Answer:
17000 joules.
Explanation:
Explanation:
With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:
ΔH=mCΔT, where
ΔH=change in enthalpy (J)
m= mass of substance being heated (g) i.e. water in this question
C= specific heat capacity (J/g°C)
ΔT= change in temperature (°C)
We know mass=65g and ΔT=76°C−12°C=64°C
The specific heat capacity of water is 4.18J/g°C
Therefore, ΔH=65g⋅4.18Jg°C⋅64°C
=17388.8J
=17000J (2 significant figures)
30 ml of gas is changed from 4 atm to 2 atm what is the new volume
Answer:
[tex]\boxed {\boxed {\sf 60 \ mL}}[/tex]
Explanation:
In this problem, volume and pressure are changing, so we use Boyle's Law. This states that the volume of a gas is inversely proportional to the pressure. The formula for this law is:
[tex]P_1V_1=P_2V_2[/tex]
Originally the gas has a volume of 30 milliliters and a pressure of 4 atmospheres.
[tex]4 \ atm * 30 \ mL=P_2V_2[/tex]
The pressure is changed to 2 atmospheres, but the new volume is unknown.
[tex]4 \ atm * 30 \ mL = 2 \ atm *V_2[/tex]
We want to solve for the new volume (V₂). It is being multiplied by 2 atmopsheres. The inverse operation of multiplication is division, so we divide both sides by 2 atm.
[tex]\frac{4 \ atm * 30 \ mL}{ 2 \ atm}= \frac{ 2 \ atm *V_2}{2 \ atm}[/tex]
[tex]\frac{4 \ atm * 30 \ mL}{ 2 \ atm}= V_2[/tex]
The units of atmospheres (atm) cancel.
[tex]\frac{4 * 30 \ mL}{ 2 }= V_2[/tex]
[tex]\frac{120 \ mL}{2}= V_2[/tex]
[tex]60 \ mL= V_2[/tex]
The new volume of the gas is 60 milliliters.
How much heat is absorbed if 75.4 g of CO2 reacts?
Answer:
6x
Explanation:
Answer:
Δ
H
=
−
389 kJ