What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged particle as it travels through water (which has an index of refraction of n

Answer:

The car is going to slow down to 3N.

Explanation:You have a force going 10N to the left and if you put an opposing force of 7N you get 3N of total force.

Answer:

12.5 m/s

Explanation:

If the avg speed is 10 m/s we assume that the speed is constant and not fluctuating

If VT (Velocity*Time) is equal to speed at the end of the 4 seconds of accel. it is the top speed at the finish line

since the speed is 0 at the beginning of races, we will use V0= 0 m/s

So the avg velocity for those 4 seconds is (VT+V0) /2 = or 1/2 VT (for 40% of the race)

The avg velocity for the last 6 seconds is, of course, VT (for 60% of the race

hence

(1/2VT)(.4) + VT(.6) = 10 m/s

VT = 10/.8 = 12.5 m/s

Answer:

1.548K

Explanation:

Given that f= 160.23GHz

c= 3E8m/s

b= 2.898*10^-3mk

So using

(Lambda)m x T= b

So T = b/ lambda

But wavelength ( lambda) = c/f

So T = bf/c

= 2.898E-3x 160.23E9/3E8

=1.548K

The feature that characterizes simple columnar epithelium of the digestive tract is the presence of dense microvilli.

Simple columnar epithelium is a type of tissue that lines the digestive tract, including the stomach and intestines. It is composed of a single layer of column-shaped cells that are tightly packed together. One distinguishing feature of this epithelium is the presence of dense microvilli on the apical surface of the cells. Microvilli are tiny finger-like projections that increase the surface area of the cells, facilitating absorption and secretion processes. These dense microvilli help in the absorption of nutrients and the secretion of digestive enzymes, allowing for efficient digestion and absorption of nutrients in the digestive tract. The microvilli significantly increase the surface area available for these functions, enabling more efficient nutrient absorption. Therefore, the correct answer is (d) dense microvilli.

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Answer:

d. At the base of the fire

Explanation:

Most fire extinguisher utilize the non-combustible nature of carbon-dioxide . carbon-dioxide is what is used in fire extinguishers, because it does not support burning. Also, carbon-dioxide is denser than air, allowing it to sink down. Aiming at the bottom of the flame allows the carbon-dioxide to sink down on the base of the flame, covering the base of the fire, and cutting off its supply of oxygen which is vital for combustion.

Answer:

Explanation:

We shall represent all the displacement in terms of vector . We shall consider east as i , and north as j . south of west direction will be represented by - i - j .

displacement of 1.9 km due east

D₁ = 1.9 i

vector representing south of west = - i - j

unit vector = - i - j / √ 2

7.2 km south of west = 7.2 ( - i - j ) / √ 2

D₂ = - 5.09 ( i + j )

Total displacement

= D₁ + D₂

= 1.9 i  - 5.09 ( I + J )

D = - 3.19 i - 5.09 j .

magnitude of D = √ ( 3.19² + 5.09² )

= 6 km .

Direction of D

Tanθ = 5.09 / 3.19 = 1.59

θ = 58°

So direction will be 58° south of west .

To reach the starting point , he shall have to go in opposite direction .

So he shall have to go in the direction of north of east at angle 58° by a displacement of 6 km .

Answer:

d' = 0.86 mm

Explanation:

First we need to find the area of low power field:

A = πd²/4

where,

A = Area = ?

d = diameter = 1.5 mm

Therefore, using the value of diameter, we get:

A = π(1.5 mm)²/4

A = 1.767 mm²

Now, the new object occupies 1/3rd of this area:

A' = (1/3)A

πd'²/4 = (1/3)A

d'² = (4/3π) A

d'² = (4/3π)(1.767 mm²)

d' = √(0.75 mm²)

d' = 0.86 mm

Answer:

9.3

Explanatin:

Answer:

4.5

Explanation:

Answer:

5730 guppies

Explanation:

1 liter= 38.2 guppies

150 liters= 150×38.2

On planet Q the standard unit of volume is called guppi. Space travelers from Earth have determined that one liter = 38.2 guppies. Guppies in 150 liters is 5730 guppies.

Volume, which is measured in cubic units, is the 3-dimensional space occupied by matter or encircled by a surface. The cubic meter (m³), a derived unit, is the SI unit of volume. A addition new nickname for the cubic (dm³) is a liter (L).

Given that in the question on planet Q the standard unit of volume is called guppi, the conversion of different volume unit,

1 liter = 38.2 guppies, so

150 litre =  5730 guppies

Guppies in the given 150 liters of volume is 5730 guppies.

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Answer:

B) We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

C) Volume of Prism = 78 cm³

Explanation:

PART C:

Since, the volume of prism s given by the following formula:

Volume of Prism = (Area of Base of Prism)(Height of Prism)

Therefore,

Height of Prism = 6.6 cm

Area of Base of Prism = Length x Width

Area of Base of Prism = 5.6 cm x 2.1 cm

Area of Base of Prism = 11.76 cm²

Hence, the equation gives:

Volume of Prism = (11.76 cm²)(6.6 cm)

Volume of Prism = 77.616 cm³

Since, the initial values had 2 significant figures, so rounding off to two significant figures:

Volume of Prism = 78 cm²

PART B:

We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

Answer:

the sphere

Explanation:

From the given information,

A free flow body diagrammatic expression  for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane  can be seen in the image attached below.

From the diagram;

The Normal force mgsinθ - Friction force F  = mass m × acceleration a

Meanwhile; the frictional force

[tex]F = \dfrac{I \alpha }{R}[/tex]

where

[tex]\alpha = \dfrac{a}{R}[/tex]  in a rolling motion

Then;

[tex]F = \dfrac{I a }{R^2}[/tex]

∴

The Normal force mgsinθ - F  =  m ×  a     can be re-written as:

[tex]\mathtt{mg sin \ \theta- \dfrac{Ia}{R^2} = ma}[/tex]

making a the subject of the formula, we have:

[tex]a = (\dfrac{mg \ sin \theta}{m + \dfrac{I}{R^2}})[/tex]

Similarly;

I = mk²  in which k is the radius of gyration

∴

replacing I = mk² into the above equation , we have:

[tex]a = (\dfrac{mg \ sin \theta}{m + \dfrac{mk^2}{R^2}})[/tex]

where;

the uniform disk [tex]\dfrac{k^2}{R^2 }= \dfrac{1}{2}[/tex]  

the uniform  sphere [tex]\dfrac{k^2}{R^2 }= \dfrac{2}{5}[/tex]

∴

[tex]a = \dfrac{2}{3} \ g sin \theta \ for \ the \ uniform \ disk[/tex]

[tex]a = \dfrac{5}{7} \ g sin \theta \ for \ the \ uniform \ sphere[/tex]

We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.

Answer:

Explanation:

A. Using

Sinစ= y/ L = 0.013/2.7= 0.00481

စ=0.28°

B.here we use

Alpha= πsinစa/lambda

= π x (0.0351)sin(0.28)/588E-9m

= 9.1*10^-2rad

C.we use

I(စ)/Im= (sin alpha/alpha) ²

So

{= (sin0.091/0.091)²

= 3*10^-4

Answer:

0N

Explanation:

When trying to figure out opposing forces, you have to add them together,

10 + -10 = 0,

so your answer is 0N

Answer:the answer is 0 N

Explanation:

The electromagnetic spectrum consists of series of waves that are arranged from longest wavelength to shortest.

Answer:

32.6mm

Explanation:

Using area of a sphere(bulb) = 4πr²

So A is proportional to radius²

So the Energy will be proportional to r²

But 120/80 = 1.5 is the energy factor so

Using

1.5/d² = 1/r²

1.5/40²= 1/r^2

r = √( 40²/ 1.5)

r = 32.6m

Answer:

this occurs because the energy of the constituents is greater than the energy of the material formed and this excess is what we can appreciate in the form of ligh

Explanation:

When the light stick breaks, it allows substances to mix, produced by a chemical reaction, which releases light into the environment.

The energy released is the energy energy of the excess when the transformation takes place, this occurs because the energy of the constituents is greater than the energy of the material formed and this excess is what we can appreciate in the form of light,

Answer:

Explanation:

What is average speed?

It is the total distance traveled divided by the time taken to cover the total distance traveled

Given that the various distances are

20 miles and 10 miles

the total distance traveled is 20+10= 30 miles

the average speed is expressed as

average speed= total distance/time taken

average speed= 30/1

average speed= 30 miles/hour

The average velocity is a vector quantity

the velocity is the average displacement divided by time taken

[tex]displacement= \sqrt{1^2+2^2} \\\\displacement= \sqrt{1+4} \\\\displacement=2.24 miles[/tex]

average velocity= displacement / time

average velocity= 2.24 /1

average velocity= 2.24 miles/hour

Answer:

243.83 Hz

Explanation:

Given the following :

Recall :

When source is stationary and observe is in motion:

Moving away from the source :

Observed frequency f₀ = f(v-v₀/v)

Moving towards the source :

f₀ = f(v+v₀/v)

Hence ;

v₀ = 12.1 m/s ; f of trumpeter = 262 Hz ; speed of sound (v) = 337m/s

f(v+v₀/v) = 262(v-v₀/v)

f = 262(v-v₀/v) / (v+v₀/v)

f = 262(v-v₀/v) * (v / v+v₀)

f = 262 (v-v₀ / v+v₀)

f = 262 ((337 - 12.1) / (337 + 12.1))

f = 262 (324.9 / 349.1)

f = 262 (0.93067888857)

f = 243.83

f = 244Hz

Answer:

The value is [tex]B = 7.7106 *10^{-12 } \ T[/tex]

Explanation:

From the question we are told that

The energy is [tex]E = 10.0 MeV = 10.0 *10^{6} \ eV = 10.0 *10^{6} * 1.60*10^{-19} = 1.6 *10^{-12} \ J[/tex]

The  radius  is  [tex]R = 5.80 *10^{10} \ m[/tex]

Generally the magnetic field is mathematically represented as

       [tex]B = \frac{m * v }{q * R }[/tex]

Where m is the mass of  proton with value  [tex]m = 1.6*10^{-27} \ kg[/tex]

 v is the velocity of the proton which is mathematically deduced  from the formula for kinetic energy as

                   [tex]v = \sqrt{ \frac{E }{ 0.5 * m } }[/tex]

Here E is also equivalent to kinetic energy of the proton so

                   [tex]v = \sqrt{ \frac{1.6 *10^{-12} }{ 0.5 * 1.6*10^{-27} } }[/tex]

                 [tex]v = 4.47214 *10^{7} \ m/s[/tex]

So  

     [tex]B = \frac{1.60 *10^{-27} * 4.47214 *10^{7}}{ 1.60 *10^{-19} * 5.80*10^{10}}[/tex]

      [tex]B = 7.7106 *10^{-12 } \ T[/tex]

The magnetic field in the region has a magnitude of 7.7×[tex]10^{-12}[/tex] T.

Let's consider the magnetic field in the region be B. Now the proton in the given orbit is in equilibrium under the influence of centripetal force ([tex]F_{c}[/tex]) and magnetic force([tex]F_{b}[/tex]).

[tex]F_{c}[/tex] = [tex]F_{b}[/tex]

m[tex]v^{2}[/tex]/R = qvB

⇒ B = mv/qR

where, m is the mass of proton =  1.6 × [tex]10^{-27}[/tex] kg

            q is the charge of proton = 1.6 × [tex]10^{-19}[/tex] C

            R is the radius of the orbit = 5.8 × [tex]10^{10}[/tex] m

now we can calculate the velocity of the proton, v, from the energy of the proton given in the question that is E = 10 MeV.

1 MeV = 1.6 × [tex]10^{-19}[/tex] J

           v = [tex]\sqrt{\frac{2E}{m} }[/tex]

               =[tex]\sqrt{\frac{2*10*10^{6}* 1.6*10^{-19} }{1.6*10^{-27} } }[/tex]

            v = 4.47 × [tex]10^{7}[/tex] m/s

now,

        B = mv/qR

           = [tex]\frac{1.6*10^{-27}*4.47*10^{7} }{1.6*10^{-19}*5.8*10^{10} }[/tex]

       B = 7.7 ×[tex]10^{-12}[/tex] T

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Answer:

It depends on the materials of the medium in involved

Answer:

The summary including its circumstances in question is outlined in the illustrating segment below.

Explanation:

Answer: (b) Approximately 32 years .

Explanation:

Moves = 2n-1 .

It takes (224-1) are the minimum number of moves required to move 24 disks, which is 16777216.

Now each move takes 1 minute, therefore total time in (mintes) = 16777216 .

Now in one year we have 525600 minutes.

Therefore time in years = 16777216/525600 = 31.920121765601217656012176560122 = 32 years (approx)

The star is approximately 45° above the celestial equator.  (A)

"Declination" on the celestial coordinate system is equivalent to latitude on the terrestrial one.

Answer:

16 secs.

Explanation:

Data obtained from the question include the following:

Period on earth (T) = 8 secs

Next period (Tn) =?

Next, we shall determine the length of the string. This can be obtained as follow:

Period on earth (T) = 8 secs

Acceleration due to gravity on earth (gE) = 9.8 m/s²

Pi (π) = 3.14

Length of string (L) =?

T = 2π√(L/gE)

8 = 2 × 3.14 ×√(L/9.8)

8 = 6.28 × √(L/9.8)

Divide both side by 6.28

8/6.28 = √(L/9.8)

Take the square of both side

(8/6.28)² = L/9.8

Cross multiply

L = (8/6.28)² × 9.8

L = 15.9 m

Therefore the length of string is 15.9 m

Next, we shall determine the new period of the pendulum as follow:

Length (L) = constant = 15.9 m

Pi (π) = 3.14

Acceleration due to gravity on earth (gE) = 9.8 m/s²

Acceleration due to gravity on the planet (g) = 1/4 gE = 1/4 × 9.8 m/s²

= 2.45 m/s²

New period (Tn) =?

Tn = 2π√(L/g)

Tn = 2 × 3.14 × √(15.9/2.45)

Tn = 6.28 × √(15.9/2.45)

Tn = 16 secs.

Therefore, the new period of the pendulum is 16 secs.

Answer:

We know that

Velocity= wavelength x frequency

And f= 1/2π√T/u

So we also know that

The frequency of nth harmonic standing wave is

fn=nv/2L

So from the relationships above

We can see that as propagational velocity increases, the frequency increases and the wavelength decreases. So finally we can say that sinusoidal pattern on a string is shorter when there is a greater propagation velocity

Answer:

Acceleration (a) = 1.167 m/s²

Distance travel = 105 m (Approx)

Explanation:

Given:

Initial speed (u) = 14 m/s

Final speed (v) = 21 m/s

Time taken (t) = 6 sec

Find:

Acceleration

Distance travel

Computation:

v = u + at

21 = 14 + a(6)

7 = 6a

Acceleration (a) = 1.167 m/s²

S = ut + (1/2)(a)(t²)

S = (14)(6) + (1/2)(1.167)(6²)

S = 84 + 21

S = 105 m (Approx)

Distance travel = 105 m (Approx)

Answer:

Hey!

Your answer is 10^12 nanometers!

Explanation:

AKA

1,000,000,000,000  nm

HOPE THIS HELPS!!

Answer:

A) 443 Hz

B) She has to loosen the string

Explanation:

A) Given;

Beat frequency;f_beat = 3 Hz

Frequency of electronically generated tone; f_e = 440 Hz

We know that formula for beat frequency is given by;

f_beat = |f1 - f2|

Now, applying it to this question, we have;

f_beat = f_v - f_e

Where f_v is frequency of the note played by the violinist

Thus, plugging in the relevant values;

3 = f_v - 440

f_v = 3 + 440

f_v = 443 Hz

B) In the concept of wave travelling in a string, the frequency is directly proportional to the square root of the force acting on the string.

Now, for the violinist to get her violin perfectly tuned to concert A from what it was when she heard the 3-Hz beats, the beat frequency will have to be zero. Which means it has to decrease by 3 Hz. For it to decrease, it means that the force applied has to decrease as we have seen that frequency is directly proportional to the square root of the force acting on the string.

Thus, she would have to loosen the string.