Answer:
288g
Explanation:
Given parameters:
Number of moles of H₂O = 16moles
Unknown:
Mass of the water = ?
Solution:
To solve this problem, first find the molar mass of H₂O;
Molar mass of H₂O = 2(1) + 16 = 18g/mol
Mass of H₂O = number of moles x molar mass
= 16 x 18
= 288g
1-bromobutane undergoes dehydrohalogenation by an elimination reaction when heated in the presence of base. what is the identity of the organic product
Answer:
1-butene
Explanation:
In this case, the problem is already stating and saying the reaction involved here.
1-bromobutane undergoes a dehydrohalogenation in presence of a base. This will cause an elimination reaction forming a product.
As this is an elimination product, this can be done in two ways.
The first way is with an unimolecular reaction where the halide is eliminated from the starting reactant in a two step reaction involving a carbocation formation. This is known as E1 reaction. However, the conditions for this reaction is to be in acid medium.
The second way is with a bimolecular reaction where the halide is eliminated from the starting reactant in just one step, and no carbocation is formed. This is known as E2 reaction and is commonly used with bases.
In the case of this problem, we are undergoing an E2 reaction, therefore, the mechanism of reaction is just one step, and when this happens, the base substract the hydrogen from Carbon 2, eliminates the bromide and forms a double bond, giving the 1-butene.
You can see the mechanism in the following picture.
Hope this helps
1-butene is the organic byproduct of 1-bromobutane's dehydrohalogenation in the presence of a base.
In the process of dehydrohalogenation, a molecule loses both a hydrogen and a halogen atom (such as a halogen from chlorine, bromine, or iodine) to create an unsaturated compound. The production of alkenes or alkynes, which are crucial in organic chemistry, is frequently accomplished using this reaction. Eliminating a hydrogen halide (HX) from a halogenoalkane or alkyl halide is the most important step in dehydrohalogenation. The E1 and E2 reactions are the two basic processes that can be used to do this. There are two steps in the E1 reaction. The halogenoalkane first passes through ionisation and creates a carbocation intermediate.
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explain how the particles of a substance change as a substance changes from a solid to a liquid to a gas.
Answer:
Some substances can change from the solid state to the gas state without ever becoming a liquid. During this process, known as sublimation, the sur- face particles of the solid gain enough energy to become a gas.When dry ice becomes a gas, it absorbs thermal energy from water vapor in the air.
Explanation:
Which of these is smallest?
cells
atoms
matter
elements
Answer:
atoms
Explanation:
i hope that help you
Answer:
atoms
Explanation:
You find yourself in a room with dark gray walls. Medeleev’s image says, “This element is essential for plant life to thrive and is found in heavy clay minerals and the ash from your campfire.” What element are these walls made from?
Answer:
juvn hgf jb ujvi i junk food sux
Explanation:
Rank the following elements in INCREASING Atomic Radius: Fe, Ni, K, Ti (SMALLEST TO
LARGEST)
a. Ti, Ni, Fe, K
b. Ni, Fe, Ti, K
c. Fe, Ti, K, Ni
d. K, Ti, Fe, Ni
Answer:
b. Ni, Fe, Ti, K
Explanation:
The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.
Atomic radius:
" It is the smallest distance from nucleus to the outer most valance shell of an atom"
When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.
As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Ni ∠ Fe ∠ Ti ∠ K
The diagram illustrates photosynthesis.
Which best describes what is happening in the area marked X?
Carbon dioxide enters the stem through xylem.
Oxygen enters the stem through stomata.
Water is carried to the leaves by stomata.
Water is carried to the leaves by xylem.
Answer:
I think Water is carried to the leaves by xylem.
Answer:
d
Explanation:
During a chemistry lab exercise, a student isolates a compound at STP. In her
lab report, she has identified it as an ionic compound. If it is an ionic compound, it
will likely have a _________boiling point and be a _______ at STP.
Choose the answer with the words in the correct order that complete the
passage.
A. high; liquid
B. low; gas
C. high; solid
D. low; solid
please answer asap thank you !! :)
Ionic compounds have a high boiling point and be a solid at STP.
What is ionic compound?Ionic compounds are those compounds which are formed due to high electrostatic attraction between cations and anions.
Ionic compounds are generally present in the solid state because of the presence of strong ionic bond. And due to this rigid structure boiling point of ionic compounds are very high as they want more energy to break their bonds.
Therefor, at standard temperature pressure (STP) ionic compounds will likely have a high boiling point and be a solid at STP.
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what is the chemical symbol for fluoride
Answer:
I think F
Explanation:
Please help asap! Giving brainliest to correct answer.
Three sections of the periodic table are labeled A, B, and C in the image below.
Which of the following statements is most likely true for an element present in section B?
Select one:
a. It is a highly reactive metal.
b. It is an inert gas at room temperature.
c. It may act as an insulator or a conductor.
d. It is a highly reactive liquid at room temperature.
Answer:
C. It may act as an insulator or a conductor.
Explanation:
Group B are the metalloids, so they have properties of both metals and nonmetals.
The statement which is most likely true for an element present in section B is: C. It may act as an insulator or a conductor.
A periodic table can be defined as an organized tabular array of all the chemical elements, which is typically arranged in order of increasing atomic number or number of protons (in rows).
In this diagram, the chemical element that is present in section B of the periodic table is a metalloid.
A metalloid can be defined as a chemical element that are typically intermediate between those of semiconductors, non-metals and metals.
Thus, a metalloid has both chemical and physical properties that are a combination of metals and non-metals or semiconductors.In this context, the statement which is most likely true for an element present in section B is that it may act as an insulator or a conductor because it is a metalloid.
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if you start with 4.3 moles of NH3, how many moles of NANH2 can be produced
Explanation:
Mole ratio of NH3 to NaNH2 = 2 : 2.
Moles of NaNH2 produced
= 4.3mol * (2/2) = 4.3mol.
A given compound has the following solubility properties. At room temperature, it is soluble in diethyl ether but insoluble in both ethanol and water. At higher temperatures, it is soluble in both diethyl ether and ethanol, but insoluble in water. Propose a procedure for purifying this compound by recrystallization.
Answer:
See explanation
Explanation:
If we desire to recrystallize the given compound then we must do the following;
1) Add the compound to ethanol and heat the system
2) As the solute dissolves, the solution is allowed to cool
3) The solution may be seeded or the vessel scratched to aid crystallization.
4) The pure crystals are now filtered out, washed and dried.
Remember that recrystallization has to do with dissolving a solute in a solvent in which it is only soluble at high temperature but insoluble at low temperature.
The solvent dissolves the impure solute while pure crystals emerges as the temperature decreases.
A pi bond involves: Select the correct answer below: direct orbital overlap with the electron density concentrated along the internuclear axis. side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis. side-by-side, or lateral orbital overlap with the electron density concentrated along the internuclear axis. none of the above
Answer:
side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.
Explanation:
Pi bond is a type of covalent bond in which the internuclear axis has regions of orbital overlap below and above it i.e on opposite sides. As a result of the orbital overlap, a node is created along the internuclear axis.
This ultimately implies that, a pi bond is formed due to the lateral (side-by-side) overlap of the unhybridized P-orbital comprising of at least a node along the internuclear axis.
Hence, a pi bond involves side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.
Additionally, a node is typically formed where an electron cannot be found.
A sample of compound A (a clear, colorless gas) is analyzed and found to contain 4.27g carbon and 5.69g oxygen. A sample of compound B (also a clear, colorless gas) is analyzed and found to contain 5.19g carbon and 13.84g oxygen. Are these data an example of the law of definite proportions, the law of multiple proportions, or neither? What do these data tell you about substances A and B?
Answer:
law of multiple proportions
Explanation:
The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in simple multiple ratio.
We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.
The substances A and B must be CO and CO2 respectively.
Which refers to any disturbance that carries energy from one place to another?
Answer:
A wave
Explanation:
A wave is a disturbance that carries energy from one place to another. Matter is not carried with the wave but instead a wave can move through matter.
Answer:
A Wave
Explanation:
Define the following Vocabulary words
1. Archae Bacteria
2. Bacteria
3. Eukarya Kingdom
4. Domain
Which best describes a hydrate?
A.) It has water molecules bonded directly to it.
B.) It lacks water molecules ik it’s crystal lattice.
C.) It lacks hydrogen and oxygen atoms, which make up water.
D.) It has water molecules incorporated into its crystal lattice.
Why do we see this star pattern in the winter, but not at other times of the year? (2 points)
Answer: We see constellations at different times of the year - spring, summer, fall, & winter. This occurs because the Earth is orbiting the Sun.
Explanation:
It’s a simple question in Welding when you use a torch if you add a lot of oxygen to the fuel what happens does it burn faster or what I want to know
Answer:
Easy, the flame is smaller but burns hotter.
Explanation:
what do you think will happen if there is no coal.
Answer:
If coal and petroleum will get exhausted it will be very difficult for us to transport because most vehicles depends on petroleum, Transport on Earth will became complicated, and if coal will get exhausted we will lose an unique fossil fuel. Coal is used in various domestic and industrial purposes.
In a disproportionation reaction, the disproportionate substance
A. has exactly one oxidation state.
B. has exactly two oxidation states.
C. has at least three oxidation states.
D. has either one or two oxidation states.
Answer:
The answer is C: has at least three oxidation states.
Explanation:
you're welcome
Answer:
C
Explanation:
got it right on Edge
이
Determine the the nuclei indicated in blanks in the
right side when Radium (Ra-226) undergoes an
alpha decay
Ne
226/ 88
Ra -->
+
The daughter isotope : Radon-222 (Rn-222).
Further explanationGiven
Radium (Ra-226) undergoes an alpha decay
Required
The daughter nuclide
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
alpha α particles ₂He⁴ beta β ₋₁e⁰ particles gamma particles ₀γ⁰ positron particles ₁e⁰ neutron ₀n¹The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same
Radium (Ra-226) : ₈₈²²⁶Ra
Alpha particles : ₂⁴He
So Radon-226 emits alpha α particles ₂He⁴ , so the atomic number decreases by 2, mass number decreases by 4
The reaction :
₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn
(10 points) A basement (with volume V) in a residence is found to be contaminated with radon coming from the ground through the floor drains. The concentration of radon in the room is [Co] under steady-state conditions. The room behaves as a CSTR, and the decay of radon is a firstorder reaction with a decay rate constant of [k]. a. Now the condition changes: The source of radon is closed off but there is no ventilation. What is the equation that describes the concentration of radon in the basement with time [Ct]
Answer:
[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]
Explanation:
The equation that describes the concentration of the radon in the basement with time Ct is;
[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\theta} + k \Big) t \Big ] }[/tex]
where;
[tex]C_o[/tex] = concentration of the radon
[tex]C _ {Out}[/tex] = allowable radon concentration
k = decay rate constant
= theoretical detention
t = time needed to lower the radon concentration
The theoretical detention [tex]\theta =\dfrac{V}{Q}[/tex]
∴
[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]
Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene
Answer:The correct names for the structure are:
--> 1. 1-bromo-3-chlorobenzene.
--> 3. meta-bromochlorobenzene.
--> 6. m-bromochlorobenzene.
Explanation:
Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.
Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.
The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:
--> the functional group is benzene
--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)
--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.
The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.
--> ortho or O : this is used when the substituents are close to each other in the benzene ring.
--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.
--> para or (p): This is used when the substituents are across each other in the benzene ring
From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.
What happens to the reaction rate as a reactant gets used up?
A. The rate varies,
B. The rate goes down,
O c. The rate goes up.
D. The rate stays constant.
Answer: B. The rate goes down
Explanation:
Help pls!!!!!!!!!!!!!
Answer:
3rd
Explanation:
Part A
Summarize your research, and describe the attributes of the savanna.
Answer:
Savanna regions have two distinct seasons - a wet season and a dry season. There is very little rain in the dry season. In the wet season vegetation grows, including lush green grasses and wooded areas.
Savannas are grasslands found in Africa, Australia, South America, and India. The climate is warm or hot. Savannas experience both dry and rainy seasons. Each year, savannas receive about 20 to 50 inches of rain in a span of six to eight months. The other months are dryer. There’s also a threat of wildfires because of the severe dryness during these months. Grasslands are true to their name because their vegetation is mostly grass. Savannas are home to a wide range of animals, including different species of beetles and insects, which many creatures consume. Squirrels, mice, elephants, gazelles, and antelopes are the plant-eating animals that live in the savanna. Hyenas, lions, and leopards are some of the meat-eating animals in these areas. Some of the nonliving components of the system include very porous soil that allows water to drain easily.
Geosmin is an aroma compound found in raindrops. It's chemical formula is C12H22O. The molar mass is 182 g/mol. If you perform combustion analysis of 1.77 grams of this compound, how many grams of carbon should be isolated as CO2 during the analysis?
Answer:
5.13 g of CO₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C₁₂H₂₂O + 17O₂ —> 12CO₂ + 11H₂O
Next, we shall determine the mass of C₁₂H₂₂O that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of C₁₂H₂₂O = 182 g/mol.
Mass of C₁₂H₂₂O from the balanced equation = 1 × 182 = 182 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Mass of CO₂ from the balanced equation = 12 × 44 = 528 g
SUMMARY:
From the balanced equation above,
182 g of C₁₂H₂₂O reacted to produce 528 g of CO₂.
Finally, we shall determine the mass of CO₂ produced from the reaction. This can be obtained as follow:
From the balanced equation above,
182 g of C₁₂H₂₂O reacted to produce 528 g of CO₂.
Therefore, 1.77 g of C₁₂H₂₂O will react to produce = (1.77 × 528)/182 = 5.13 g of CO₂.
Thus, 5.13 g of CO₂ were obtained from the reaction.
Hurry I need Now!!!In which biome would the climax species be reached most quickly following a fire?
A Taiga
B desert
C Grassland
D. deciduous forest
E tropical rain forest
Answer:
D. Deciduous Forest.
Explanation:
Convert 8.876 × 10^12 m^2 to units of km^2.
Answer:
[tex]8.876\times 10^{18}\ km^2[/tex]
Explanation:
In this problem, we need to convert [tex]8.876 \times 10^{12}\ m^2[/tex] to km².
We know that,
1 km = 1000 m
⇒ 1 km² = 10⁶ m²
So,
[tex]8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2[/tex]
So, [tex]8.876 \times 10^{12}\ m^2[/tex] is equal to [tex]8.876\times 10^{18}\ km^2[/tex].
Breathing equipment used by rescue workers needs to capture the CO2 the humans breath out and produce O2 for them to breath in, like a plant during photosynthesis. One compound capable of doing this is potassium superoxide (KO2), which produces the salt by-product potassium carbonate. What is the balanced chemical equation for this reaction? Don't include states of matter.
Answer: [tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for reaction of potassium superoxide with carbon dioxide to produce oxygen and potassium carbonate will be:
[tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]