Answer:
There is no graph i can aswer it soww
Explanation:
Some types of bacteria contain chains of ferromagnetic particles parallel to their long axis. The chains act like small bar magnets that align these magnetotactic bacteria with the earth's magnetic field. In one experiment to study the response of such bacteria to magnetic fields, a solenoid is constructed with copper wire, 1.0 mmmm in diameter, evenly wound in a single layer to form a helical coil of length 40 cmcm and diameter 12 cmcm. The wire has a very thin layer of insulation, and the coil is wound so that adjacent turns are just touching. The solenoid, which generates a magnetic field, is in an enclosure that shields it from other magnetic fields. A sample of magnetotactic bacteria is placed inside the solenoid. The torque on an individual bacterium in the solenoid’s magnetic field is proportional to the magnitude of the magnetic field and to the sine of the angle between the long axis of the bacterium and the magnetic-field direction.
What current is needed in the wire so that the magnetic field experienced by the bacteria has a magnitude of 150μT?
a. 0.095 A
b. 0.12 A
c. 0.30 A
d. 14 A.
Answer:
the required current is 0.12 A
Option b) 0.12 A is the correct answer
Explanation:
Given the data in the question,
to determine the current needed in the wire, we use the following relation;
B = μ₀n[tex]I[/tex]
[tex]I[/tex] = B / μ₀n
where μ₀ is the magnetic constant ( 4π × 10⁻⁷ T.m/A )
n is the number of turns ( 1 / 1mm[tex]\frac{10^{-3}m}{1 mm}[/tex]) = 1000 m⁻¹
B is magnitude ( 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) )
so we substitute
[tex]I[/tex] = [ 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) ] / [ ( 4π × 10⁻⁷ T.m/A ) × 1000 m⁻¹ ]
[tex]I[/tex] = [ 0.00015 ] / [ 0.00125 ]
[tex]I[/tex] = 0.12 A
Therefore, the required current is 0.12 A
Option b) 0.12 A is the correct answer
which is an example of a scientist using a mathematical model to describe the weather?
A. The scientist finds an equation that predicts how long a rainstorm will last.
B. The scientist says that a lightning bolt is like a long snake.
C. The scientist uses cotton balls to represent clouds, and grass to represent the ground.
D. The scientist thinks of a cloud as a giant ball of cotton candy.
(its A)
Answer:
The scientist finds an equation that predicts how long the rainstrom will last.
Explanation:
I just answered it :)
A particle of ink in a ink-jet printer carries a charge of -8x 10^-13 C and is deflected onto paper force of 3.2x10^-4. Find the strength of the electric field
A ray of laser light strikes a glass surface at an angle a=25.0° tot he normal and it is refracted to an angle b=18.5° to the normal. What is the index of refraction nb for this type of glass? Na=1.00
A. 3.26
B. 3.52
C. 1.32
D. 1.89
Answer:
1.33
Explanation:
According to snell's law,
n = sin(a)/sin(b)
Given
a = 25.0°
b = 18.5°
Substitute
n = sin25/sin18.5
n = 0.4226/0.3173
n = 1.33
Hence the index of refraction nb for this type of glass is 1.33
help pls thx!!!!!!!
this is my last question i hope!
Answer:
Left
Explanation:
newtons is a measure of force. Since there is more newtons(force) pushing to the left, the object will move left. the 15 newtons cancel each other out, leaving only 5 newtons pushing to one side with no resistance.
Which of the following is the most important difference between a permanent magnet and a electromagnet
Answer:
Explanation: the major difference between an electromagnet and permanent magnet is that the former can have a magnetic field when electric current flows through it and disappears when the flow of the current stops. ... It will always displays the magnetic behaviour.
Why did the “yielders” conform in Asch’s experiment?
Answer:
Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.
A vertical spring scale can measure weights up to 225 N . The scale extends by an amount of 12.5 cm from its equilibrium position at 0 N to the 225 N mark. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.65 Hz. Ignoring the mass of the spring, what is the mass m of the fish?
Answer:
The mass of the fish is 6.493 kilograms.
Explanation:
The spring-mass system experiments a Simple Harmonic Motion, then the angular frequency ([tex]\omega[/tex]), in radians per second, is determined by the following equation:
[tex]\omega = 2\pi\cdot f[/tex] (1)
Where [tex]f[/tex] is the frequency, in hertz.
In addition, the mass of the fish ([tex]m[/tex]), in kilograms, is:
[tex]m = \frac{k}{\omega^{2}}[/tex] (2)
Where [tex]k[/tex] is the spring constant, in newtons per meter.
And the spring constant is determined by Hooke's Law:
[tex]k = \frac{F}{\Delta x}[/tex] (3)
Where:
[tex]F[/tex] - Elastic force, in newtons.
[tex]\Delta x[/tex] - Spring elongation, in meters.
If we know that [tex]F = 225\,N[/tex], [tex]\Delta x = 0.125\,m[/tex] and [tex]f = 2.65\,hz[/tex], then the mass of the fish is:
[tex]\omega = 2\pi\cdot f[/tex]
[tex]\omega \approx 16.650\,\frac{rad}{s}[/tex]
[tex]k = \frac{F}{\Delta x}[/tex]
[tex]k = 1800\,N[/tex]
[tex]m = \frac{k}{\omega^{2}}[/tex]
[tex]m = 6.493\,kg[/tex]
The mass of the fish is 6.493 kilograms.
This question involves the concepts of Hooke's Law, and the frequency of spring-mass system.
The mass of the fish is "6.5 kg".
First, we will calculate the angular speed of the system:
[tex]\omega=2\pi f[/tex]
where,
ω = angular speed = ?
f = frequency = 2.65 Hz
Therefore,
[tex]\omega = 2\pi(2.65\ Hz)\\\omega = 16.65\ rad/s\\[/tex]
Now, we will use the Hooke's Law to find out the spring constant of the spring:
[tex]K =\frac{F}{\Delta x}[/tex]
where,
K = spring constant = ?
F = force applied = maximum weight = 225 N
Δx = extension = 12.5 cm = 0.125 m
Therefore,
[tex]k=\frac{225\ N}{0.125\ m}\\\\k = 1800\ N/m\\[/tex]
Now, we will use the formula for the angular speed of a spring-mass system to find out the mass of the fish:
[tex]\omega = \sqrt{\frac{k}{m}}\\\\m = \frac{k}{\omega^2}\\\\m=\frac{1800\ N/m}{(16.65\ rad/s)^2}[/tex]
m = 6.5 kg
Learn more about Hooke's Law here:
brainly.com/question/13348278?referrer=searchResults
The attached picture illustrates Hooke's Law.
Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the water’s surface to knock them into the water, where the fish can eat them. A 65-g fish at rest just at the surface of the water can expel a 0.30-g drop of water in a short burst of 5.0 ms. High-speed measurements show that the water has a speed of 2.5 m/s just after the archerfish expels it. What is the average force the fish exerts on the drop of water?
(a) 0.00015 N;
(b) 0.00075 N;
(c) 0.075 N;
(d) 0.15 N.
Answer:
(d) 0.15 N
Explanation:
mass of the fish, m₁ = 65 g = 0.065 kg
initial velocity of the fish, u₁ = 0
mass of water expelled by the fish, m₂ = 0.30 g = 0.0003 kg
time during which the water was expelled, t = 5.0 ms = 5.0 x 10⁻³ s
velocity of the water, v = 2.5 m/s
The magnitude of force of the exerted water is equal to the magnitude of force the fish exerted on the water.
The magnitude of force of the exerted water is calculated as follows;
[tex]F = ma = m\frac{v}{t} \\\\F = \frac{mv}{t} \\\\F = \frac{m_2 \ \times \ v}{t} \\\\F = \frac{0.0003 \ \times \ 2.5}{5 \times 10^{-3}} \\\\F = 0.15 \ N[/tex]
The correct option is D.
Therefore, the average force the fish exerts on the drop of water is 0.15 N.
Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV reciever consisting of a circular dish of radius RRR which focuses the electromagnetic energy incident from the satellite onto a receiver which has a surface area of 5 cm2cm2. How large does the radius RRR of the dish have to be to achieve an electric field vector amplitude of 0.1 mV/mmV/m at the receiver
Answer:
R₁ = 0.126 m
Explanation:
Let's use the definition of intensity which is the power per unit area
I = P / A
the generated power is constant
P = I A
power is
P = E / t
if we perform the calculations for a given time, the wave energy is
E = q V
we substitute
P = [tex]\frac{q V\ A}{t}[/tex]
we can write this equation for two points, point 1 the antenna and point 2 the receiver
V₁A₁ = V₂A₂
A₁ = [tex]\frac{V_2}{V_1} \ A_2[/tex]
A₁ = 0.1 10⁻³ 5 10⁻⁴ /V₁
A₁ = 5 10⁻⁸ /V₁
In general, the electric field on the antenna is very small on the order of micro volts, suppose V₁ = 1 10⁻⁶ V
let's calculate
A₁ = 5 10⁻⁸ / 1 10⁻⁶
A₁ = 5 10⁻² m²
the area of a circle is
A = π r²
we substitute
π R1₁²= 5 10⁻²
R₁ = [tex]\sqrt{ \frac{5 \ 10^{-2} }{\pi } }}[/tex]
R₁ = 0.126 m
So the the greater the height, the
farther something can fall, the greater
the potential energy.
True
False
10 You are given the following list of vo-
lumes: 0.45 m3; 375 cm3; 75 cL; 0.6 dm3.
a. Express all the volumes of the list in
liters.
b. Arrange these volumes in a descending
order.
Volumes can be transfered to liters only when their measurement units are dm³. a) Which means that: 0.45m³=450dm³ you move the decimal place three places to the right because m³ is larger measurement unit than dm³. 375 cm³ = 0.375 dm³; 75cl = 0.75l because of the prefix centi. 0.6dm³ = 0.6 dm³
So it will be 450l; 0.375l; 0.75l; 0.6l
b) 450l>0.75l>0.6l>0.375l
0.45m³>75cl>0.6dm³>375cm³
I hope i didn't make a mistake, but it would be good if somebody else answered too, so you can compare the answers and see if i made a mistake
The given volumes in liter will be 450 L, 0.375 L, 0.75 L, 0.6 L and the arrangement in descending order will be 450 L > 0.75 L > 0.6 L > 0.37 L .
What is Volume?Every three-dimensional item takes up space in some way. The volume of this area is what is used to describe it. The area covered within an entity's three-dimensional bounds is referred to as its volume. The object's size is another name for it.
As per the given information in the question,
a.
The given volume in a meter cube is 0.45.
Unit conversion:
1 m³ = 1000 L
So, 0.45 m³ = 0.45 × 1000
= 450 L
The given volume in a centimeter cube is 375.
Unit conversion:
1 cm³ = 0.001 L
375 cm³ = 0.001 × 375
= 0.375 L.
The given volume in a centiliter cube is 75.
Unit conversion:
1 cl³ = 0.01 L
75 cl³ = 75 × 100
= 0.75 L
The given volume in the decimeter cube is 0.6.
1 dm³ = 1 L
0.6 dm³ = 0.6 L
b.
So, the volumes in descending order will be,
450 L > 0.75 L > 0.6 L > 0.37 L or,
0.45 m³ > 75 cl³ > 0.6 dm³ > 375 cm³
To know more about Volume:
https://brainly.com/question/13338592
#SPJ2
The ratio of the elements in a binary ionic compound are based on the element's ________________.
Answer:oxidation number
Explanation:
i just took quiz;)
The ratio of the elements in a binary ionic compound are based on the element's oxidation number.
What is Oxidation number?Oxidation number can be generally described as the number which is allocated to the chemical elements in a chemical combination of different compounds. The oxidation number of an element is basically the number or count of electrons that atoms in a molecule can share, lose or gain while they are forming chemical bonds with the other atoms of a different element or atom.
The oxidation state, or oxidation number is the hypothetical charge which is present on an atom if all of the bonds in an atom to different atoms were fully ionic in nature. Oxidation state describes the degree of oxidation of an atom in a chemical compound or molecule. The oxidation state may be positive, negative or zero depending upon the loss or gain of electrons.
Learn more about Oxidation number here:
https://brainly.com/question/29263066
#SPJ2
o reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD
Complete question
To reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD=0.3 for a passenger car.
Answer:
22.22%
$57
Explanation:
From the question we are told that
Initial area of frontal area [tex]a_1=18ft^2[/tex]
Final area of frontal area [tex]a_2=14ft^2[/tex]
Distance covered a year [tex]D=12000mile[/tex]
Average speed a year [tex]V_{avg}=55mile/h[/tex]
Density [tex]\rho=50 lbm/ft3[/tex]
Price [tex]P= $3.10/gal[/tex]
Density of air [tex]\rho_{air} 0.075 lbm/ft3[/tex]
Heating value of gasoline [tex]Q=20,000 Btu/lbm[/tex]
Efficiency [tex]\eta=30\%[/tex]
Drag coefficient [tex]CD=0.3[/tex]
[tex]\triangle A=18-14ft^2=4ft^2[/tex]
Generally the equation for drag force [tex]C_D[/tex] is mathematically given as
[tex]F_D=\frac{C_DAPV^2}{2}[/tex]
[tex]F_D=\frac{0.3*18*0.075*(80.685^2)*A}{2}[/tex]
[tex]F_D=73.24Alb[/tex]
where [tex]v=55mil/h*1.467=80.685ft/s[/tex]
Generally the equation for work done W is mathematically given as[tex]W=F_D*L[/tex]
where [tex]L=12000mile*5280[/tex]
[tex]L=63360000[/tex]
[tex]W=73.24A*63360000[/tex]
[tex]W=4.6*10^9A[/tex]
Generally the equation for overall efficiency [tex]\eta[/tex] is mathematically given as
where
[tex]W_{req}=required\ gasoline\ power\ efficiency[/tex]
[tex]\eta=\frac{W}{W_{req}}[/tex]
[tex]W_{req}=\frac{W}{\eta}[/tex]
[tex]W_{req}=\frac{4.6*10^9}{0.3}[/tex]
[tex]W_{req}=1.55*10^{10}A[/tex]
Generally the equation for reduction fee with change in frontal area [tex]\triangle M[/tex] is mathematically given as
[tex]\triangle M =\triangle Vgasoline*cost[/tex]
Where
[tex]\triangle Vgasoline= volume\ reduction\ of\ gasoline[/tex]
[tex]\triangle Vgasoline=\frac{E_{req}}{H*P}[/tex]
[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]
if
[tex]20000btu/ibm=20000*778.169*32.2(1bm.ft^2/s)[/tex]
[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]
[tex]\triangle Vgasoline=0.61859A[/tex]
Therefore
[tex]\triangle M =0.61859A*3.10[/tex]
if [tex]1ft^2=7.48gal[/tex]
[tex]\triangle M =0.61859(4)*3.10*7.48[/tex]
[tex]\triangle M = \$ 57.671[/tex]
Generally the equation for reduction of fuel [tex]F_r[/tex]is mathematically given as
[tex]F_r=\frac{\triangle A}{\triangle i}*100[/tex]
where
[tex]\triangle i=18ft^2[/tex]
[tex]F_r=\frac{4}{18}*100[/tex]
Fuel reduction price by reducing front area is 22.22%
Money saved per year is $57
Which wave has the longest wavelength?
A. A
B. B
C. C
D.D
Answer:
In my opinion, ''A" would be the longest wavelength.
PLEASE HELP ME IN THE QUESTION ALSO! because I didn't understand
Answer:
3.69 m/s²
Explanation:
weight = mass × Acceleration of gravity
479.96 = 129.72 × Acceleration of gravity
Acceleration of gravity = 479.96/129.72 = 3.69 m/s²
Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?
The wavelength of this radio signal is equal to 3.18 meters.
Given the following data:
Frequency = [tex]9.45 \times10^7[/tex] Hz.Speed of light = [tex]3 \times 10^8[/tex] m/s.What is wavelength?Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.
How to calculate wavelength.Mathematically, the wavelength of a wave is given by this formula:
[tex]\lambda = \frac{V}{F}[/tex]
Where:
F is the frequency of a wave.V is the speed of a sound wave.[tex]\lambda[/tex] is the wavelength of a sound wave.Substituting the given parameters into the formula, we have;
[tex]\lambda = \frac{3 \times 10^8}{9.45 \times10^7}[/tex]
Wavelength = 3.18 meters.
Find more information on waves here: brainly.com/question/23460034
The wavelength of the radio signal travel at speed of light is 3.17m.
Given the data in the question;
Frequency of the radio wave; [tex]f = 9.45 * 10^{7}Hz = 9.45 * 10^{7} s^{-1}[/tex]Wavelength of a radio signal; [tex]\lambda = \ ?[/tex]WavelengthWavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( [tex]c = 3*10^8m/s[/tex] )
We substitute our values into the expression above.
[tex]\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m[/tex]
Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.
Learn more about wavelength: brainly.com/question/16776907
If a gas turned into a solid without going through the liquid state and how do you reverse it?
Answer:
put it in a volcano
Explanation:
4 points
Bonus: We know that a huge star went supernova in our area a long time
ago because of the large amount of
on earth.
Water
Oxygen
Iron
Carbon
Answer: i may not be 100% accurate but i believe it is iron, there is a fire work that uses iron to shine a certain way and is found on stars.
what energy does a spillway produce?
Answer: Energy dissipation
As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base).
HOPE THIS HELPS
Answer: Energy dissipation
Explanation: As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base). Hope this helps. Can u give me brainiliest
Calculate the force of an object that has a mass of 10kg and an acceleration of 4m/s²
A-40N
B-8N
C-2.5N
D-0.4N
A Newtonian fluid with a viscosity drains through the space between two large parallel plates as shown in the figure. The gap distance between the plates is 2b. Obtain relations for the shear stress distribution, shear stress at the walls, velocity profile and volumetric flow rate assuming laminar flow and negligible end effects. You can begin the derivations by considering that vz=vz(x) only and pressure at the inlet and outlet is atmospheric.
Answer:
well
Explanation:
basically it's like
Aliens from the planet Mars can have long or short antennas. The allele for a long antenna is DOMINANT, and the allele for a short antenna is RECESSIVE. Which of the following is the pair of alleles an alien would have to inherit to have a short antenna?
Recessive, dominant
Dominant, dominant
Recessive, recessive
Dominant, recessive
Answer:
Recessive, dominant
Explanation:
umm thats the answer
Helppp answer question pic in photo
According to Newton, which of these will determine if and how an object will move?
1. how much energy the object has
2. how unstable the object is
3. whether a net force acts on the object
4. he total mass of the object
Answer:
3
Explanation:
Answer:
whether a net force acts on the object
Types of RM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays, and gamma rays.
True
False
Answer:
True
Explanation:
The electromagnetic spectrum can be regarded as term that give description of range of light that are in existence, and this range from radio waves up to gamma rays. It can be explained as
range of frequencies that electromagnetic radiation takes with thier respective wavelengths as well as photon energies
The Types of electromagnetic radiation that make up the electromagnetic spectrum are
✓ microwaves
✓ infrared light
✓ ultraviolet light
✓X-rays,
✓gamma rays.
. A circular wire loop 40 cm in diameter has 100 Ohm resistance and lies in a horizontal plane. A uniform magnetic field points vertically downward, and in 25 ms it increases from 5 mT to 55 mT. Find the magnetic flux through the loop at (a) the beginning and (b) the end of 25 ms period. (c) What is the loop current during this time
Answer:
(a) 6.283 Wb (b) 69.11 Wb (c) I = 0.628 A
Explanation:
Given that,
The diameter of the loop, d = 40 cm
Radius, r = 20 cm
Initial magnetic field, B = 5 mT
Final magnetic field, B' = 55 mT
Initial magnetic flux,
[tex]\phi_i=BA\\\\=5\times 10^{-3}\times \pi \times 20^2\\\\=6.283\ Wb[/tex]
Final magnetic flux,
[tex]\phi_f=B'A\\\\=55\times 10^{-3}\times \pi \times 20^2\\\\=69.11\ Wb[/tex]
Due to change in magnetic field an emf will be generated in the loop. It is given by :
[tex]\epsilon=-\dfrac{d\phi}{dt}\\\\=\phi_f-\phi_i\\\\=69.11-6.283\\\\=62.827\ V[/tex]
Let I be the current in the loop. We can find it using Ohm's law such that,
[tex]\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{62.827}{100}\\\\=0.628\ A[/tex]
Hence, this is the required solution.
large roll of fabric
Costume Rendering
Scissors
Pattern
Bolt
Answer:
Do we have to choose out of those three?
Explanation:
Help answer question in picture
A bat emits a sonar sound wave
(343 m/s) that bounces off a
mosquito 8.42 m away. How
much time elapses between
when the bat emits the sound
and when it hears the echo?
(Unit = s)
Please help I am very confused with this topic
The time between when the bat emits the sound and when it hears the echo is 0.05 s
From the question given above, the following data were obtained:
Velocity of sound (v) = 343 m/s
Distance (x) = 8.42 m
Time (t) =?We can obtain obtained the time as illustrated below:
v = 2x / t
343 = 2 × 8.42 / t
343 = 16.84 / t
Cross multiply
343 × t = 16.84
Divide both side by 343
t = 16.84/343
t = 0.05 sThus, the time between when the bat emits the sound and when it hears the echo is 0.05 s
Learn more: https://brainly.com/question/10128949
Answer:
0.0491
Explanation: