what's a drawback to using a histogram?

Suppose 60% of American adults believe Martha Stewart is guilty of obstruction of justice and fraud related to insider trading.

We will take a random sample of 20 American adults and ask them the question. Then the sampling distribution of the sample proportion of people who answer yes to the question is a binomial distribution.

A binomial distribution is a statistical distribution that represents the likelihood of one of two outcomes in a sequence of independent trials. Binomial distributions can be used to model a variety of phenomena, including flipping coins, rolling dice, and performing multiple independent experiments.

The probability of getting k successes in n trials in a binomial distribution with probability of success p and probability of failure q is given by the following formula:P (k) = nCk * p^k * q^(n-k)Where nCk is the binomial coefficient, which represents the number of ways to select k items from a set of n items without regard to order.

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Answer:

[tex]26 > n + 15[/tex]

[tex]11 > n[/tex]

[tex]n < 11[/tex]

Step-by-step explanation:

p-grams have equal opposite side lengths

soooo  

 5x+7   =  27  

               x = 4

then 22x = 22(4) = 88  units      ( this is also AB length)

Answer:49 = 7×7; 64 = 8×8; Difference Square is the answer. where a =7u; b = 8v. Hope that you carry out the rest Bianca,.. Jung Tran

Step-by-step explanation:

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

The absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

a. To determine if there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2, we can plug in each value of x in the interval into the equation and see if we get 0.

g(x) = 2x^3 - 5x^2 + 4x - 1

For x = -3, g(-3) = 2(-3)^3 - 5(-3)^2 + 4(-3) - 1 = -55, which is not 0.

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

b. To find the absolute minimum and maximum values of g on the interval -7 ≤ x ≤ 9, we can use the Extreme Value Theorem, which states that a continuous function on a closed interval will have both an absolute minimum and maximum value on that interval.

To find these values, we can take the derivative of g(x) and set it equal to 0 to find critical points, and then evaluate g(x) at those critical points as well as at the endpoints of the interval.

g(x) = 2x^3 - 5x^2 + 4x - 1

g'(x) = 6x^2 - 10x + 4 = 2(3x-2)(x-1)

Setting g'(x) = 0, we get critical points x = 2/3 and x = 1.

g(-7) = -765, g(2/3) = -23/27, g(1) = 0, and g(9) = 1720.

Therefore, the absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

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Answer: 1.26 × 10 to the 10th power

Step-by-step explanation:

The equation |a + 5| = −5 − a is not true for any value of a, while the equation |a + 5| = a + 5 is true for values of a greater than or equal to -5.

The absolute value of a number is defined as the distance of the number from zero on a number line. Thus, |a + 5| is equal to the distance of (a + 5) from zero on a number line. Since distance is always non-negative, |a + 5| is always non-negative.

On the other hand, the expression −5 − a is always negative, since the sum of a negative number (-5) and any number (a) is always negative.

Therefore, for the equation |a + 5| = −5 − a to be true, the absolute value of (a + 5) would have to be negative, which is impossible since absolute value is always non-negative.

For the equation |a + 5| = a + 5 to be true, a must be greater than or equal to -5, because when a is greater than or equal to -5, (a + 5) is already non-negative, so the absolute value of (a + 5) is equal to (a + 5).

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In the following question, among the conditions given, There are 26^4 x 10^5 possible license plates that can be issued using this condition.

Hence, This is because the license plates consist of 4 letters and 5 digits. There are 26 possible letters that can be used in the first four places, so the total possible combinations of 4 letters is 26^4. There are 10 possible digits that can be used in the last five places, so the total possible combinations of 5 digits is 10^5. Multiplying these two together gives the total number of possible license plates: 26^4 x 10^5.

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There are a total of $26^4 × 10^5$ possibilities, which simplifies to 26,000,000,000 (twenty-six billion) possibilities. Therefore, with this condition, twenty-six billion license plates can be issued.

A state's license plates consist of 4 letters followed by 5 digits.

How many possible license plates can be issued using this condition?

When designing a license plate, the condition provided in the question suggests that a license plate should consist of 4 letters followed by 5 digits.

Therefore, we can count the total number of license plates in two phases.

The number of choices for each segment must be taken into account separately for the letters and the numbers.

When considering the letter possibilities, there are 26 options for each position since there are 26 letters in the alphabet.

For the first 4 positions, there are a total of $26^4$ = 456,976 possibilities.

Similarly, for the last 5 positions,

there are 10 options for each position since there are 10 digits.

There are $10^5$ = 100,000 possibilities for the last 5 positions.

The entire plate's total number of combinations is obtained by multiplying these numbers.

There are a total of $26^4 × 10^5$ possibilities

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Answer: 60%

Step-by-step explanation:

As mentioned earlier, we need to know the number of senior nutrition majors and sophomore non-nutrition majors to calculate the exact probability. Without this information, we cannot provide a specific answer to the question.

However, we can provide a general formula for computing the probability, assuming that the selections are made without replacement and the population of students is large enough to assume independence:

Probability of selecting a senior nutrition major and then a sophomore non-nutrition major = (Number of senior nutrition majors / Total number of students) × (Number of sophomore non-nutrition majors / (Total number of students - 1))

Once we have the values for the number of senior nutrition majors and sophomore non-nutrition majors, we can substitute them into this formula to obtain the probability, which will be a decimal number rounded to four decimal places.

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Answer: 27.50

Step-by-step explanation: 2.50 X 7 =17.50 + 10 = 27.50

The value of p from the given equation is 4.5.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign [tex]=\\[/tex].

The given equation is [tex]0.5p-3.45=-1.2[/tex]

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

The equation can be solved as follows

[tex]0.5p-3.45=-1.2[/tex]

[tex]0.5p= -1.2+3.45[/tex]

[tex]0.5p= 2.25[/tex]

[tex]p= 2.25\div0.5[/tex]

[tex]p= 4.5[/tex]

Therefore, the value of p is 4.5.

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The standard deviation for a chi square distribution for given degree of freedom is 7.0711.

The chi-square distribution is parameterized by the number of degrees of freedom (df). As the number of degrees of freedom increases, the shape of the distribution becomes more symmetrical and approaches a normal distribution.

The standard deviation (σ) of a chi-square distribution with k degrees of freedom is given by the formula:

σ = sqrt(2k)

Therefore, for a chi-square distribution with 25 degrees of freedom:

σ = sqrt(2(25)) = sqrt(50) ≈ 7.0711

Rounding this to four decimal places gives a standard deviation of approximately 7.0711.

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Answer:

G (-3,-1)

H (-2,-3)

I (1,1)

Step-by-step explanation:

After a reflection across y=2, the y-coordinates of the vertices will change sign while the x-coordinates remain the same. Thus, the new coordinates of the vertices will be:

G (-3,-1)

H (-2,-3)

I (1,1)

Answer:

G (3,3) , H (2,5), I (-1,1)

Step-by-step explanation:

Since it’s flipped over the Y-Axis, the X-Axis numbers remain the same.

WRONG!!

didnt read the question correctly, so the vertices are incorrect lol.

This problem is a classic example of applying the stars and bars combinatorial method.

To solve this problem, we need to distribute 23 identical objects into 7 distinct containers so that none of the containers is empty. Let's start by assuming that each container has at least one object. This means we have distributed 7 objects, leaving 16 objects to be distributed.

We can now use the stars and bars method to distribute these 16 objects. Imagine placing all 16 objects in a line, and placing 6 dividers between them to separate them into 7 groups (one for each container). Each group will then receive the objects that are to the left of the divider.

For example, if we have the sequence OO|OOO|O|OOO|OO|OO|O, this corresponds to 2 objects in the first container, 3 objects in the second container, 1 object in the third container, and so on.

The number of ways to place the 6 dividers in the sequence of 16 objects is the same as the number of ways to choose 6 positions out of 16 to place the dividers. This can be computed using the formula for combinations:

$${16 \choose 6} = \frac{16!}{6!(16-6)!} = 8008$$

Therefore, there are 8008 ways to distribute 23 identical objects into 7 distinct containers so that no container is empty.

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If you know 63 people have swim suits on and 43 have sunglasses, 32 people have swim suits on but not sunglasses.

To find out how many people have swim suits on but not sunglasses, we can use the principle of inclusion-exclusion.

We know that there are 75 people in the park, and 63 of them have swim suits on. We also know that 43 people have sunglasses. However, some people have both swim suits and sunglasses. Let's denote the number of people who have both by x. Then we can use the formula:

total = swim suits + sunglasses - both

Substituting in the given values, we get:

75 = 63 + 43 - x

Simplifying, we get:

x = 31

Therefore, 31 people have both swim suits and sunglasses, and the number of people who have swim suits on but not sunglasses is:

63 - 31 = 32

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Answer:

  5240 kg/m³

Step-by-step explanation:

You want the average density of a planet with radius 6052 km and mass 4.87×10^27 g.

The mass is given in grams, and the corresponding unit in the desired answer is kilograms. There are 1000 g in 1 kg, so 4.87×10^27 g = 4.87×10^24 kg.

The radius is given in km, and the corresponding unit in the desired answer is meters. There are 1000 meters in 1 km, so 6052 km = 6052×10^3 m. (We could adjust the decimal point, but we choose to let the calculator do that.)

The units of density tell you it is computed by dividing the mass by the volume:

  ρ = mass/volume

The volume of the sphere is found using the given formula, so the density is ...

  ρ = (4.87×10^24 kg)/(4/3π(6052×10^3 m)^3)

  ρ ≈ 5240 kg/m³

The average density of the planet is about 5240 kg/m³.

__

Additional comment

This is comparable to the average density of Earth, which is about 5520 kg/m³.

Answer:

16 represents the hours available to sew gloves.

2 represents the cost of producing gloves for a small pair.

Step-by-step explanation:

The MCAT scores variable can predict some of the variation in the response variable.

The logistic regression model is a type of regression analysis that is widely used in various fields. A logistic model can be fitted using the glm() function in R. Now fit a logistic model with a single explanatory variable, MCAT scores.In logistic regression, the null deviance is the deviance for a model that has only the intercept. The null deviance will always be equal to the residual deviance if the model has only the intercept.The null deviance is calculated based on the difference between the saturated and null models' likelihoods. It is the amount of variation in the response variable that cannot be explained by the model when no predictor variables are used. When the single predictor variable MCAT scores is added to the null model, it reduces the null deviance by 11.59. This is significant because it indicates that the MCAT scores variable can predict some of the variation in the response variable.

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The correct option is c: 46lb x (16 oz / 1lb). Thus, amount of medicine given for the weight of dog in ounce is 736 ounce.

The same attribute is expressed using a unit conversion, but in a different measurement unit. For example say, time can be mentioned in minutes rather than hours, and distance can be expressed in kilometres, feet, or any other measurement unit instead of miles.

Measurements are frequently offered in one set of measurements, like feet, but are required in another set, like chains. A conversion factor is a mathematical equation that facilitates an equal exchange of feet for chains.

Given data:

ratio of ounces to pounds = 16:1

16 ounce / 1 pound

Let the weight of dog in ounce be 'x'.

weight of dog in pounds = 46 pounds.

ratio : x ounce /  46 pounds

Equating both ratios:

16 ounce / 1 pound = x ounce /  46 pounds

Cross multiplying:

x = 16*46  ounce

x = 736 ounce

The correct option is c: 46lb x (16 oz / 1lb)

Thus, amount of medicine given for the weight of dog in ounce is 736 ounce.

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Complete question is-

The ratio of ounces to pounds is 16:1. A veterinarian is treating a dog that weighs 46 pounds. To calculate the correct amount of medicine, the vet must convert the dog's weight

ounces. Which ratio shows the conversion to ounces?

The full question is attached.

After dividing and simplifying we get (x-3)/(x+3)

One of the four fundamental operations of arithmetic, or how numbers are combined to create new numbers, is division. The additional operations are addition, subtraction, and multiplication.

At a fundamental level, counting the instances in which one number is contained within another is one interpretation of the division of two natural numbers. There is no requirement that this quantity be an integer. For instance, if there are 20 apples and they are divided equally among four people, each person will get 5 apples (see picture).

The integer quotient, which is the quantity of times the second number is entirely contained in the first number, and the remainder are both produced by the division with remainder or Euclidean division of two natural numbers.

1/(x+4) divide by  [tex](x-3)/(x^2 + 7x +12)[/tex]

Simplify : [tex]x^2 +7x +12[/tex]

[tex]x^2 + (3+4)x + 12[/tex]

[tex]x^2 + 3x +4x + 12[/tex]

[tex]x(x + 3) + 4(x + 3)[/tex]

[tex](x+3)(x+4)[/tex]

[tex]1/(x + 4) x (x-3)/(x+3)(x-4)[/tex]

After dividing and simplifying we get the following answer;

[tex]= (x-3)/(x+3)[/tex]

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Rounded to two decimal places, the value of the test statistic is 0.41.

The value of the test statistic to compare the publisher's reported percentage of 75% and the marketing executive's claim that the actual percentage is different can be found by using the formula z = (p1 - p2)/(sqrt[p*(1-p)*((1/n1)+(1/n2))]), where p is the pooled proportion, p1 is the proportion of the publisher's readers owning the particular make of car, p2 is the proportion of the random sample owning the particular make of car, n1 is the total number of the publisher's readers, and n2 is the total number of the random sample.

In this case, p = [tex](75% + 69%)/2 = 72%, p1 = 75%, p2 = 69%, n1[/tex]is unknown, n2 = 250. Thus, the test statistic is z =[tex](75%-69%)/(sqrt[72%(1-72%)((1/n1)+(1/250))]) = 0.41.[/tex]

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The median of a normal distribution with a mean of $\mu$ and standard deviation of $\sigma$ is simply equal to the mean $\mu$. Therefore, for a normal distribution with a mean of 61 and a standard deviation of 14, the median is also 61.

This is because the normal distribution is a symmetric distribution, with the mean, median, and mode all located at the same point on the horizontal axis. The mean represents the center of the distribution and is also the balance point for the distribution, so half of the observations will be less than the mean and half will be greater than the mean.

Therefore, for a normal distribution with a given mean and standard deviation, we can use the mean as an estimate of the median. In this case, the mean is exactly equal to the median, so the median is 61.

It is worth noting that this property of normal distributions only holds for normal distributions, and not necessarily for other types of distributions. For example, in a skewed distribution, the mean and median may be quite different from each other.

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The sum of all eight factors is 96

Let's express the integer as a product of its prime factors, in the form

n = p1^a1 × p2^a2 × ... × pn^an

where p1, p2, ..., pn are prime numbers and a1, a2, ..., an are positive integers.

We know that the integer has 8 factors, which means that its prime factorization must have the form:

n = p1^2 × p2^2 × p3^4

since (2+1) × (2+1) × (4+1) = 3 × 3 × 5 = 45, which is the total number of factors for this product.

We also know that 15 and 21 are factors of the integer, so they must be expressible in terms of the prime factors of n. We can write

15 = 3 × 5 = p1 × p2

21 = 3 × 7 = p1 × p3

From these expressions, we can see that p1 = 3, p2 = 5, and p3 = 7.

Therefore, the prime factorization of n is

n = 3^2 × 5^2 × 7^4

The eight factors of n are

1, 3, 5, 7, 9, 15, 21, and 35

Their sum is

1 + 3 + 5 + 7 + 9 + 15 + 21 + 35 = 96

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The probability using the demand distribution of a stockout is given as 0.6293.

Out-of-stock situations, commonly referred to as stockouts, occur when a company runs out of a product that a client is prepared to purchase. Stockouts have a direct influence on customer satisfaction and are a major reason for bad reviews, additional expenses, and lost revenue or, worse, customers.

Let X = no of demand for the toy

μ =20,000

P(10000 < X < 30000) = 0.90

X follows  normal distribution

z=x−μ​/σ

P(10000 < X < 30000)=0.90

P((10000−20000​)/σ) < (x−20000​)/σ < (30000−20000​)/σ )=0.90

as probability is 0.90, the z-score =1.645.

(30000−20000)​/σ =1.645

10000​/σ=1.645

σ=10000​/1.645

σ=6079

1.P(X>15,000)

=P(Z> (15000−20000​)/6079)

=P(Z> −0.82)

=P(Z< 0.82)

=0.5+0.1293

=0.6293

2. P(X> 24000)

=P(Z> (24000−20000​)/6079)

=P(Z> 0.66)

=0.5−0.2454

=0.2546

3.Expected profit = (profit per unit )*(no of sold units) + (loss per unit )*(of units unsold)

profit = $8

loss = -$11

a. profit if 15000 units are sold =(8)(15000) + (-11)(0) = $120,000

b. if there is demand for 15,000 units but orders only 18000 units profit is (8)(15000) + (-11)(3000) = $87,000

c. if there is demand for 18,000 units but orders only 24000 units profit is (8)(18000)+(-11)(6000)= $78,000.

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Complete question:

(a) What is the expected profit if all 15,000 units are sold? type your answer...

(b) Suppose there is demand for 15,000 units, but Specialty Toys orders 18,000 units? What is the expected profit? type your answer...

(c) Suppose there is demand for 18,000 units, but Specialty Toys orders 24,000 units? What is the expected profit? type your answer... 15 3 points Based on what you know about the distribution of demand, the probability of stock-outs, and the expected profit, how many units of Weather Teddy do you recommend that Specialty Toys purchase?

The scale of proportionality is given as 8 from the table that you have presented

The table here was not properly arranged in the question. I have done so below

64 88 104

8 11 13

lets say that 8p = 64

then p = 64 / 8

p = 8

we would have to determine if the value 8 when multiplied with scaled factor  would be able to give us the original factor

8 * 11 = 88

8 * 13 = 104

Hence the scale of proportionality is given as 8

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[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 850\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=years \end{cases} \\\\\\ 850 = 500[1+(0.1)(t)] \implies \cfrac{850}{500}=1+0.10t\implies \cfrac{17}{10}=1+0.10t \\\\\\ \cfrac{17}{10}-1=0.10t\implies \cfrac{7}{10}=0.10t\implies \cfrac{7}{(10)(0.10)}=t\implies 7=t[/tex]

Answer:

................

Step-by-step explanation:

.................

Answer:

Since the decoration is in the shape of a triangle, we can use the formula for the area of a triangle to solve for its height. The area of a triangle is given by:

Area = (1/2) x base x height

Let's call the height of the decoration h. We know that the base after firing is 9 inches, so we can plug in the given values and solve for h:

Area = (1/2) x 9 x h

Area = 4.5h

We don't know the exact area of the decoration, but we do know that the decoration maintains its shape after firing. This means that the ratio of the areas before and after firing is the same, and so is the ratio of the heights and bases. Since the height and base are proportional, we can write:

h / 15 = 9 / 10

Simplifying the equation, we get:

h = (9/10) x 15

h = 13.5

Therefore, the height of the finished decoration is 13.5 inches.

To begin, we know that the median of the original collection of five positive integers is 4, which means that the middle number is 4. We also know that the unique mode is 3, which means that there is only one number in the collection that occurs more frequently than any other number.

Let's call the five positive integers in the original collection a, b, c, d, and e.

Since the mean of the original collection is 4.4, we can set up the equation:

(a+b+c+d+e)/5 = 4.4

Multiplying both sides by 5 gives:

a+b+c+d+e = 22

We also know that the mode is 3, which means that one of the numbers in the collection must be 3. Let's assume that a = 3, then we have:

3+b+c+d+e = 22

b+c+d+e = 19

Since the median is 4 and 3 is the unique mode, we can conclude that b, c, d, and e must be either 4 or 5. However, since there is only one unique mode, we know that there is only one number in the collection that is equal to 3. Therefore, we can conclude that the collection of five positive integers must be: 3, 4, 4, 4, 5.

If we add 8 to this collection, the new collection becomes: 3, 4, 4, 4, 5, 8. The new collection has six numbers, so the median is now the average of the two middle numbers. Since the middle two numbers are 4 and 5, the median is (4+5)/2 = 4.5.

Therefore, the new median is 4.5, expressed as a decimal to the nearest tenth.

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