What test would be done to prove the color of specific compounds is due to metal ions apart from flame test

1) A 45.7 g sample of glass was brought to thermal equilibrium with boiling water and then transferred to 250.0 g of water that was at 22.5 °C. This combination reached thermal equilibrium at 24.2 °C. What is the specific heat capacity of glass?

2) What mass of silver at 100.0 °C, when added to 150.0 g of water at 21.0 °C, would raise the water’s temperature to 24.0 °C ?

3) The molar heat of fusion of H2O is 6.1 kJ/mole. What amount of energy would be needed to melt 376 g of ice at 0.0 °C?

Answer:

B

Explanation:

B

have cells with a cell wall and are heterotrophic

Answer:

Outside air

Nose

Lungs

Bloodstream

Cell

Explanation:

We breathe in oxygen from the outside air in through our nose and it travels to our lungs. Inside our lungs, we have Avioli's that diffuse oxygen into our bloodstream and the bloodstream helps the oxygen travel into our cells.

Hope this helps :)

Respiration is the process of exchange of gases between the cell and atmosphere. The path of respiration involves Outside Air⇒  Nose⇒ Lungs⇒ Bloodstream⇒ Cell.

Respiration is the movement of oxygen from the outside environment to the cells and the removal of carbon dioxide from the cells into the outside environment.

Respiration is of two types depending upon the presence of oxygen:

1. Aerobic Respiration: This takes place in the presence of oxygen

2. Anaerobic Respiration: This takes place in the absence of oxygen.

The path of respiration includes inspiration of outside air into the nose, through the nostrils this air is passed on to the lungs. The alveoli is the site of gaseous exchange in the lungs. In the lungs, oxygen is inspired and carbon dioxide is expired.

The oxygen gas which is inspired by the lungs is dissolved in the blood. Oxygen forms a complex with the hemoglobin protein present in the blood. This blood is then circulated to all the cells and tissues of body. Thus, the oxygen is supplied to all the cells and tissues. The path includes Outside Air⇒  Nose⇒ Lungs⇒ Bloodstream⇒ Cell.

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Answer:

ionic bonds in the solute are broken and new ion-dipose forces in the solution are formed

Explanation:

Answer:

Atoms

Explanation:

According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.

Answer:

Option D, 116 g of NaNO3

Explanation:

An unsaturated solution is the one in which the amount of salt dissolved in more than the maximum amount of salt that can be dissolved in it.

At 50 degree Celsius, 37 grams of salt can be dissolved in 100 ml of water. Hence, 116 gram of salt is the correct answer

(◕‿◕✿) Hey There!

Answer → The Waves Size depends on ★ wind speed ★ , ★ wind duration★ , and the ★ area over which the wind is blowing ★

✨Hope This Helps!✨

Answer:

1. 250 J

2. 500000 J

3. 146250 J

4. 400 J

Explanation:

1. Determination of the energy of the ball.

Mass (m) = 5 Kg

Velocity (v) = 10 m/s

Energy (E) =?

E = ½mv²

E = ½ × 5 × 10²

E = 2.5 × 100

E = 250 J

2. Determination of the energy of the rock.

Mass (m) = 250 Kg

Height (h) = 200 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E) =?

E = mgh

E = 250 × 10 × 200

E = 500000 J

3. Determination of the energy of the car.

Mass (m) = 1300 Kg

Velocity (v) = 15 m/s

Energy (E) =?

E = ½mv²

E = ½ × 1300 × 15²

E = 650 × 225

E = 146250 J

4. Determination of the energy of the bullet.

Mass (m) = 0.005 Kg

Velocity (v) = 400 m/s

Energy (E) =?

E = ½mv²

E = ½ × 0.005 × 400²

E = 0.0025 × 160000

E = 400 J

Answer:

Sorry for the late answer but

Number 1 is 250 J

Number 2 is 500000 J

Number 3 is 146250 J

Number 4 is 400 J

Explanation:

Answer:

the answer is b

hope this helps you!!

Have a lovely day!

-millie :D

Answer:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

The coefficients are: 1, 6, 3, 2

Explanation:

__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃

To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃

There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:

Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

Now, the equation is balanced.

Therefore, the coefficients are: 1, 6, 3, 2

Answer:

The new volume will be  

0.7 L

Explanation:

This is an illustration of Charles' law, some of the time called the temperature-volume law. It expresses that the volume of a gas is straightforwardly corresponding to the Kelvin temperature, while pressing factor and sum are held steady.  The condition is  V  1  T  1  =  V  2  T  2  , where  V  is volume and  T  is temperature in Kelvins.  Known  V  1  =  0.5 L  T  1  =  20  ∘  C  +  273.15  =  293 K  T  2  =  150  ∘  C  +  273.15  =  423 K  Obscure  V  2  Arrangement  Revise the condition to confine  V  2  . Substitute the known qualities into the condition and address.  V  2  =  V  1  T  2  T  1  V  2  =  (  0.5  L  ×  423  K  )  293  K  =  0.7 L  adjusted to one huge figure

Answer:

Insects belong to the class Insecta, and arachnids to the class Arachnida; both classes fall under the Arthropoda phylum, along with crustaceans (crabs, lobster and shrimp). All arthropods have an exoskeleton and jointed legs. They have segmented bodies and appendages, which are divided into different segments. Arachnids belong to an even larger group of animals called “arthropods” which also include insects and crustaceans (lobster, crabs, shrimp, and barnacles).

Explanation:

Answer:

587.5 L (Option A)

Explanation:

The reaction is:

2 C₈H₁₈ + 25O₂  → 16CO₂  + 18H₂O

We know that in STP conditions 1 mol of any gas is contained in 22.4L

Then, we can make a rule of three, to determine the moles of produced carbon dioxide.

22.4L is the volume for 1 mol

376 L will be the volume for  (376 . 1) 22.4 = 16.78 moles at STP conditions.

Stoichiometry is 16:25.

16 moles of CO₂ are produce by the reaction of 25 moles of O₂

Then, 16.78 moles of CO₂ were produced by (16.78 . 25) /16 = 26.2 moles.

Now, the rule of three again.

1 mol of oxygen gas is contained at 22.4L, at STP conditions

26.2 moles might be contained at (26.2 . 22.4)/1 = 587.5 L

Answer:

4.90 x 10 24 atoms

Explanation:

the 24 is the exponent for the 10

Answer:

MgO

is the correct answer

hope it helps

Answer:

gravity

Explanation:

Gravity is the force that pulls us to the surface of the Earth, keeps the planets in orbit around the Sun and causes the formation of planets, stars and galaxies.

Hope this helped!!!

Answer:

2.7*10^-13

coefficient= 2.7

exponent= -13

Explanation:

Answer: 2.7 x 10^-13

Explanation:

Answer:

52

Explanation:

Answer:

3) The People

Explanation:

Members Of Congress In Both Houses ( Democrats And Republicans ) Are Elected By Direct Popular Vote. Senators Are Elected Via A Statewide Vote ( The People All Around The World ) And Representatives Are Elected By Voters In Each Congressional District.

1 mole is equal to 1 moles CaCO3, or 100.0869 grams.

A mole is just a measuring scale. In reality, it's one of the International System of Units' seven foundation units (SI). When already-existing units are insufficient, new ones are created.

The mole is a SI unit that is used to quantify any quantity of a substance. The word "mole" is shortened to "mol".

A mole consists of precisely 6.022140761023 particles. The "particles" could be anything, from tiny things like electrons or atoms to enormous things like stars or elephants.

Therefore, 1 mole is equal to 1 moles CaCO3, or 100.0869 grams.

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Answer:

[tex]206.6\ \text{kPa}[/tex]

Explanation:

[tex]P_1[/tex] = Initial pressure = 200 kPa

[tex]P_2[/tex] = Final pressure

[tex]T_1[/tex] = Initial temperature = [tex]30^{\circ}\text{C}[/tex]

[tex]T_2[/tex] = Final temperature = [tex]40^{\circ}\text{C}[/tex]

We have the relation

[tex]\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=\dfrac{T_2}{T_1}P_1\\\Rightarrow P_2=\dfrac{40+273.15}{30+273.15}\times 200\\\Rightarrow P_2=206.6\ \text{kPa}[/tex]

The pressure that would be exerted after the temperature change is [tex]206.6\ \text{kPa}[/tex].