallopian tubes in the process called ovulation

Answer:

Pure solids or liquids are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction. The concentration of a pure liquid or solid equals its density divided by its molar mass.

Explanation:

Hope this helps!!!

Answer:

Top left: RR Top right: Rr Bottom left: Rr Bottom right: rr

Explanation:

if both parents are heterozygous then the table will always look like this. the chances of the offspring being heterozygous are 50%. the offspring has a 25% chance of having two recessive traits and a 25% chance of having two dominant traits.