Answer:
Refraction is merely one of several possible boundary behaviors by which a light wave could behave when it encounters a new medium or an obstacle in its path. The transmission of light across a boundary between two media is accompanied by a change in both the speed and wavelength of the wave.
Explanation:
3. Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth's orbit remained
the same as it is now, then compared with gravitational force between Earth and the sun, the gravitational force
between Earth and the star would be -
A. half as much
B. the same
C. two times as much
D. four times as much
Answer:
F1 = G M m / R^2 current force on earth
F2 = G M * 2 m / R^2 force if mass were doubled
F2 / F1 = 2 the force would be twice as large
The gravitational force between two objects not only depends on the mass but also the distance between them. If the distance to the star is same as to sun, then by doubling mass force also doubles. Thus option C is correct.
What is universal law of gravitation?Gravitational force is the attractive force by which an object attracts other objects into its centre of mass. We are all standing in the ground because of the gravitational pull by earth.
The gravitational force between two objects of mass M1 and M2 at a distance r is written as follows:
g = G M1 M2/ r ² . where, G is gravitational constant.
As per this relation, gravitational force is directly proportional to the mass and inversely proportional to the square of the distance.
If the star has a distance from earth equal to the distance between sun and earth, but its mass is double the mass of sun, then the gravitational force will be two times compared with the sun.
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Compare the amount of kinetic energy of particles in each state of matter- solid, liquid, gas
Answer:
gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)
A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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What do scientists theorize about the origins of the Moon? Choose the most accepted explanation.
Answer:
What is most widely accepted today is a the giant-impact theory. It proposes that the Moon formed during a collision between the Earth and another small planet, about the size of Mars. The debris from this impact collected in an orbit around Earth to form the Moon.
To overcome an object's inertia, it must be acted upon by __________. A. Gravity B. Energy C. Force D. Acceleration Please select the best answer from the choices provided. A B C D.
Taking into account the Newton's first Law, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.
Newton's First Law, also called the Law of inertia, indicates that "Every body perseveres in its state of rest or of uniform rectilinear motion unless it is forced to change its state by forces impressed on it." This means that for a body to come out of its state of rest or of uniform rectilinear motion, it is necessary for a force to act on it.
In other words, it is not possible for a body to change its initial state (be it rest or motion) unless one or more forces intervene.
Finally, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.
Learn more:
https://brainly.com/question/1083492https://brainly.com/question/14113252?referrer=searchResultsAnswer:
C) Force
Explanation:
Is mechanical energy the result of both kinetic and potential energy?
Answer:
Yes
Explanation:
Because putting them together would make a type of energy making the answer yes
The force involved in falling of an apple from a tree is known as? (a) Magnetic force (b) electrostatic force (c) Contact force (d) gravitational force
Answer:
it is known as gravitational force
Answer:
Gravitational force.
Explanation:
Gravitational force is the force that allows objects to drop which is how the apple dropped.
How long did it take Sally riding her bike to slow down from 18 km/h to 6 km/h if the deceleration was at a rate of 4 km/h/s?
4.5 seconds
3 seconds
3 hours
6 seconds
If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?
Answer:
10 m/sExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
Since we're finding the velocity we make v the subject
That's
[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]
From the question
k = 5 J
m = 0.1 kg
We have
[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]
We have the final answer as
10 m/sHope this helps you
A neutral object has:
a. Zero electrons.
b. Zero protons.
c. Only neutrons.
d. An attraction to negative objects.
e. An attraction to neutral objects.
Answer:
c. Only neutrons.
hope it helps :)
GUYS COULD SOMEONE PLEASE HELP ME?
PLEASE ASAP
Write a summary of how the eye works:
Answer:
Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.
Explanation:
Now you need to put handles on your cookware! You have five different options, including metals and nonmetals such as wood. Based on specific heat, which material would be the best choice? the material with the smallest specific heat the material with the greatest specific heat the material whose specific heat is farthest from the specific heat of the metal pan the material whose specific heat is closest to the specific heat of the metal pan.
Answer: B the material with the greatest specific heat
Explanation:
Just did the assignment
Answer:
B. The material with the greatest specific heat
Explanation:
yvonne van gennip of the netherlands ice skated 10.0 km with an average speed of 10.8 m/s. suppose vang ennip crosses the finish line at her average speed and takes a huge boquet of flowers handed to her by a fan. as a result her speed drops t o10.01 m/s. if van gennip’s mass is 63.0 kg what is the mass of the boquet?
By conservation of momentum, we will find that the mass is 4.97 kg.
So in the original system, we have two objects, the bouquet of flowers of mass M that is not moving and Yvonne, which has a mass of 63 kg and a speed of 10.8 m/s.
Then the total momentum of this system is:
P = (63kg)*(10.8m/s) + M*(0 m/s) = 680.4 kg*m/s.
Remember the conservation of momentum, thus, the final momentum must be equal to the above one.
In the final situation, Yvonne and the bouquet move together with a speed of 10.01 m/s,
Then the final momentum is:
P' = (63kg + M)*(10.01 m/s)
And that must be equal to the initial momentum, then we have the equation:
(63kg + M)*(10.01 m/s) = 680.4 kg*m/s.
630.63kg*m/s + M*10.01 m/s = 680.4 kg*m/s.
M*10.01 m/s = 680.4 kg*m/s - 630.63kg*m/s = 49.77 kg*m/s
M = (49.77 kg*m/s)/(10.01 m/s) = 4.97 kg
So the mass of the bouquet is 4.97 kg
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A car traveling at 100 km/hr strikes and unfortunate bug and splatters it.the net force of impact is
Answer:
it's zero
Explanation:
it is there is your answer
Desperate Please Hurry
What was the evidence that Earth was round before there were photos from space?
Answer:
?????
Explanation:
????????????????????‽,??????????????????‽????????????????????????????????????
A digital stopwatch reading 0:13 37. Read the elapsed time on the stopwatch and answer the questions. In which digit is there the least amount of confidence? How many significant figures does this measurement have?.
The digit with the least amount of confidence can be seen in the second part which is 7.
The number of significant figures in the measurement of the stopwatch is 4.
An elapsed time is the difference between the time prior to the commencement of an event and the time at which the event has ended.
From the stopwatch, the elapsed time is given as:
0hour : 13 minutes : 37 seconds
The digit with the least amount of confidence can be seen in the seconds part is 7.
A significant figure is a real figure that is dependable and absolutely essential to convey the quantity of something.
The number of significant figures in the measurement of the stopwatch is 4.
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Answer: 7 and 4
Explanation: A digital stopwatch reading 0:13 37.
Read the elapsed time on the stopwatch and answer the questions.
In which digit is there the least amount of confidence?
7
How many significant figures does this measurement have?
4
A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.
Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.
A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is
A. 1350 J
B. 8820 J
C. 4410 J
D. 0 J
and his velocity is
E. 4.5 m/s
F. 0 m/s
G. 3.2 m/s
H. 9.9 m/s
Please help will mark brainliest
Answers:
The gravitational potential energy of the diver when he reaches point C is 4410 J.
The velocity of the diver is 9.9 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
[tex]\\ \sf\longmapsto PE=mgh[/tex]
[tex]\\ \sf\longmapsto PE=90(5)(9.8)[/tex]
[tex]\\ \sf\longmapsto PE=4410J[/tex]
Now
It's converted to kinetic energy while reaching ground.
[tex]\\ \sf\longmapsto K.E=4410[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]
[tex]\\ \sf\longmapsto 90v^2=8820[/tex]
[tex]\\ \sf\longmapsto v^2=98[/tex]
[tex]\\ \sf\longmapsto v=9.9m/s[/tex]
what are the ending materials produced from cell respiration
Answer:
The products of cellular respiration are carbon dioxide and water
Explanation:
Find the area of the given figure
Answer:
77 sq.cm
Explanation:
Solution,
Trapezium
Perpendicular (P1)=8cm
Perpendicular(P2)=14cm
height(h)=7cm
Now,
We know that,
Area(A)= 1/2 ×h (P1+P2)
= 1/2 × 7cm (8cm+14cm)
= 1/2 × 7cm(22cm)
= 1/2 × 154 squarecm
=77 sq.cm
13. What are some ways that you can conserve energy?
Answer:
Adjust your day-to-day behaviors.
Replace your light bulbs.
Use smart power strips.
Install a programmable thermostat.
Use energy efficient appliances.
Reduce water heating expenses.
Install energy efficient windows.
Upgrade your HVAC system.
Turn Off Lights and Electronics When You Aren't Using Them. ...
Replace Traditional Light Bulbs with LEDs. ...
Get a Smart Thermostat. ...
Ensure Your Home is Properly Insulated. ...
Put Decorative Lights on a Timer. ...
Identify and Unplug Energy Vampires. ...
Reduce Appliance Use. ...
Use Less Hot Water.
1 If you measured the distance travelled by a snail in
inches and the time it took in minutes, what would
be the units of its speed?
Is science based off observations? Explain how observations are important to your experiment.
Answer:
Observation is essential in science. Scientists use observation to collect and record data, which enables them to construct and then test hypotheses and theories. Scientists observe in many ways – with their own senses or with tools such as microscopes, scanners or transmitters to extend their vision or hearing. These tools allow for more precise and accurate observations. Scientists also use equipment to measure things like radiation or pH – phenomena not directly observable.
Explanation:
Two 3.0g bullets are fired with speeds of 40.0 m/s
and 80.0 m/s, respectively. What are their kinetic
energies? Which bullet has more kinetic energy? What is the ratio of their kinetic energies?
[tex] = \sf \frac{1}{2} m {v}^{2} [/tex]
Kinetic energy of the 1st bullet [tex] \sf = \frac{1}{2} \times m1 \times {(v1)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(40)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 1600J \\ \sf = 2.4J[/tex]Kinetic energy of the 2nd bullet [tex] \sf = \frac{1}{2} \times m2 \times {(v2)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(80)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 6400J \\ \sf = 9.6J[/tex] So, the 2nd bullet which has greater velocity has more kinetic energy.Therefore, the ratio of their kinetic energies[tex] \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4[/tex]
Answer:
The kinetic energies of the bullets are 2.4 J and 9.6 J.
The bullet having greater velocity has more kinetic energy.
The ratio of their kinetic energies is 1 : 4.
Hope you could get an idea from here
Doubt clarification - use comment section.
The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.
The ratio of the kinetic energy of the bullets is 1:4.
What is kinetic energy?The kinetic energy of an object is the energy possessed by the object due to its motion.
The kinetic energy of the two bullets is calculated as follows;
[tex]K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J[/tex]
Ratio of the kinetic energy of the bullets is calculated as follows;
[tex]K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4[/tex]
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PLEASE HELP!! WILL GIVE BRAINLIEST IF YOU SHOW WORK. ITS DUE SOON :(
If the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, what is its angular displacement in 2.0 s? What is it's Linear displacement on the edge in 2.0 s? Please show work :(
Answer:
theta = ω t = 5.0 / sec * 2 s = 10 rad
S = R theta = 6 cm * 10 rad = 60 cm
The angular displacement of CD if the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, is 10 rad, and the linear displacement is 60 cm.
What is velocity?When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Given:
The radius of the CD, r = 6 cm,
The angular velocity, v = 5 rad / sec
The time, t = 2 sec,
Calculate the angular displacement by the formula given below,
[tex]v = s / t[/tex]
5 = s / 2
s = 10 rad,
Calculate the linear displacement by the formula given below,
Linear displacement = [tex]r\ s[/tex]
Linear displacement = 6 × 10
Linear displacement = 60 cm
Therefore, the angular displacement of CD if the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, is 10 rad, and the linear displacement is 60 cm.
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Is the image formed by a plane mirror always real?
True or false?
A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark. Assume each tick mark represents 1 cm. Calculate the total displacement if a toy car starts at 0, moves 5 cm to the left, then 8 cm to the right, and then 3 cm to the left. The car moves cm, so there is no displacement.
The total displacement of the toy car at the given positions is 0.
The given parameters;
First displacement of the car, = 5 cm leftSecond displacement of the car, = 8 cm rightThird displacement of the car, = 3 cm to the leftThe total displacement of the car is calculated as follows;
Let the left direction be "negative direction"Let the right direction be "positive direction"[tex]\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0[/tex]
Thus, the total displacement of the toy car at the given positions is 0.
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Answer:0
Explanation:
What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
(a) How far did he travel?
(b) What was his average speed?
(c) What was his displacement?
(d) What was his average velocity?
Answer:
Explanation:
See the attachment for the details. A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times. The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.
The individual driving times and distances are summed to provide:
(a) How far did he travel?
103 km
(b) What was his average speed?
12.88 km/h
(c) What was his displacement?
73.82 km
(d) What was his average velocity?
9.228 km/h
When the mass of the cylinder increased by a factor of 3, from 1. 0 kg to 3. 0 kg, what happened to the cylindera's gravitational potential energy? It decreased by a factor of 3. It decreased by a factor of 2. It increased by a factor of 2. It increased by a factor of 3.
The mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
The given parameters:
Initial mass of the cylinder, m₁ = 1.0 kgFinal mass of the cylinder, m₂ = 3.0 kgThe gravitational potential energy of an object is calculated as follows;
P.E = mgh
where;
m is the mass
g is acceleration due to gravity
h is the height of the cylinder
when the mass = 1 kg
P.E = 1 x g x h
P.E = gh
when the mass = 3 kg
P.E = 3 x gh
P.E = 3gh
Thus, when the mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
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A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *
A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car
The force on the truck is the same in magnitude as the force on the car.
The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.
J = Ft
where;
J is the impulse experienced by the objectt is the timeThe increase in the force applied to an object causes an increase in the impulse experienced by the object.
Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.
Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.
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