Answer:
4.96 eV
Explanation:
Recall the Einstein photoeletric equation;
KE = E - Wo
Where;
KE = kinetic energy of the ejected photoelectron
E= energy of the incident photon
Wo = Work function
But
KE = eV= 1.6 * 10^-19 C * 7 V /1.6 * 10^-19 C = 7 eV
E = hf/e = 6.6 * 10^-34 * 2.9 ✕ 10^15 Hz/1.6 * 10^-19
E = 11.96 eV
Hence;
Wo = E - KE
Wo = 11.96 eV - 7eV
Wo = 4.96 eV
Which of these would NOT produce visible light? A) flint B) lightning C) microwave D) sun
Answer:
A microwave
Explanation
The human retina can only detect incident light that falls in waves 400 to 720 nanometers long, so we can't see microwave or ultraviolet wavelengths. This also applies to infrared lights which has wavelengths longer than visible and shorter than microwaves, thus being invisible to the human eye.
Answer:
C.) Microwave
Explanation:
USAtestprep
5kg
P= 210 N
[2]
2 kg
3 kg
5 kg
P = 210 N
M = 0.2
141
1 kg
Answer:
2
Explanation:
ate kinus to plis ffffg
3. Which of the following statements about a scientific theory is wrong?
What are the following statements?
A capacitor has plates separated by
8.89 x 10-7 m. To create a
capacitance of 1.11 x 10-9 F, what
must the area of the plates be?
We know, formula of capacitance in parallel plate capacitor is given by :
[tex]C = \dfrac{\epsilon_o A}{d}[/tex]
Here, [tex]\epsilon_o = 8.85 \times 10^{-12} \ F.m^{-1}[/tex]
So,
[tex]A = \dfrac{Cd}{\epsilon_o}\\\\A = \dfrac{1.11 \times 10^{-9}\times 8.89 \times 10^{-7}}{8.85\times 10^{-12}}\\\\A = 1.11 \times 10^{-4}\ m^2 \ or \ 1.11 \ cm^2[/tex]
Hence, this is the required solution.
Answer:
7.09797297 • 10^-7
Explanation:
You just follow the formula:
C = εA/d
ε = 8.85 • 10^-12
A = 8.89 • 10^-7
D = 1.11• 10 ^-9
So:
C = (8.85 • 10^-12)(8.89• 10^-4)/1.11 • 10 ^-9 = 7.09797297 • 10^-7
Good Luck! :)
What is the efficiency of a car's engine when heat input is 400,000 joules and
the waste heat is 300,000 joules?
O A. 25%
B. 35%
O C. 75%
D. 85%
Answer: A. 25%
Explanation: Ap3x
how to calculate light year, minute and second?
Answer:
A light-year is the distance light travels in one year. How far is that? Multiply the number of seconds in one year by the number of miles or kilometers that light travels in one second, and there you have it: one light-year. It's about 5.88 trillion miles (9.5 trillion km).
Explanation:
Describe the change to the stores of energy of the wood, pipe and water as the water is heated
Answer:
thermal energy or proportional energy
Explanation:
when the wood is moved the energy is changed thoughout the wood and it would be the same as the pipe and water
A copper wire has a circular cross section with a raduis of 1.25mm. If the wire carries a current of 3.70A, find the drift speed of electron in this wire.
Answer: 0.043mm/s
Explanation:
The drift speed of electron in this wire will ba calculated as:
= I/nqA
= I/nqπr²
= 3.7/[(1.1 × 1^29) × (1.6 × 10^19) × (3.14 × 0.00125²)
= 4.3 × 10^-5
= 0.043mm/s
The drift speed of the electron in this wire is 0.043mm/s.
Question 4
The diagram represents the motion of a sound wave. The distance between points A and C is 9 meters (m), and it initially takes the wave 3 seconds (s) to travel.
What will be the wavelength of the sound wave if the velocity of the wave remains constant but the pitch is tripled?
A 3 meters
B 6 meters
с 9 meters
D 18 meters
Answer:A
Explanation:
The wavelength of the sound wave will be 3 meters.
What is wavelength?
The wavelength of any wave is defined as the distance between two max adjacent amplitudes, or the distance between two successive troughs or crest.
Now it is given that:
Distance =9 meters
time = 3 seconds
pitch=1/3 seconds
The velocity of the sound will be
[tex]V=\dfrac{d}{t}=\dfrac{9}{3}=3\ \frac{m}{s}[/tex]
Now from the question the wavelength of the sound wave if the velocity of the wave remains constant but the pitch is tripled
so [tex]f=3\times \dfrac{1}{3}=1 herts[/tex]
Now the velocity of the sound will be
[tex]v=f\times \lambda[/tex]
[tex]\lambda=\dfrac{v}{f}=\dfrac{3}{1}=3\ m[/tex]
Thus the wavelength of the sound wave will be 3 meters.
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Question 1 (1 point)
All solid objects will deform when enough force is applied.
O True
False
Answer:
Solid objects will deform when adequate loads are applied to them; if the material is elastic, the object will return to its initial shape and size after removal. This is in contrast to plasticity, in which the object fails to do so and instead remains in its deformed state.
Explanation:
Answer:
It is false
Explanation:
because when it like a rolling ball it can deform no matter what unlesss you throw it at the ground really hard then it breaks but a soft or sometimes metal yeah it can deform but not all things solid deform.
Below is a single strand of DNA, what is the complementary base pair for the strand?
AAG, GCA, TCA, GAT
Give details of aids in brief and explain how to protect yourself and prevent.
Answer:
(AIDS) is a chronic, potentially life-threatening condition caused by the human immunodeficiency virus (HIV). By damaging your immune system, HIV interferes with your body's ability to fight infection and disease. HIV is a sexually transmitted infection (STI). It can also be spread by contact with infected blood or from mother to child during pregnancy, childbirth or breast-feeding.
Explanation:
To help prevent the spread of HIV: 1. Use treatment as prevention (TasP). If you're living with HIV, taking HIV medication can keep your partner from becoming infected with the virus.
Two vehicles A and B accelerate uniformly from rest.
Vehicle A attains a maximum velocity of 30ms - in los
while B attains a maximum velocil) ol 40ms in the same
time. Both vehicles maintain these velocities for 6s belore
they are decelerated to rest in 6s and 4s respectively
Sketch on the same axes, velocity time graphs
for the motion of the vehicles
Calculate the velocity of each vehicle 18s aftur
the start. (VA
= 20ms -land vs
and vs = 20ms-')
How far will the two vehicles be from one
another during the moment in (ii) above?
(SA = 380m and SB
= 500m: SAB
120m). plz help
Answer:
(i) Please find attached the required velocity time graphs plotted with MS Excel
(ii) The velocity of vehicle A at the 18th second = 20 m/s
The velocity of vehicle B at the 18th second = 0 m/s
(iii) The distance between the two vehicles at the moment in (ii) above is 60 meters
Explanation:
The given parameters of the motion of vehicles A and B are;
The acceleration of vehicles A and B = Uniform acceleration starting from rest
The maximum velocity attained by vehicle A = 30 m/s
The time it takes vehicle A to attain maximum velocity = 10 s
The maximum velocity attained by vehicle B = 30 m/s
The time it takes vehicle B to attain maximum velocity = The time it takes vehicle A to attain maximum velocity = 10 s
The time duration vehicle A maintains its maximum velocity = 6 s
The time duration vehicle B maintains its maximum velocity = 4 s
(i) From the question, we get the following table;
[tex]\begin{array}{ccc}Time &V_A&V_B\\0&0&0\\10&30&40\\14&30&40\\16&30&20\\18&20&0\\22&0&\end{array}[/tex]
From the above table the velocity time graphs of vehicles A and B is created with MS Excel and can included here
(ii) The velocity of vehicle A at the start = 0 m/s
After accelerating for 10 seconds, the velocity of vehicle A = The maximum velocity of vehicle A = 30 m/s
The maximum velocity is maintained for 6 seconds which gives;
At 10 s + 6 s = 16 s, the velocity of vehicle A = 30 m/s
The time it takes vehicle A to decelerate to rest = 6 s
The deceleration of vehicle A, [tex]a_A[/tex] = (30 m/s - 0 m/s)/(6 s) = 5 m/s²
Therefore, we get;
v = u - [tex]a_A[/tex]·t
At the 18th second, the deceleration time, t = 18 s - 16 s = 2 s
u = 30 m/s
∴ v₁₈ = 30 - 5 × 2 = 20
The velocity of vehicle A at the 18th second, [tex]V_{18A}[/tex] = 20 m/s
For vehicle B, we have;
At the 14th second, the velocity of vehicle B = 40 m/s
Vehicle B decelerates to rest in, t = 4 s
The deceleration of vehicle B, [tex]a_B[/tex] = (40 m/s - 0 m/s)/(4 s) = 10 m/s²
For vehicle B, at the 18th second, t = 18 s - 14 s = 4 s
∴ [tex]v_{18B}[/tex] = 40 m/s - 10 m/s² × 4 s = 0 m/s
The velocity of the vehicle B at 18th second, [tex]v_{18B}[/tex] = 0 m/s
(iii) The distance covered by vehicle A up to the 18th second is given by the area under the velocity-time graph as follows;
The area triangle A₁ = (1/2) × 10 × 30 = 150
Area of rectangle, A₂ = 6 × 30 = 180
Area of trapezoid, A₃ = (1/2) × (30 + 20) × 2 = 50
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = A₁ + A₂ + A₃
∴ [tex]S_A[/tex] = 150 + 180 + 50 = 380
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = 380 m
The distance covered by the vehicle B in the 18th second is given by the area under the velocity time graph of vehicle B as follows;
Area of trapezoid, A₅ = (1/2) × (18 + 4) × 40 = 440
The distance covered by the trapezoid, [tex]S_B[/tex] = 440 m
The distance of the two vehicles apart at the 18t second, [tex]S_{AB}[/tex] = [tex]S_B[/tex] - [tex]S_A[/tex]
∴ [tex]S_{AB}[/tex] = 440 m - 380 m = 60 m
The distance of the two vehicles from one another at the 18th second, [tex]S_{AB}[/tex] = 60 m.
convert 67kelvin to degrees celcius
67 kelvin is -206.15 celcius
A 1200 kg car rounds a curve of radius 80 meters banked at an angle of 20°. What speed must the car travel to experience no friction between the tires and the road?
Answer:
if you wanna watch it in English it's called dub
A typical sound wave has a wavelength of 1 meter. The wavelength of green light is about 500 billionths of a meter. Which type of wave will tend to diffract more through a narrow gap that is about 1 centimeter wide? Explain.
Answer: Sound wave diffracts more.
Explanation: Width of gap d is smaller than wavelength λ of the gap.
You can estimate it from equation d sin α = n λ
The constant n is order of diffraction, n = 0,1,2,..
sin α = n λ / d is greater when λ/d is greater.
Sound wave will tend diffract more through a narrow gap that is about 1 centimeter wide.
What is Diffraction?Diffraction is the spreading of waves around obstacles. Diffraction takes place with sound; with electromagnetic radiation, such as light, X-rays, and gamma rays; and with very small moving particles such as atoms, neutrons, and electrons, which show wave like properties.
d sin α = n λ
Width of gap d is smaller than wavelength λ of the gap.
The constant n is order of diffraction, n = 0,1,2,..
sin α = n λ / d
Diffraction is greater when λ/d is greater.
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A 450.0N force is applied for 9.90s, what is the momentum?
Answer:
Momentum = 4455 Ns
Explanation:
Given the following data;
Force = 450 N
Time = 9.9 seconds
To find the momentum;
According to Newton's second law of motion in terms of momentum states that the net force acting on an object is equal to change in momentum divided by time.
Mathematically, it is given by the formula;
Net Force = change in momentum/time
Momentum = force * time
Substituting into the formula, we have;
Momentum = 450 * 9.9
Momentum = 4455 Ns
Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E midway between these two charges?
Answer:
The intensity of the net electric field will:
[tex]E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C[/tex]
Explanation:
Here we need first find the electric field due to the first charge at the midway point.
The electric field equation is given by:
[tex]|E_{1}|=k\frac{q_{1}}{d^{2}}[/tex]
Where:
k is Coulomb's constantq(1) is 20.00 μC or 20*10⁻⁶ Cd is the distance from q1 to the midpoint (d=10.0 cm)So, we will have:
[tex]|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}[/tex]
[tex]|E_{1}|=1.8*10^{7}\: N/C[/tex]
The direction of E1 is to the right of the midpoint.
Now, the second electric field is:
[tex]|E_{2}|=k\frac{q_{2}}{d^{2}}[/tex]
[tex]|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}[/tex]
[tex]|E_{2}|=7.2*10^{6}\: N/C[/tex]
The direction of E2 is to the right of the midpoint because the second charge is negative.
Finally, the intensity of the net electric field will:
[tex]E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C[/tex]
I hope it helps you!
The net electric field midway between these two charges is 2.52 x 10⁷ N/C.
Electric field strengthThe electric field strength between two point charges is the force per unit charge.
Electric field strength due to +20.0 μC charge
[tex]E _1 = \frac{kq_1}{r^2} \\\\E_ 1 = \frac{9 \times 10^9 \times 20 \times 10^{-6}}{(0.1)^2} \\\\E _1 = 18 \times 10^6 \ N/C[/tex]
Electric field strength due to -8μC charge
[tex]E _2 = \frac{kq_2}{r^2} \\\\E_ 2 = \frac{9 \times 10^9 \times 8 \times 10^{-6}}{(0.1)^2} \\\\E _2 = 7.2 \times 10^6 \ N/C[/tex]
The net electric field midway between these two charges is calculated as follows;
[tex]E_{net} = 18 \times 10^6 \ + \ 7.2 \times 10^6\\\\E_{net} = 25.2 \times 10^6 \ N/C\\\\E_{net} = 2.52 \times 10^7 \ N/C[/tex]
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Two resistors, one with 7.00 Ω of resistance and the other with 11.00 Ω of resistance, are connected in series to a 9.00 V battery. How much power is dissipated by these two resistors?
Answer:
4.5 W
Explanation:
Applying,
P = V²/(R₁+R₂).................. Equation 1
Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.
From the question,
Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00 Ω
Substitute these values into equation 1
P = 9²/(7+11)
P = 81/(18)
P = 4.5 Watt.
Hence the power dessipated by the two resistors is 4.5 watt
Throw a paper ball towards a hard wall.
a) Did the wall apply force on the ball? If yes, then what is the name of the force?
b) What are the effects of the force applied by the wall
please help..!
also if possible could you give the explanation too....??
A 90-meter train travels at a constant speed of 10 meters per second. How long will it take to cross a 0.06 bridge?
Answer:
The time taken for the train to cross the bridge is 9.01 s
Explanation:
Given;
length of the train, L₁ = 90 m
length of the bridge, L₂ = 0.06 m
speed of the train, v = 10 m/s
Total distance to be traveled, = L₁ + L₂
= 90 m + 0.06 m
= 90.06 m
Time of motion = Distance / speed
Time of motion = 90.06 / 10
Time of motion = 9.006 s ≅ 9.01 s
Therefore, the time taken for the train to cross the bridge is 9.01 s
Which scenario BEST describes an action-reaction pair? *
O A. A person pushes a cart and it rolls forward.
O B. A skateboarder pushes against the ground so she can move forward.
O C. An acrobat jumps on a trampoline and the trampoline moves downwards.
Both A and C
Answer:
C. An acrobat jumps on a trampoline and the trampoline moves downwards.
Both A and C
[tex] - trixiejane[/tex]
Why is the EM important?
Answer:
It is important because it furnishes information about the composition, the temperature and maybe the mass or relative velocity of the body that emits or absorbs it.
Explanation:
which of the following best describes the function of a resistor in an electrical circuit?
Answer:
It controls the amount of current.
Explanation:
A resistor helps control and maintain the circuit which is it's main function.
why are dams have broader walls at the bottom?
everything is perished.........(is it,isn't it, aren't they, are they
Answer:
everything is perished isn't it?
hope it helps.
Answer:
isn't it is the answer of your question
hope it is helpful to you
Two trains each of length 100m are running on two parallel trucks .One train overtakes the other in 20s and one train crosses the other in 10s.Calculate the velocity of each train
Answer:
The velocity of one of the trains is 15 m/s
The velocity of the other train 5 m/s
Explanation:
The given parameters of the two trains and the motion of the trains are;
The length of each train, l = 100 m
The time it takes one train to overtake the other, Δt₁ = 20 s
The time it takes the one train to cross the other, Δt₂ = 10 s
Let 'v₁' represent the velocity of one of the trains, and let 'v₂' represent the velocity of the other train, we have;
When one train overtakes the other, the trains are moving in the same direction and the relative velocity of the overtaking train, v = v₁ - v₂
The distance the train travels when overtaking or crossing, d = 2 × l
∴ d = 2 × 100 m = 200 m
d = 200 m
Therefore, we get;
v = v₁ - v₂ = d/Δt₁ = (200 m)/(20 s) = 10 m/s
∴ v₁ - v₂ = 10 m/s [tex]{}[/tex] Equation (1)
When one train crosses the other train, the trains are moving in opposite directions on the different tracks, therefore, we have;
For the overtaking trains, v = v₁ + v₂ = d/Δt₂ = (200 m)/(10 s) = 20 m/s
∴ v₁ + v₂ = 20 m/s [tex]{}[/tex] Equation (2)
Adding equation (1) to equation (2) gives;
v₁ - v₂ + v₁ + v₂ = 2·v₁ = 10 m/s + 20 m/s = 30 m/s
∴ v₁ = 30 m/s/2 = 15 m/s
The velocity of one of the trains, v₁ = 15 m/s
From equation (2), we have;
v₁ + v₂ = 20 m/s
v₂ = 20 m/s - v₁
∴ v₂ = 20m/s - 15 m/s = 5 m/s
The velocity of the other train, v₂ = 5 m/s.
Give three examples of how biotechnology affects our everyday lives.
Write and complete sentences
Site your sources
Answer: But what about beer-brewing, crop breeding, and the antibiotic penicillin? These processes and products – some of which have been around for thousands of years – are also examples of biotechnology.
Explanation:
Specifically, industrial biotechnology uses enzymes and micro-organisms to make bio-based products in sectors such as chemicals, food ingredients, detergents, paper, textiles and biofuels. ... Since that time, industrial biotechnology has produced enzymes for use in our daily lives and for the manufacturing sector.
12. You and a friend are playing a game of basketball. Explain why the
basketball appears orange, be sure to use terms reflected and absorbed
in your answer. [4]
Help me plssss I’m giving out brainlest and 10 points
Answer:
If the basket ball appears orange then it can be said that it reflects orange light
Explanation:
The color of the object reflected by an object is the color which is viewed by a viewer. Hence, if the basket ball reflects the orange color light , then the ball will appear orange in color to the viewer.
The light absorbed by the object has no role in deciding the color of the object visible to a viewer.
hence, if the basket ball appears orange then it can be said that it reflects orange light.
A wave is moving at the rate of 40 cm/s. Its wavelength is 5 cm. What is the frequency of the wave? INCLUDE THE CORRECT UNIT!
Answer:
Solution given:
velocity=40cm/s
wave length=5cm
we have
frequency =velocity/wavelength=40/5=8hertz.
the frequency of the wave is 8 hertz.