What type of chemical bond holds 2Na+ and O2-together in
Na20?
a Metallic Bond
blonic Bond
C Molecular Bond
d Van der Waals' force
e Covalent Bond

Answer:

The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz

Explanation:

The wavelength of the electromagnetic wave, λ = 415 nm

The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s

Given that an electromagnetic wave is a periodic wave, we have;

The speed of the electromagnetic wave, c = f×λ

Where;

f = The frequency of the electromagnetic wave

Therefore, we have;

f = c/λ

From which we have;

f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz

The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz

Answer: 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Cr_2O_3=\frac{50g}{152g/mol}=0.33moles[/tex]

The decomposition of [tex]Cr_2O_3[/tex] follows the equation :

[tex]2Cr_2O_3\rightarrow 4Cr+3O_2[/tex]  

According to stoichiometry :

2 moles of [tex]Cr_2O_3[/tex] produce = 4 moles of [tex]Cr[/tex]

Thus 0.33 moles of [tex]Cr_2O_3[/tex] will produce=[tex]\frac{4}{2}\times 0.33=0.66moles[/tex]  of [tex]Cr[/tex]

Mass of [tex]Cr=moles\times {\text {Molar mass}}=0.66moles\times 52g/mol=34g[/tex]

Thus 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]

1.1 mol Ne

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 6.5 × 10²³ atoms Ne

[Solve] moles Ne

Step 2: Identify Conversion

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.07938 mol Ne ≈ 1.1 mol Ne

Answer:

The cytoplasm of erythrocytes is rich in hemoglobin, an iron-containing biomolecule that can bind oxygen and is responsible for the red color of the cells and the blood. Each human red blood cell contains approximately 270 million of these hemoglobin molecules.

Answer:

1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.

2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}[/tex]

3) The value of [tex]K_c[/tex] is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.

Answer:

0.2 mole

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 12.06×10²²

Number of mole =?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

12.06×10²² molecules = 12.06×10²² / 6.02×10²³

12.06×10²² molecules = 0.2 mole

Thus, 12.06×10²² molecules is equivalent to 0.2 mole

Answer:

Cathode: Mn → Mn²⁺  +  2e⁻    (Oxidation)

Anode: Zn²⁺  +  2e⁻  →  Zn   (Reduction)

Mn | Mn²⁺ ||  Zn²⁺  | Zn

Explanation:

To identify the half reaction we need to see the oxidation states.

Mn(s) → Ground state → Oxidation state = 0

Mn(NO₃)₂ → Mn²⁺  → The oxidation state has increased.

This is the oxidation reaction. It has released two electrons:

Mn → Mn²⁺  +  2e⁻

Zn(NO₃)₂ →  Zn²⁺

Zn → Ground state → The oxidation state was decreased.

This is the reduction reaction. It has gained two electrons:

Zn²⁺  +  2e⁻  →  Zn

Cathode: Mn → Mn²⁺  +  2e⁻

Anode: Zn²⁺  +  2e⁻  →  Zn

Mn | Mn²⁺ ||  Zn²⁺  | Zn

Answer:

1:aerobic

2:anaerobic

3:aerobic

0.127 mol Au

Math

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 25.0 g Au

[Solve] moles Au

Step 2: Identify Conversions

[PT] Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.126923 mol Au ≈ 0.127 mol Au

Answer:

[tex]\boxed {\boxed {\sf 0.127 \ mol \ Au}}[/tex]

Explanation:

To convert from mass to moles, the molar mass must be used. This can be found on the Periodic Table.

Use this number as a ratio.

[tex]\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]

Multiply by the given number of grams.

[tex]25.0 \ g \ Au*\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]

Flip the fraction so the grams of gold will cancel.

[tex]25.0 \ g \ Au*\frac {1 \ mol \ Au}{196.96657 \ g\ Au }[/tex]

[tex]25.0*\frac {1 \ mol \ Au}{196.96657 }[/tex]

[tex]\frac {25.0 \ mol \ Au}{196.96657 }[/tex]

[tex]0.1269250919 \ mol \ Au[/tex]

The original measurement has 3 significant figures, so the answer must have the same. For the number we calculated that is the thousandth place. The 9 in the ten thousandth place tells us to round the 6 to a 7.

[tex]0.127 \ mol \ Au[/tex]

25.0 grams of gold is about 0.127 moles of gold.

Answer: The answer is both diseases and availability of resources can limit the growth of a population of organisms which is A

Explanation:

Answer:

q= -40.236 or 40.236 KJ of heat released

Explanation:

I attached a picture + a cooling curve.

Answer:

polyvinyl chloride

Explanation:

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

Answer:

C. One type of atom is oxidized and another is reduced

D. Electrons are transferred from one atom to another

Explanation:

just took the test, i hope this helps!!

have a nice day and take care of yourself!! :))

One type of atom is oxidized and another is reduced and  Electrons are transferred from one atom to another. Therefore, the correct options are options C,D.

Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Numerous oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.

The combined processes of oxidation and reduction are known as redox reactions due to their complimentary nature. The oxidising agent is the reactant that causes the oxidation, while the reducing agent itself reduces this reagent.  One type of atom is oxidized and another is reduced and  Electrons are transferred from one atom to another.

Therefore, the correct options are options C,D.

To know more about redox reaction, here:

https://brainly.com/question/13293425

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1100 mmHg

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Gas Laws

Stoichiometry

Step 1: Define

[Given] 1.5 atm

[Solve] mmHg

Step 2: Identify Conversions

1 atm = 760 mmHg

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1140 mmHg ≈ 1100 mmHg

Answer: Mechanical weathering

Explanation:

Mechanical weathering breaks rocks into smaller pieces

Answer:

c. 2s2 2p5

Explanation:

2s2 2p5 has 7 valence electrons and only needs one electron to complete the octet.  This element will be the most electronegative.

Answer:

1. Causes air to vibrate 2. A hydroelectric dam generating electricity on a river

Answer:

N2 (nitrogen) O3 (ozone) CaO (calcium oxide) C6H12O6 (glucose, a type of sugar)

Answer:

dihydrogen monoxide

dinitrogen monosulfide

Explanation:

If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.

- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B

Answer:

Without the process of cell differentiation, multicellular organisms would not be possible.

Answer:

E sound

Explanation:

Answer:

Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.

Let me know if this helps!

Answer:

Electrical energy

Explanation:

The wind Mill is an example of a device that converts wind energy into electrical energy