What types of reactions are these 3 chemical equations?-
*2Kl+Pb(NO3)2=PbI2+2KNO3
*2Al+3CuSO4=Al2(SO4)3+3Cu
*C2H5OH+3O2=2CO2+3H2O

Answers

Answer 1

Answer:

*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.

*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.

*C2H5OH+3O2=2CO2+3H2O: combustion.

Explanation:

Hello there!

In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.

In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.

Regards!

What Types Of Reactions Are These 3 Chemical Equations?-*2Kl+Pb(NO3)2=PbI2+2KNO3*2Al+3CuSO4=Al2(SO4)3+3Cu*C2H5OH+3O2=2CO2+3H2O

Related Questions

Please help this is due tonight

Answers

4. the nervous system uses electrical impulses to send messages through neurons while endocrine glands use hormones to send messages

5. Hormones are released from the endocrine glands

6. a. neck
b. Chest

7. help regulate important functions, such as growth, blood pressure and reproduction; it is small and small and bean shaped.

8. produces hormones that regulate the body's metabolic rate controlling heart, muscle and digestive function, brain development.

9. regulate your metabolism, immune system, blood pressure, respond to stress etc.

10. “enzymes” - break down sugars, fats, and starches

11. cells are unable to use glucose (can’t break down sugar to use as energy)

How it affects your lives or the lives of people near the area where soil erosion happened?




Please Answer! thanks! ​

Answers

Answer:

negatively

Explanation:

when soil erosion happens,by the agent of water for example,the soil will eventually lose it's valuable minerals and become infertile, people won't be able to grow crops there.

How many moles of O2 did you produce the 8.31 moles of H2O

Answers

the equation is not present.

If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases from 20.5°C to 47.8 °C.

a. Is this an example of an endothermic or exothermic reaction?

b. What is the q for the reaction? (Remember since the NaOH dissolves in water add the masses to get the m)

c. How many moles of NaOH are dissolved?

d. What is the ΔH for the reaction?

Answers

Explanation:

Have a good luck with ur exam

decay mode for cesium-137

Answers

Answer:

Beta decay

Explanation:

Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.

Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.

The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.

Beta decay decreases the neutron - proton ratio.

How many moles are 4.20 * 10 ^ 25 atoms of Ca?

Answers

Answer:

~69.744 moles of Ca

Explanation:

Using Avogadro's constant , we know that:

1 mole = 6.022 x 10^23 atoms

S0, the number of moles in 4.20 x 10^25 atoms of Ca:

=(4.20 x 10^25 x 1 )/(6.022 x 10^23)

~69.744 moles of Ca

Q2:How many atoms are in 0.35 moles of oxygen?

1 mole = 6.022 x 10^23 atoms

S0, the number of atoms in 0.35 moles of  oxygen:

=[0.35 x (6.022 x 10^23)]

=2.1077 x 10^23 atoms of Oxygen

Hope it helps:)

A radioactive material, with half-life of six months, has 100 thousand unstable nuclei.
(a) Find the number of unstable nuclei present after three months.
(b) What will be its activity at this time (after three months)?

Answers

Answer:

See Explanation

Explanation:

Given that;

N/No = (1/2)^t/t1/2

Where;

No = amount of radioactive isotope originally present

N = A mount of radioactive isotope present at time t

t = time taken

t1/2 = half life

N/1000=(1/2)^3/6

N/1000=(1/2)^0.5

N = (1/2)^0.5 * 1000

N= 707 unstable nuclei

Since the value of the initial activity of the radioactive material was not given, the activity of the radioactive material after three months is given by;

Decay constant = 0.693/t1/2 = 0.693/6 months = 0.1155 month^-1

Hence;

A=Aoe^-kt

Where;

A = Activity after a time t

Ao = initial activity

k = decay constant

t = time taken

A = Aoe^-3 *0.1155

A=Aoe^-0.3465

A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.840 J/g°C and the temperature goes up by 9.25°C of soil. How many grams of soil are there?

Answers

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

m = 6400 ÷ 7.77

m = 823.7g

Answer:

There are 823.68 grams.

Explanation:

Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.

Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:

Q= C*m* (T2- T1) = C*m* ΔT

In this case:

Q= 6400 JC= 0.840 [tex]\frac{J}{g*C}[/tex]m= ?ΔT= 9.25 C

Replacing:

6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C

Solving:

[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]

m=823.68 grams

There are 823.68 grams.

Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.

Answers

Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

If 10.0 moles of NO are reacted with 6.0 moles of O2, How many moles of NO2 are produced?​

Answers

Answer:

We have to find out which of the reactants that is the Limiting Reagent.

The Limiting Reagent is the reactant that finishes before reaction is complete or simply put... Its the reactant that's NOT IN EXCESS.

We use the reactant that's not in excess to find the Number of moles of product because once that reactant is used up.... The reaction also ends or stops(hence the name;Limiting reactant).

Now

We have 10moles of NO

We also have 6moles of O2

The balanced equation of Reaction is

2NO + O2 ===> 2NO2

Now

looking at this equation

2moles of NO is required to react with 1mole of O2

So since we have NO=10moles and O2 = 6moles

It means that

20moles of NO is required to react with 6 moles of O2.

We were only given 10moles of NO and this is not even enough to react with the whole 6moles of Oxygen because from what we just discovered... We need 20moles of NO to react with all 6moles of O2.

So

This means that NO is the LIMITING REACTANT. It is in short supply and would be used up before the whole reaction takes place.

So we use the limiting reactant to find the Number of Moles of Product formed.

Now

From the eqn of reaction

2moles of NO forms 2Moles of NO2.

Their Mole ratio is 2:2 or 1:1...

This simply means that an equal amount of NO2 will be Produced

MEANING.... 10 MOLES OF NO2 IS PRODUCED.

HAVE A GREAT DAY!!!

Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s​

Answers

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

[tex]R = \dfrac{u^2 sin 2\theta}{g}[/tex] ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

[tex]R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m[/tex]

Therefore, the horizontal range of projectile is 80 m.

The MO diagram of CN is similar to N2. Based on the molecular orbital energy-level diagram of CN, which of the following statements are correct?

i. The CN bond order is 2.
ii. CN is diamagnetic.
iii. The bond enthalpy in CN- ion is higher than CN.
iv. CN has longer bond length than CN-

answer choices:
a. ii, iv
b. iii, iv
c. i, iii
d. i, ii
e. i, iv

Answers

Answer:

Nitrogen molecule (N2)

The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.

The total number of electrons present in the nitrogen molecule (N2) is 14.

In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.

N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2

Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.

The bond order of N2can be calculated as follows:

Here, Nb = 10 and Na = 4

Bond order = (Nb−Na) /2

B.O = (10−4)/2

B.O = 3

So your answer should be C3.

What is the total mass of products formed when 64.18 grams of CH4 is burned with excess oxygen?

Answers

80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen so ur answer is

80 GRAMS

If the temperature decreases, then the pressure will​

Answers

then the temperature decreases.

Write a balanced chemical equation for the reaction. Na2CO3Na2CO3 and AgNO3AgNO3 Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Na = 2[tex]CO_{3}[/tex] = 1Ag = 1[tex]NO_{3}[/tex] = 1

Number of atoms present on product side are as follows.

Na = 1[tex]CO_{3}[/tex] = 1Ag = 2[tex]NO_{3}[/tex] = 1

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?

Answers

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

please help me quickly ????

Calculate the equilibrium solubility of silver arsenate

(Ksp = 6 * 10-23) in a solution that buffered to a pH of :

a) 3

b) 6

c) 9

For H3ASO4

Ka1 = 5 * 10-3

Ka2 = 1.1 * 10-7

Ka3 = 3.2 * 10-12​

Answers

Answer:

sorry don't know the answer!!!

THIS NOT MY WORK. its for my sister. HELP HER

Answers

Answer:

Your answer will be b(molten material from the outer core makes its way to the surface of earth)

Explanation:

Answer:

C

Explanation:

I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!

Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant? (3 points)


SO2

O2

Fe2O3

FeS2

Answers

Answer:

O2

Explanation:

for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:

MM FeS2 = 120n  = 26.2g / 120g/mol = 0,218 mol

MM O2  = 32n = 5,44g/32g/mol = 0,17 mol

The limiting reactant is  

O2

Write the formulas for each of the compounds in the following table.
1.
Ferric sulfate
2.
Strontium oxalate
3
.
Chromic acid
4.
Nickel(III) carbonate
5.
Silver bromate
6
.
Dinitrogen difluoride
1.
Magnesium molybdate
8.
Sodium hydrogen phosphate​

Answers

Answer:

1. Ferric sulfate - Fe2(SO4)3

2. Strontium oxalate – SrC2O4

3. Chromic acid – CrO3

4. Nickel (III) carbonate – NiCO3

5. Silver bromate – AgBrO3

6. Dinitrogen difluoride - N2H2

7. Magnesium molybdate – MgMoO4

8. Sodium hydrogen phosphate - Na2PO4

Look at the table of dissociation constants for some acids.

Acid Ka Acetic acid 18 x 10-6 1.2 x 10-2 Chlorous acid Nitrous acid 4.0 x 10 -4 Propionic acid 1.3 x 10-5

Which of these is the strongest acid?

acetic acid
chlorous acid
nitrous acid
propionic acid

*Answer is B*​

Answers

Answer:

chlorous acid

Explanation:

The acidic equilibrium of weak acids, HX, occurs as follows:

HX ⇄ H+ + X-

Where Ka is written as:

Ka = [H+] [X-] / [HX]

The strongest acid is the acid that produce more H+. The acid with the higher Ka is the acid that produce more [H+] and is, thus, the strongest acid.

The higher Ka is the Ka of chlorus acid = 1.2x10-2

Right answer is:

chlorous acid

Answer:

chlorous acid :)

Explanation:

Student Exploration: Limiting Reactants Vocabulary: chemical equation, chemical formula, chemical reaction, coefficient, limiting reactant, molecule, product, reactant, subscript Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Imagine you and your friends are making hot dogs. A complete hot dog consists of a wiener and a bun. At the store, you buy four packages of eight wieners and three bags of 10 buns. 1. How many total hot dogs can you make

Answers

Answer:

30 hot dogs

Explanation:

It is given that :

There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners

There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns

One hot dogs need 1 bun and 1 wiener to make a hot dog.

There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.

Therefore, 30 hot dogs.

And the number of extra wieners left = 32 - 30 = 2 wieners.

How many molecules are in 1.75 moles of Caco3?

1.75 molecules
3.440 x 1023 molecules
1.054 x 1024 molecules
O 2.907 x 10-24 molecules

Answers

Answer:

1.054 x 10²⁴ molecules

Explanation:

In order to convert moles of any given substance into a number of molecules, we need to use Avogadro's number, which states the number of molecules -or atoms, in the case of elements- present in one mol:

In one mol there are 6.023x10²³ molecules.

We now convert 1.75 moles into molecules:

1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ molecules

Magnesium metal reacts with a solution of silver nitrate in a single-replacement reaction, producing aqueous magnesium
nitrate and silver metal.
If a reaction starts with 0.480 mol Mg, how many moles of silver are produced?
You must show a proper set up for the calculation, the answer with a proper unit, and
the proper significant figures.

Answers

Answer:

0.960 mol of Ag

Explanation:

Mg(s) + 2AgNO3(aq) → Mg(NO3)2(aq) + 2Ag(s)

1.00 mol of Mg ---- 2.00 mol of Ag

0.480 mol of Mg ---- x

x = (0.480×2)/1 = 0.960 mol of Ag

hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((​

Answers

Answer:

Boiling - The process of a liquid changing to gas.

Boiling point - The temperature at which a liquid boils.

Condensing - The process of a gas changing to a liquid.

Distillate - The liquid collect from the condenser.

Residue - The liquid left behind in the distillation flask.

Vapour - Another name for gas.

Hope it helps :)

using a map give the coordinates of the capital of the neighboring countries of the philippines e.g tokyo japan​

Answers

Answer:

The correct answer is -

1. Malaysia - Kuala Lumpur 3.1390° N, 101.6869° E

2. Indonesia - Jakarta - 6.2088° S, 106.8456° E

3. Vietnam - Hanoi - 21.0278° N, 105.8342° E

4. Taiwan - Taipei  -25.0330° N, 121.5654° E

5. China - Beijing - 39.9042° N, 116.4074° E

6. Palau - Ngerulmud  - 7.5004° N, 134.6243° E

7. Japan - Tokyo - 35.6762° N, 139.6503° E

Explanation:

The Philippines does not share its land borders with any country, however, the Philippines claims that they share their boundary with Malaysia. Other than land borders they also share maritime borders with Palau, Taiwan, Vietnam,  China, Indonesia, and Japan.

All these neighboring countries have capitals that are as follows with their coordinates on the atlas-

1. Malaysia - Kuala Lumpur 3.1390° N, 101.6869° E

2. Indonesia - Jakarta - 6.2088° S, 106.8456° E

3. Vietnam - Hanoi - 21.0278° N, 105.8342° E

4. Taiwan - Taipei  -25.0330° N, 121.5654° E

5. China - Beijing - 39.9042° N, 116.4074° E

6. Palau - Ngerulmud  - 7.5004° N, 134.6243° E

7. Japan - Tokyo - 35.6762° N, 139.6503° E

What would the IUPAC name be?

Answers

Answer:

methyl ethanoate

Explanation:

To name the compound given above, the following must be obtained:

1. Determine the functional group of the compound.

In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.

2. Determine the longest chain before the functional group and the compound after the functional group.

In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.

3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.

This is illustrated below:

After the functional group => methyl

Before the functional group => ethane

Name of the compound => methyl ethanoate

What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2? 1.4 × 10–4 M H3O+ and 7.1 × 10–11 M OH– 3.8 × 10–6 M H3O+ and 2.6 × 10–9 M OH– 8.3 × 10–9 M H3O+ and 1.2 × 10–6 M OH– 6.3 × 10–11 M H3O+ and 1.6 × 10–4 M OH–

Answers

Answering:

It is D

Explanation:

Just took the test

The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] are:

1. Concentration of hydronium ion [H₃O⁺] is 6.3×10¯¹¹ M 2. Concentration of Hydroxide ion [OH¯] is 1.6×10¯⁴ M

The pH of a solution is simply a measure of the acidic or alkalinity of the solution.

The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] can be obtained as illustrated below:

Step 1

Data obtained from the question

pH = 10.2

Concentration of hydronium ion [H₃O⁺] =…? Concentration of Hydroxide ion [OH¯] =…?

Step 2

Determination of the concentration of hydronium ion [H₃O⁺]

pH = 10.2

Concentration of hydronium ion [H₃O⁺] =…?

pH = –log[H₃O⁺]

10.2 =  –log[H₃O⁺]

Multiply though by –1

–10.2 = log[H₃O⁺]

Take antilog of –10.2

[H₃O⁺] = antilog(–10.2)

[H₃O⁺] = 6.3×10¯¹¹ M

Step 3:

Determination of the pOH

pH = 10.2

pOH =?

pH + pOH = 14

10.2 + pOH = 14

Collect like terms

pOH = 14 – 10.2

pOH = 3.8

Step 4

Determination of the concentration of Hydroxide ion [OH¯].

pOH = 3.8

Concentration of Hydroxide ion [OH¯] =…?

pOH = –log[OH¯]

3.8 = –log[OH¯]

Multiply through by –1

–3.8 = log[OH¯]

Take the antilog of –3.8

[OH¯] = antilog(–3.8)

[OH¯] = 1.6×10¯⁴ M

SUMMARY:

1. Concentration of hydronium ion [H₃O⁺] = 6.3×10¯¹¹ M

2. Concentration of Hydroxide ion [OH¯] = 1.6×10¯⁴ M

Learn more: https://brainly.com/question/13387755

Hydration of alkynes gives good yields of single compounds only with symmetrical or terminal alkynes. Draw the major organic product(s) formed when 3-methylcyclodecyne undergoes hydration in the presence of HgSO4 and H2SO4.

Answers

Answer:

Following are the solution to the given choice:

Explanation:

Hex-2-yne is just not alkyne symmetric, therefore two things respectively hexan-3-one and hexan-2-one are to be given.

The attached file it displayed the response along with the mechanism, please find the.

In the ground state, the valence electrons of a krypton atom are found in
1. The first shell
2. The outermost shell
3. Both the nucleus and the first shell
4. Both the first shell and the outermost shell

Answers

Answer: 2. The outermost shell

Explanation:

In an elements ground state, its electrons have the least amount of energy that they could have so they stay in their shells. When Krypton is in this state therefore, its valence electrons will stay in the outermost shell.

As Krypton has a total of 36 electrons in this state, there will be 8 valence electrons and they will all be in the outer shell.

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