Answer:
Eruptions/Volcano
Explanation:
poop fell from the sky
Susan uses a system of pulleys to lift a 355 N box, but she only exerts 25 N. What is the MA of the pulley system?
Answer:
oof
Explanation:
oof
Kepler's second law states that a line from the sun to a planet sweeps out equal areas in equal times. 2 d coordinate system with an elliptical orbit of planet around the sun. The elliptical orbit is centered at the origin. The Sun is located on the x axis between the origin and the far left edge of the orbit. The Planet is on the orbital path in the first quadrant and has a velocity vector that is pointing counter-clockwise on the orbital path. There is a line connecting the sun and the planet. The Perihelion is marked as the point where the orbit crosses the x axis closest to the Sun. The Aphelion is marked as the point where the orbit crosses the x axis farthest away from the Sun. The aphelion is the point in the orbit where the planet is the furthest distance from the sun, The perihelion is the point at which the planet is closest to the sun. At which point must the speed of the planet be greater
Answer:
the speed is higher in the PERIHELIUM
Explanation:
As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.
L = r x p = m r x v
where m is the planet mass and the Sun is considered fixed
Let's analyze this expression, if the anglar momentum is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed
So the speed is higher in the PERIHELIUM
Can you describe how and why the molecules move from one side to the other?
The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.
The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.
The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.
The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.
Learn more about molecules here:-https://brainly.com/question/26044300
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When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing
A or B??????????????
lodine-131 has a half life of about 8 days. If you had 60 grams of , how much would remain after 24 days?
Answer:
7.5 grams
Explanation:
From the question,
(R/R')ᵇ = 2ᵃ.................... Equation 1
Where b = half life, R = Original mass of iodine, R' = Remaining mass of Iodine after disintegration, a = Total time taken.
⇒ R/R' = 2ᵃ/ᵇ............... Equation 2
Given: R = 60 grams, a = 24 days, b = 4 days
Substitute these values into equation 2
60/R' = 2²⁴/⁸
60/R' = 2³
R' = 60/2³
R' = 60/8
R' = 7.5 grams
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
If one 9V battery is used in a circuit with a total resistance of 39Ω, what is the current in the circuit?
Answer:
Using V= IR
I= 0.2307 Ampere
if 332 waves passes through a medium in one second with the speed of 332m/s, then wavelength is?
Answer:
1 metresExplanation:
Using the formula
v = fλ
v is the speed
f is the frequency
λ is the wavelength
Given the following
v = 332m/s
Frequency is the number of oscillation completed in one second. Since 332 waves passes through a medium in one second, hence the frequency us 222 Hertz
From the formula
λ = v/f
λ = 332/332
λ = 1m
Hence the wavelength is 1m
1
Describe the kinetic energy of the pins at
the beginning of the video. Explain your
answer.
Answer:
I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”
Hope this help!:)
1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins
Answer:
The name given to the underwater mountains in the middle of oceans is;
Mid-ocean ridges
Explanation:
Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.
The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.
Please help me!!!!! It's due soon!!!! NO LINK PLEASE!!!!!!
Answer:
The direction of partlcle movement is perpendicular to the direction of movement of energy of the wave.
Which of these is emitted during beta decay ?
A) high-energy electromagnetic radiation
B) a small neutral particle
C) a small charged particle
D) a positively charged helium nucleus
Answer:
C. a small charged particle.
Explanation:
typically beta radiation emits an electron which is a small negativity charged particle.
hope it helps. :)
Answer:
A small charged particle.
Explanation:
A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder
Answer:
[tex]1311.5\ \text{Nm}[/tex]
Explanation:
l = Length of ladder = 8.57 m
m = Mass of ladder = 21.4 kg
F = Force on ladder = 258 N
[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Net torque is given by
[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]
The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].
Renewable energy resources like solar energy and wind power are still too expensive to be practical on a large scale. True or False?
Answer: False
Explanation:
If you slow the motion of water molecules down, they are more likely to become
A)
a gas
B)
hotter
O
colder
D
absorbed
how to test the pH level of a soap?
Answer:
One of the most common is to use pH strips.
Explanation:
This was merely an accident and I did not mean to post a question.
Answer:
ok a good rest of your day
Explanation:
Un coche que lleva una velocidad constante de 90 km/hora durante 2 horas ¿Cuánto espacio recorre?Si encuentra un obstáculo en la carrera y tiene que parar 10 segundos calcula la aceleración
Answer:
(i) El coche recorre 180 kilómetros.
(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Explanation:
El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.
Primera parte - Viaje a velocidad constante
La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:
[tex]x = v\cdot t[/tex] (1)
Donde:
[tex]x[/tex] - Distancia recorrida, en kilómetros.
[tex]v[/tex] - Velocidad, en kilómetros por hora.
[tex]t[/tex] - Tiempo, en horas.
Si sabemos que [tex]v = 90\,\frac{km}{h}[/tex] y [tex]t = 2\,h[/tex], entonces la distancia recorrida por el coche es:
[tex]x = v\cdot t[/tex]
[tex]x = 180\,km[/tex]
El coche recorre 180 kilómetros.
Segunda parte - Deceleración
Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:
[tex]a = \frac{v-v_{o}}{t}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.
[tex]v[/tex] - Velocidad final, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
Si sabemos que [tex]v_{o} = 25\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], entonces la deceleración experimentada por el coche es:
[tex]a = -2.5\,\frac{m}{s^{2}}[/tex]
El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]
let's calculate
v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]
v = 17.30 m / s
If the mass of the cement is 15000kg. calculate the density of this cement sample in kgm-3
The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]
Given the following data:
Mass of cement = 15000 kgLength = 1.1 mWidth = 2 mHeight = 2.5 mTo calculate the density of this cement sample:
First of all, we would determine the volume of the rectangular block.
[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]
Now, can calculate the density of this cement sample:
Mathematically, the density of a substance is given by the formula;
[tex]Desnity =\frac{Mass}{Volume}[/tex]
Substituting the values into the formula, we have;
[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]
Read more: https://brainly.com/question/18320053
Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N
A wave is introduced into a thin wire held tight at each end. It has an amplitude of 3.8
cm, a frequency of 51.2 Hz and a distance from a crest to the neighbouring trough of
12.8 cm. Determine the period of such a wave.
this is in my physics I haven't touched on waves in so long. just can't figure it out could someone help me?
Explanation:
[tex]period = 1 \div frequency[/tex]
frequency is given
calculate the time period from this
Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
1) .90amps
2) .40amps
3) .30 amps
Answer:
incomplete question, resistor must be there
Explanation:
5. List five materials that we use in compost?
Leaves.
Grass clippings.
Brush trimmings.
Manure (preferably organic)
Any non-animal food scraps: fruits, vegetables, peelings, bread, cereal, coffee grounds and filters, tea leaves and tea bags (preferably minus the staples)
Old wine.
what is the range of plane if the angle of the projective is 30° with a speed of √2g?
Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
why brittles of a paint brush spread when in water and cling when taken out of water
Answer:
surface tension
Explanation:
because of surface tension in water
What could damage the eardrum and bones of the middle ear?
a) earwax
b) harmful noise
c) hammer
d) anvil
Answer:
B or D
Explanation:
I wanna say B but I don't really know if it's a trick question
my explanation for D is that anvils are usually 110 decibles and ear drums usually are damaged when exposed to 82dbs or higher at a consistant rate so I'd imagine that'd be the answer I hoped this helped
Answer:
the answer is B
Explanation:
Any harmful noises can be bad. yes, an Anvil and Hammer can be bad but so can explosions and gun fire and having music to loud
580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?
(Remember, nano means 10^-9.)
(Unit=deg)
Answer:
0.66 degrees
Explanation:
The computation of the angle of the third dark interference is shown below:
The condition of the minima is
Path difference = (2n +1) × [tex]\lambda[/tex]÷ 2
For third minima, n = 2
Now
xd ÷ D = (2 × 2 + 1) × [tex]\lambda[/tex]÷ 2
d tan Q_3 = 5[tex]\lambda[/tex] ÷ 2
tan Q_3 = 5[tex]\lambda[/tex] ÷ 2d
Q_3 = tan^-1 × (5[tex]\lambda[/tex] ÷2d)
= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)
= 0.66 degrees
Find the displacement in meters a runner would travel in 5 hours at an average velocity of 12km/h to the southwest
*show you work pleasee*
]
Answer:
60,000m
Explanation:
Convert km/h to m/s by multiplying with 1000/3600.
Convert hours to seconds by multiplying with 3600.
Because displacement is a vector quantity and deals with the shortest distance between points, simply plug it into the equation s=vt.