What scientific law or principle allows us to
say that all the PE is converted to KE?

Answer:

The parallel plate capacitor is the simplest form of capacitor. ... The property of a capacitor to store charge on its plates in the form of an electrostatic field is called the Capacitance of the capacitor. Not only that, but capacitance is also the property of a capacitor which resists the change of voltage across it.

Explanation:

credits :- adultsscience

Explanation:

Capacitance exists wherever conductive material is separated by insulating material. 

Capacitive structures have the ability to store energy as an electric field;

when a capacitive structure has been designed as an electrical component that has a specified amount of capacitance, it is called a capacitor.

Capacitance symbol is C

you can get a meter for Capacitance

Capacitance formula is C = ε(A/d) where ε represents the absolute permittivity of the dielectric material being used.

simple piece of wire has very low capacitance

Answer:hereeee for pointssss only

Explanation:

The acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]

It is given that for a simple pendulum on Ganymede

Lenth= 1.00 m

the time period  T= 10.5 sec

The formula for a time period of simple pendulum will be

[tex]T=2\pi\sqrt{\dfrac{l}{g} }[/tex]

By rearranging the formula

[tex]g=l\times (\dfrac{2\pi}{T} )^2[/tex]

[tex]g=1\times (\dfrac{2\pi}{10.5} )^2=0.3577\frac{m}{s^2}[/tex]

[tex]g=0.3577\ \frac{m}{s^2}[/tex]

Thus the acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]

To know more about simple pendulums follow

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Answer:

N = 198.3 N,  fr = 126.98 N and    μ = 0.64

Explanation:

For this exercise we must use the translational equilibrium condition.

Let's set a reference system with the x-axis horizontally and the y-axis vertical. Let's use trigonometry to decompose the applied force

      cos θ = Fₓ / F

      sin θ = F_y / F

      Fₓ = F cos θ

      F_y = F sin θ

      Fₓ = 159 cos 37 = 126.98 N

      F_y = 159 sin 37 = 95.69 N

Y axis  

    N + F_y - W = 0

    N = W - F_y

    N = 294 - 95.69

    N = 198.3 N

X axis

    Fₓ -fr = 0

     Fₓ = fr

     fr = 126.98 N

the expression for the friction force is

       fr = μ N

       μ = fr / N

       μ = 126.98 / 198.3

       μ = 0.64

Answer: [tex]337.5\ N[/tex]

Explanation:

Given

Energy associated with football is [tex]E=108\ J[/tex]

The receiver takes 0.32 m to stop the ball

Suppose F is the force applied

[tex]\therefore W=F\cdot d\\\text{Insert the values}\\\\\Rightarrow 108=F\times 0.32\\\\\Rightarrow F=\dfrac{108}{0.32}\\\\\Rightarrow F=337.5\ N[/tex]

Answer:

the answer is

D.refraction

The correct option is: "none of these statements is true".

To find out the correct option among all the options, we need to know more about the electron and proton.

Thus, we can conclude that the option (e) is correct.

Learn more about electron and proton here:

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#SPJ2

Explanation:

Efficiency is often measured as the ratio of useful output to total input, which can be expressed with the mathematical formula r=P/C, where P is the amount of useful output ("product") produced per the amount C ("cost") of resources consumed.

i dont know what the answer really is but this is what i think

Answer:

1.#(#('#;#+#('#;#+jwhsjjshajahkqhwmskek

Explanation:

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bifjibjtgitkriwgi eror iurh oryi ehiwyrfoerhfoefoeuis in het begin van een tui ueen uitgebreide beschrijving ygt grup u een uitgebreide keuze u guugu

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Answer:

This is because it is derived from newtons and metres as shown in the expression;

Explanation:

[tex]pressure = \frac{force}{area} \\ P= \frac{F}{A} \\ P= \frac{newtons}{ {m}^{2} } \\ = pascals[/tex]

Answer:

Unit of pascal is called derived unit because it involves three fundamental units i.e.meter,kg,and second.

Explanation:

formula of pascal=kg/m/s^2

Answer:

6.67

Explanation:

[tex]ke = \frac{1}{2} m {v}^{2} [/tex]

[tex]44 = \frac{m {4}^{2} }{2} \\ \frac{88}{16} = m \\ 5.5 = m[/tex]

Answer:

32 g

Explanation:

Applying,

R = (R')2ᵃ/ⁿ............... Equation 1

Where R = Amount of mercury-197 needed to be ordered, R' = amount of mercury-197 needed for the study, a = time allowed for shipment, n = half life.

From the question,

Given: R' = 1 g, a = 15 days, n = 3 days

Substitute these values into equation 1

R = 1(2¹⁵/³)

R = 1(2⁵)

R = 32 g

Answer:

Solution given:

any three applications of electromagnetic waves are:

2.

Solution given;

power [P]=100W

Current [I]=5A.

Voltage [V]=?

we have

P=IV

100=5*V

V=[tex] \frac{100}{5} [/tex]=20V

the voltage of the battery used in the car is 20V.

Answer:

Explanation:

1. Electromagnetic waves are used to broadcast radio and TV signals. It is also used for wireless charging cell phones. Cell phone itself uses electromagnetic waves for its cell signal.

See attached drawing for ray diagram.

2. Given: the power of a bulb of car is 100 W and 5A current flows through the filament of the bulb.

Power of a bulb is given by voltage * current.

So 100W = voltage * 5A

Voltage = 100/5 = 20V

Answer:

[tex]1.78\:\mathrm{m}[/tex]

Explanation:

Kinematics equations used:

[tex]v_f=v_i+at,\\\\\Delta y = v_it+\frac{1}{2}at^2,\\\\v_f^2=v_i^2+2a\Delta x[/tex]

Other equations used:

[tex]\Delta x =v_i\cdot t,\\\text{-basic trigonometry for right triangles},\\\text{-application of physics concepts}[/tex]

By finding the horizontal component of the projectile's initial launch, we can find how long it will take for the projectile to reach the hill.

Since the projectile is launched at 12 m/s 30 degrees above the horizontal, we can use basic trig for a right triangle to find the horizontal component of the launch:

[tex]\cos 30^{\circ}=\frac{x}{12},\\x=12\cos 30^{\circ}\approx 10.3923048454\:\text{m/s}[/tex]

Now we can use [tex]\Delta x =v_x\cdot t[/tex] to find the time it will take to reach the hill:

[tex]7.5=10.3923048454\cdot t,\\t=\frac{7.5}{10.3923048454}\approx 0.72168783648\:\text{s}[/tex]

To find the total flight time the projectile would take if it were to land back to the same height it started out with, we can use the following kinematics equation:

[tex]v_f=v_i+at[/tex]

We'll use basic trig for a right triangle again to find the vertical component of the velocity at launch:

[tex]\sin 30^{\circ}=\frac{y}{12},\\y=12\sin 30^{\circ}=6\:\text{m/s}[/tex]. (recall [tex]\sin 30^{\circ}=\frac{1}{2}[/tex])

Now plugging this value in:

*Note: the projectile will hit the ground with a vertical velocity equal in magnitude but opposite in direction than the projectile's initial vertical velocity at launch

[tex]-6=6+(-9.8\cdot t),\\t=\frac{-12}{-9.8},\\t=1.22448979592\:\text{s}[/tex]

^This is the total flight time the projectile would take if it were to land back to the same height it started with. Since acceleration is constant, we can divide this time by two to find the time it would take to reach maximum height.

[tex]1.22448979592\div 2=0.61224489795\:\text{s}[/tex]

Thus, it will take [tex]0.61224489795\:\text{s}[/tex] to reach maximum height, meaning that it will take [tex]0.72168783648 - 0.61224489795=0.10944293853\:\text{s}[/tex] to land on the hill after reaching maximum height. Now that we've found this, we can use the following kinematics equation to find the vertical displacement from the projectile's max height to the hill:

[tex]\Delta y =v_it+\frac{1}{2}at^2[/tex]

At maximum height, the projectile's vertical velocity will be zero. Therefore, [tex]v_i=0[/tex] and we have:

[tex]\Delta y =\frac{1}{2}at^2[/tex]

Plugging in values , we have:

[tex]\Delta y =\frac{1}{2}\cdot 9.8\cdot 0.10944293853^2=0.05869100829\:\text{m}[/tex]

This means that the hill is [tex]0.05869100829\:\text{m}[/tex] lower than the max. height the object will reach.

To find the height of the hill from the ground, we will use the following kinematics equation:

[tex]v_f^2=v_i^2+2a\Delta x,\\-6^2=0+2\cdot-9.8\cdot\Delta x,\\36=-19.6\Delta x,\\\Delta x =\frac{36}{-19.6},\\\Delta x =-1.83673469388\:\text{m}[/tex]

Therefore, the max. height that the object will reach is [tex]1.83673469388\:\text{meters}[/tex].

Thus, the hill's height is [tex]1.83673469388-0.05869100829=1.77804368559\:\text{m}\approx\boxed{1.78\:\mathrm{m}}[/tex].

Answer:

please give me brainlist and follow

Explanation:

The measuring sensitivity of liquid-in-glass thermometers increases with the amount of liquid in the thermometer. The more liquid there is, the more liquid will expand and rise in the glass tube. For this reason, liquid thermometers have a reservoir to increase the amount of liquid in the thermometer.

Answer:

Explanation:

a. the sound energy is converted into electrical signals using diaphragm present in the microphone and these signals then reach to the speakers and then convert- ed back to sound. The electrical current generated by a micro- phone is very small and referred to as MIC-level; this signal is typically measured in millivolts.

b. Thermodynamics

Answer:

Given that refractive index of the material is √2. i.e. n = √2. Hence, critical angle for the material is 45°

Answer:

It is 3 m/s² downward.

Explanation:

The mass of an object, m = 30 kg

Upward force, F = 200 N

Downward force, F' = -300 N

We need to find the magnitude and direction of its acceleration.

Net force = F+F'

= 200+(-300)

= -100 N

We know that,

Force, F = ma, a is acceleration of the object

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{-100}{30}\\\\a=-3.33\ m/s^2\approx -3\ m/s^2[/tex]

Hence, the acceleration is -3 m/s² and it is acting in the downward direction.

Answer:

Horizontal component = 60.05 m/s

vertical component = 22.96 m/s

Explanation:

cosine(angle) = adjacent / hypotenuse or  horizontal / angled velocity

angled velocity * cosine (angle) = horizontal velocity

65 m/s * cosine(22.5) = 60.05 m/s

sine(angle) = adjacent/ hypotenuse or vertical/ angled velocity

angled velocity * sine (angle) = vertical velocity

65m/s sine(22.5) = 22.96 m/s

Answer:

Explanation:

This is an energy conservation problem in that the total energy available to a system s constant trhoughout the whole problem. That is, in equation form:

TE = PE + KE. This is a bit of a problem due to sig figs here, but I will keep with the rules for them all the way up til the end of the problem (I'll tell you when I veer away from the rule and why I did when I get there).

We first need to find the total energy available to the system and then use that value throughout the rest of the problem.

TE = PE + KE where

PE = mgh (mass times gravity times height of the object) and

KE = [tex]\frac{1}{2}mv^2[/tex] (one-half times the mass of the object times the square of the velocity of the object). We solve for PE first, rounding to the correct number of sig figs:

PE = 97(9.8)(3.1) and

PE = 2900 J (2 sig figs here since all the numbers given have 2 sig figs in them). Now for KE

[tex]KE=\frac{1}{2}(97)(8.0)^2[/tex] which, to 2 sig figs (notice I added a .0 to the 8), is

KE = 2200. This means that the total energy available to the sled throughout the whole trip is

TE = 2900 + 2200 so

TE = 5100 J

Now for the second part of the problem, the sled is at a different height so the PE is different, and we are asked to find the velocity at the top of this second hill. The total energy equation then is

5100 = PE + KE. Solving for PE first:

PE = (97)(9.8)(1.2) and, to 2 sig figs:

PE = 82. Now for the KE:

[tex]KE=\frac{1}{2}(97)v^2[/tex]. Plugging all of that into the total energy equation gives us:

[tex]5100=82+\frac{1}{2}(97)v^2[/tex] and isolating the v:

[tex]v=\sqrt{\frac{2(5100-82)}{97} }[/tex] and this is where I veer away from the sig figs. Doing the subtracting first, as we should, means that we would round to the hundreds place. Since the least significant place in the number 82 is the tens place and the least significant place in the 5100 is in the hundreds place, we round to the hundreds place. But I didn't keep to this rule because I'm not sure how adamant your physics teacher is about sig figs. I'll give you the answer that I would expect from my students (the right one) after I give you this one. I just simply subtracted 5100 - 82 and used the answer the calculator gave me which was 5018:

[tex]v=\sqrt{\frac{2(5018)}{97} }[/tex] gives us that the velocity at the top of the 1.2 meter hill is

10.2 m/s.

Doing this the right way, using the rules for sig figs properly:

[tex]v=\sqrt{\frac{2(1500)}{97} }[/tex] gives us, to 2 sig figs,

v = 1.0 × 10¹ m/s

Answer:

greater than

Explanation:

A bowling ball is bigger than a golf ball and greater than means bigger.

Answer:

Gravity.

Rocket ships.

Ball.

Basketball.

Explanation:

Gravity has to do a lot with air. It puts the planets in there area.

Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.

A ball gets throwed in the air, which gravity comes into place.

Basketball is also a similar example to a ball.

Answer:

The force that must be applied to maintain a constant velocity is equal o the friction force which is 2,650 N

The total force required from rest is (2,650·t + 20,972.[tex]\overline 2[/tex])/t N

Explanation:

The given data of the car in motion are;

The mass of the car, m = 1,510 kg

The force of friction from the road, [tex]F_f[/tex] = 2,650 N

When the car is moving at 50.0 km/hr, we have;

v = 50.0 km/hr = 250/9 m/s ≈ 13.88889 m/s

According to Newton's first Law of motion, a body will continue in a state of rest or in uniform motion along a straight line unless acted on by a force

The force acting on the car in motion = 2,650 N

When the car is moving at a constant velocity, the forces acting on the  car are in equilibrium and the net force is zero

Therefore;

The magnitude of the force that will keep the car moving at a constant velocity = The friction force of the road = 2,650 N

The direction of the force = In the direction of motion of the car

Where the time it takes the car to accelerate from rest to 50.0 km/hr = t seconds, we have;

The force required to move at a constant speed = 1,510 kg × (250/9 m/s - 0)/t s = 20,972.[tex]\overline 2[/tex]/t N

The total force required to move forward with a constant velocity of 50.0 km/hr becomes 20,972.[tex]\overline 2[/tex]/t N + 2,650 N = (2,650·t + 20,972.[tex]\overline 2[/tex])/t N

Where;

t = The time it takes the car to reach 50.0 km/hr from rest.

Answer:

Some of the universe's heavier elements are created by neutron star collisions. ... Light elements like hydrogen and helium formed during the big bang, and those up to iron are made by fusion in the cores of stars. Some heavier elements like gallium and bromine need something more, such as a supernova.

Explanation:

Answer:

barometer

Explanation:

Answer:

barometer

Explanation:

Answer: • Fewer teens admitted to drinking and driving in 2013 than in 2004.

• In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Explanation:

The conclusions about alcohol and teen driving that are supported by the data provided will be:

• Fewer teens admitted to drinking and driving in 2013 than in 2004.

• In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Other options are incorrect as the conclusion wasn't gotten from the data that was orovufed

Answer:

Fewer teens admitted to drinking and driving in 2013 than in 2004.

In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Explanation:

Answer:

i think its 470

Explanation:

Answer:

transferred from one object to another. Charged objects can exert forces on other charged ... Electric charge can be measured using the law for the forces between charges

The electric force exerted by the +2 C on another +2 C when at a distance of 25 m is 5.76×10⁷ N

F = Kq₁q₂ / r²

Where

F = Kq₁q₂ / r²

F = (9×10⁹ × 2 × 2) / (25)²

F = 36×10⁹ / 625

F = 5.76×10⁷ N

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