What volume occupied by 256 g of SO2 gas at 227C and 1520 torr? (Molar mass of SO2 is 64.07 g/mol, 760 torr = 1 atm)10.7 L68.5 L 0.108 L37.2 L82.0 L

The mass of solid AgCl produced when 525 mL of 0.35 M AlCl3 is used with excess Ag2SO4 solution is 78.97 g.

The balanced chemical equation for the reaction between AlCl3 and Ag2SO4 is:

2 AlCl3 + 3 Ag2SO4 → Al2(SO4)3 + 6 AgCl

From the equation, we can see that 2 moles of AlCl3 react with 3 moles of Ag2SO4 to produce 6 moles of AgCl. Therefore, the mole ratio of AlCl3 to AgCl is 2:6 or 1:3.

To calculate the moles of AgCl produced, we need to first calculate the moles of AlCl3 used.

Moles of AlCl3 = concentration x volume / 1000

Moles of AlCl3 = 0.35 mol/L x 0.525 L

Moles of AlCl3 = 0.18375 mol

Since the mole ratio of AlCl3 to AgCl is 1:3, the moles of AgCl produced is:

Moles of AgCl = 3 x Moles of AlCl3

Moles of AgCl = 3 x 0.18375 mol

Moles of AgCl = 0.55125 mol

The molar mass of AgCl is 143.32 g/mol. Therefore, the mass of AgCl produced is:

Mass of AgCl = moles of AgCl x molar mass of AgCl

Mass of AgCl = 0.55125 mol x 143.32 g/mol

Mass of AgCl = 78.97 g

Therefore, the mass of solid AgCl produced when 525 mL of 0.35 M AlCl3 is used with excess Ag2SO4 solution is 78.97 g.

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The repetition of the exercise over time is the IV (independent variable) in this example of an experimental design.

Exercise is physical activity that is done to maintain or improve one's physical health and fitness. It usually entails exercises like jogging, running, cycling, swimming, weightlifting, or taking part in sports.

Adam is experimenting with the IV to see whether it has an impact on the DV (dependent variable), which is the number of times he can open and shut the clothes pin using only his thumb and forefinger in 60 seconds, by doing the exercise several times. Adam is checking the DV to determine whether there has been a change as a result of the IV.

Adam has regulated various factors to guarantee that the outcomes are trustworthy. For each experiment, he is, for instance, using the same clothes pin, opening and closing it with the same fingers, and timing each trial for exactly 60 seconds. In order to prevent weariness from impairing his performance, Adam is also taking a one-minute break between each session.

The idea is that if Adam performs the exercise repeatedly over time, he will get more adept at it. This theory is predicated on the idea that repetition and practice can enhance a person's capacity to carry out a physical job.

Adam will compare how many times he opened and closed the clothes pin in each trial, starting with the first, to determine the outcomes. The increase in the number indicates that Adam becomes more adept at the practice. If the number falls or stays the same, the hypothesis is refuted, then it may be said that repetition had no positive effect on performance.

Overall, this scenario for an experimental design provides a straightforward yet efficient approach to evaluate the claim that doing a physical activity repeatedly will increase performance. It highlights the significance of limiting variables and calculating the DV to get relevant results.

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The ionization constant (Ka) of a weak monoprotic acid is the measure of the acid's ability to dissociate into its ions in solution.

The Ka value can be calculated as Ka = 10^(pH - pKa). Therefore, for a 0.10 M solution of a weak monoprotic acid with a pH of 3.0, the Ka value is 10^(-3).

It is a measure of the equilibrium between the acid and its ions in water. The Ka value is defined as the ratio of the concentrations of the ions and the acid in solution.

For a 0.10 M solution of a weak monoprotic acid with a pH of 3.0, the Ka value can be calculated using the Henderson-Hasselbalch equation. This equation states that pH = pKa + log ([A-]/[HA]), where [A-] is the concentration of the ions and [HA] is the concentration of the acid.

Thus, the Ka value can be calculated as Ka = 10^(pH - pKa). Therefore, for a 0.10 M solution of a weak monoprotic acid with a pH of 3.0, the Ka value is 10^(-3).

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The sweet fiber in cat tail roots provides an abundance of starchy carbohydrates. The common cattail is not a perfect flower. Among the given options, cat tails  absorb nitrates from polluted water. The correct option is A.

The cattail flower spikes can be possible to boil and can be eaten just like the corn on the cob. Pollen from the matured flowers can be collected and can be used with other flour to make biscuits, muffins and pancakes.

Cattails have an amazing ability to absorb phosphorous, nitrogen and other elements which can destruct the water bodies and sediment beds. They play a vital function in treating wastewater.

Thus the correct option is A.

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Only  the condensation is an exergonic phase change.

Exergonic refers to a process that releases energy. Among the given options, the exergonic phase change is condensation. When a gas turns into a liquid during condensation,

it releases heat energy. This is because the molecules lose kinetic energy and move closer together, forming stronger attractive forces. The energy that was previously used to keep the gas molecules apart is released as heat energy.

On the other hand, melting and vaporization are endergonic phase changes, which require an input of energy to occur. Melting requires heat energy to break the intermolecular bonds between the solid molecules,

while vaporization requires even more energy to overcome the stronger intermolecular forces in the liquid and form a gas.

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First you must calculate the number of moles of NaCl

MM NaCl = 35 + 23 = 58

NaCl moles = 10g /58 g/mol = 0,17 mol

By definition, 1 mole contains 6,02 × 10²³ atoms, therefore you simply need to multiply the Avogadro's number by the number of moles

6,02 × 10²³ × 0,17 mol = 1,02 × 10²³

Carl has concluded that substance have ionic bonds.

The usual guideline is that a bond is considered nonpolar if the difference in electronegativities is less than or equal to 0.4, while there are no hard and fast rules, and polar if the difference is greater.

The bond between two hydrogen atoms is an illustration of a nonpolar covalent bond since they equally share electrons. The bond between two chlorine atoms is another illustration of a nonpolar covalent bond since they also equally share electrons.

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Question:

During che distry class, Cort performed several lab tests on two white solids. The results of three tests are seen in the data table. Based on this data, Carl has concluded that substance have ________ bonds.

A) covalent

B) diatomic

C) ionic

D) metallic

To determine what color the solution would be at given pH, we need to know the pKa of indicator.

Based on the information given, it can be inferred that the substance in question is an acid that undergoes an ionization reaction. When an acid ionizes, it donates a proton (H+) to water, forming a conjugate base and hydronium ions (H3O+).

At a low pH, the solution would be acidic and the substance would be predominantly in its ionized form, which is likely blue in color due to the presence of the conjugate base. As the pH increases, the solution becomes less acidic and more basic, which favors the un-ionized form of the substance, which is yellow in color. Therefore, the color of the solution at a given pH would depend on the relative concentrations of the ionized and un-ionized forms of the substance, as well as the specific wavelengths of light that are absorbed and transmitted by each form.

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The pH of a solution with yellow color and blue colored conjugate base will have a pH of around 2-3.

Explanation:

Based on the given information, we can assume that the substance in question is an acid since an acid dissociates to give its conjugate base. When an acid is dissolved in water, it donates a proton (H+) to water molecules, creating hydronium ions (H3O+). This results in a decrease in pH and a shift towards the acidic end of the pH scale.
At low pH values, the solution would appear yellow due to the unionized form of the acid. As the pH increases, more of the acid will dissociate into its conjugate base form, which is blue. Therefore, the color of the solution would shift from yellow to blue as the pH increases.
To be more specific, we can use the pH colors of the solution as a guide. At a pH of around 2-3, the solution would be yellow. As the pH increases to around 4-5, the solution would be yellowish-orange. At a pH of 7, the solution would be green (neutral). As the pH increases further, the solution would shift towards blue-green and eventually to blue.

Therefore, if the acid in question has a yellow un-ionized form and a blue conjugate base, the solution would appear yellow at low pH values and shift towards blue as the pH increases.

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The solubility product (Ksp) of a substance is a measure of the maximum solubility of that substance in a given solution. It is calculated as the product of the molar concentrations of the ions present in the solution.

In the case of lead(II) iodide, the Ksp can be calculated as the product of the molar concentrations of Pb2+ and I− ions present in the solution.

At the given temperature, the solubility of lead(II) iodide is 0.064 /100 ml. Therefore, the molar concentrations of Pb2+ and I− ions in the solution would be 0.064/100 ml divided by the molar mass of lead(II) iodide (364/mol). This gives a Ksp of 4.07 x 10-9, which can be rounded to 4.1 x 10-9. This is the solubility product of lead(II) iodide at the given temperature.

In summary, the solubility product of lead(II) iodide at a certain temperature is 4.1 x 10-9 when rounded to two significant figures.

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(a) The HCO₃⁻ / CO₂ ratio is 20 : 1.

(b) The concentration of each buffer  present at the pH=7. 4 is [CO₂] = 1.20 × 10⁻³ M, [HCO₃⁻] = 0.0240 M.

(c) The pH be if 0. 01M H⁺ is added ,the excess CO2 is not released is 6.20.

(d) The pH be if 0. 01M H⁺ is added , the excess CO2 is released. is 7.17.​

(a) pH = pka + log HCO₃ / CO₂

HCO₃⁻ / CO₂ = 10^pH - pka

HCO₃⁻ / CO₂ = 10 ^7.4 - 6.1

HCO₃⁻ / CO₂ = 20 : 1

(b) Total concentration = 0.0252 M

HCO₃⁻ + CO₂ = 0.0252

20 CO₂ + CO₂ = 0.0252

[CO₂] = 1.20 × 10⁻³ M

[HCO₃⁻ ] = 0.0240 M

(c) pH = pka + log HCO₃ / CO₂

pH = 6.1 + log 0.0140 / 0.0112

pH = 6.20

(d) pH = pka + log HCO₃ / CO₂

pH = 6.1 + log 0.0140 / 1.20 × 10⁻³

pH = 7.17

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11.2 moles of [tex]\rm O_2[/tex] are required to react completely with 3.2 moles of [tex]\rm C_2H_6[/tex]. Therefore option D is correct.

The balanced chemical equation for the complete combustion of [tex]\rm C_2H_6[/tex] (ethane) with oxygen (O2) is: 2 [tex]\rm C_2H_6 + 7 O_2\ - > 4 CO_2 + 6 H_2O[/tex]

From the balanced equation, we can see that 2 moles of [tex]\rm C_2H_6[/tex] react with 7 moles of [tex]\rm O_2[/tex]. To find out how many moles of [tex]\rm O_2[/tex] are required to react completely with 3.2 moles of [tex]\rm C_2H_6[/tex], we can set up a proportion:

(7 moles [tex]\rm O_2[/tex] / 2 moles [tex]\rm C_2H_6[/tex]) = (x moles [tex]\rm O_2[/tex] / 3.2 moles [tex]\rm C_2H_6[/tex])

Solving for x:

x = (7 moles [tex]\rm O_2[/tex] / 2 moles [tex]\rm C_2H_6[/tex]) * 3.2 moles [tex]\rm C_2H_6[/tex]

x = 11.2 moles [tex]\rm O_2[/tex]

So, 11.2 moles of [tex]\rm O_2[/tex] are required to react completely with 3.2 moles of [tex]\rm C_2H_6[/tex]. Therefore, the correct answer is 11.2 moles of [tex]\rm O_2[/tex].

Therefore option D is correct.

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The mixing of solid materials by continuously heaping them together with a spatula until a homogeneous mixture is reached.

Spatulation is a manual mixing technique commonly used in pharmacy and chemistry to mix solid ingredients. It involves using a spatula to heap the solid ingredients on a flat surface and repeatedly mixing and flattening them until a uniform mixture is achieved. The process is done by using the flat end of the spatula to push the powders together into a pile, then flattening the pile and repeating the process.

Spatulation is useful for preparing small batches of powders or creams and is often used in compounding medications or preparing laboratory samples. The other options in the question are not correct definitions of spatulation.

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The highest principal quantum number for electrons in a neutral tungsten atom is 6. Therefore, the answer is (F) 6.

Tungsten (W) has an atomic number of 74, meaning it has 74 protons in its nucleus. In a neutral atom of tungsten, the number of electrons is also 74, since the number of electrons equals the number of protons in a neutral atom.

When tungsten forms a cation, it loses electrons to become positively charged. The charge of the cation will depend on the number of electrons lost. Since the principal quantum number represents the energy level of the electron, the electrons that are lost when tungsten forms a cation will typically come from the outermost energy level, which is represented by the highest principal quantum number.

The highest principal quantum number for electrons in a neutral tungsten atom is 6. Therefore, the answer is (F) 6.

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The most important use of an element's atomic number is that it determines the identity of an element. From a neutral atom's atomic number, we can also determine the number of electrons in that atom.

The most important use of an element's atomic number is that it determines the element's unique identity and its position on the periodic table. The atomic number is equal to the number of protons in the nucleus of an atom, which also determines the number of electrons in a neutral atom.

From a neutral atom's atomic number, we can also determine the element's symbol, its electron configuration, and its properties such as its atomic mass and the number of isotopes it has. Additionally, the atomic number can provide information about the element's reactivity and its ability to bond with other elements to form compounds. Overall, the atomic number is a fundamental characteristic of an element that is used in many different areas of chemistry and physics.

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The most important use of an element's atomic number is that it determines the element's unique identity and properties.

The atomic number also tells us the number of protons in the nucleus of an atom, which in turn determines the number of electrons in the neutral atom. Additionally, the atomic number can give us information about the element's electron configuration and its position on the periodic table. Overall, the atomic number is a crucial piece of information for understanding an element's properties and behavior.
Hi! The most important use of an element's atomic number is to identify the specific element and its position in the periodic table. The atomic number represents the number of protons in the nucleus of an atom of that element.

From a neutral atom's atomic number, we can also determine the number of electrons, as a neutral atom has an equal number of protons and electrons. This information helps us understand the element's chemical properties and reactivity, as the arrangement of electrons in the atom's electron shells influences its behavior in chemical reactions.

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The actuation method triggered by a product-of-combustion detector in a CO2 system is typically referred to as "automatic actuation."

In this method, the product-of-combustion detector senses the presence of a fire or heat source and sends a signal to the CO2 system, causing it to automatically release CO2 to extinguish the fire.

This actuation method is commonly used in areas where fires may start unexpectedly, such as in server rooms, electrical substations, and other critical infrastructure facilities. It provides a fast and effective response to fires, helping to minimize damage and protect personnel.

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The concentration of [tex]Zn_{2}[/tex]+ at the cathode at the new potential is 0.297 M.

To solve this problem, we can use the Nernst equation, which relates the concentration and potential of the ions in the cell:

E = E° - (RT/nF) * ln(Q)

Where:
- E is the new potential of the cell
- E° is the standard potential of the cell (given as 0.01826 V)
- R is the gas constant (8.314 J/K*mol)
- T is the temperature in Kelvin (assumed to be constant)
- n is the number of electrons transferred in the reaction (assumed to be 2 for Zn2+)
- F is Faraday's constant (96485 C/mol)
- Q is the reaction quotient, which is equal to [[tex]Zn_{2}[/tex]+] at the cathode divided by [Zn2+] at the anode.

We can rearrange the equation to solve for [[tex]Zn_{2}[/tex]+] at the cathode:

[[tex]Zn_{2}[/tex]+] cathode = [[tex]Zn_{2}[/tex]+] anode * e^(nF(E° - E)/RT)

Plugging in the given values, we get:

[[tex]Zn_{2}[/tex]+] cathode = 1.27 * e^(2*96485*(0.01826-0.009535)/(8.314*298*0.0259))

Solving this equation gives us [[tex]Zn_{2}[/tex]+] cathode = 0.297 M.

Therefore, the concentration of [tex]Zn_{2}[/tex]+ at the cathode at the new potential is 0.297 M.

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2NaCl --> 2Na + Cl2 but I have never seen something this reaction happening

The only incorrect statement in the diagram is (d) Cr202-7 can be used in aqueous H2SO4.

Option (d) is incorrect because the half-cell reaction involving Cr2O7^2- and H+ (aq) produces H2CrO4, which can decompose in acidic solutions, leading to inaccurate results. Therefore, Cr2O7^2- should not be used in aqueous H2SO4 for the quantitative estimation of Fe(NO3)2-.

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The Only incorrect statement is option C

Electrochemistry is a branch of chemistry that deals with the study of the relationship between electrical energy and chemical reactions.

It involves the study of the behavior of electrons and ions in chemical reactions that occur in a solution or at the interface between two different phases, such as a solid electrode and a liquid electrolyte.

We can see that it is better to use HCl instead of the use of the H2SO4 acid as we have in the options.

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The equilibrium constant (Kc) for the given reaction at 800 K is 1.

What is Equilibrium?

Chemical equilibrium is described by the equilibrium constant, which is a numerical value that quantitatively expresses the ratio of concentrations (or partial pressures) of reactants and products at equilibrium. The equilibrium constant is denoted by the symbol K, and its value depends on the specific chemical reaction and the temperature at which the reaction occurs.

According to the given information, at equilibrium, the concentration of C[tex]O_{2}[/tex] is 0.42 mol in a 14 L reaction vessel. Therefore, the equilibrium concentration of C[tex]O_{2}[/tex] ([C[tex]O_{2}[/tex]]) is 0.42 mol / 14 L = 0.03 mol/L.

The concentrations of CO ([CO]) and [tex]H_{2}O[/tex]([[tex]H_{2}O[/tex]]) at equilibrium can be calculated using the initial moles and the change in moles for each species. Since 1 mol of CO reacts with 1 mol of [tex]H_{2}O[/tex] to produce 1 mol of C[tex]O_{2}[/tex], the change in moles for CO and H2O is also 0.42 mol.

Equilibrium concentration of CO ([CO]) = Initial moles of CO - Change in moles of CO = 1 mol - 0.42 mol = 0.58 mol

Equilibrium concentration of [tex]H_{2}O[/tex] ([tex]H_{2}O[/tex]]) = Initial moles of [tex]H_{2}O[/tex] - Change in moles of [tex]H_{2}O[/tex] = 1 mol - 0.42 mol = 0.58 mol

Now, we can substitute these equilibrium concentrations into the equilibrium expression for Kc:

Kc = [C[tex]O_{2}[/tex]] / ([CO] * [[tex]H_{2}O[/tex]])

Plugging in the values:

Kc = (0.42)(0.42) / (0.42 * 0.42)

Kc = 1

So, the equilibrium constant (Kc) for the given reaction at 800 K is 1.

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Answer:

91

Explanation:

ok

False. The interstitium around capillaries generally has a lower PO2 and higher PCO2 due to the exchange of gases between the blood in the capillaries and the surrounding tissue. Oxygen diffuses from the capillaries into the tissue, leading to a decrease in PO2, while carbon dioxide diffuses from the tissue into the capillaries, leading to an increase in PCO2.

When blood flows through capillaries, oxygen diffuses from the capillary into the interstitium, while carbon dioxide diffuses from the interstitium into the capillary. This exchange of gases is driven by differences in their partial pressures in the blood and interstitium. The partial pressure of oxygen is higher in the capillary than in the interstitium, while the partial pressure of carbon dioxide is higher in the interstitium than in the capillary. This difference in partial pressures creates a concentration gradient that drives the diffusion of gases.

Therefore, the interstitium around capillaries generally has a lower PO2 and a higher PCO2 than the capillary blood. However, the exact partial pressures of these gases in the interstitium can vary depending on factors such as tissue metabolism, blood flow, and respiratory function.

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The statement "the interstitium around capillaries generally have a higher  [tex]P_{O2}[/tex] than  [tex]P_{CO2}[/tex]" is true.

In the interstitium around capillaries, [tex]P_{O2}[/tex] (partial pressure of oxygen) is generally higher than  [tex]P_{CO2}[/tex] (partial pressure of carbon dioxide) because oxygen is continuously diffusing from the capillaries into the interstitial fluid to be taken up by cells, while carbon dioxide is diffusing from cells into the interstitial fluid and then into the capillaries to be transported away for removal from the body. This exchange of gases maintains the higher  [tex]P_{O2}[/tex] and lower [tex]P_{CO2}[/tex] in the interstitial fluid surrounding the capillaries. Therefore, the oxygen-rich blood in the capillaries increases the  [tex]P_{O2}[/tex]in the interstitium, while the carbon dioxide produced by cells decreases the  [tex]P_{CO2}[/tex] in the interstitium.

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The chemical shift number of 2.25 ppm found on the proton NMR for BHT is due to the protons attached to the methyl group of BHT. Option 4 is correct.

This is because the protons on the methyl group are shielded from the magnetic field by the nearby bulky t-butyl groups, causing them to resonate at a higher chemical shift than protons on other parts of the molecule. This is a common phenomenon in NMR spectroscopy known as the "shielding effect" of electron-donating or bulky groups.

The proton on the alcohol group of BHT would appear at a different chemical shift, around 3-5 ppm, depending on the solvent and other factors. The protons attached directly to the benzene ring of BHT would appear at around 6-8 ppm. Hence Option 4 is correct.

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The two half-reactions that occur in this electroplating process are oxidation and reduction. the diagram is attached

Oxidation is a chemical reaction in which an atom or molecule either loses or gains electrons. This process results in the oxidation of the atom or molecule, leading to a chemical change in the molecule. Oxidation occurs when electrons are removed from the molecule, causing it to become more positively charged. This can lead to the formation of new molecules, such as oxygen (O₂) and carbon dioxide (CO₂).

Oxidation occurs at the anode, where electrons are released from the copper strip and it is oxidized to form copper ions (Cu²⁺). The copper ions are then dissolved into the electrolyte solution. Reduction occurs at the cathode, where the copper ions in the electrolyte solution are reduced using electrons from the battery and deposited onto the coin (or nail). The direction of electron flow is from the positive terminal of the battery, to the anode, to the electrolyte solution, to the cathode, and finally to the negative terminal of the battery.

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The correct answer is option D. Vitamin E is an antioxidant that helps to neutralize free radicals by donating electrons.

By reacting with reactive oxygen species, it breaks the chain of oxidative reactions by generating a stable end product.

It aids in preventing oxidative cell damage, which can result in illnesses like cancer. It has been demonstrated that vitamin E lowers the risk of heart disease and aids in the reduction of inflammation.

It has also been connected to better brain health because it has been demonstrated to fend off age-related cognitive decline.

Numerous foods, such as nuts, seeds, and vegetable oils, as well as supplements, contain vitamin E.

Complete Question:

Which of the following helps to neutralize free radicals by donating electrons?

Group of answer choices

A. Superoxide Dismutase

B. Catalase

C. Glutathione Peroxidase

D. Vitamin E

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Chromatography can be used to separate chlorophyll into a variety of pigment colours.

The leaf contains the chlorophyll molecule, which can be isolated using paper chromatography. Based on the distance that pigment molecules on the paper in a nonpolar solvent travelled, the paper chromatography separates the pigments in the leaf.

During paper chromatography, pigments separate because of their various polarity. Being polar, cellulose interacts more with polar pigments than non-polar pigments. Capillarity and absorbance are essential for chromatography.

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Question:

Using chromatography you can separate chlorophyll into several different pigment colors. Which statement is true about chlorophyll in this context, and what is its role in photosynthesis?

Alkenes typically undergo addition type reactions with electrophiles, whereas arenes react with electrophiles in substitution type reactions.

In an addition reaction, an electrophile adds to the double bond of an alkene, breaking the double bond and forming a single bond to each carbon atom. This results in a new single bond to the electrophile. For example, the reaction of propene with hydrogen chloride (HCl) is an addition reaction:

CH3CH=CH2 + HCl → CH3CH(Cl)-CH3

In contrast, in a substitution reaction, an electrophile substitutes for a hydrogen atom on an aromatic ring. The electrophile replaces the hydrogen atom, forming a new bond to the ring and resulting in a new substituted aromatic compound. For example, the reaction of benzene with nitric acid (HNO3) is a substitution reaction:

C6H6 + HNO3 → C6H5NO2 + H2O

The substitution reaction occurs via an electrophilic aromatic substitution (EAS) mechanism, in which the electrophile attacks the aromatic ring and forms a resonance-stabilized intermediate before the final substitution product is formed.

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The volume of the container is 16.9 L.To find the volume of the container, we can use the ideal gas law: PV = nRT

where P is the pressure in atmospheres (convert 812 mmHg to atm), V is the volume in liters (what we're solving for), n is the number of moles of gas (we're given 13.8 g of neon, which we can convert to moles using the atomic weight), R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (convert 34°C to K).

First, let's convert the pressure:

812 mmHg = 1.068 atm

Next, let's convert the temperature:

34°C = 307 K

Now, let's convert the mass of neon to moles:

13.8 g / 20.18 g/mol = 0.683 mol

Now we can plug in all the values and solve for V:

V = (nRT) / P
V = (0.683 mol x 0.0821 L·atm/mol·K x 307 K) / 1.068 atm
V = 16.9 L

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Answer:

Explanation:

17L - 64grams

12L - x grams (where x = mass at 12L)

X = [tex]\frac{12*64}{17}[/tex]

x = [tex]\frac{768}{17}[/tex]

x = 45.2g

moles,n = mass,m/ molar mass

molar mass of O2 = 16*2 = 32

moles, n = [tex]\frac{45.2}{32}[/tex]

moles, n = 1.4125 mol

Therefore O2 occupys 1.4125moles at 12L