When 100.0 mL of 1.000 M HCl is reacted with 100.0 mL of 1.000 M NH4OH, the solution’s temperature increases 7.01 °C. Calculate LaTeX: \DeltaΔHreaction in units of kJ/mol. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL.

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jdooley · Accepted Answer

Answer:Explanation:volume of solution = 100 + 100 = 200 mL mass of reaction mixture = 200 x 1.010 = 202 g specific heat of solution mixture = 4.184 J/g-Cheat evolved = mass x specific heat x rise in temperature = 202 x 4.184 x 7.01 = 5924.63 J 100 mL of 1 M HCl = .1 L of 1M HCl will contain .1 mole of HCl .1 mole reacts with .1 mole of NHOH to make 5924.63 J of heat 1 mole reacts with 1 mole of NHOH to make 59246.3 J of heat heat of reaction = 59246.3 J / mol = 59.246 kJ / mol = 59.3 kJ / mol .

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