what's 2x + 60 = 100?

Answer:

x=4

Step-by-step explanation:

bshdnbsskbewidbehhe

Answer:

yes

Step-by-step explanation:

lets use a significance level of = 0.1

Determine if the sequence indicates randomness

First step :

H0 : pattern is random

H1 : pattern not random

n1 ( number of true answers ) = 10

n2 ( number of false answers ) = 10

also number of runs for T = 5

       number of runs for F = 5

Total number of runs = 5+ 5 = 10

Given that critical value at 0.05 = 23

we will reject the null hypothesis ( i.e the sequence departs from randomness )

Answer:

You multiply them 2x each time.

Step-by-step explanation:

Multiply

Answer:

1) y = 17

2) w = 20

Step-by-step explanation:

Answer:

y= 17

w= 20

Step-by-step explanation:

Answer:

(5x+7) (5x-7)

Step-by-step explanation:

you can look up the answer on symbolab if needed

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that [tex]n = 1600, \pi = \frac{8}{1600} = 0.005[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095[/tex]

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

A sample of n is required, and n is found for M = 0.009. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}[/tex]

[tex]\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2[/tex]

[tex]n = 407.3[/tex]

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use [tex]\pi = 0.5[/tex]

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575*0.5[/tex]

[tex]\sqrt{n} = \frac{2.575*0.5}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575*0.5}{0.009})^2[/tex]

[tex]n = 20464.9[/tex]

Rounding up:

A sample of 20465 is required.

Answer:

(0.25 ; 21.75)

8.7 (1 decimal place)

Step-by-step explanation:

Net change in scores : X = 6,14,12,23,0

Sample mean, xbar = (6 + 14 + 12 + 23 + 0) /5 = 55 /5 = 11

Sample standard deviation, s = 8.66 ( from calculator)

Sample standard deviation = 8.7( 1 decimal place)

Sample size, n = 5

The 95% confidence interval; we use t, because n is small

Tcritical at 95%, df = 4 - 1 = 3 ; Tcritical = 2.776

Xbar ± standard Error

Standard Error = Tcritical * s/√n

Standard Error = 2.776 * 8.66/√5

Standard Error = 10.751086 = 10.75

Lower boundary = (11 - 10.75) = 0.25

Upper boundary = (11 + 10.75) = 21.75

(0.25 ; 21.75)

The

Answer:

The cost for 4 snacks is 18 dollars.

Cost for x snacks: 4.5x

Step-by-step explanation:

4 x 4.5 = 18

Answers:

The algebraic expression shown above is the same as writing 52+4.50x

You may not need to type in "dollars" or a dollar sign, as your teacher may just want the numbers and algebraic symbols.

=====================================================

Explanation:

There are four people going to the movies, and each ticket costs $13 a piece, so that means the total so far is 4*13 = 52 dollars.

If we want to include snacks, then it costs $4.50 per snack. Buying 4 packages will cost an additional 4.50*4 = 18 dollars. In total, if Kiran wants to buy four snacks, then he'll need 52+18 = 70 dollars.

---------------------

Instead of computing 4.50*4 to get 18, we can leave the "4.50*4" like it is. Adding it onto the 52 found earlier leads to the expression 52+4.50*4

Now imagine that instead of "4", we just had a generic placeholder x take over. The x is standing in for any positive real number, or it could stand in for 0 if Kiran decides to not buy any snacks at all.

If we replace that "4" with x, then the expression

52+4.50*4

is the same as

52+4.50*x

Often times, you'll see the multiplication symbol omitted and the expression could look like 52+4.50x

Because we can add two numbers in any order, that expression above is the same as 4.50x+52

-------------------

Extra info (optional section):

The useful thing about something like 4.50x+52 is that we can graph y = 4.50x+52 and/or set up a table to be able to quickly determine how much money it will cost for buying any amount of snacks.

For example, let's say he wants to buy 10 snacks. That means we replace x with 10 and evaluate like so

4.50x+52 = 4.50*10+52 = 45+52 = 97

Buying 10 snacks, on top of the 4 movie tickets, cost $97 in total.

Answer:

false

Step-by-step explanation:

[tex] \rm \dashrightarrow \: {x}^{2} - 6x + 5 = 0 \\ \rm \dashrightarrow \: {( - 1)}^{2} - 6( - 1) + 5 = 0 \\ \rm \dashrightarrow \: 1 + 6 + 5 = 0 \\ \rm \dashrightarrow \: 7 + 5 = 0 \\ \rm \dashrightarrow \: 12 \cancel{ = }0[/tex]

Answer:

Last Option

Step-by-step explanation:

Last one because the dot on top of the 4 is filled in and that means it can also equal 4. The rest of the line is going to the right of the 4 so x will be more than 4. The little line below the more than sign means it can also equal 4. Hope this helped :)

Answer:

Option D, x ≥ 4

Step-by-step explanation:

Rule 1: Closed circle: the inequality sign with a line at the bottom, its called greater than or equal to (≥), and less than or equal to (≤), that means that the number 4 is included in the data set.

Rule 2: Since the line is going to the right of 4, there are values greater than 4 in the data set which means x (any value) has to be greater than 4.

So bringing both rules together the equation would be: x ≥ 4

Hope this helps!

Answer:

2/5

Step-by-step explanation:

3/8 = 375/1000

1/2 = 500/1000

2/5 = 400/1000

Answer:

Step-by-step explanation:

2x+10x=12x

12x=-21

x=-1.75

Answer:

x=-7,-3

Step-by-step explanation:

x2+10x+21

(x+7)(x+3)

x=-7,-3

Answer:

6

Step-by-step explanation:

the constant is the y-intercept

Answer:

This is an impossible question. tan(0) = 0 If this means that you are supposed to just add 3/4 to each of these, then sin(20) = 1.09

Hope that this helps!

Answer:

-1

Step-by-step explanation:

Answer:74inch

Step-by-step explanation:

Assuming this is a right triangle you do pythogreom theorm and get 74 inches

Answer:

Step-by-step explanation:

9. disagree;

error: he should have divided 60 by 4, not subtracted. So the correct answer is x = 15.

10. disagree;

error: it should be 3x + 2 = 127 (opposite angles)

so x = 125/3

Answer:

x = 9

Step-by-step explanation:

4(5 + 4) = 3(x + 3) => Intersecting secants theorem

4(9) = 3(x + 3)

Open bracket by applying distributive property

36 = 3x + 9

Subtract 9 from each side

36 - 9 = 3x + 9 - 9

27 = 3x

Divide both sides by 3

27/3 = 3x/3

9 = x

x = 9

Answer:

It is 603 units greater

Step-by-step explanation:

Given

See attachment for table

Average rate of change over (a,b) is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For interval [7,9], we have:

[tex][a,b] = [7,9][/tex]

So, we have:

[tex]Rate = \frac{f(9) - f(7)}{9-7}[/tex]

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

From the table:

[tex]f(9) = 3878[/tex]

[tex]f(7) = 1852[/tex]

So:

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

[tex]Rate = \frac{3878 - 1852}{2}[/tex]

[tex]Rate = \frac{2026}{2}[/tex]

[tex]Rate = 1013\\[/tex]

For interval [4,6], we have:

[tex][a,b] = [4,6][/tex]

So, we have:

[tex]Rate = \frac{f(6) - f(4)}{6-4}[/tex]

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

From the table:

[tex]f(6) = 1178[/tex]

[tex]f(4) = 358[/tex]

So:

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

[tex]Rate = \frac{1178 - 358}{2}[/tex]

[tex]Rate = \frac{820}{2}[/tex]

[tex]Rate = 410[/tex]

Calculate the difference (d) to get how much greater their rate of change is:

[tex]d = 1013 - 410[/tex]

[tex]d = 603[/tex]

Answer:

603

Step-by-step explanation:

i took it

Answer:

Step-by-step explanation:

1). Given equation is,

   2x² - 3x = 6

   2x² - 3x - 6 = 0

   To find the solutions of the equation we will use quadratic formula,

   x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

   Substitute the values of a, b and c in the formula,

   a = 2, b = -3 and c = -6

   x = [tex]\frac{3\pm\sqrt{(-3)^2-4(2)(-6)}}{2(2)}[/tex]

   x = [tex]\frac{3\pm\sqrt{9+48}}{4}[/tex]

   x = [tex]\frac{3\pm\sqrt{57}}{4}[/tex]

   x = [tex]\frac{3+\sqrt{57}}{4},\frac{3-\sqrt{57}}{4}[/tex]

   Therefore, there are two real solutions.

2). Given equation is,

    x² + 1 = 2x

    x² - 2x + 1 = 0

    (x - 1)² = 0

     x = 1

     Therefore, there is one real solution of the equation.

3). 2x² + 3x + 2 = 0

     By applying quadratic formula,

     x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

      x = [tex]\frac{-3\pm\sqrt{3^2-4(2)(2)}}{2(2)}[/tex]

      x = [tex]\frac{-3\pm\sqrt{9-16}}{4}[/tex]

      x = [tex]\frac{-3\pm i\sqrt{7}}{4}[/tex]

      x = [tex]\frac{-3+ i\sqrt{7}}{4},\frac{-3- i\sqrt{7}}{4}[/tex]

      Therefore, there are two complex (non real) solutions.

9514 1404 393

Answer:

  A, F

Step-by-step explanation:

Points A(-1, 0) and F(-3, 8) lie on the 2nd line. (Its equation is 4x+y=-4.)

9514 1404 393

Answer:

  [tex]\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right][/tex]

Step-by-step explanation:

The system of equations can be written in standard form as ...

  x + 0y = 2

  0x +2y = 2

The augmented matrix representation of these is ...

  [tex]\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right][/tex]

Answer:

report me !!! dont ask why or how

Step-by-step explanation:

Answer:

6 ways.

There are one red, one blue and one green maker. So there are 3 markers they are in 3! = 3×2 = 6 ways.

Please mark brainliest! <3

Given:

The pair of expressions in the options.

To find:

The two expressions are equivalent for any value of y.

Solution:

Two expressions are equivalent for any value of y, iff they are equivalent.

[tex]3(3y+3)=3(3y)+3(3)[/tex]

[tex]3(3y+3)=9y+9[/tex]

Clearly, [tex]3(3y+3)[/tex] is not equivalent to [tex]6y+6[/tex] or [tex]9y+6[/tex]. So, options A and B are incorrect.

[tex]9(y+3)=9(y)+9(3)[/tex]

[tex]9(y+3)=9y+27[/tex]

[tex]9(y+3)=27+9y[/tex]

The expression [tex]9(y+3)[/tex] is not equivalent to [tex]12+9y[/tex]. So, option C is incorrect.

The expression [tex]9(y+3)[/tex] is equivalent to [tex]27+9y[/tex].

Therefore, the correct option is D.

Answer:

translation

Step-by-step explanation:

Answer:

I think it's dilation or none

Step-by-step explanation: