Write 753 in scientific notation ?
The given number is
[tex]753[/tex]We want to write this number in scientific notation.
To convert the number into the scientific notation we shift the decimal point towards left until one decimal digit is left.
This could be best understood with the help of a few examples.
Example:
Let's say the number is 4000.
Now shift the decimal point to the left so that only the digit 4 is left.
[tex]4.0x10^3[/tex]Since we shifted the decimal point towards left by 3 points that's why we raised the power of 10 to 3 times.
Now let's come back to 753.
Now shift the decimal points towards left by 2 points so that only 7 digit is left
[tex]7.53x10^2[/tex]Since we shifted the decimal point towards left by 2 points that's why we raised the power of 10 to 2 times.
If you multiply 7.53 with 10² then you will get 753.
I need help with question 8 i just need the answer I just want to see if I’m right
Answer:
No
Explanation:
The function is one-to-one if when we draw a horizontal line in the graph, the line crosses the function once. In this case, we get:
Since the line crosses the graph twice, the given function is not one-to-one.
So, the answer is No.
Find the area of this circle. Use 3 for a.=A = ar2A = T?[?]= T16 inHint: First plug the value of theradius into the formula for r.Since the diameter is 16, theradius is 16 divided by 2.
Looking at the image, we can see that the diameter of the circle is 16 inches.
Since the radius measures half the diameter, so the radius of this circle is equal to 8 inches.
So the missing value in the area formula is 8.
Then, calculating the area, we have:
[tex]\begin{gathered} A=\pi\cdot8^2 \\ A=3\cdot64 \\ A=192\text{ in}^2 \end{gathered}[/tex]The circle area is equal to 192 in².
Since the question first asks only for the missing value in the formula, so the
The---------------- is the annual amount you pay just to own a credit card.
You need to pay a yearly fee to own a credit card.
Moreover, you need to pay interest on the amount you spend.
This is how credit card works.
Also, the bank checks your credit before issuing a credit card.
The yearly fee, the annual fee, is charged at the end of every fiscal year.
1. Find (x - 7) 58 degrees
x - 7 = 58 ( vertical angles are congruent)
add t to both-side of the equation
x = 58 + 7
x = 65°
Cole needs to include at least 11 mg and at most 22 mg of iron in his diet each day. Cole plans to eat multiple bananas daily, and each banana has 0.3 mg of iron. Cole will get the rest of his iron from vitamins. Each whole vitamin contains 1 mg of iron. Part A If Cole eats 3 bananas each day, what is the least number of whole vitamins he must take in order to stay within his daily iron requirement? What is the greatest number of whole vitamins he can take in order to stay within his daily iron requirement? Use inequalities to solve. Respond in the space provided.
Let x be the number of vitamins Cole takes in a day. Since he eats 3 bananas each day and they represent 0.3 mg of iron, the total ammount of iron the bananas represent is 0.9 mg.
This is going to be complemented by the vitamins he takes, since each vitamin has 1 mg of iron, the total ammount of iron he takes in a day is:
[tex]x+0.9[/tex]We know that he has to take at least 11 mg and at most 22 mg of iron each day, then, the total ammount of iron he takes and is permitted can be express as:
[tex]11\leq x+0.9\leq22[/tex]Solving for x, we have:
[tex]\begin{gathered} 11\leq x+0.9\leq22 \\ 11-0.9\leq x\leq22-0.9 \\ 10.1\leq x\leq21.91 \end{gathered}[/tex]Therefore, Cole has to take at least 11 vitamins and at most 21 vitamins per day.
O GRAPHS AND FUNCTIONSTransforming the graph of a function by shrinking or stretching
A.
The graph of y= f(0.5x) invoves shrinking the graph by a factor of 0.5
This is shown below
Please help me on number one It’s all one question
Given:
[tex]f(x)=2x^2+12x+10[/tex]a) Standard form of the function is,
[tex]\begin{gathered} f(x)=2x^2+12x+10 \\ f(x)=2(x^2+6x+5+9-9) \\ f(x)=2(x^2+6x+9-4) \\ f(x)=2(x+3)^2-8 \end{gathered}[/tex]Standard form is,
[tex]f(x)=2(x+3)^2-8[/tex]b) The vertex of the given function
The vertex of the parabola having form,
[tex]\begin{gathered} y=ax^2+bx+c \\ \text{Vertex}=\frac{-b}{2a} \\ f(x)=2x^2+12x+10 \\ \text{Vertex}=\frac{-b}{2a}=\frac{-12}{2(2)}=-\frac{12}{4}=-3 \\ \text{Put x=-3 in }f(x)=2x^2+12x+10 \\ f(x)=2(-3)^2+12(-3)+10=18-36+10=-8 \end{gathered}[/tex]Vertex is ( -3,-8)
c) x and y-intercept is,
[tex]\begin{gathered} Set\text{ y=0 that means f(x)=0} \\ f(x)=2x^2+12x+10 \\ 2x^2+12x+10=0 \\ 2(x^2+6x+5)=0 \\ x^2+6x+5=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a},a=1,b=6,c=5 \\ x=\frac{-12\pm\sqrt{12^2-4\cdot\:2\cdot\:10}}{2\cdot\:2} \\ x=\frac{-12\pm\: 8}{4} \\ x=-1,x=-5 \end{gathered}[/tex]x- intercepts are (-1,0) and (-5,0).
For y-intercept , set x=0
[tex]\begin{gathered} f(x)=2x^2+12x+10 \\ y=2x^2+12x+10 \\ y=2(0)+12(0)+10 \\ y=10 \end{gathered}[/tex]y-intercept is (0,10)
d) the graph of the function is,
e) The domain and range of the function is,
[tex]\begin{gathered} \text{For range of the function f(x)=ax}^2+bx+c\text{ with vertex (x,y)} \\ \text{If a}<0\text{ range is }f(x)\leq y \\ \text{If a>0, range is f(x)}\ge\text{y} \end{gathered}[/tex]For the given function,
[tex]\begin{gathered} f(x)=2x^2+12x+10\text{ with vertex (-3,-8)} \\ a=2>0,\text{ range is f(x)}\ge\text{-8} \\ \text{Domain is -}\inftyTherefore,[tex]\begin{gathered} \text{Domain of f is (-}\infty,\infty) \\ \text{Range of f is \lbrack-8,}\infty) \end{gathered}[/tex]Given ΔQRS≅ΔTUV, QS=3v+2andTV=7v−6, find the length of QS and TV.
Since the triangles ΔQRS and ΔTUV, their corresponding sides are also congruent, this means that
[tex]\begin{gathered} QR\cong TU \\ RS\cong UV \\ QS\cong TV \end{gathered}[/tex]Since QS and TV are congruent, this means that they have the same measures, therefore
[tex]\begin{gathered} QS=TV \\ 3v+2=7v-6 \end{gathered}[/tex]Solving this equation for v, we have
[tex]\begin{gathered} 3v+2=7v-6 \\ 3v-7v+2=-6 \\ -4v=-6-2 \\ 4v=8 \\ v=2 \end{gathered}[/tex]Using this value for v in our expression for the sides, we have
[tex]\begin{gathered} QS=3\cdot2+2=8 \\ TV=7\cdot2-6=8 \end{gathered}[/tex]Both sides are equal to 8.
Let f(x) = -3x3 + 4 and g(x) = -8x2 + 2x. What is f(x) · g(x)?
We are given the following functions
[tex]\begin{gathered} f(x)=-3x^3+4 \\ g(x)=-8x^2+2x \end{gathered}[/tex]Let us find the product of the two functions.
[tex]\begin{gathered} f(x)\cdot g(x)=(-3x^3+4)\cdot(-8x^2+2x) \\ f(x)\cdot g(x)=(-3x^3\cdot-8x^2)+(-3x^3\cdot2x)+(4\cdot-8x^2)+(4\cdot2x) \\ f(x)\cdot g(x)=(24x^{3+2})+(-6x^{3+1})+(-32x^2)+(8x) \\ f(x)\cdot g(x)=(24x^5)+(-6x^4)+(-32x^2)+(8x) \\ f(x)\cdot g(x)=24x^5-6x^4-32x^2+8x \end{gathered}[/tex]Therefore, the product of the functions f(x) and g(x) is
[tex]24x^5-6x^4-32x^2+8x[/tex]The 1st option is the correct answer.
What are the first 5 multiples of 5 what are the first 5multiples of 2 what is the least common multiple(LCM) of 5 and 2
The first 5 multiples of 5 is
Multiples of 5:
5, 10, 15, 20, 25
The first 5 multiples of 2 is
Multiples of 2:
2, 4, 6, 8, 10
Therefore, the LCM of 5 and 2 is 10.
Find the perimeter of the composite figureA) 18 ftB) 14 ftC) 16 ft D) 17 ft
The perimeter of a figure is the sum of all of its sides.
In the given figure we can observe two missing sides, so we need to find its lengths as follows:
So:
[tex]\begin{gathered} 3ft+y=4ft \\ y=4ft-3ft \\ y=1ft \\ And \\ x+2ft=5ft \\ x=5ft-2ft \\ x=3ft \end{gathered}[/tex]Thus, the perimeter is:
[tex]\begin{gathered} P=3ft+5ft+4ft+2ft+y+x \\ P=3ft+5ft+4ft+2ft+1ft+3ft \\ P=18ft \end{gathered}[/tex]The answer is A) 18 ft.
Solve for the indicated variable in the parenthesis.6 and 8
6) y = mx + b
We need to make b the subject of the formula:
subtract mx from bith sides:
y - mx = mx - mx + b
y - mx =0 + b
b = y - mx
8) A = 1/2 h(b + c)
We need to make b the subject of formula:
Expand the parenthesis with h:
[tex]\begin{gathered} A\text{ = }\frac{1}{2}(bh\text{ + hc)} \\ \text{Multiply through by 2 as this will cancel the half:} \\ 2A=2\times\frac{1}{2}(bh\text{ + hc)} \\ 2A\text{ = bh + hc} \end{gathered}[/tex][tex]\begin{gathered} \text{subtract hc from both sides:} \\ 2A-\text{ hc = bh + hc - hc} \\ 2A\text{ - hc = bh} \\ \text{divide both sides by h:} \\ \frac{2A\text{ - hc}}{h}\text{ = }\frac{\text{ bh}}{h} \\ b\text{ = }\frac{2A\text{ - hc}}{h}\text{ } \end{gathered}[/tex]In KLM, R is the centroid. If KR=14 find RP. I P N R M M K Q
As R is the centroid. The following property is true:
The distance between the centroid and its corresponding vertex is twice the distance between the centroid and the opposite side.
In the given triangle:
R is the centroid
KR is the distance from centroid to vertex
RP is the distance from centroid to opposite side.
KR is twice RP
RP is half of KR
[tex]\begin{gathered} RP=\frac{1}{2}KR \\ \\ RP=\frac{14}{2} \\ \\ RP=7 \end{gathered}[/tex]Then, RP is 7which value of x makes x - 3 / 4 + 2/3 equals 17/12 true
Find probability of getting a king and a spade in a deck with one drawnFind the probability of getting a king and a spade if one card is drawn from a deck
The only way to get a king and a spade if only one card is drawn is getting a king of spades. The probability of getting this is 1/52.
Information about an event is shown$265 worth of tickets were sold Adult tickets cost $6Child tickets cost $2.5057 tickets were sold
According to the given information, the equation that can be used to represent the escenario are:
[tex]\begin{gathered} x+y=57 \\ 6x+2.5y=265 \end{gathered}[/tex]This is because x and y represent the number of adults and child tickets respectively, since 57 tickets were sold, the sum of x and y is 57.
Also, the sum of the cost of each ticket times the number of tickets sold is 265.
To find how many tickets were sold, we have to solve the system of equations and find x. We can use equalization method to solve it:
[tex]\begin{gathered} y=57-x \\ y=\frac{265-6x}{2.5} \end{gathered}[/tex][tex]\begin{gathered} 57-x=\frac{265-6x}{2.5} \\ 2.5(57-x)=265-6x \\ 142.5-2.5x=265-6x \\ 6x-2.5x=265-142.5 \\ 3.5x=122.5 \\ x=\frac{122.5}{3.5} \\ x=35 \end{gathered}[/tex]35 adult tickets where sold.
simplify 3x squared minus 6x plus 12 minus 6x plus 10
Given:
[tex]3x^2-6x+12-6x+10[/tex]Let's simplify:
Collect like terms and evaluate
[tex]3x^2-6x-6x+12+10[/tex][tex]3x^2-12x+22[/tex]ANSWER:
[tex]3x^2-12x+22[/tex]The three lines represent the number of hot dogs eaten by three contestants at a hot dog eating competition. Which contestant was eating at the slowest rate?A. Contestant J B. Contestant KC. Contestant L
B. Contestant K.
By looking at the graph we can see that the line K has the lowest slope ( change on y/ change on x)
Module 1: Ratios and unit rates: Q... elect three ratios that are equivalent 16 : 12. hoose 3 answers: 8:6
16:12 is equivalent to 8:6 and is equivalent to 4:3
this is a multiple choice question no need for it to be long
In order to determine which from the given equation represents the given data, first consider that while x increases y decreases. It means that the slope of the line is positive.
Furthermore, calculate the slope by using the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where (x1,y1) and (x2,y2) are two points of the table. You can select any pair of points, for example:
(x1,y1) = (0,2)
(x2,y2) = (2,-4)
replace the previous values into the formula for m:
[tex]m=\frac{-4-2_{}}{2-0}=-\frac{6}{2}=-3[/tex]Hence, the slope of the line is -3.
Hence, you can conclude that the equation of the line that best respresents the given data is:
y = -3x + 2
How many solutions does this systems of equations have?y = 3x - 2-3x + y = 4 One TWONoneInfinite
-3x + y = 4
can be rewritten as follows:
3x -3x + y = 3x + 4
y = 3x + 4
this equation of a line and the equation y = 3x - 2, are parallel (they have the same slope but different y-intercept). Then there is no intersection between. In consequence, there is no solution for the system of equations.
In right triangle ABC, altitude CD withlength h is drawn to its hypotenuse. Wealso know AD 12 and DB = 3. What isthe value of h?
Hence, the value of height,h, is 6
find the area of the figure and write the mixed number in simplest form
Okay, here we have this:
Considering the provided figure, we are going to calculate the requested area of the figure, so we obtain the following:
So to calculate the area of the figure we will separate it into a rectangle and a trapezoid to calculate their areas separately and finally we will add their areas to find the total area, then we have
Area of the rectangle=5 in * 9 1/2 in
Area of the rectangle=5 in * 19/2 in
Area of the rectangle=95/2 in^2
Area of the rectangle=47 1/2 in^2
Area of the trapezoid=(b1+b2)h/2
Area of the trapezoid=(5 in+2 1/2in)1 in/2
Area of the trapezoid=(7 1/2in)1 in/2
Area of the trapezoid=(7 1/2in^2)/2
Area of the trapezoid=(15/2in^2)/2
Area of the trapezoid=15/4in^2
Area of the trapezoid=3 3/4in^2
Total area=Area of the rectangle+Area of the trapezoid
Total area=47 1/2 in^2+3 3/4in^2
Total area=190/4 in^2+ 15/4in^2
Total area=205/4in^2
Total area=51 1/4in^2
Finally we obtain that the total area of the figure is 51 1/4 in^2.
The total cost (c) in dollars of renting a car for d days is given by the equationc =50 + 10n. If the total cost was $130, for how many days was the car rented?A. 8B. 13C. 3D. 18
Given:
The equation of total cost is, c = 50+10n.
The total cost is, c = $130.
The objective is to find the number of days for renting the car.
Substitute the value of c in the given equation of total cost.
[tex]\begin{gathered} 130=50+10n \\ 130-50=10n \\ 80=10n \\ n=\frac{80}{10} \\ n=8 \end{gathered}[/tex]Thus, the number of days for renting the car is 8.
Hence, option (A) is the correct answer.
the point (4,-3) is a
Notice that of all the points that the parabolla has, the point (4,3) is its vertex, or in this case, its the minimum value if we take it as the graph of a function
can you please explain to me how to do this c:
From the given image, notice that 8 out of 9 rectangles are colored green. Four are colored with a dark green and the other four are colored with a light green.
Since those 8 rectangles are separated on two groups of 4 rectangles, then 4 is 1/2 of 8. Consequently, 4/9 is 1/2 of 8/9.
Therefore, 1/2 of 8/9 is:
[tex]\frac{4}{9}[/tex]At 8:00 A.M., Brittany started filling a 3,600-gallon pond. At 10:00 A.M., she had filled 1,800 gallons. At what time will the pond be full? The pond will be full at
The size of the gallon is 3600 gallon . From 8 am to 10 am she had filled 1800 gallons. This means she fill it at the rate of 1800/2 =900 gallons per hour .
Therefore,
[tex]\begin{gathered} 900\text{ gallons = 1 hour} \\ 3600\text{ gallons =}\frac{3600}{900}=\text{4 hours} \\ \text{The whole gallons will be filled in 4 hours .} \end{gathered}[/tex]The pond will be filled at 12 pm(8 + 4hours).
Factor each expression you can check your answer by Distributing 16u+6v+10
16u + 6v + 10
2(8u +3v + 5)
This is the best you can go as far as factorisation is concerned.
Can someone please help me with this question? ITS NOT A TEST, Appreciate it