Answer:
see below
Step-by-step explanation:
We need to write it on vertex form (f(x) = a(x - c)² + d where (c, d) is the vertex) and to do that we will complete the square.
f(x) = x² + 3x - 2
= (x² + 3x + 9/4) - 9/4 - 2
= (x + 1.5)² - 4.25
The vertex is (-1.5, -4.25).
at the rate of 15 per 6 oz. bar of chocolate, how much would a pound
Answer:
40
Step-by-step explanation:
We know there are 16 oz in a pound
We can use ratios
15 x
----- = ----------
6 oz 16 oz
Using cross products
15 * 16 = 6x
240 = 6x
divide by 6
240/6 = 6x/6
40 =x
2) The senior classes at High School A and High School B planned separate trips to the local
amusement park. The senior class at High School A rented and filled 2 vans and 14 buses with
294 students. High School B rented and filled 3 vans and 7 buses with 161 students. Each van
and each bus carried the same number of students. Find the number of students in each van and
in each bus.
A) Van: 9, Bus: 28 B) Van: 11, Bus: 27
C) Van: 20, Bus: 7 D) Van: 7, Bus: 20
Answer:
D) Van: 7, Bus: 20
Step-by-step explanation:
Add the amount of students together (455 students in total)
Then I added the amount of buses and vans together (5 Vans and 21 Buses)
Then I plugged in each answer
5 x 7 = 35
455 - 35 = 420
420 / 21 = 20
if a student is selected at random find the probability the student is a male given that it's a senior. Round to the nearest whole percent.
Answer: 40%.
Step-by-step explanation:
From the table : Total Seniors = 2+3= 5
Number of male seniors = 2
If a student is selected at random find the probability the student is a male given that it's a senior:
P(Male | senior)[tex]=\dfrac{\text{Number of male seniors}}{\text{Total seniors}}[/tex]
[tex]=\dfrac{2}{5}[/tex]
In percent, [tex]\dfrac{2}{5}\times100=40\%[/tex]
Hence, the probability the student is a male given that it's a senior. =40%.
The probability of the student is a male senior is 7%.
Given, here from the 2- way table the total no. students will be 30.
We have to find out the probability of the student select at random, student is a senior male .
We know that, the probability of an event E, will be
[tex]P(E)=\dfrac{No.\ of \ favaurable\ outcomes}{Total\ outcomes}[/tex]
Now,
[tex]P( Senior\ male)= \dfrac{2}{30} \\\\P( Senior\ male)=0.06\\[/tex]
Representing it in percentage as,
[tex]P( Senior\ male)=0.06666\times100\%\\P( Senior\ male=6.66\%[/tex]
Hence the nearest whole percent will be 7%.
Thus probability of the student is a male senior is 7%.
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The side length of an equilateral triangle is 6 cm. What is the height of the triangle? 2
Answer:
h=3√3 cm
Step-by-step explanation:
An equilateral triangle has 3 Equal sides
The height of an equilateral triangle with side a =a√3/2
That is,
h=a√3/2
Where,
h=height of the equilateral triangle
a=side length
From the triangle given,
a=6cm
Therefore,
h=6√3/2
=3√3
h=3√3 cm
can someone please help me
Answer:
B
Step-by-step explanation:
Because this equation is just a normal greater than symbol, it has to be a dotted line.
This graph starts at -2 and goes up 1 and right 3(this cancels out C as an option)
Than you shade the region with the larger number vaules, since it is greater than.
which of the graphs best represents f(x)= -2 cos 4x-1?
Answer:
see file attached
Step-by-step explanation:
WILL MARK BRAINLIEST!!! PLZ HELP!!! Which graph best represents the function f(x) = (x + 1)(x − 1)(x − 4)? I think it's D, but im not sure
Answer:
D
Step-by-step explanation:
Find the x intercepts from the equation and apply them to the graphs. It matches up with D. Your thought is correct
Answer:
[tex]\boxed{\mathrm{D}}[/tex]
Step-by-step explanation:
[tex]y= (x + 1)(x - 1)(x - 4)[/tex]
Let x = 0, find the y-intercept.
[tex]y= (0 + 1)(0 - 1)(0 - 4)[/tex]
[tex]y= ( 1)(- 1)(- 4)[/tex]
[tex]y=4[/tex]
The function crosses the y-axis at 4.
The only graph that shows this is graph D.
5x+4y=25 - (5x+2y=3)
Answer:
T1he values for x and y of the equations is y = 11, and x = -19/5.
Step-by-step explanation:
To solve this question, we need to rearrange the expression:
5x+4y=25 - (5x+2y=3)
Look, if we subtract one equation to the other, then:
5x+4y=25 [1]
-(5x+2y=3) [2]
Which is the same as:
5x+4y=25
-5x-2y=-3
Subtract them:
5x+4y=25
-5x-2y=-3
---------------
2y =22
y = 22/2 = 11
Then, y = 11.
To find x, we can substitute y in either equation [1] or [2].
Let us use [1]
5x+4y=25
5x+4(11)=25
5x+44=25
5x=25-44
5x=-19
x = -19/5
Then, the values for x and y of the equations is y = 11, and x = -19/5.
Which is the best estimate for the percent equivalent of 7 Over 15
Approximate what the value of [tex]7/15[/tex] is by using calculator.
[tex]7/15\approx0.47[/tex].
And now just multiply by 100 to get percentage.
[tex]100\cdot0.47=\boxed{47\%}[/tex].
Hope this helps.
Answer:
24%
Step-by-step explanation:
7\15 x 100
simplify and get=140\3
dived140\3=48\2
simplify 48\2=24%
3. Consider the sequence,-8, -5, -2, 1, ...
a) Determine the explicit formula for the general term, 1,, of this sequence in simplified
form. (2 marks)
b) Use this formula to determine the value of t20. (1 mark)
c) Algebraically determine which term has a value of 40. (1 mark)
Answer:
a) [tex]a_n=3\,n-11[/tex]
b) [tex]a_{20}=49[/tex]
c) term number 17 is the one that gives a value of 40
Step-by-step explanation:
a)
The sequence seems to be arithmetic, and with common difference d = 3.
Notice that when you add 3 units to the first term (-80, you get :
-8 + 3 = -5
and then -5 + 3 = -2 which is the third term.
Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:
[tex]a_n=a_1+(n-1)\,d[/tex]
That in our case would give:
[tex]a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11[/tex]
b)
Therefore, the term number 20 can be calculated from it:
[tex]a_{20}=3\,(20)-11=60-11=49[/tex]
c) in order to find which term renders 20, we use the general form we found in step a):
[tex]a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17[/tex]
so term number 17 is the one that renders a value of 40
Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0. x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals 5 plus or minus the square root of 33, all over 2 x equals negative 5 plus or minus the square root of 33, all over 2 x equals 5 plus or minus the square root of 17, all over 2 x equals negative 5 plus or minus the square root of 17, all over 2
Answer:
x = [ -b +- sqr root (b^2 - 4ac)] / 2a
a = 1
b = -5
c = -2
x = [- - 5 +- sqr root (-5^2 -4 * 1 * -2)] / 2 * 1
x = [5 +- sqr root (25 + 8)] / 2
x1 = 5.3723
x2 =-0.37228
Step-by-step explanation:
Exact solution for the give quadratic equation are
[tex]x=\frac{5+\sqrt{33}}{2},\:x=\frac{5-\sqrt{33}}{2}[/tex]
Quadratic EquationQuadratic equation of the form [tex]ax^2+bx+c=0[/tex]
For any quadratic equation we get two values for x. we can find the values for x by applying quadratic formula .
Quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
Given equation is [tex]x^2-5x-2=0[/tex]
The value of a=1, b= -5 and c=-2
Substitute all the values in the formula.
To find out exact solutions , we need to simplify the final answer.
Exact solutions are without any decimals.
[tex]x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}\\x=\frac{-\left(-5\right)\pm \sqrt{33}}{2\cdot \:1}\\x=\frac{-\left(-5\right)\p+ \sqrt{33}}{2\cdot \:1}\\\\x=\frac{5+\sqrt{33}}{2}\\\\x=\frac{-\left(-5\right)- \sqrt{33}}{2\cdot \:1}\\\\x=\frac{5-\sqrt{33}}{2}\\[/tex]
Exact solutions are
[tex]x=\frac{5+\sqrt{33}}{2},\:x=\frac{5-\sqrt{33}}{2}[/tex]
Learn more information about 'Quadratic formula ' here
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HELP ME PLEASSSSEE On a winter morning, the temperature before sunrise was -10℉. The temperature then rose by 1℉ each hour for 7 hours before dropping by 2℉ each hour for 3 hours. What was the temperature, in degrees Fahrenheit, after 10 hours?
Answer:
3 degrees F
Step-by-step explanation:
if the temperature rose 1* for 7 hours, times 1 by 7. which is 7 and add to -10. which is -3. then, since the temperature rose by 2* for 3 hours, times 2 by 3 which is 6 and add to -3, which is 3.
i hope this helped?
What is the area of this polygon?
Enter your answer in the box.
units2
Answer:
39 units²
Step-by-step explanation:
The figure is composed of a rectangle VEDR and Δ RMV
Area of rectangle = VE × ED = 5 × 6 = 30 units²
Area of Δ = 0.5 × RV × perpendicular from M to RV
= 0.5 × 6 × 3 = 9 units²
Thus
Area of polygon = 30 + 9 = 39 units²
Zhi bought 18 tickets for games at a fair. Each game requires 3 tickets. Zhi wrote the expression 18 – 3g to find the number of tickets she has left after playing g games. Diego correctly wrote another expression, 3(6 – g), that will also find the number of tickets Zhi has left after playing g games. Use the drop-down menus to explain what each part of Zhi's and Diego's expressions mean.
Answer: In zhi's equation, the 18 is the initial amount of tickets, and the 3g means 3 times the amount of games.
Diegos equation is the same, but write in factorised form. The 3 multiplies with the 6 to create 18, and the 3 multiple with the g to create 3g
Hey loves. Again, needing help with a math question.When will this end? Never, or at least until I get it.:). Help is much appreciated
Answer:
Hey there!
SL=KR
We can't prove that the triangles are congruent, but since SL=SK+KL, and KR=RL+LK. We have RL=SK, so we have two lines:
SL=SK+KL
KR=SK+KL
These are clearly congruent, making these two lines congruent.
Hope this helps :)
Please can someone help
Answer:
a) 0
b) 1
c) 0
Step-by-step explanation:
These are common values from the unit circle but you could also just check with your calculator. Just be sure to set it to degree mode and not radian mode.
Given the function [tex]h:x=px-\frac{5}{2}[/tex] and the inverse function [tex]h^{-1} :x=q+2x[/tex], where p and q are constants, find a) the value of p and q c)[tex]h^{-1} h(-3)[/tex]
Answer:
[tex]p = \frac{1}{2}[/tex]
[tex]q = 5[/tex]
[tex]h^{-1}(h(3)) = 3[/tex]
Step-by-step explanation:
Given
[tex]h(x) = px - \frac{5}{2}[/tex]
[tex]h^{-1}(x) = q + 2x[/tex]
Solving for p and q
Replace h(x) with y in [tex]h(x) = px - \frac{5}{2}[/tex]
[tex]y = px - \frac{5}{2}[/tex]
Swap the position of y and d
[tex]x = py - \frac{5}{2}[/tex]
Make y the subject of formula
[tex]py = x + \frac{5}{2}[/tex]
Divide through by p
[tex]y = \frac{x}{p} + \frac{5}{2p}[/tex]
Now, we've solved for the inverse of h(x);
Replace y with [tex]h^{-1}(x)[/tex]
[tex]h^{-1}(x) = \frac{x}{p} + \frac{5}{2p}[/tex]
Compare this with [tex]h^{-1}(x) = q + 2x[/tex]
We have that
[tex]\frac{x}{p} + \frac{5}{2p} = q + 2x[/tex]
By direct comparison
[tex]\frac{x}{p} = 2x[/tex] --- Equation 1
[tex]\frac{5}{2p} = q[/tex] --- Equation 2
Solving equation 1
[tex]\frac{x}{p} = 2x[/tex]
Divide both sides by x
[tex]\frac{1}{p} = 2[/tex]
Take inverse of both sides
[tex]p = \frac{1}{2}[/tex]
Substitute [tex]p = \frac{1}{2}[/tex] in equation 2
[tex]\frac{5}{2 * \frac{1}{2}} = q[/tex]
[tex]\frac{5}{1} = q[/tex]
[tex]5 = q[/tex]
[tex]q = 5[/tex]
Hence, the values of p and q are:[tex]p = \frac{1}{2}[/tex]; [tex]q = 5[/tex]
Solving for [tex]h^{-1}(h(3))[/tex]
First, we'll solve for h(3) using [tex]h(x) = px - \frac{5}{2}[/tex]
Substitute [tex]p = \frac{1}{2}[/tex]; and [tex]x = 3[/tex]
[tex]h(3) = \frac{1}{2} * 3 - \frac{5}{2}[/tex]
[tex]h(3) = \frac{3}{2} - \frac{5}{2}[/tex]
[tex]h(3) = \frac{3 - 5}{2}[/tex]
[tex]h(3) = \frac{-2}{2}[/tex]
[tex]h(3) = -1[/tex]
So; [tex]h^{-1}(h(3))[/tex] becomes
[tex]h^{-1}(-1)[/tex]
Solving for [tex]h^{-1}(-1)[/tex] using [tex]h^{-1}(x) = q + 2x[/tex]
Substitute [tex]q = 5[/tex] and [tex]x = -1[/tex]
[tex]h^{-1}(x) = q + 2x[/tex] becomes
[tex]h^{-1}(-1) = 5 + 2 * -1[/tex]
[tex]h^{-1}(-1) = 5 - 2[/tex]
[tex]h^{-1}(-1) = 3[/tex]
Hence;
[tex]h^{-1}(h(3)) = 3[/tex]
HELLLLLLPPPPPP MEEEE PLEASEEEEE!!!!!! Find the times (to the nearest hundredth of a second) that the weight is halfway to its maximum negative position over the interval . Solve algebraically, and show your work and final answer in the response box. Hint: Use the amplitude to determine what y(t) must be when the weight is halfway to its maximum negative position. Graph the equation and explain how it confirms your solution(s).
Answer:
0.20, 0.36 seconds
Step-by-step explanation:
We have already seen that the equation for y(t) can be written as ...
y(t) = √29·sin(4πt +arctan(5/2))
The sine function will have a value of -1/2 for the angles 7π/6 and 11π/6. Then the weight will be halfway from its equilibrium position to the maximum negative position when ...
4πt +arctan(5/2) = 7π/6 or 11π/6
t = (7π/6 -arctan(5/2))/(4π) ≈ 0.196946 . . . seconds
and
t = (11π/6 -arctan(5/2))/(4π) ≈ 0.363613 . . . seconds
The weight will be halfway from equilibrium to the maximum negative position at approximately 0.20 seconds and 0.36 seconds and every half-second thereafter.
The equation of line l is -3y+4x=9 Write the equation of a line that is parallel to line l and passes through the point (-12,6). a) -3y+4x-69=0 b)-3y+4x-69=0 c)-3y+4x-39=0 d) 3x-3y+66=0
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
- 3y + 4x = 9
3y = 4x - 9
Divide both sides by 3
y = 4/3x - 3
Comparing with the above formula
Slope / m = 4/3
Since the lines are parallel their slope are also the same
So slope of the parallel line l is also 4/3
Equation of the line using point (-12 , 6) is
y - 6 = 4/3(x + 12)
Multiply through by 3
That's
3y - 18 = 4(x + 12)
3y - 18 = 4x + 48
We have the final answer as
4x - 3y + 66 = 0Hope this helps you
Hassan built a fence around a square yard. It took 48 m^2 of lumber to build the fence. The fence is 1.5 meters tall.
Answer:
Step-by-step explanation:
Please check ones more because this might be incorrect.
The area is in square meters...Let's change it
Square 48= 48*48 =2304
2304 divided by 4( 4 since the formula for the area of a sqaure is s*s and square has 4 sides)
2304 divided by 4 = 576
The formula for area of a square is S*S(side times side)
Let's apply the formula here.
so, 576 times 576
331776 square meters
Hope this is right and helps! :)
( This just my point of view. Please check this onces again)
Answer:
the answer is 64
Step-by-step explanation:
khan
ASAP!!! PLEASE help me solve this question! No nonsense answers, and attach solutions please.
Answer:
2<F(x)<5
Step-by-step explanation:
We can guess that it come between 2 and 5 given the pattern that we see in the table, but there’s no reason we can’t solve it to be sure.
F(x)=3 (Times the square root of 1.5-1)+2
3(square root of .5)+2
3(0.7)+2
2.12+2
4.12
So, yes, it is between 2 and 5
2<F(x)<5
Taylor had \$147$147dollar sign, 147. Then she spent \$42$42dollar sign, 42 on sneakers. Then, Taylor earned \$53$53dollar sign, 53 by winning a race in her new sneakers! Estimate how much money Taylor has left
Answer:
She has 158 dollars.
Step-by-step explanation:
This problem tells us that originally Taylor had 147 dollars, but she spent 42 dollars on sneakers, thus she now has [tex]147-42 = 105[/tex] dollars. However, she later won a race wearing those sneakers and earned 53 dollars, therefore she now has [tex]105 + 53 = 158[/tex] dollars.
Thus, Taylor has 158 dollars left now.
Exercise topic: Permutations and Combinations. A company wants to hire 3 new employees, but there are 8 candidates, 6 of them which are men and 2 are women. If the selection is random: a) In how many different ways can choose new employees? b) In how many different ways can choose a single male candidate? c) In how many different ways can choose at least one male candidate? with procedures. Help me please..
Answer:
(a) 56 ways
(b) 6 ways
(c) 56 ways
Step-by-step explanation:
Given:
candidates: 6 mail, 1 female
number to hire : 3
a) In how many different ways can choose new employees?
use the combination formula to choose r to hire out of n candidates
C(n,r) = C(8,3) = 8! / (3! (8-3)! ) = 40320 / (120*6) = 56 ways
b) In how many different ways can choose a single male candidate?
6 ways to choose a male, one way to choose two female, so 6*1 = 6 ways
c) In how many different ways can choose at least one male candidate?
To choose at least 1 male candidate, we subtract the ways to choose no male candidates out of 56.
Since there are only two females, there is no way to choose 3 female candidates.
In other words, there are 56-0 = 56 ways (as in part (a) ) to hire 3 employees with at least one male candidate.
3x (4x^2 + 4xy + 5y - 6) = ?
Answer:
12x^3 + 12x^2y + 15xy - 18x
Step-by-step explanation:
I simply expanded the equation by multiplying everything in the parentheses by 3x.
Answer:
12x^3+12x^2y+15xy-18x
Step-by-step explanation:
3x (4x^2 + 4xy + 5y - 6)
Distribute
3x *4x^2 +3x* 4xy + 3x*5y -3x* 6
12x^3+12x^2y+15xy-18x
Please help! "Create a real-life scenario involving an angle of elevation or depression. Draw an appropriate diagram and explain how to solve your example."
Answer:
Height of the kite = 86.60 meter (Approx)
Step-by-step explanation:
The angle of elevation to see a kite from a stone lying to the ground is 60 degrees. If a thread is tied with a kite and a stone, then that thread is 100 meters long, find the height of the kite.
Given:
Length of thread = 100 meter
Angle of elevation = 60°
Find:
Height of the kite.
Computation:
Using trigonometry application:
Height of the kite / Length of thread = Sin 60°
Height of the kite / 100 = √3 / 2
Height of the kite = [√3 / 2]100
Height of the kite = 50√3
Height of the kite = 86.60 meter (Approx)
Which is the correct algebraic expression after combining like terms? 6 + 8 x minus 7 minus x 7 x minus 1 7 x + 13 9 x minus 1 9 x + 13
Answer:
7x-1
Step-by-step explanation:
i did the test
Answer:
7x-1
Step-by-step explanation:
correct answer on edge
Which describes how to graph g (x) = RootIndex 3 StartRoot x minus 5 EndRoot + 7 by transforming the parent function?
Answer:
[tex]f(x) =\sqrt[3]{x}[/tex]
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
[tex]g(x) = \sqrt[3]{x-5}+7[/tex]
To have the the parent function, we must find the parent one, let's call it by f(x).
[tex]f(x) =\sqrt[3]{x}[/tex]
This function satisfies the Domain of the given one, because the Domain is still [tex](-\infty, \infty)[/tex] and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
Answer:
5 units to the right and 7 units up (B on edge)
Step-by-step explanation:
Jordon will play a triangle at his school’s music program. As its name suggests, the musical instrument is shaped like a triangle. Jordon has customized the dimensions to produce a unique melody, which is played when the shortest side is hanging down, parallel to the ground. Which side of the musical instrument should be parallel to the ground if its dimensions are as shown in the diagram?
Answer:
A. AB
Step-by-step explanation:
Given that the musical instrument has a shape of ∆ABC, we can determine the shortest side that would be parallel to the ground by comparison of the 3 angles of the triangle corresponding to each side that is opposite each of them.
What this means is that, the larger angle would have the largest side opposite it. The medium angle will have medium length side opposite it, while the smallest angle will have the smallest side opposite it.
m < A = 59°
m < C = 57°
m < C = 180 - (59+57) (sum of angles in a triangle)
m < C = 64°
The smallest angle out of the three angles is angle C = 57°.
The side opposite it, is side AB.
Side AB is the shortest side of ∆ABC.
Therefore, AB should be parallel to the ground.
The
side
of the musical instrument that should be parallel to the ground if the
dimensions
are as given is side AB, which is option A.
Given that:
Jordon will play a
triangle
in his school’s music program.
When playing, the shortest side
is hanging down,
parallel
to the ground.
From the figure:
m∠A = 59°
m∠C = 57°
By the
angle sum
property,
m∠A + m∠B + m∠C = 180°
59° + m∠B + 57° = 180°
m∠B + 116° = 180°
m∠B = 180° - 116°
= 64°
The
shortest side
will be the side that is opposite to the smallest angle.
So, the smallest side is the side opposite to C.
So, the side is AB.
Hence, the side is AB, which is option A.
Learn more about
Triangles
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Which glide reflection describes the mapping ABC DEF. This is practice for me plz, give answer with explanation. Non-sense answer will get reported
Answer:
c. translation (x,y) -> (x-4, y-1) followed by reflection about y=0
Step-by-step explanation:
The strategy is to translate B to E then reflect about the x-axis (y=0)
From B to E, the process is
(x,y) -> (x-4, y-1)
Therefore it is a translation (x,y) -> (x-4, y-1) followed by reflection about y=0
These tables of values represent continuous functions. For which function will the y-values be the greatest for very large values of x?
Answer:
The table D represents the function that will have the greatest y-values for very large values of x.
Step-by-step explanation:
The table A represents a linear function, for which each one unit increment in the "x" variable produces a three unit increment in the "y" variable. This means that the growth rate of this function is 3.
The table B also represents a linear function, for which each one unit increment in the x variable produces a 100 unit increment in the y variable. This means that the growth rate of this function is 100.
The table C also represents a linear function, for which each one unit increment in the x variable produces a 10 unit increment in the y variable. This means that the growth rate of this function is 10.
The table D on the other hand does not represent a linear function, since the growth rate is variable and increases for greater values of x. This means that as x grows larger, the growth rate of the function also grows larger, resulting in a much greater y value for very large x values if we compare it to a linear function, like the other options.
Answer:
D
Step-by-step explanation:
BIGBRAIN