When 394 Beach Boys fans were surveyed, 113 said that California girls was their fav song. Find a point estimate for the true proportion of BB fans who favor that song??

1. 0.713
2. 113
3. 0.287
4. 0.95
5. None of the above

Answers

Answer 1

Answer: 3. 0.287

Step-by-step explanation:

Let p be the true proportion of BB fans who favor that song.

As per given, Sample size for survey of Beach Boys fans = 394

Number of Beach Boys fans said that California girls was their fav song = 113

Then, the sample proportion of BB fans who favor that song: [tex]\hat{p}=\dfrac{113}{394}[/tex]

[tex]=0.286802030457\approx0.287[/tex]

Since sample proportion is the best estimate for the true proportion.

Hence, a point estimate for the true proportion of BB fans who favor that song is 0.287.

So, the correct option is 3. 0.287 .


Related Questions

Check whether these statements are wff or not:(a) (p˅q) ∧∼r

Answers

Answer:

It is a well formed formula

Step-by-step explanation:

1 - p,q,r are well formed formulas.

2 - [tex]p \ \lor \ q[/tex]  is a well formed formula as well.

3 - [tex]\neg r[/tex] is a well formula as well

4 - [tex](\ p \ \lor \ q) \ \land \ \neg r[/tex] is a well formula as well.

6th grade math help me, please. :)

Answers

Step-by-step explanation:

Hello there!!

no need to be panic we will help you, alright.

look solution in picture ok...

sorry for cutting in middle.

Hope it helps...

Please HELP best answer will receive a BRAINLIEST. Given the probability density function f ( x ) = 1/3 over the interval [ 4 , 7 ] , find the expected value, the mean, the variance and the standard deviation.

Answers

Answer:

[tex] E(X) =\int_{4}^7 \frac{1}{3} x[/tex]

[tex] E(X) = \frac{1}{6} (7^2 -4^2) = 5.5[/tex]

Now we can find the second moment with this formula:

[tex] E(X^2) =\int_{4}^7 \frac{1}{3} x^2[/tex]

[tex] E(X^2) = \frac{1}{9} (7^3 -4^3) = 31[/tex]

And the variance for this case would be:

[tex] Var(X)= E(X^2) -[E(X)]^2 = 31 -(5.5)^2 = 0.75[/tex]

And the standard deviation is:

[tex] Sd(X)= \sqrt{0.75}= 0.866[/tex]

Step-by-step explanation:

For this case we have the following probability density function

[tex] f(x)= \frac{1}{3}, 4 \leq x \leq 7[/tex]

And for this case we can find the expected value with this formula:

[tex] E(X) =\int_{4}^7 \frac{1}{3} x[/tex]

[tex] E(X) = \frac{1}{6} (7^2 -4^2) = 5.5[/tex]

Now we can find the second moment with this formula:

[tex] E(X^2) =\int_{4}^7 \frac{1}{3} x^2[/tex]

[tex] E(X^2) = \frac{1}{9} (7^3 -4^3) = 31[/tex]

And the variance for this case would be:

[tex] Var(X)= E(X^2) -[E(X)]^2 = 31 -(5.5)^2 = 0.75[/tex]

And the standard deviation is:

[tex] Sd(X)= \sqrt{0.75}= 0.866[/tex]

Help ASAP it’s Math I need this rightnow 31 points

Answers

Answer:

AC (b)

Step-by-step explanation:

Since 10 is half of 20, you have to find the variable closest to the middle. Which in this case, is C. So, your awnser is B. (AC)

Answer:

[tex]\boxed{\sf C}[/tex]

Step-by-step explanation:

The whole segment is [tex]\sf \sqrt {20}[/tex], we can see that AD is approximately 75% of the segment AE.

[tex]75\%*\sqrt{20} = 3.354102[/tex]

[tex]\sqrt{10}= 3.162278[/tex]

AC is almost half of AE.

[tex]\frac{\sqrt{20} }{2} = 2.2360679775[/tex]

[tex]\sqrt{10} = 3.16227766017[/tex]

It isn’t close to the option C.

when a stone falls freely, the time taken to hit the ground varies as the square root of the distance fallen. If it takes four seconds th fall 78.4m, find how long would it takefor a stone to fall 500m​

Answers

Answer:

The stone would take approximately 10.107 seconds to fall 500 meters.

Step-by-step explanation:

According to the statement of the problem, the following relationship of direct proportionality is built:

[tex]t \propto y^{1/2}[/tex]

[tex]t = k\cdot t^{1/2}[/tex]

Where:

[tex]t[/tex] - Time spent by the stone, measured in seconds.

[tex]y[/tex] - Height change experimented by the stone, measured in meters.

[tex]k[/tex] - Proportionality constant, measured in [tex]\frac{s}{m^{1/2}}[/tex].

First, the proportionality constant is determined by clearing the respective variable and replacing all known variables:

[tex]k = \frac{t}{y^{1/2}}[/tex]

If [tex]t = 4\,s[/tex] and [tex]y=78.4\,m[/tex], then:

[tex]k = \frac{4\,s}{(78.4\,m)^{1/2}}[/tex]

[tex]k \approx 0.452\,\frac{s}{m^{1/2}}[/tex]

Then, the expression is [tex]t = 0.452\cdot y^{1/2}[/tex]. Finally, if [tex]y = 500\,m[/tex], then the time is:

[tex]t = 0.452\cdot (500\,m)^{1/2}[/tex]

[tex]t \approx 10.107\,s[/tex]

The stone would take approximately 10.107 seconds to fall 500 meters.

A rectangle has a width of 3/4 inches and a length of 9/10 inches. Another rectangle
is larger but still proportional to the first rectangle. It has a width of 30 inches and a length of 36 what proportion could model this situation

Answers

Answer:

Bigger size   / smaller size = 40

Step-by-step explanation:

Notice that we      

36 / (9/10)    =    30 / (3/4)   = 40

Therefore the proportion model would be

Bigger size   / smaller size = 40

When the input is 4, the output of f(x) = x + 21 is

Answers

Answer:

25

Step-by-step explanation:

When the input is 4, the output of f(x) = x + 21 is f(4).

Substitute x = 4 to f(x):

f(4) = 4 + 21 = 25

Answer:

25

Step-by-step explanation:

We can find the output by plugging in 4 as x into the function:

f(x) = x + 21

f(4) = 4 + 21

f(4) = 25

If jimmy has 15 apples and give 7 to gohn how many does jimmy have?

Answers

Answer:

Hey there!

Jimmy has 15-7, or 8 apples left.

Hope this helps :)

A crew clears brush at a rate 2/3 acre in 2 days. How long will it take the same crew to clear the entire plot of 4 acres?

Answers

Answer:

It takes the crew 12 days to clear the bush.

Step-by-step explanation:

Given clears 2/3 acres / 2 days, or 1/3 acre per day

Time to clear 4 acres

= 4 / (1/3)

= 4 * (3/1)

= 12 days

Enter your answer in the box

____

Answers

Answer:

  [tex]\boxed{2144}[/tex]

Step-by-step explanation:

The sum can be found by adding the parts:

  [tex]\sum\limits_{n=1}^{32}{(4n+1)}=4\sum\limits_{n=1}^{32}{n}+\sum\limits_{n=1}^{32}{1}=4\cdot\dfrac{32\cdot 33}{2}+32\\\\= 2112+32=\boxed{2144}[/tex]

__

The sum of numbers 1 to n is n(n+1)/2.

Simplify the expression . 39*x / 13

Answers

Answer:

3x

Step-by-step explanation:

39*x / 13

39/13 * x

3*x

3x

Answer:

3x

Step-by-step explanation:

We are given the expression:

39*x /13

We want to simplify this expression. It can be simplified because both the numerator (top number) and denominator (bottom number) can be evenly divided by 13.

(39*x /13) / (13/13)

(39x/13) / 1

3x / 1

When the denominator is 1, we can simply eliminate the denominator and leave the numerator as our answer.

3x

The expression 39*x/13 can be simplified to 3x

Find the value of annuity if the periodic deposit is $400 at 4% compounded monthly for 18 years

Answers

Answer:

~820.8$

Step-by-step explanation:

The total money (M) after 18 years could be calculated by:

M = principal x (1 + rate)^time

with

principal = 400$

rate = 4% compounded monthly = 0.04/12

time = 18 years = 18 x 12 = 216 months (because of compounded monthly rate)

=> M = 400 x (1 + 0.04/12)^216 = ~820.8$

Data was collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below. 2 4 6 8 10 amount of sugar (mg) 180 182 184 186 188 190 192 194 Frequency What is the sample size for this data set?

Answers

Answer:

The sample size is 30.

Step-by-step explanation:

The sample size of a histogram can be calculated by summing up all the frequencies of all the occurrences in the data set

From the question the frequency is given as

Frequency = 2 4 6 8 10

The sample size n =

2 + 4 + 6 + 8 + 10

= 30

Therefore the sample size n of the data set = 30

What is the base of the expression 11^12? A. 3 B. 11 C. 12 D. 21

Answers

Answer: B. 11

An exponential has the base at the bottom, or the lower portion. Think of "basement" to help remember this. The exponent is the number up top, so 12 is the exponent.

Answer:

The person above me is correct ( :

Step-by-step explanation:

B

Solve the given systems of equations:
x-y+z=1
-3x+2y+z=1
2x-3y+4z=3​

Answers

Answer:

x = 3/2

y = 2

z = 3/2

Step-by-step explanation:

There are multiple methods to solve these. Message me for the method you need to see step by step.

50 points + brainliest!

Answers

Answer:

( x+2) ^2 = 11

x =1.32,-5.32

Step-by-step explanation:

x^2 + 4x -7 = 0

Add the constant to each side

x^2 + 4x -7+7 = 0+7

x^2 + 4x = 7

Take the coefficient of the x term

4

Divide by 2

4/2 =2

Square it

2^2 = 4

Add this to each side

x^2 + 4x +4 = 7+4

Take the 4/2 as the term inside the parentheses

( x+2) ^2 = 11

Take the square root of each side

sqrt( ( x+2) ^2)  =±sqrt( 11)

x+2 = ±sqrt( 11)

Subtract 2 from each side

x = -2 ±sqrt( 11)

To the nearest hundredth

x =1.32

x=-5.32

Answer:

[tex](x+2)^2=11[/tex]

[tex]x=-2 \pm \sqrt{11}[/tex]

Step-by-step explanation:

[tex]x^2+4x-7=0[/tex]

[tex]x^2+4x=7[/tex]

[tex]x^2+4x+4=7+4[/tex]

[tex](x+2)^2=11[/tex]

[tex]x+2=\pm\sqrt{11}[/tex]

[tex]x=-2 \pm \sqrt{11}[/tex]

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 11 ft high

Answers

Answer:

0.0526ft/min

Step-by-step explanation:

Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.

Volume of a cone V = πr²h/3

If the diameter and the height are equal, then r = h

V = πh²h/3

V = πh³/3

If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min

Using chain rule to get the expression for dV/dt;

dV/dt = dV/dh * dh/dt

From the formula above, dV/dh = 3πh²/3

dV/dh =  πh²

dV/dt = πh²dh/dt

20 = πh²dh/dt

To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.

20 = π(11)²dh/dt

20 = 121πdh/dt

dh/dt = 20/121π

dh/dt = 20/380.133

dh/dt = 0.0526ft/min

This means that the height of the pile is increasing at  0.0526ft/min

At a deli counter, there are sandwiches with meat and vegetarian sandwiches. Kira is at the counter buying sandwiches for a picnic. In how many ways can she choose sandwiches if fewer than must be vegetarian sandwiches

Answers

Answer:

The number ways to choose between meat and vegetarian sandwiches can be computed using computation technique.

Step-by-step explanation:

There are two types of sandwiches available at the deli counter. The possibility of combinations can be found by computation technique of statistic. It is assumed that order does not matter and sandwiches will be selected at random. The sandwiches can be arranged in any order and number ways can be found by 2Cn.

A hotel rents 210 rooms at a rate of $ 60 per day. For each $ 2 increase in the rate, three fewer rooms are rented. Find the room rate that maximizes daily revenue.

Answers

Answer:

r=$14,400

The hotel should charge $120

Step-by-step explanation:

Revenue (r)= p * n

where,

p = price per item

n = number of items sold

A change in price leads to a change in number sold

A variable to measure the change in p and n needs to be introduced

Let the variable=x

Such that

p + x means a one dollar price increase

p - x means a one dollar price decrease

n + x means a one item number-sold increase

n - x means a one item number-sold decrease

for each $2 price increase (p + 2x) there are 3 fewer rooms are rented (n-3x)

know that at $60 per room, the hotel rents 210 rooms

r = (60 + 2x) * (210 - 3x)

=12,600-180x+420x-6x^2

=12,600+240x-6x^2

r=2100+40x-x^2

= -x^2 +40x+2100=0

Solve the quadratic equation

x= -b +or- √b^2-4ac / 2a

a= -1

b=40

c=2100

x= -b +or- √b^2-4ac / 2a

= -40 +or- √(40)^2 - (4)(-1)(2100) / (2)(-1)

= -40 +or- √1600-(-8400) / -2

= -40 +or- √ 1600+8400 / -2

= -40 +or- √10,000 / -2

= -40 +or- 100 / -2

x= -40+100/-2 OR -40-100/-2

=60/-2 OR -140/-2

= -30 OR 70

x=70

The quadratic equation has a maximum at x=70

p+2x

=60+2(30)

=60+60

=$120

r= (60 + 2x) * (210 - 3x)

={60+2(30)}*{(210-3(30)}

r=(60+60)*(210-90)

=120*120

=$14,400

15 POINTS+BRAINLIEST (Hurry now) A train goes past you in 10 seconds and goes past a 100 meter long bridge in 30 seconds. What is the length (in meters) and the speed (inm/s) of the train?

Answers

Answer:

speed=3.33m/s

Step-by-step explanation:

speed= distance÷time

3.33 m/s

length = ?

Answer:

Length  : 50m

Speed   : 5 m  /  s

im sorry if im too late :'(

amanda teaches the art of quilling to 4 students. These students each teach art of quilling to 4 other students. If this process continues for 5 generation after amanda, BLANK people other than amanda will know the art of qiulling

Answers

Answer:

1024

Step-by-step explanation:

4 * 4 * 4 * 4 * 4

Construct a frequency distribution and a frequency histogram for the given data set using the indicated number of classes. Describe any patterns.

Number of​ classes: 8

Data​ set: Reaction times​ (in milliseconds) of 30 adult females to an auditory stimulus.

430 386 352 301 450 291 429 467 454 385 380
373 386 307 321 336 310 413 306 357 514 443
442 326 508 424 386 429 412 418

Answers

Answer:

The histogram for the data is attached below.

Step-by-step explanation:

Arrange the data in ascending order as follows:

S = {291 , 301 , 306 , 307 , 310 , 321 , 326 , 336 , 352 , 357 , 373 , 380 , 385 , 386 , 386 , 386 , 412 , 413 , 418 , 424 , 429 , 429 , 430 , 442 , 443 , 450 , 454 , 467 , 508 , 514}

Compute the range:

[tex]Range=Max.-Min.\\=514-291\\=223[/tex]

Compute the class width:

[tex]Class\ Width =\frac{Range}{No.\ of\ classes}=\frac{223}{8}=27.875\approx 28[/tex]

The classes are as follows:

290 - 318

319 - 347

348 - 376

377 - 405

406 - 434

435 - 463

464 - 492

493 - 521

Compute the frequency distribution as follows:

Class Interval         Frequency

 290 - 318                     5

 319 - 347                      3

 348 - 376                     3                  

 377 - 405                     5

 406 - 434                     7

 435 - 463                     4

 464 - 492                     1

 493 - 521                      2

The histogram for the data is attached below.

Help!! It’s much appreciated in this time

Answers

Answer:  D. y = (x - 3)² + 2

Step-by-step explanation:

Inverse is when you swap the x's and y's and solve for y.

               y = [tex]\sqrt{x-2}[/tex] + 3

Swap:      x = [tex]\sqrt{y-2}[/tex] + 3

Solve:  x - 3 = [tex]\sqrt{y-2}[/tex]

           (x - 3)² = [tex](\sqrt{y-2})^2[/tex]

           (x - 3)² = y - 2

    (x - 3)² + 2 = y

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases.

a. Central area = 0.95, df = 10
b. Central area = 0.95, df = 20
c. Central area = 0.99, df = 20
d. Central area = 0.99, df = 60
e. Upper-tail area = 0.01, df = 30
f. Lower-tail area = 0.025, df = 5

Answers

Answer:

a) Central area = 0.95, df = 10 t = (-2.228, 2.228)

(b) Central area = 0.95, df = 20 t= (-2.086, 2.086)

(c) Central area = 0.99, df = 20 t= ( -2.845, 2.845)

(d) Central area = 0.99, df = 60 t= (-2.660, 2.660)

(e) Upper-tail area = 0.01, df = 30 t= 2.457

(f) Lower-tail area = 0.025, df = 5 t= -2.571

Step-by-step explanation:

In this question, we are to determine the t critical value that will capture the t-curve area in the cases below;

We can use the t-table for this by using the appropriate confidence interval with the corresponding degree of freedom.

The following are the answers obtained from the table;

a) Central area = 0.95, df = 10 t = (-2.228, 2.228)

(b) Central area = 0.95, df = 20 t= (-2.086, 2.086)

(c) Central area = 0.99, df = 20 t= ( -2.845, 2.845)

(d) Central area = 0.99, df = 60 t= (-2.660, 2.660)

(e) Upper-tail area = 0.01, df = 30 t= 2.457

(f) Lower-tail area = 0.025, df = 5 t= -2.571

please help me ☣️☢️☢️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️▫️​

Answers

Answer:

acute isosceles triangle

vertex angle, y =  44.0 degrees. (smallest angle)

Step-by-step explanation:

If the sides are in the ratio 4:4:3,

two of the sides have equal lengths, so it is an isosceles triangle.

Also, the sum of square of the two shorter sides is greater than the square of the longest side, so it is an acute triangle.

To find the smallest angle, we draw the perpendicular bisector of the base (side length 3) and form two right triangles.

The base angle x is given by the ratio

cos(x) = 1.5/4 = 3/8

Consequently the base angle is  arccos(3/8) = 68.0 degrees.

The vertex angle equals twice the complement of 68.0

vertex angle, y = 2 (90-68.0) = 44.0 degrees. (smallest angle)

Identify an equation in point-slope form for the line perpendicular to
y= - 1/3x - 6 that passes through (-1,5).

O A. y + 1 = 3(x - 5)
O B. y + 5 = 1/3(x - 1)
O C. y - 5 = 3(x + 1)
O D. y - 5 = - 1/3(x + 1)

Answers

Answer:

hope you get it....sorry for any mistake calculations

Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence interval for mu is:______.

Answers

Answer:

The  90%  confidence interval for population mean is   [tex]14.7 < \mu < 19.1[/tex]

Step-by-step explanation:

From the question we are told that

   The sample mean is  [tex]\= x = 16.9[/tex]

    The confidence level is  [tex]C = 0.90[/tex]

     The sample size is  [tex]n = 45[/tex]

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       [tex]\alpha = 1-0.90[/tex]

       [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex]  from the standardized normal distribution table. The values is  [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

The  reason we are obtaining critical values for [tex]\frac{\alpha }{2}[/tex]  instead of  that of  [tex]\alpha[/tex]  is because [tex]\alpha[/tex]  represents the area under the normal curve where the confidence level 1 - [tex]\alpha[/tex] (90%)  did not cover which include both the left and right tail while [tex]\frac{\alpha }{2}[/tex]  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        [tex]MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]MOE = 1.645* \frac{ 9 }{\sqrt{45} }[/tex]

         [tex]MOE = 2.207[/tex]

The  90%  confidence level interval is mathematically represented as

      [tex]\= x - MOE < \mu < \= x + MOE[/tex]

substituting values

     [tex]16.9 - 2.207 < \mu < 16.9 + 2.207[/tex]

    [tex]16.9 - 2.207 < \mu < 16.9 + 2.207[/tex]

     [tex]14.7 < \mu < 19.1[/tex]

         

QUESTION 4 (10 MARKS)
A retired couple requires an annual return of $2,000 from investment of $20,000. There are 3
options available:
(A) Treasury Bills yielding 9%;
(B) Corporate bonds 11%;
Junk Bonds. 130%
How much should be invested in each to achieve their goal? Give 3 sets of options that can
achieve their goal.[10 Marks]​

Answers

Answer:

  (T, C, J) = (in dollars)

     (10000, 10000, 0),

     (15000, 4915.97, 84.03),

     (18181.82, 1680.67, 137.51)

Step-by-step explanation:

There are a number of ways to approach this question. We have chosen an approach that determines the investments required to achieve interest rate targets.

__

For an overall interest rate of I, the proportion that must be invested at rate I1 < I < I2 is ...

  proportion at I1 = (I2 -I)/(I2 -I1)

Similarly, the proportion that must be invested at I2 is what's left over. It can be computed similarly:

  proportion at I2 = (I -I1)/(I2 -I1)

__

We want an overall interest rate of $2000/$20000 = 10%.

Given available interest rates of 9%, 11%, and 130%, we need to have investments at a rate lower than 10% and at a rate higher than 10%.

If we use only the options for 9% and 11% (no junk bonds), then we can compute ...

  proportion at 9% = (11 -10)/(11 -9) = 1/2

  proportion at 11% = (10 -9)/(11 -9) = 1/2

1st Option:

  $10,000 in treasury bills; $10,000 in corporate bonds

__

Suppose we want to achieve a 13% return on our investments at 11% and 130%. Then the proportion invested at 9% will use this value for I2:

  proportion at 9% = (13 -10)/(13 -9) = 3/4

Of the remaining 1/4 of the money, we can achieve a 13% return by mixing the investments like this:

  proportion at 11% = (130 -13)/(130 -11) = 117/119

  proportion at 130% = (13 -11)/(130 -11) = 2/119

2nd option:

  $20,000 × 3/4 = $15,000 in treasury bills

  $5000 × 117/119 = $4,915.97 in corporate bonds

  The remaining amount, $84.03 in junk bonds

__

Let's suppose we want a 20% return on our investment in junk bonds and corporate bonds. Then the proportion of the money invested at 9% will be ...

  proportion at 9% = (20 -10)/(20 -9) = 10/11

And the proportion at 11% will be ...

  proportion at 11% = (130 -20)/(130 -11) = 110/119 . . . (of the remaining 1/11 of the funds)

3rd option:

  $20,000 × 10/11 = $18,181.82 in treasury bills

  $1,818.18 × 110/119 = $1,680.67 in corporate bonds

  The remaining amount, $137.51 in junk bonds

_____

Additional comment

The most that could be invested in Junk Bonds is $165.29. If the remainder is invested in Treasury Bills, then the overall return will be $2000. (You could consider this to be a 4th option.)

A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took 13.5\text{ m}^213.5 m 2 13, point, 5, start text, space, m, end text, squared of material to build the cube. What is the volume inside the giant sugar cube?

Answers

Answer:

3.375

Step-by-step explanation:

Answer:

3.375

Step-by-step explanation:

Had it on Khan

Part F
I NEED HELP!
What is the geometric mean of the measures of the line segments A Dand DC? Show your work.

Answers

Answer:

AC2  =  AB2 + BC2     --->     AC2  =  122 + 52     --->   AC  =  13

AD / AB  =  AB / AC     --->     AD / 12  =  12 / 13     --->     AD  =  144/13

DC  =  AC - AD     --->   DC  =  13 - 144/13     --->     DC  =  25/13

AD / DB  =  DB / DC     --->   DB2  =  AD · DC     --->     DB2  =  (144/13) · (25/13)  --->     DB  =  60/13

DB is the geometric mean of AD and DC.

Step-by-step explanation:

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