What is the surface area of the cylinder in terms of pi? The diagram is not drawn to scale.A) 288B) 360C) 72D) 162thank you ! :)

What Is The Surface Area Of The Cylinder In Terms Of Pi? The Diagram Is Not Drawn To Scale.A) 288B) 360C)

Answers

Answer 1

ANSWER :

B. 360π in^2

EXPLANATION :

Recall the surface area of a cylinder :

[tex]SA=2\pi r^2+2\pi rh[/tex]

From the problem, the radius is 6 inches and the height is 24 inches.

Using the formula above :

[tex]\begin{gathered} SA=2\pi(6)^2+2\pi(6)(24) \\ =72\pi+288\pi \\ =360\pi\text{ }in^2 \end{gathered}[/tex]


Related Questions

Graph the piecewise function f(x) = 3/2x+1 , -4 <= x<= 0 x-5 , 1 <= x<= 3 The image is attached for reference.

Answers

The piecewise function f(x) is composed bt two lines: 3/2x + 1 and x - 5. To graph a line, we need to connect two points that lie on the line. In the case of the first line, we can use its endpoints x = -4 and x = 0.

Substituting x = -4 into the equation of the first line, we get:

[tex]\begin{gathered} y=\frac{3}{2}(-4)+1 \\ y=-6+1 \\ y=-5 \end{gathered}[/tex]

Then, the point (-4, -5) lies on the first line.

Substituting x = 0 into the equation of the first line, we get:

[tex]\begin{gathered} y=\frac{3}{2}(0)+1 \\ y=1 \end{gathered}[/tex]

Then, the point (0,1) lies on the first line.

In the case of the second line, the endpoints x = 1 and x = 3.

Substituting x = 1 into the equation of the second line, we get:

[tex]\begin{gathered} y=1-5 \\ y=-4 \end{gathered}[/tex]

Then, the point (1,-4) lies on the second line.

Substituting x = 3 into the equation of the second line, we get:

[tex]\begin{gathered} y=3-5 \\ y=-2 \end{gathered}[/tex]

Then, the point (3,-2) lies on the second line.

Connecting these points with two different lines as stated before, we get the graph of f(x) as follows:

Algebra:What is the value of this expression when t = -12?-3|t − 8| + 1.5A. 61.5B. 13.5C. -10.5D. -58. 5

Answers

1) Given that t =-12 let's plug into that expression the value for t

2) Now let's plug into that and solve it.

-3|t-8| +1.5 Applying the absolute value property

-3|t -8| +1.5 Plug into that t=-12

-3|-12 -8| +1.5

-3|-20| +1.5

-3*20 +1.5

-60 +1.5

-58.5

which of the following functions has a graph in which the vertex and axis of symmetry are to the left of the vertex and axis of symmetry of the graph of f (x) =(x - 1)^2+ 1 select all that apply

Answers

Input data

The vertex and axis of symmetry are to the left of the vertex

What is the volume of a marble sphere is about 7,238.23 cubic millimeters. What is the radius? (Round your answer to the nearest millimeter.)

Answers

The volume of a sphere can be calculated using this formula:

[tex]V=\frac{4}{3}\pi r^3[/tex]

Where "r" is the radius of the sphere and "V" is the volume of the sphere.

If you solve for "r", you get this new formula:

[tex]r=\sqrt[3]{\frac{3V}{4\pi}}[/tex]

In this case you know that:

[tex]V\approx7,238.23\operatorname{mm}^3[/tex]

Therefore, you can substitute this value into the second formula and then evaluate, in order to find the radius of this sphere:

[tex]\begin{gathered} r=\sqrt[3]{\frac{(3)(7,238.23\operatorname{mm}^3)}{4\pi}} \\ \\ r\approx12\operatorname{mm} \\ \end{gathered}[/tex]

The answer is:

[tex]r\approx12\operatorname{mm}[/tex]

Mr. Morales drove 360 to a conference. He had transmission problems on the return trip and it took him 3 hours longer at an average speed of 30 mph less than the trip going. What was his average speed on the return trip?

Answers

Remember that

The speed is equal to divide the distance by the time

speed=d/t

Let

t ----> time spend to go to the conference in hours

s ----> speed trip going

Conference trip

s=360/t ------> equation 1

Return trip

speed=360/(t+3)

speed=s-30

s-30=360/(t+3) ------> equation 2

substitute equation 1 in equation 2

(360/t)-30=360/(t+3)

Multiply both sides by t(t+3) to remove fractions

360(t+3)-30t(t+3)=360t

360t+1,080-30t^2-90t=360t

simplify

30t^2+90t-1,080=0

Solve the quadratic equation

The solutions for t are

t=-7.7 h -----> is not a solution, because is a negative number

t=4.69 hours

Find out the average speed on the return trip

speed=360/(t+3)

speed=360/(4.69+3)

speed=46.81 mph

Which of the following would be the variance of this population data set: 3, 9,8, 9, 4, 5, 7, 11, 9, 7, 5, 4, 3, 1

Answers

GIVEN:

We are given the set of data as indicated below;

[tex]3,9,8,9,4,5,7,11,9,7,5,4,3,1[/tex]

Required;

To find the variance of the data set.

Step-by-step solution;

We begin by calculating the mean of the data set as follows;

[tex]\begin{gathered} Mean=\frac{3+9+8+9+4+5+7+11+9+7+5+4+3+1}{14} \\ \\ Mean=\frac{85}{14}=6.07142857143 \end{gathered}[/tex]

We now round the mean to two decimal places and we have;

[tex]Mean\approx6.07[/tex]

Next we subtract the mean from EACH value in the data set. the individual results are the "deviation from the mean."

After that we square each deviation from the mean, and then add them all up.

This is effectively explained by the formula for the variance which is;

[tex]\begin{gathered} variance=s^2 \\ \\ s^2=\frac{\Sigma(x-\bar{x})^2}{n-1} \end{gathered}[/tex]

We now have;

[tex]\begin{gathered} (3-6.07)^2+(9-6.07)^2+(8-6.07)^2+...+(3-6.07)+(1-6.07)^2 \\ \\ =9.4249+8.5849+3.7249+8.5849+4.2849+1.1449+0.8649+24.3049 \\ \\ +8.5849+0.8649+1.1449+4.2849+9.4249+25.7049 \\ \\ =110.9286 \end{gathered}[/tex]

Now we can refine the formula as shown below;

[tex]\begin{gathered} s^2=\frac{\Sigma(x-\bar{x})^2}{n-1} \\ \\ Where,\text{ }n=14 \\ \\ s^2=\frac{110.9286}{14-1} \\ \\ s^2=\frac{110.9286}{13} \\ \\ s^2=8.53296923077 \end{gathered}[/tex]

We can round this to 2 decimal places and the variance therefore is;

ANSWER:

[tex]variance\approx8.53[/tex]

given ️KPM =~ ️AYC complete each of the following statements

Answers

a)

[tex]\bar{KM}\cong\bar{AC}[/tex]

b)

[tex]\bar{CY}\cong\bar{MP}[/tex]

c)

[tex]\bar{PK}\cong\bar{AY}[/tex]

d)

[tex]\angle Y\cong\angle P[/tex]

e)

[tex]\angle K\cong\angle A[/tex]

f)

[tex]\angle ACY\cong\angle KMP[/tex]

g)

[tex]\Delta\text{MPK}\cong\Delta CYA[/tex]

h)

[tex]\Delta\text{YAC}=\Delta\text{PKM}[/tex]

The perimeter of a square field is 292 yards. How long is each side

Answers

We know that the four side of a square are congruent, this means that

every side have the same length. Then, the perimeter (P) is given by

[tex]\begin{gathered} P=L+L+L+L=4L \\ or\text{ equivalenlty,} \\ P=4L \end{gathered}[/tex]

From the given information, we know that P= 292 yards. So we have

[tex]4L=292\text{ yd}[/tex]

Then, by dividing both sides by 4, we get

[tex]\begin{gathered} L=\frac{292}{4} \\ L=73 \end{gathered}[/tex]

Therefore, each side measures 73 yards

Answer:

73 yards

Step-by-step explanation:

292 divided by 4= 73

Please mark brainliest have a nice day

please find amplitude period and phase shifty=sin(2x-pi/2)

Answers

For the sinusoidal function:

[tex]y=A\sin (Bx+C)+D[/tex]

we have that:

A represents the amplitude

2pi/B represents the Period

C is the phase shift

D is the vertical shift.

In this case, we have the following equation:

[tex]y=\sin (2x-\frac{\pi}{2})[/tex]

then, the amplitude is A = 1.

For the period, we have the following:

[tex]\begin{gathered} B=2 \\ \Rightarrow\frac{2\pi}{B}=\frac{2\pi}{2}=\pi=\text{Period} \\ \end{gathered}[/tex]

thus, the period is pi.

Finally, notice that C = -pi/2, thus, the phase shift is -pi/2

((5x-16) cubed -4)cubed = 216,000X = _________

Answers

Given the equation:

[tex]((5x-16)^3-4)^3=216000[/tex]

Applying the exponent laws:

[tex]\begin{gathered} \sqrt[3]{((5x-16)^3-4)^3}=\sqrt[3]{216000} \\ (5x-16)^3-4=60 \end{gathered}[/tex]

Simplify:

[tex]\begin{gathered} (5x-16)^3-4+4=60+4 \\ (5x-16)^3=64 \end{gathered}[/tex]

Applying the exponent laws:

[tex]\begin{gathered} \sqrt[3]{(5x-16)^3}=\sqrt[3]{64} \\ Simplify \\ 5x-16=4 \\ 5x-16+16=4+16 \\ 5x=20 \\ \frac{5x}{5}=\frac{20}{5} \\ x=4 \end{gathered}[/tex]

Answer: x = 4

GameStop sells used games the games are usually $60 but are on sale for 15% off what is the percent decrease between the original and sale price for the game

Answers

Percentage decrease in price

Original price = $60

Find 15% of 60

Then

10% of 60 is $6

5% of 60 is $6/2 = $3

In consecuence 15% of $60 is 6+3 = $9

Then precent decrease in price is $9

And New price is 60-9 = $51

Sari had 3/4 of a bag of pretzels. Her younger brother ate some, leaving her with 1/8 of a bag.What fraction of the bag did Sari's brother eat?M. 4/12P. 2/4R. 5/8S. 7/8

Answers

To solve this problem you have to subtract the remaining pretzels from the initial number of bags of pretzels.

Computing the subtraction, you get:

[tex]\frac{3}{4}-\frac{1}{8}=\frac{6}{8}-\frac{1}{8}.[/tex]

Simplifying the above result, you get:

[tex]\frac{5}{8}.[/tex]Answer: [tex]\frac{5}{8}.[/tex]

Is this statement true or not? cos (cos^-1 (2)) = 2 Explain why or why not.

Answers

True

1) Let's evaluate that, using one identity for that:

[tex]\begin{gathered} \cos (\cos ^{-1}(2))= \\ \cos (\cos ^{-1}(\theta))=\theta \\ \cos (\cos ^{-1}(2))=2 \end{gathered}[/tex]

2) Since the cosine of the arc cosine (theta) is equal to theta, we can state that this trigonometric equation is true.

3) Hence, that's true.

I need help with several questions, I don't really understand pre algbrea at all.

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

Using the data in the table to find the rate of change in the length of the baby girl:

Choosing any two consecutive points, we have that the:

[tex]\text{Average Rate of change =}\frac{Differen\text{ce in the two consecutive lengths }}{\text{Difference in the consecutive months}}[/tex][tex]Average\text{ Rate of change = }\frac{21.5\text{ -20}}{6-4}[/tex][tex]\begin{gathered} \text{Average Rate of change =}\frac{1.5}{2} \\ =\text{ 0.75 inch per month} \end{gathered}[/tex]

CONCLUSION:

The final answer = 0. 75 inch per month

#3ItYour piggy bank is filled with coins!contains 27 quarters, 18 dimes, 11 nickels,and 124 pennies. You turn you bank upside-down and a coin falls out. What is theprobability the coin is worth less than 25¢?

Answers

Given data:

27 quarters (25¢)

18 dimes (10¢)

11 nickels (5¢)

124 pennies (1¢)

Total coins: 180

Coins that are less than 25¢: 27+18+11=56

Probability that the coin that falls out worths less than 25¢:

[tex]P(<25)=\frac{coins\text{ }<25}{total\text{ }coins}=\frac{56}{180}=\frac{14}{45}\approx0.311[/tex]Then, the probability that the coin that falls out worths less than 25¢ is 14/45 or approximately 0.311

I need help with this expected value out come assignment

Answers

To fill the values, we are given a list of the percentage of customers that spend a specific amount of money.

The x1, x2, x3, and x4 are the money spent, and the P(x1), P(x2),... are the proportion of customers that spend that amount, in decimal

Then, we can complete:

[tex]\begin{gathered} X_1=8 \\ . \\ P(X_1)=0.20 \\ . \\ X_1\cdot P(X_1)=8\cdot0.20=1.6 \\ \end{gathered}[/tex][tex]\begin{gathered} X_2=10 \\ . \\ P\left(X_2\right)=0.35 \\ . \\ X_3\cdot P(X_3)=10\cdot0.35=3.5 \end{gathered}[/tex][tex]\begin{gathered} X_3=12 \\ . \\ P(X_3)=0.40 \\ . \\ X_3\cdot P(X_3)=12\cdot0.40=4.8 \end{gathered}[/tex]

[tex]\begin{gathered} X_4=15 \\ . \\ P(X_4)=0.05 \\ . \\ X_4\cdot P(X_4)=15\cdot0.05=0.75 \end{gathered}[/tex]

Find the approximate volume of the cylinder below in cubic centimeters. Round your answer to the nearest hundredth. 14 cm 20 cm

Answers

Answer: Volume of a cylinder = 3, 077.20 cubic centimeter

Given data

Diameter of the cylinder = 14cm

Height of the cylinder = 20cm

Radius = diameter / 2

radius = 14/2

radius = 7 cm

[tex]\begin{gathered} \text{Volume of the cylinder = }\pi\cdot r^2\cdot\text{ h} \\ \pi\text{ = 3.14, r = 7cm, and h = 20cm} \\ \text{V = 3.14 }\cdot7^2\cdot\text{ 20} \\ \text{V = 3.14 x 49 x 20} \\ \text{V = 3.14 x 980} \\ \text{V = 3, 077.20 cm}^3 \end{gathered}[/tex]

Use the pair of functions to find f(g(x)) and g(f(x)). Simplify your answers. f(x)=x−−√+2, g(x)=x2+9

Answers

We have the next functions

[tex]\begin{gathered} f(x)=\sqrt[]{x}+2 \\ g(x)=x^2+9 \end{gathered}[/tex]

For f(g(x))

[tex]f(g(x))=\sqrt[]{x^2+9}+2[/tex]

For g(f(x))

[tex]\begin{gathered} g(f(x))=(\sqrt[]{x}+2)^2+9 \\ g(f(x))=x+4\sqrt[]{x}+4+9 \\ g(f(x))=x+4\sqrt[]{x}+13 \end{gathered}[/tex]

ANSWER

[tex]f(g(x))=\sqrt[]{x^2+9}+2[/tex][tex]g(f(x))=x+4\sqrt[]{x}+13[/tex]

Can someone please explain it to me I don't get it

Answers

We have the general rule for a rotation of 90° counterclockwise:

[tex]r_{90}(x,y)=(y,-x)[/tex]

and the general rule for a y=-x reflection is:

[tex]r_{y=-x}(x,y)=(-y,-x)[/tex]

In this case, we have the points R=(2,-2), S=(5,-1) and T=(3,-5).

Then, we first have to use the 90° rotation on all points:

[tex]\begin{gathered} r_{90}(R)=r_{90}(2,-2)=(-2,-2)=R^{\prime} \\ r_{90}(S)=r_{90}(5,-1)=(-1,-5)=S^{\prime} \\ r_{90}(T)=r_{90}(3,-5)=(-5,-3)=T^{\prime} \end{gathered}[/tex]

Now we use the y=-x reflection on our new points:

[tex]\begin{gathered} r_{y=-x}(R^{\prime})=r_{y=-x}(-2,-2)=(2,2)=R^{\doubleprime} \\ r_{y=-x}(S^{\prime})=r_{y=-x}(-1,-5)=(5,1)=S^{\doubleprime} \\ r_{y=-x}(T^{\prime})=r_{y=-x}(-5,-3)=(3,5)=T^{\doubleprime} \end{gathered}[/tex]

therefore, the final points after the transformations are:

R''=(2,2)

S''=(5,1)

T''=(3,5)

10 The model below shows Jonathan's rate of pay by hours. How much will he get paid for the greatest number of hours shown on the model below? S105 $?

Answers

From the model, we notice that for three hours Jonathan earns $105. This means that he earns $35 (105 divided by 3) per hour.

Now, we have in total 10 hours in the model, hence he will earn a total of $350 (35 times 10).

I have I have two patterns and I need to find the correct equation

Answers

First pattern

The number of squares in the first term is 3

The second term is 5

The third term is 7

So this pattern increased by 2

The rule of any pattern increased by a constant number is

y = a + (x-1)d, where

a is the first term

d is the constant difference

x is the position of the term

So a = 3

and d = 2

The equation is

y = 3 + (x - 1)2

Multiply 2 by the bracket

y = 3 + 2x - 2

Add the like terms

y = 2x + 1

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write the point slope form of the equation of the line passing through the points ( -5, 6) and (0 , 1)

Answers

Let us find the slope first

[tex]\begin{gathered} m=\text{slope = }\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-6}{0+5} \\ m=-\frac{5}{5}=-1 \end{gathered}[/tex]

The equation can be found as follows using the points (0 ,1)

[tex]\begin{gathered} m=\frac{y-y_1}{x-x_1_{}_{}} \\ m=\frac{y-1}{x-0} \\ -1=\frac{y-1}{x} \\ -x=y-1 \\ y=-x+1 \end{gathered}[/tex]

Is the LCD ( X + 2 ) and 3( X + 6) ?

Answers

To add 2 algebraic fractions we must make their denominators the same

Then we must have the LCM of both denominators

Since the denominators area (x + 2) and (3x + 6), then

We can take 3 as a common factor from the 2nd denominator

[tex]\begin{gathered} 3x+6=3(\frac{3x}{3}+\frac{6}{3}) \\ 3x+6=3(x+2) \end{gathered}[/tex]

Then the LCM of the 2 denominators is 3(x + 2)

Now we can change the first denominator to 3(x + 2) by multiplying up and down by 3

-50=3(15)+b solve for b

Answers

Given that -50=3(15)+b

expand

-50=45+b

collect like terms

-50 - 45 = 45 - 45 + b

-95 = b

b = -95

Find the range of allowable values based on the given information. Round to the nearest tenth.15; can vary by 2%Enter the correct answers in the boxes.Hide HintMultiply the percentage by the number to find the amount of error allowed.• Add and subtract the amount of error from the original number to find the range.to

Answers

15 can vary by 2%, this means that the range of values you can observe are 2% below 15 and 2% above 15.

First, you have to determine how much does the percentage represents with regards to the value of reference. To do so, you have to calculate the 2% of 15:

-Multiply 2 by 15 and divide the result by 100

[tex]\frac{2\cdot15}{100}=\frac{30}{100}=3[/tex]

The 2% of 15 is 3, which means that the range of values you are looking for is 3 units below 15 and 3 units above.

The minimum value of the range: subtract 3 to 15

[tex]15-3=12[/tex]

The maximum value of the range: add 3 to 15

[tex]15+3=18[/tex]

The range of allowable values is [12;18]

COSEddQuestions9.75725 pes1Karina wants to solve the following quadratic equation by factoring154.r? – 25.1 +6=0She started the problem as shown below. Help her finish factoring, show all your steps, and solve for x,Show Your WorkCorrect answer

Answers

To factor the given equation, rewrite the middle terms as binomials.

[tex]4x^2-24x-x+6=0[/tex]

Group the terms and then factor out the common monomial from each group.

[tex]4x(x-6)-(x-6)=0[/tex]

Factor the common binomial factor.

[tex](4x-1)(x-6)=0[/tex]

Since the factored form of the expression at the left is

[tex](4x-1)(x-6)=0[/tex]

we may obtain the values inside the squares by multiplying the factors. We may use the FOIL method to obtain each term.

Thus, we get the following.

Product of the first terms:

[tex](4x)(x)=4x^2[/tex]

Product of the Outer Terms:

[tex](4x)(-6)=-24x[/tex]

Product of the Inner Terms:

[tex](-1)(x)=-x[/tex]

Product of the Last Terms:

[tex](-1)(-6)=6[/tex]

Thus, the terms inside the first figures should be -x and -24x, respectively.

Physicists tell us that altitude h in feet of a projectile t seconds after firing is h=-16t^2+v0t+h0, where v0 is the initial velocity in feet per second and h0 is the altitude in feet from which it is fired. If a rocket is launched from a hilltop 2400 feet above the desert with an initial upward velocity of 400 feet per second, then when will it land on the desert ?

Answers

The formula that the physicists told was

[tex]h(t)=-16t^2+v_0t+h_0[/tex]

We know that

v₀ = 400 ft/s

h₀ = 2400 ft

Then let's put it into the formula

[tex]\begin{gathered} h(t)=-16t^2+400t+2400 \\ \\ \end{gathered}[/tex]

We want to know then it will land on the desert, in other words, when the height is equal to zero, then

[tex]-16t^2+400t+2400=0[/tex]

Then we must solve that quadratic equation, to solve it let's first divide all by 16

[tex]\begin{gathered} -16t^2+400t+2400=0 \\ \\ -t^2+25t+150=0 \end{gathered}[/tex]

Because it's an easier equation to solve and the solution is the same. Now we can apply the quadratic formula

[tex]t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Plug the values

[tex]\begin{gathered} t=\frac{-25\pm\sqrt{25^2-4\cdot(-1)\cdot150}}{2\cdot(-1)} \\ \\ t=\frac{-25\pm\sqrt{625+4\cdot150}}{-2} \\ \\ t=\frac{25\pm\sqrt{625+600}}{2} \\ \\ t=\frac{25\pm\sqrt{1225}}{2} \\ \\ t=\frac{25\pm35}{2} \\ \\ t=\frac{25+35}{2}=\frac{60}{2}=30\text{ seconds} \end{gathered}[/tex]

We can ignore the other solution because it's negative and negative time is not a valid solution. Therefore, 30 seconds after its launch, the rocket will land in the desert

You are planning to rent a car for a road trip. Company A charges a base price of $56 plus a charge of 0.25 per mile. A competing car company, Company B, charges a base price of $45 plus a charge of $0.58 per mile,(a) Write a formula for the total cost Ca, of renting a car from Company A as a function of the number of miles, m: driven.(b) Write a formula for the total cost Cb , of renting a car from Company B as a function of the number of miles, m. driven.(c) At what mileage will the cost of renting a car be the same from both companies? Round decimal to two places.

Answers

Part a)

Since m is the number of miles driven and company A charges a base price of $56 plus a charge of $0.25 per mile, we can write the following equation:

[tex]Ca=56+0.25m[/tex]Part b)

Again, since m is the number of miles driven and company B charges a base price of $45 plus a charge of $0.58 per mile, we can write the following equation:

[tex]Cb=45+0.58m[/tex]Part c)

The cost of renting a car from both companies will be the same when:

[tex]Ca=Cb[/tex]

Then, we solve the following equation for m:

[tex]\begin{gathered} 56+0.25m=45+0.58m \\ \text{ Subtract 56 from both sides of the equation} \\ 56+0.25m-56=45+0.58m-56 \\ 0.25m=0.58m-10 \\ \text{ Subtract 0.58 m from both sides of the equation} \\ 0.25m-0.58m=0.58m-10-0.58m \\ -0.33m=-10 \\ \text{ Divide by 0.33 from both sides of the equation} \\ \frac{-0.33m}{-0.33}=\frac{-10}{-0.33} \\ m\approx33.33\Rightarrow\text{ The symbol }\approx\text{ is read "approximately"} \end{gathered}[/tex]

Therefore, the cost of renting a car from both companies will be the same at 33.33 miles.

Are the two lines parallel, perpendicular, or neither? Parallel Perpendicular O Neither

Answers

Answer:

Explanation:

• Parallel lines ,are lines that ,do not intersect ,no matter how long the line is drawn.

,

• Perpendicular lines, are lines that ,form an angle of 90 degrees, with one another.

From the given options, the following options apply:

• Graph 1: Parallel

,

• Graph 2: Neither

,

• Graph 3: Perpendicular

,

• Graph 4: Neither

solving quadratic function by completing the squares

Answers

Consider the given equation,

[tex]-32=2(x^2+10)[/tex]

Apply the method of completing square as follows,

[tex]\begin{gathered} -32=2(x^2+2(x)(5)) \\ -32+50=2(x^2+2(x)(5))+2(25) \\ 18=2(x^2+2(x)(5)+25) \\ 18=2(x^2+2(x)(5)+(5)^2) \\ 18=2(x+5)^2 \\ \frac{18}{2}=(x+5)^2 \\ (x+5)^2=9 \\ x+5=\sqrt[]{9} \\ x+5=\pm3 \\ x+5=3\text{ }or\text{ }x+5=-3 \\ x=3-5\text{ }or\text{ }x=-3-5 \\ x=-2\text{ }or\text{ }x=-8 \end{gathered}[/tex]

Thus, the solutions of the quadratic equation are -2 and -8.

Other Questions
What is the equation for the graph shown?y=-1/2x+2y=-1/2x-1y=1/2x+2y=-1/2x+3 In a recent year, 16.8% of all doctors were female. If there were 57,600 female registered doctors that year, what was the total number of registered doctors?Round your answer to the nearest whole number. Which equation has a constant of proportionality equal to 5?Choose 1 answerY = 5xY = 10/5xY = 5/25xY = 1-2x I don't know what to do at the last part Complete each statement about multiplying positive and negative integers using word positive or negative. Then provide an example for each statementA. Positive + PositiveB. positive + negativeC. negative + negative Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10). Suppose the outcomes are equally likely. Compute the probability of the event E = 'an odd number less than 9."P(E)=(Type an integer or a decimal. Do not round.) According to the US blood bank about 35.7% of the US has A positive blood. 1. If 3 people are chosen at random then what is the probability that no one has A positive blood?2. If 3 people are chosen at random then what is the probability that all 3 have A positive blood?Show all your work and make sure to round your answer to 3 decimal places. Rob weighed how much candy he ate each month. His measurements were:2.4 lbs, 2.2 lbs, 1.6 lbs, 1.4 lbs, and 2.3 lbs. Find the range and mode of thegiven data. Water is a polar liquidOil is a non-polar liquidBenzene is a non-polar liquidWhich combination of liquids will be immiscible ?(Choose all that apply) Group of answer choiceswater and oiloil and benzenebenzene and water Show 1.25 and -1.25 as points on a number line. + - 1 + 1 -2 0 2 What is the distance between the two points? Explain. Which two points are located 7.5 units away from -1.25? Please answer the following question and match the correct term with It's correct defenition. According to scientists, the cockroach has had 300 million years to develop a resistance to destruction. In a study conducted by researchers, 4,000 roaches (the expected number in a roach-infested house) werereleased in the test kitchen. One week later, the kitchen was fumigated and 15,400 dead roaches were counted, a gain of 11,400 roaches for the 1-week period. Assume that none of the original roaches died duringthe 1-week period and that the standard deviation of the number of roaches produced por roach in a 1-week period, is 1.3. Use the number of roachos produced by the sample of 4,000 roaches to find a 90%confidence interval for the mean number of roaches produced per week for each roach in a typical roach-infested house.Find a 90% confidence interval for the mean number of roachos produced per week for each roach in a typical roach-infested house,(Round to three decimal places as needed.) 4. (01.02 MC)There are (4^2)^3 * 4^0 horses on a stud farm. What is the total number of horses on the farm? (1 point)04^64^74^24 Fifth grade DD.8 Area of parallelograms and trapezoids 05X What is the area? Write your answer as a fraction or as a whole or mixed number. 2 rt square feet Find the domain of the function.4+xf(x) =8-3xWrite your answer as an interval or union of intervals. If W (-10,4),X(-3,-1)and Y (-5,11) classify angle WXY by its sides Previous BalanceCredit Card StatementCalculate the new$310.00balance on thisFinance Charge $10.00 account after theseNew Purchases $80.00charges andPayments$(200.00)payments are$0.00appliedCreditsA. -$20.00B. $440.00C. $600.00D. $200.00 Which letter in the diagram below represents the location where blood ispumped to the lungs and picks up oxygen?A. AB. Cc. BD. D Create an equation with parentheses and a solution of x=2 find the sum of the interior angles of a regular decagon