Answers
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
Related Questions
inclined plane meaning
Answers
Answer:
inclined plane is another name of ramp
Explanation:
it is a machine which is used to lift a load L to the height h by applying an effort E along the distance l.
Sam wants to upgrade his toy "golf ball launcher". Right now when he shoots the toy vertically,
the golf ball reaches a height of 1.75 m. A golf ball has a mass of 46 grams and the toy can
hold a spring that can be compressed 24 cm. Using a different spring, Sam believes he can
increase the distance it can be compressed to 32 cm. What spring constant will Sam need the
new spring to be if he wants it to launch the golf ball vertically to a height of 3.0 m?
Answers
The initial kinetic energy of the golf ball can be found using:
KE = (1/2)mv^2
where
m = 0.046 kg (mass of golf ball)
v = ? (velocity of golf ball)
The potential energy of the golf ball at its maximum height is:
PE = mgh
where
h = 3.0 m (maximum height of golf ball)
Since the launcher is spring-powered, we can relate the initial kinetic energy to the potential energy using the spring constant and the distance the spring is compressed.
The initial kinetic energy can be found using the work-energy theorem:
W = KE
where
W = Fd (work done by the spring)
F = kx (force exerted by the spring)
x = 0.24 m (distance the spring can be compressed with the old spring)
k = ? (spring constant of new spring)
Substituting in the values, we get:
KE = (1/2)mv^2 = Fd = kx^2/2
Solving for k, we get:
k = (mv^2)/(x^2)
Now we can substitute in the values and solve for k:
k = (0.046 kg)(9.81 m/s^2)(1.75 m)/(0.24 m)^2 = 13.6 N/m
Therefore, Sam will need the new spring to have a spring constant of 33.7 N/m to launch the golf ball vertically to a height of 3.0 m.
HELP! Photo attached worth 60+ points
Answers
The period of the wave from the calculation can be seen to be 10 s
What is the period of a wave?When we talk about the period of the wave what we mean is the inverse of the frequency of the wave. Thus the period and the the frequency of the wave are actually the opposites of each other as we know in physics.
Given f = 0.10 Hz
T = 1/f = 1/0.10
T = 10 seconds
In the study of wave motion, the period of a wave is a crucial variable that is employed in many fields, such as optics, seismology, and communication systems.
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Consider an elastic collision between two pucks on an air-hockey table (no friction). The first
puck has a mass of 0.500 kg and is travelling at 4.00 m/s along the x-axis. The second puck
has a mass of 0.300 kg and is at rest. After the collision, the first puck has a velocity of 2.00 m/s
in an unknown direction, O, and the second puck travels at an unknown velocity v2₂ and an
unknown direction of O₂. Determine the 3 missing values.
(6 marks)
Answers
Conservation of momentum:
m1v1i + m2v2i = m1v1f + m2v2f
where
m1 = 0.500 kg (mass of first puck)
v1i = 4.00 m/s (initial velocity of first puck)
m2 = 0.300 kg (mass of second puck)
v2i = 0 m/s (initial velocity of second puck)
v1f = 2.00 m/s (final velocity of first puck)
v2f = v2₂ (final velocity of second puck)
Substituting in the values, we get:
(0.500 kg)(4.00 m/s) + (0.300 kg)(0 m/s) = (0.500 kg)(2.00 m/s) + (0.300 kg)(v2₂)
Simplifying and solving for v2₂, we get:
v2₂ = 6.00 m/s
Now we can use the conservation of kinetic energy:
(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2
Substituting in the values, we get:
(1/2)(0.500 kg)(4.00 m/s)^2 + (1/2)(0.300 kg)(0 m/s)^2 = (1/2)(0.500 kg)(2.00 m/s)^2 + (1/2)(0.300 kg)(6.00 m/s)^2
Simplifying and solving for v2f, we get:
v2f = 2.00 m/s
Therefore, the three missing values are:
- The final velocity of the second puck is 6.00 m/s in an unknown direction.
- The direction of the final velocity of the first puck is unknown.
- The final velocity of the second puck is 2.00 m/s in the opposite direction of the initial velocity of the first puck.
The equipotential lines are the dotted lines in the diagram below. the circles represent sets of points that are equidistant from point p and only serve to give you a sense of scale. this circle on which point a is located represents a distance of 1 cm from point p.
(A) if the distance between points A and B is approximately 3.0 cm, what is approximate magnitude of the electric field between these two points?
(B) Rank the strength of the electric field at the points ABCDEFP from strongest to weakest. Explain how you determined your rankings.
(C) Draw an arrow at points A, B, C and D to indicate the electric field at those locations.
Answers
A) The approximate magnitude of the electric field between points A and B is 1.3 V/cm; B) The ranking from strongest to weakest electric field is B>A>C>D>E>F>P; C) The arrows indicating the electric field at points A, B, C, and D should be drawn perpendicular to the equipotential lines in the direction of decreasing potential.
Equipotential lines are imaginary lines that connect points in a space that have the same electric potential or voltage. They indicate areas of uniform electric potential in an electric field.
(A) To find the approximate magnitude of the electric field between points A and B, we need to use the formula:
E = ΔV / Δd
where ΔV is the potential difference between points A and B, and Δd is the distance between them. We can estimate ΔV by counting the number of equipotential lines between points A and B, which appears to be around 4. The distance Δd is approximately 3.0 cm. Therefore, the approximate magnitude of the electric field between points A and B is:
E = 4 / 3.0 ≈ 1.3 V/cm
(B) To rank the strength of the electric field at points ABCDEFP, we need to look at the spacing between the equipotential lines. The closer the lines are, the stronger the electric field. Based on the diagram, the ranking from strongest to weakest electric field is:
B > A > C > D > E > F > P
This ranking is determined by observing the spacing between the equipotential lines. The electric field is strongest at point B because the equipotential lines are closest together there, indicating a steep potential gradient.
(C) To draw arrows indicating the electric field at points A, B, C, and D, we need to draw the arrows perpendicular to the equipotential lines, in the direction of decreasing potential. The arrows should be longer where the equipotential lines are closer together. Based on the diagram, the arrows should be drawn as follows:
At point A, the arrow should point to the left, because the potential is decreasing in that direction.
At point B, the arrow should point to the left and be longer than the arrow at point A, because the potential gradient is steeper.
At point C, the arrow should point upward, because the potential is decreasing in that direction.
At point D, the arrow should point downward, because the potential is increasing in that direction.
Hence, The electric field between points A and B has an approximate magnitude of 1.3 V/cm; the order of the electric fields from strongest to weakest is B>A>C>D>E>F>P; and the arrows indicating the electric field at each of the four points should be drawn perpendicular to the equipotential lines in the direction of decreasing potential.
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A device that changes only the direction of force is known as____.
Answers
A device that changes only the direction of force is known as simple machine.
What is a simple machine?A simple machine in physics or engineering is a mechanical device that only requires the application of a single force to work.
A simple machine changes the direction or magnitude of a force. In general, they can be defined as the simplest mechanisms that use mechanical advantage (also called leverage) to multiply force.
Examples of simple machines are as follows;
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Consider the group of three +2.4 nC point charges at three corners of a rectangle as shown in the figure. Point A is located at the 4th corner of the rectangle and point B is located 3 cm to the right of the top right charge. What is the potential difference, VB-VA, between points A and B?
Answers
The potential difference between points A and B is 2.95 volts.
To find the potential difference between points A and B, we need to first find the electric potential at each point.
The electric potential at a point due to a point charge can be calculated using the formula:
V = kq/r
where V is the electric potential, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the point charge and the point where we want to find the potential.
Using this formula, we can calculate the electric potential at point A due to each of the three charges:
V1 = kq/r1 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
V2 = kq/r2 = (9 x 10^9)(2.4 x 10^-9)/(4 x 10^-2) = 5.4 V
V3 = kq/r3 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
The total electric potential at point A due to the three charges is the sum of these individual potentials:
VA = V1 + V2 + V3 = 7.2 + 5.4 + 7.2 = 19.8 V
To find the electric potential at point B, we need to consider the electric potential due to the charge at the top right corner of the rectangle and the other two charges together.
The electric potential due to the charge at the top right corner can be calculated using the formula:
V4 = kq/r4 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
To calculate the electric potential due to the other two charges at point B, we need to find the net electric field at point B due to these two charges. The electric field at point B due to each charge can be calculated using the formula:
E = kq/r^2
where E is the electric field, k is Coulomb's constant, q is the charge, and r is the distance between the point charge and the point where we want to find the field.
Using this formula, we can calculate the electric fields at point B due to the two charges:
E1 = kq/r1^2 = (9 x 10^9)(2.4 x 10^-9)/(4 x 10^-2)^2 = 4.5 x 10^4 N/C
E2 = kq/r2^2 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2)^2 = 7.4 x 10^4 N/C
Since these two charges are in opposite directions, we need to subtract their electric fields to find the net electric field at point B:
E_net = E2 - E1 = (7.4 x 10^4) - (4.5 x 10^4) = 2.9 x 10^4 N/C
The electric potential at point B due to the other two charges can be calculated using the formula:
V5 = E_net * d = (2.9 x 10^4) * (3 x 10^-2) = 870 V
The total electric potential at point B is the sum of the potentials due to the charge at the top right corner and the other two charges:
VB = V4 + V5 = 7.2 + 870 = 877.2 V
Using the formula for the potential difference between two points:
VB-VA = kq1q2/r1 - kq1q3/r2 + kq2q3/r3
where k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1, q2, and q3 are the charges (in Coulombs) at the three corners, r1, r2, and r3 are the distances between the charges and point B, and the negative sign indicates that the potential at point A is higher than at point B.
Plugging in the given values, we have:
VB-VA = (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.03 m) - (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.04 m) + (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.03 m)
Simplifying, we get:
VB-VA = (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)(1/0.03 - 1/0.04 + 1/0.03)
VB-VA = 2.95 V
Therefore, the potential difference between points A and B is 2.95 volts.
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Which of the following is a hypothesis?
A. The thickness of transparent glass affects how much light passes through.
B. Light may pass through a transparent sheet of glass.
C. A transparent sheet of glass has some effect on light.
D. Light will travel slowly through glass.
Answers
The hypothesis is, the thickness of transparent glass affects how much light passes through. Option A is correct.
A hypothesis is a proposed explanation or prediction for a phenomenon or observation that is based on limited evidence and subject to testing and validation through further investigation. It is an essential part of the scientific method, which involves developing a research question, making observations, and forming a hypothesis to explain the observed phenomenon.
The hypothesis should be testable, falsifiable, and based on evidence and reasoning. Testing the hypothesis involves designing experiments and collecting data, which can either support or refute the hypothesis. If the hypothesis is supported by the data, it may be further developed into a scientific theory, which is a widely accepted explanation of a natural phenomenon that has been extensively tested and validated. Option A is correct.
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When discussing you will be defending your thoughts of the following questions:
1. Children’s appetites and willingness to eat are strongly influenced by the mealtime environment. Identify and briefly discuss several features that can be used to create an atmosphere that encourages children to eat.
2. Review the My Plate food guide and suggest appropriate snack foods from each food group that would be appropriate for school-age children.
3. In what ways can adults help children learn to enjoy nutritious food and establish healthy eating habits?
Answers
To encourage children to eat, create a pleasant and distraction-free mealtime environment, serve a variety of visually appealing and small portions of favorite foods, involve them in meal planning and preparation, provide a relaxed and comfortable atmosphere, and avoid using food as a reward or punishment. Appropriate snack foods from each food group for school-age children can be selected from fruits, vegetables, grains, protein, and dairy. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food choices, and avoiding using food as a reward or punishment.
1. To create an atmosphere that encourages children to eat, several features can be used, such as:
A pleasant and inviting mealtime environment that is free of distractions such as television, mobile phones, or tablets.
Serve a variety of colorful, visually appealing foods in small portions, making sure to include favorite foods of the child.
Involve children in meal planning and preparation, giving them the opportunity to select foods and participate in simple meal preparation tasks.
Provide a relaxed and comfortable atmosphere by allowing enough time for meals and offering positive reinforcement for good eating behaviors.
Avoid using food as a reward or punishment and ensure that mealtimes are stress-free and enjoyable for children.
2. MyPlate is a visual representation of the five food groups that form a healthy and balanced diet. Appropriate snack foods from each food group for school-age children could include:
Fruits: apple slices, berries, bananas, or orange wedges.
Vegetables: carrot sticks, cherry tomatoes, cucumber slices, or celery sticks.
Grains: whole-grain crackers, granola bars, rice cakes, or air-popped popcorn.
Protein: hard-boiled eggs, cheese sticks, nut butter, or hummus.
Dairy: yogurt, milk, or cheese cubes.
3. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by:
Modeling healthy eating behaviors and food choices themselves.
Encouraging children to try new foods and flavors, involving them in grocery shopping, and meal planning.
Making meals enjoyable and fun by creating a positive mealtime environment and involving children in meal preparation tasks.
Providing healthy food choices and limiting the availability of unhealthy options at home and school.
Offering regular mealtimes and avoiding using food as a reward or punishment.
Hence, Encourage children to eat by providing a pleasant and distraction-free mealtime environment, serving a variety of visually appealing and small portions of favorite foods, involving them in meal planning and preparation, providing a relaxed and comfortable environment, and avoiding using food as a reward or punishment. Fruits, vegetables, grains, protein, and dairy are examples of appropriate snack foods from each food group for school-age children. Adults can assist children in learning to enjoy nutritious food and develop healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food options, and avoiding using food as a reward or punishment.
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Consider the 5-step staircase. All steps provide an equal elevation gain. The potential energy (PE) on the 4th step is 40.0 J. Determine the PE and KE values of the ball at the indicated positions. I NEED KE4
Answers
Potential energy is the energy acquired by an object by virtue of its position.
Potential energy of the ball at the 4th step = 40 J
Let the mass of the ball, m is 1 kg
So, potential energy at 4th step,
mgh = 40
h = 40/1 x 9.8
h = 4.1 m
So, the height of each steps, h' = 4.1/4
h' = 1.025 m
Therefore, potential energy at 1,
PE₁ = 1 x 9.8 x 1.025
PE₁ = 10.045 J
Therefore, potential energy at 2,
PE₂ = 1 x 9.8 x 2 x 1.025
PE₂ = 20.09 J
Therefore, potential energy at 3,
PE₃ = 1 x 9.8 x 3 x 1.025
PE₃ = 30.13 J
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A gas expands from I to F in the figure. The
energy added to the gas by heat is 430 J when
the gas goes from I to F along the diagonal
path.
1): What is the change in internal energy of the
gas?
Answer in units of J.
2): How much energy must be added to the gas
by heat for the indirect path IAF to give the
same change in internal energy?
Answer in units of J.
Answers
The change in internal energy of the gas is -5570 J, and 860 J of energy must be added to the gas by heat for the indirect path IAF to give the same change in internal energy.
1. The change in internal energy of the gas is equal to the work done on the gas plus the heat added to the gas. From the diagram, we can see that the work done on the gas when it expands from I to F along the diagonal path is negative. This is because the gas expands against a constant external pressure, and its volume increases, so the work done by the gas is positive, and the work done on the gas is negative. The work done on the gas can be calculated as:
W = -PΔV = -1.5 × 10^5 Pa × 0.04 m^3 = -6000 J
The change in internal energy is then:
ΔU = Q + W = 430 J - 6000 J = -5570 J
Therefore, the change in internal energy of the gas is -5570 J.
2. For the indirect path IAF, we can break it down into two steps: I to H along the horizontal path, and H to F along the vertical path. For the first step, the work done on the gas is zero, since the volume does not change. So, the heat added to the gas is equal to the change in internal energy:
Q1 = ΔU = -5570 J
For the second step, the work done on the gas can be calculated as:
W2 = -PΔV = -1.5 × 10^5 Pa × 0.08 m^3 = -12000 J
The heat added to the gas for this step must be equal to the change in internal energy minus the work done on the gas:
Q2 = ΔU - W2 = -5570 J - (-12000 J) = 6430 J
The total heat added to the gas for the indirect path IAF is then:
Q = Q1 + Q2 = -5570 J + 6430 J = 860 J
So, 860 J of energy must be added to the gas by heat for the indirect path IAF to give the same change in internal energy.
Hence, The gas's internal energy changes by -5570 J, while the indirect path IAF requires that 860 J of energy be given to the gas via heat in order to produce the same internal energy change.
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Which theory has been proposed that would explain the neurology of memory
Group of answer choices
neurogenesis
alteration is synaptic transmission
localized neural circuits
All of these are correct
Answers
The theory that has been proposed that would explain the neurology of memory are;
neurogenesisalteration is synaptic transmissionlocalized neural circuitsWhat is neurophysiological theory of learning?The neurophysiology of learning can be described as the theory that cover the three main cognitive processes and this can be regarded as core value of the the information processing system.
It should be noted that the information processing system usually make use of the brains which helps to remember information through attention, perception and all this are found in the functionality of the brain system in the human system.
Therefore, All of these are correct.
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Why does Earth have a liquid water supply and Mars does not?
A. Mars is too cold.
B. Mars has no magnetic field.
C. Earth was never bombarded with comets.
D. Mars is much larger than Earth.
Answers
Answer:
Earth have a liquid water supply and Mars does not because of the difference in their magnetic fields. Therefore the option B is correct.
Explanation:
The atmosphere of Earth is shielded from solar winds and radiation by a potent magnetic field, which keeps the atmosphere from being torn away. This enables water to remain liquid on the surface of the planet.
Mars, in contrast, has a weaker magnetic field, which results in a thinner atmosphere that is unable to support liquid water. Mars is hence more colder and drier than Earth.
One of the main reasons that Mars has no life as we know it is because it lacks a magnetic field, whereas the magnetic field of Earth is crucial in fostering the conditions necessary for life to flourish.
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Help! Photo Attached!!! WORTH: 60+ POINTS! Difficulty: Medium
Answers
The wavelength of the given wave is 4 meters and the amplitude of the wave is 2 meters.
Wavelength of the wave is the distance between two crests or two troughs and the amplitude is the maximum height of the wave.
From the given figure,
the distance between two crests or two trough,
wavelength = 4 × 1 meter
λ = 4 meter.
The maximum distance of the crest or trough,
Amplitude (a) = 2×1 meter
a = 2 meter
Hence, the wavelength of the wave is 4 meter and the amplitude of the wave is 2 meter.
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Ramp 1 Ramp 2 Ramp 3
Trial 1 0.95 s 0.78 s 1.31 s
Trial 2 0.87 s 0.75 s 1.27 s
Trial 3 0.92 s 0.80 s 1.44 s
Avg. Time 0.91 s 0.78 s 1.34 s
Which of the following conclusions can be made from the above data?
Answers
From this data it is clear that the time require to complete ramp 3 is more than any other, hence it can be large ramp or there are more objectless or turns. Ramp 2 requires least time to complete, it can be shorter or having less number of obstacles.
An inclined plane, also known as a ramp, is a flat supporting surface that is slanted at an angle from the vertical direction, with one end higher than the other, and is used to help raise or reduce a weight. The inclined plane is one of the six traditional basic devices established by Renaissance scientists. Inclined aircraft are used to transport big cargoes over vertical obstructions. Examples include a ramp used to load items into a truck, a person going up a pedestrian ramp, and an automobile or railroad train climbing a gradient. it can have obstacles in the path
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1. Two waves approach each other on the same string. Which statement best describes the process of events that will happen?
a. The waves will approach, interfere with each other, then pass through each other having been altered by the interference process
b. The waves will approach, interfere with each other, then pass through each other after interfering, unchanged
c. The waves will approach, then they will bounce off each other and move away from each other as normal
d. The waves will approach, interfere with each other, then this interference will cancel them both out
2. Which of the following interferences would produce the largest amplitude resultant wave?
a. Crest of wave 1 (5 m) combines with crest of wave 2 (11.8 m)
b. Crest of wave 1 (8 m) combines with crest of wave 2 (1.1 m)
c. Crest of wave 1 (9.5 m) combines with the trough of wave 2 (3.5 m)
d. Trough of wave 1 (3.2 m) combines with the trough of wave 2 (2.8 m)
Answers
1. a. The waves will approach, interfere with each other, then pass through each other having been altered by the interference process.
2. a. Crest of wave 1 (5 m) combines with crest of wave 2 (11.8 m).
Two waves approach each other on the same string, undergo the process of interference, and then the output wave gets altered. Thus, option A is correct.
What is interference?Interference is the process of superimposing two waves. The phenomenon of two coherent waves is combined by adding their intensities, and displacements with respect to the phase change.
Interference is of two types: Constructive Interference and Destructive Interference. When the crests/trough of wave 1 is merged with the crests/trough of wave 2 gives Constructive interference and the output waves are larger in intensity and amplitude.
When the crest/trough of wave 1 is merged with the trough/crest of wave 2 results in Destructive Interference and there is no output waveform as the waves cancel each other.
From the given, two waves approach each other on the same string, interfere with each other, then pass through each other having been altered by the interference process. The crest of wave 1 (5m) is combined with crest of wave2 (11.8m).
Thus, the ideal solutions for statements 1 and 2 are Option A and Option A.
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An object that is 1.14 cm tall is placed 15.0 cm in front of a diverging lens of focal length 23.0 cm. How tall is the image (in centimeters, to three significant figures)?
Answers
The height of the image would be 9.64 cm.
We can use the thin lens equation to determine the position of the image:
1/f = 1/do - 1/di
where f is the focal length of the lens, do is the distance from the object to the lens, and di is the distance from the image to the lens. Rearranging this equation, we get:
1/di = 1/f - 1/d₀
Substituting the given values, we get:
1/di = 1/23 - 1/15
1/di = -0.007971
di = -125.3 cm
The negative sign for di indicates that the image is virtual (i.e., it appears on the same side of the lens as the object).
Now, we can use the magnification equation to determine the height of the image:
m = -di/d₀
where m is the magnification. Substituting the given values, we get:
m = -(-125.3 cm)/(15.0 cm)
m = 8.353
The negative sign for the magnification indicates that the image is inverted with respect to the object. The absolute value of the magnification tells us that the image is larger than the object by a factor of 8.353.
Therefore, the height of the image is:
hi = mho
hi = 8.3531.14 cm
hi = 9.64 cm
Rounding to three significant figures, the height of the image is 9.64 cm.
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50 POINTS ANSWEr CORRECT Explain how all the other elements heavier than iron are formed after the death of the star?
Answers
Answer:
Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.
Explanation:
Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].
So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.
[^1
Question physic help
Answers
Answer:
The correct options are
A. A penny
B. An almunium soda can
Both of these materials allow electricity to pass through them:)
You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
A. How much heat energy is released by the breaks of your car
B. If your car could recapture 40% of the heat energy released from your brakes how much energy would you recapture
C. Imagine You have an electric heart and all of the recaptured energy is put back into the battery the power is your car what speed could your car achieve from rest by using only recapture energy from part B
D. If you break from the speed in part C and start again from rest how fast will you be able to drive
E. An advertisement says that if you have regenerative brakes like these you’ll never have to put any more energy into your car again. Is this true or false explain
Answers
A car going at 30 m/s:
A. Released energy is 450,000 J.B. Amount of recaptured energy is 180,000 J.C. From rest the car can speed at 24 m/s using recaptured energy.D. The speed will be 24 m/s.E. The statement that "if you have regenerative brakes like these you'll never have to put any more energy into your car again" is false.How to calculate energy?A. The heat energy released by the brakes can be calculated using the formula
Q = mv²/2,
where Q = heat energy,
m = mass of the car and
v = initial velocity.
Substituting the given values, Q = (1000 kg)(30 m/s)²/2 = 450,000 J.
B. If 40% of the heat energy released by the brakes is recaptured, then the amount of recaptured energy
0.40(450,000 J) = 180,000 J.
C. If all the recaptured energy is put back into the battery, then the change in kinetic energy of the car can be calculated as;
ΔK = 180,000 J.
Using the formula K = mv²/2 to find the final velocity v.
Rearranging
v = √(2ΔK/m) = √(2(180,000 J)/(1000 kg)) = 24 m/s.
D. If the car is brought to rest and started again using only the recaptured energy, then the final velocity is calculated using the same formula above as in part C, but with the initial velocity set to zero.
Thus, v = √(2(180,000 J)/(1000 kg)) = 24 m/s.
E. While regenerative braking can recover part of the energy lost as heat during braking, it does not generate energy from nothing. The energy must still be supplied by another power source or the battery, and refilled some time. Furthermore, some energy will still be wasted as heat because regenerative braking is not 100% effective.
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20. The pilot of an eastbound plane finds his wind speed in relation to his aircraft. He measures a wind velocity of 320 km/h with the wind coming from the east. A woman on the ground sees the plane pass overhead, and she measures its velocity as 290 km/h. What is the wind velocity in relation to the observer?
A. 30 km/h east-to-west
B. 30 km/h west-to-east
C. 320 km/h east-to-west
D. 290 km/h east-to-west
Answers
The wind velocity in relation to the observer is 30 km/h west-to-east.
What is the relative velocity of the plane?
The relative velocity of an object is the measure of change in velocity of the object using a common reference point, known as point of reference.
The relative velocity of the wind with respect to a stationary observer is calculated as follows;
Let A be plane velocity and W wind velocity;
A + W = 320 km/h ----- 1
A - W = 290 km/h --- 2
----------------------------------
2A = 610
A = 610/2
A = 305 km/h
The relative velocity;
W - A = 320 km/h - 305 km/h
W - A = 15 km/ (east to west)
Another west to east = 15 km/hr
= 15 km/hr + 15 km/hr
= 30 km/hr west to east
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A block (mass = m) is lifted upward with the help of a wheel barrow by making an angle . Draw the FBD and write equations by showing all possible forces.
Answers
According to these equations, the normal force equals the weight component in the y direction, and the tension force equals the weight component in the x direction.
How to determine possible forces?Here is a description of the forces acting on the block:
Weight force (mg): The force due to gravity acting on the block and directed downwards.
Normal force (N): The force exerted by the wheelbarrow on the block and perpendicular to the surface of contact.
Tension force (T): The force exerted by the rope on the block and directed upwards at an angle .
Here is a free body diagram (FBD) of the forces acting on the block:
mg
↓
┌───┐
T ← ┤ ├── N
└───┘
Write the equations for the forces in the x and y directions:
In the y direction:
N - mg cosθ = 0
N = mg cosθ
In the x direction:
T - mg sinθ = 0
T = mg sinθ
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A regulation soccer ball has a mass of 0.45 KG in order to accelerate the ball at a rate of 8 m/s2 how much force would you need to apply when you kick the ball? Show FUN AL 
Answers
This is an exercise in Newton's second law, also known as the law of force or law of dynamics, which states that the net force acting on an object is equal to the object's mass multiplied by its acceleration. This law describes how force affects the motion of an object and is one of the fundamental laws of physics used to describe the motion of objects.
Net force refers to the sum of all forces acting on an object. If the net force is zero, the object is in equilibrium and is not moving. If the net force is greater than zero, the object accelerates in the direction of the net force. This acceleration depends on the mass of the object and the magnitude of the net force.
The mathematical formula that represents Newton's second law is F = m × a, where F represents the net force acting on the object, m represents the mass of the object, and a represents its acceleration. It is important to keep in mind that force, mass, and acceleration are vector magnitudes, that is, they have direction and magnitude.
Force is measured in newtons (N), mass in kilograms (kg), and acceleration in meters per second squared (m/s²). Therefore, the resulting unit of net force is newtons.
We solve the exercise:
To solve the force you will need the regulation soccer ball.
We apply the formula:
F = m × a
It tells us that the ball has a mass of 0.45 kg to accelerate the ball at a rate of 8 m/s².
We substitute and solve:
F = m × a
F = (0.45 kg)(8 m/s²)
F = 3.6 N
Therefore, to accelerate the ball at a rate of 8 m/s², a force of 3.6 N needs to be applied.
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Answer:
You would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
Explanation:
The force required to accelerate the soccer ball can be calculated using Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) times its acceleration (a):
[tex]\sf\qquad\dashrightarrow F = m * a[/tex]
In this case, the mass of the soccer ball is 0.45 kg and the desired acceleration is 8 m/s². Plugging these values into the equation above, we get:
[tex]\sf\qquad\dashrightarrow F = 0.45\: kg * 8\: m/s^2[/tex]
[tex]\sf\qquad\dashrightarrow F = \boxed{\bold{\:\:3.6\: N\:\:}}[/tex]
Therefore, you would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
What is the final velocity of a car that accelerates from rest for 7 seconds at 2.5 m/s2?
Answers
Answer:
v=7.8
Explanation:
at rest v⁰ is zero
v²= v⁰t+1/2at²
=1/2×2.5×7²
=0.5×2.5×49
=7.8
y(t) = -4 + Cos (2A10t - π/4)- Sin (2π20t)
i. Complete the energy and power
ii. Draw the spectrum of y(t)
Answers
The average power of the signal Y(t) is approximately 4.166 W.
The energy of the signal Y(t) over one period is approximately 0.833 J.
How to calculate the energyWe can calculate the average power:
P = (1/T) ∫0ⁿ |Y(t)|² dt
P = (1/0.1) ∫_0⁰¹ [(-4 + Cos(2π10t - π/4)) + Si²(2π20t)] dt
P = 2 ∫0⁰¹[16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt
P = 2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰₁
P ≈ 4.166 W
We can calculate the energy:
E = ∫-∞^∞ |Y(t)|² dt
E = T ∫0ⁿ |Y(t)|² dt
E = 0.1 ∫0^⁰¹ [(-4 + Cos(2π10t - π/4))² + Sin²(2π20t)] dt
E = 0.2 ∫0⁰¹ [16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt
E = 0.2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰¹
E ≈ 0.833 J
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Starting from mean position, a particle in SHM takes time t1 and t2 to cover the first half and second half displacement in moving from mean position to extreme position. Establish the relation between them.
Answers
The relationship between t₁ and t₂ is established as follows: t₁ + t₂ = /(k/m).
How to determine SHM?Consider a particle undergoing Simple Harmonic Motion (SHM) with amplitude A.
When the particle moves from the mean position (x = 0) to the extreme position (x = A), it covers the first half of the displacement, which is A/2, in time t₁.
Similarly, when the particle moves from the extreme position (x = A) to the mean position (x = 0), it covers the second half of the displacement, which is also A/2, in time t₂.
Now, the time period of SHM is given by T = 2π/ω, where ω is the angular frequency.
it can also be expressed as the time period, T = 2t₁ + 2t₂, since the particle completes one full oscillation in time T, which consists of two halves, each covered in time t₁ and t₂.
Therefore:
2t₁ + 2t₂ = T = 2π/ω
Dividing both sides by 2:
t₁ + t₂ = π/ω
Now, the angular frequency is related to the mass and spring constant of the system as:
ω = √(k/m)
where k = spring constant and m is the mass of the particle.
Substituting this expression for ω in the above equation:
t₁ + t₂ = π/√(k/m)
Therefore, it is established that the relation between t₁ and t₂ is:
t1 + t2 = π/√(k/m)
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Consider the arrangement shown in the figure below where R = 8.50 Ω, ℓ = 1.10 m, and B = 2.00 T. A vertical bar and two parallel horizontal rails lie in the plane of the page, in a region of uniform magnetic field, vector B, pointing into the page. The parallel rails run from left to right, with one a distance ℓ above the other. The left ends of the rails are connected by a vertical wire containing a resistor R. The vertical bar lies across the rails to the right of the wire. Force vector Fapp points from the bar toward the right. HINT (a) At what constant speed (in m/s) should the bar be moved to produce a current of 1.70 A in the resistor? (b) What power (in W) is delivered to the resistor? W (c) What magnetic force (in N) is exerted on the moving bar? (Enter the magnitude.) N (d) What instantaneous power (in W) is delivered by the force Fapp on the moving bar?
Answers
The velocity of the conducting bar is 6.6 m/s.
Resistance, R = 8.5 Ω
Length of the bar, l = 1.1 m
Magnetic field, B = 2 T
Current in the bar, I = 1.7 A
The expression for motional emf is given by,
ε = B x l x v
where v is the velocity of the conducting bar.
a) Applying Ohm's law,
I x R = Blv
Therefore, v = IR/Bl
v = 1.7 x 8.5/(2 x 1.1)
v = 6.6 m/s.
b) Power delivered to the resistor,
P = (Blv)²/R = (2 x 1.1 x 6.6)²/8.5
P = 24.8 W
c) Force exerted on the bar,
F(ext) = B²l²v/R = (2 x 1.1)²x 6.6/8.5
F(ext) = 3.75 N
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lectric Charges
The glass is attracting the pieces of paper. What does
this tell you about the charges on the glass and the
paper?
The glass and the paper have the same charge.
O The glass and the paper have different charges.
ONeither the glass nor the paper has a charge.
Answers
Astronomers estimate that comet Hale-Bopp lost mass at a rate of
350,000 kg/s during it 100 day closest approach to the Sun. Estimate the total mass lost during that time? What fraction is that of the total mass of the comet (5 x 1015 kg)
Answers
Total mass lost by the comet is 30.24 x 10¹⁰ kg.
Rate at which mass is lost, R = 35 x 10⁴ kg/s
Time period, T = 100 days = 8.64 x 10⁶s
Therefore,
Total mass lost by the comet, m = R x T
m = 30.24 x 10¹⁰ kg
So,
The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵
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A 80.7 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.57 rad/s. A monkey drops a 9.57 kg bunch of bananas vertically onto the platform. They hit the platform at 45 of its radius from the center, adhere to it there, and continue to rotate with it. Then the monkey, with a mass of 21.1 kg, drops vertically to the edge of the platform, grasps it, and continues to rotate with the platform. Find the angular velocity of the platform with its load. Model the platform as a disk of radius 1.91 m.
Answers
Angular velocity of the platform with its load is 0.94 rad/s.
Since, there is no external torque acting on the system, the momentum is conserved.
So, Initial momentum, L₁ = Final momentum, L₂
I₀ω₁ = (I₀ + m₁r₁² + m₂r₂²)ω₂
I₀ω₁ = [1/2 x 80.7 x (1.91)²] (1.57)
I₀ω₁ = 147.2 x 1.57 = 231.1 kgm²/s
So,
231.1 = [147.2 + 9.57(4/5 x 1.91)² + 21.1(1.91)²]ω₂
Therefore, the final angular velocity,
ω₂ = 231.1/246.5
ω₂ = 0.94 rad/s
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