What is the value of x?
K
83°
L
M
(9x + 40)

Answer:

5.7 feet i think

Step-by-step explanation:

Answer:

36 cubic inch

Step-by-step explanation:

The formula for the volume of a rectangular prism is:

[tex]V=whl[/tex]

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So:

6 × 3 × 2 = 36

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Have a good day :)

Answer:

1. 8.9

2. 14.5

3. 10.3

4. 18.8

5. 8.0

6. 15.0

(All to the nearest tenth)

The code is the sum of all missing sides

So adding all

=75.5

Answer:

160 cm i think

Step-by-step explanation:

Answer:

x = 9

Step-by-step explanation:

Of course I'll do very simple explanation!

every time you see a straight line (nondiagonal) it measures 180°.

so if we're trying to solve for x in this case, we'll subtract 180° - 40° = 140°.

Then use the statement to solve for x

[tex]10x+50=140[/tex]

[tex]10x-50[/tex] = - 50    Subtract 50 from both sides

[tex]10x[/tex]         [tex]=[/tex]  90     Divide 10 from both sides

x             =   9      

Answer:

θ = 0° , 60°

Step-by-step explanation:

[tex]\cos^2\theta + \sqrt{3}\sin \theta \cos \theta = 1[/tex]

[tex]=> \cos^2\theta + \sqrt{3}\sin \theta \cos \theta - 1 = 1 - 1[/tex]

[tex]=> \cos^2\theta + \sqrt{3}\sin \theta \cos \theta - 1 = 0[/tex]

[tex]=> (\cos^2 \theta - 1 )+ \sqrt{3} \sin \theta \cos \theta = 0[/tex]

[tex]=> -\sin^2 \theta + \sqrt{3} \sin \theta \cos \theta = 0[/tex]

[tex]=> \sin \theta(- \sin \theta + \sqrt{3}\cos \theta) = 0[/tex]

Now solve each part separately :-

1) [tex]\sin \theta = 0[/tex]

[tex]=> \theta = \sin^{-1}0 = 0[/tex]

2) [tex]-\sin \theta + \sqrt{3} \cos \theta = 0[/tex]

[tex]=> \frac{-\sin \theta + \sqrt{3}\cos \theta }{\cos \theta} = \frac{0}{\cos \theta}[/tex]

[tex]=> \frac{-sin \theta}{\cos \theta} + \frac{\sqrt{3} \cos \theta}{\cos \theta} = 0[/tex]

[tex]=> -\tan \theta + \sqrt{3} = 0[/tex]

[tex]=> -\tan \theta + \sqrt{3} + \tan \theta = 0 + \tan \theta[/tex]

[tex]=> \tan \theta = \sqrt{3}[/tex]

[tex]=> \theta = \tan^{-1}\sqrt{3} = 60[/tex]

∴ θ = 0° , 60°

Answer:

Solution given:

[tex] \large{ {cos}^{2} \theta + \sqrt{3} sin \theta cos \theta = 1}[/tex]

[tex] 1-sin^{2} \theta+\sqrt{3} sin \theta cos \theta = 1[/tex]

[tex] 1-1 +sin^{2}\theta=\sqrt{3} sin \theta cos \theta = 1[/tex]

[tex] Sin\theta(sin\theta -\sqrt{3}cos\theta)[/tex]

Either

[tex] sin\theta=\sqrt{3} cos \theta [/tex]

[tex] \sqrt{sin\theta}{cos \theta}=\sqrt{3} [/tex]

[tex] Tan \theta =\sqrt{3}[/tex]

[tex] Tan \theta =Tan 60,Tan(180+60),Tan (360+60)[/tex]

[tex] \theta =60°,240°,420°[/tex]

in terms of π is

[tex] \theta =⅓π,\frac{4}{3}π,[/tex]

Or

[tex] Sin\theta=1[/tex]

[tex]Sin\theta=Sin0° ,Sin180°[/tex]

In terms of π is

[tex]\theta=0π,π[/tex]

so

[tex]\theta=0π,⅓π,π,\frac{4}{3}π,[/tex]

Answer:

Interest amount = 239400

Step-by-step explanation:

Below is the calculation of interest amount:

Given the loan amount or present value = 630000

Time period  = 48 months or 4 years

Interest rate give = 9.5%

Total amount = P ( 1 + rt)

P = 630000

r = 9.5%

t = 4 years

Total amount = 630000 ( 1 + 9.5% x 4)

Total amount = 869,400

Interest amount = 869400 - 630000

Interest amount = 239400

9514 1404 393

Answer:

  ₹ 30000

Step-by-step explanation:

The simple interest formula is ...

  I = Prt . . . . . . principal P invested at rate r for t years

Fill in the values you know, and solve for the one you don't know.

  9000 = P(0.06)(5)

  9000/0.30 = P = 30000

The principal that will give ₹9000 in interest is ₹30000.

A =?

P= 9000

t = 5 yrs

r = 6% = 0.06

A = p(1+r)^t

A = 9000(1+0.06)⁵

A = 9000× 1.338

A = 12044 Rs.

Answer:

Sn = -9(1-(-3)^n)/4

Step-by-step explanation:

Since r < 1, the sum of nth term of a geometric sequence is expressed as;

Sn = a(1-r^n)/1-r

a is the first term

n is the number f terms

r is the common ratio

An = -9(1-(-3)^n)/1-(-3)

Sn = -9(1-(-3)^n)/4

Hence the sum of the nth term of the series is Sn = -9(1-(-3)^n)/4

Answer:

3.12mm= 31,2cm

3.12= 0.312m

3.12 = 0.000312km

Answer:

the answer is 6.8

Step-by-step explanation:

The computation is shown below:

Since we have to determined the 50th percentile play

So,

= 50(nth value) ÷ number of observations

= 50(nth value) ÷ 10

= 5th value

= 6.8

Hence the answer is 6.8

The same is to be considered and relevant

Answer:

x+2y=-3

x+2(-1)=-3

x-2=-3

x=-3+2

x=-1

Answer:

If it is:

1,089-4,445= -3,356

but if it is the other way:

4,445-1,089= 3,356

Hope it helped!

Answer:

Its a Subtraction problem

4445-1089

=3356

Answer:

3x - 4 =  32

2x =  24

5x + 10 = 70

4x - 8 = 40

Step-by-step explanation:

Please find the complete question in the attached image

Perimeter = sum of sides of the quadrilateral

166 = 4x - 8 + 5x + 10 + 2x + 3x - 4

166 = 14x - 2

combine like terms

166 + 2 = 14x

168 = 14x

x = 12

substitute for x in each of the sides

3x - 4 = 3(12) - 4 = 32

2x = 2 x 12 = 24

5x + 10 = 5(12) + 10 = 70

4x - 8 = 4(12) - 8 = 40

Answer:

[tex]y=\frac{1}{2}x-5[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

[tex]x-2y=6[/tex]

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

[tex]x-2y-x=6-x\\-2y=-x+6[/tex]

Divide both sides by -2

[tex]y=\frac{1}{2} x-3[/tex]

Now, we can identify clearly that the slope of the given line is [tex]\frac{1}{2}[/tex] since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of [tex]\frac{1}{2}[/tex] as well. Plug this into [tex]y=mx+b[/tex]:

[tex]y=\frac{1}{2}x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=\frac{1}{2}x+b[/tex]

Plug in the given point (-6,-8)

[tex]-8=\frac{1}{2}(-6)+b\\-8=-3+b[/tex]

Add 3 to both sides to isolate b

[tex]-8+3=-3+b+3\\-5=b[/tex]

Therefore, the y-intercept is -5. Plug this back into [tex]y=\frac{1}{2}x+b[/tex]:

[tex]y=\frac{1}{2}x-5[/tex]

I hope this helps!

Answer:

Tangent

Step-by-step explanation:

Given

[tex]\angle C = 50[/tex]

See attachment for complete question

Required

Function to calculate BC

If AB is known, BC is calculated as:

[tex]\tan(C) = \frac{AB}{BC}[/tex]

Substitute d for AB and 50 for C

[tex]\tan(50) = \frac{d}{BC}[/tex]

Make BC the subject

[tex]BC = d * \tan(50)[/tex]

Hence, BC can be found using tangent

Answer:

√7 / 4

Step-by-step explanation:

Trigonometrical identity are used to show the relationship between the sides and angles of a right angled triangle. Some trigonometric identities are:

sinΘ = opposite / hypotenuse, cosΘ = adjacent / hypotenuse, tanΘ = opposite / adjacent.

Given that cosΘ = 3 / 4

Therefore, cosΘ = adjacent / hypotenuse = 3 / 4

adjacent = 3, hypotenuse = 4. Let x be the opposite side, to get the opposite side, we use Pythagoras theorem:

opposite² + adjacent² = hypotenuse²

x² + 3² = 4²

x² + 9 = 16

x² = 7

x = √7

sinΘ = opposite/hypotenuse = √7 / 4

Answer:

no  x = -8/13

Step-by-step explanation:

6x – (3x + 8) = 16x

Combine like terms

6x -3x -8 = 16

3x-8 = 16

Subtract 3x from each side

3x-8-3x = 16-3x

-8 = 13x

Divide by 13

-8/13 = 13x/13

-8/13 =x

Answer:

No, the answer would be -8/13

Step-by-step explanation:

6x-(3x+8)=16x

6x-3x-8=16x

3x-16x=8

-13x=8

x=-8/13

Answer:

D is the answer

Step-by-step explanation:

Answer:

This is called a Trapezoidal prism

Number of faces: 5

Number of edges: 9

Number of vertices: 6

Hope this helps!!

Answer:

[tex] \frac{x + 7 }{x - 3} [/tex]

Step-by-step explanation:

First factorize both expressions

[tex] \frac{ {x }^{2} + 11x + 28 }{x { }^{2} + x - 12} \\ \frac{x {}^{2 } + 7x + 4x + 28 }{x { }^{2} + 4x - 3x - 12 } \\ \frac{x(x + 7) + 4(x + 7)}{x(x + 4) - 3(x + 4) } \\ \frac{(x + 7)(x + 4)}{(x + 4)(x - 3)} [/tex]

Now you can cross out x+4

and you'll be left with

[tex] \frac{x + 7}{x - 3} [/tex]

Answer:

C

Step-by-step explanation:

Answer:

C. (-5, -2)

Step-by-step explanation:

I used

x1 + / (x2 - x1), y1 + / (y2 - y1)

so

-7 + 1/5(3 - (-7)

-7 + 1/5 (10)

-7 + 10/5

-7 + 2 = -5 (X)

then

-4 + 1/5(6 - (-4)

-4 + 1/5(10)

-4 + 10/5

-4 + 2 = -2 (Y)

(-5, -2)

Answer:

Step-by-step explanation:

I used Pythagoras Theorem to find the diagonal distance as placement of objects is right angles triangle.

[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]

a : Elm street

b : Birch street

c : Diagonal distance

c^2 = a^2 + b^2

c^2 = 15^2 + 8^2

c^2 = 225 + 64

c = √289

c = 17 blocks

I added the total distance of the original route Joline took

= 15 blocks + 8 blocks

= 23 blocks

How much less distance does she have to walk if she took the diagonal route

= Total distance of original route - distance of diagonal route

= 23 - 17

= 6 blocks

Joline have to walk less 6 blocks if she took the diagonal route compared to her original route