Rachard is studying a sample of a substance. The sample is in a large, triangle-shaped flask. Rachard moves the sample to a small, rectangular container. Both containers are closed. Below is an image of the containers used by Rachard. She notices that the shape and the volume of the substance both change when the sample is moved. In which state of matter is the substance?
The compound AlP (aluminum phosphide) is a compound semiconductor having mixed ionic and covalent bonding. Calculate the fraction of bonding that is ionic.
Answer:
0.086
Explanation:
The formula for calculating the fraction of a covalent bond can be expressed as:
= exp (-0.25ΔE²)
[tex]= exp[-0.25(E_{Al}-E_{p})^2]---(1)[/tex]
from the equation above;
[tex]E_{Al}[/tex] = the electronegativity of aluminum
[tex]E_P[/tex] = electronegativity of phosphorus
Using the data from periodic table figures;
[tex]E_{Al}[/tex] = 1.5
[tex]E_P[/tex] = 2.1
∴
fraction of the covalent = exp[-0.25(1.5 - 2.1)²]
fraction of the covalent = exp(-0.09)
fraction of the covalent = 0.914
Now, the fraction of ionic bond will be = 1 - the fraction of covalent bond
= 1 - 0.914
∴
the fraction of bond that is ionic = 0.086
An empirical formula calculation gives a molar ratio of 1.0 oxygen, 4.8 hydrogen, 4.1 carbon and 1.8 nitrogen. If the molecular mass is approximately 200 amu, what is the molecular formula
Answer:
[tex]C_8H_{10}O_2N_4[/tex]
Explanation:
Hello there!
In this case, according to the given information about the empirical formula of this compound, we can infer that these mole ratios can be rounded to the following whole numbers in order to find the empirical formula:
[tex]C_4H_5ON_2[/tex]
Whose molar mass is 97.09 amu and thus, the ratio of the molecular to the empirical molar mass is:
[tex]200/97.09=2.1[/tex]
Which is almost a factor of 2; and therefore, the resulting molecular formula is:
[tex]C_8H_{10}O_2N_4[/tex]
Regards!
HELP ME ASAP PLEASE
I need the answers I’m in a hurry
Answer: First box----Hail
Second Box-------Snow
Thrid Box-------Sleet
Forth Box-----Rain
Hope that helped! :)
If it takes 720. mL of 0.00125 M Mg(OH)2 to neutralize 425 mL of an HCI
solution, what is the concentration of the HCI? Mg(OH)2 + HCl →MgCl2
+ H20
Answer:
0.004235 M
Explanation:
The neutralization reaction of this question is given as follows:
Mg(OH)2 + 2HCl → MgCl2 + 2H2O
Using the formula below:
CaVa/CbVb = na/nb
Where;
Ca = concentration of acid (M)
Cb = concentration of base (M)
Va = volume of acid (mL)
Vb = volume of base (mL)
na = number of moles of acid = 2
nb = number of moles of base = 1
From the information provided in this question;
Ca = ?
Cb = 0.00125 M
Va = 425 mL
Vb = 720 mL
na (HCl) = 2
nb = (Mg(OH)2) = 1
Using the formula; CaVa/CbVb = na/nb
Ca × 425/0.00125 × 720 = 2/1
425Ca/0.9 = 2
472.2Ca = 2
Ca = 2/472.2
Ca = 0.004235 M
help ! thank u / ill give brainlist !
Give two examples of energy transformations that occur throughout the journey to or on the planet.
Answer:
Our bodies convert chemical energy in our food into mechanical energy for us to move.
An electric fan transforms electrical energy into kinetic energy
Reword it tho
Hope this helps!!
why does a plant have a cell wall and a cell membrane?
ASAP Pls have to turn it in at 11:00pm
Answer:
The cell wall surrounds the plasma membrane and provides the cell tensile strength and protection. ... The cell wall surrounds the plasma membrane of plant cells and provides tensile strength and protection against mechanical and osmotic stress.
hope It Helps U
Please Mark me As brainlist
Calculate the percent composition of Ca3P2
Answer:
Ca - 66%, P - 34%
Explanation:
So, this is the formula we can use to find the amount of each element:
Element count * Atomic mass = Mass
Plug in our elements for this:
Ca - 3*40.078=120.234
P - 2*30.973=61.946
Now, to find the percentage of mass, we must find total mass, and divide the two elements mass count by this total mass:
120.234+61.946=182.18
Now divide each element mass by the total mass:
Ca - 120.234/182.18=0.6599(Round to 0.65)
P - 61.946/182.18=0.34002(Round to 0.34)
Then multiply both numbers by 100 to get the percentage:
Ca - 65%
P - 34%
So these our your two answer!
Hope this helps!
is a glow stick Endothermic or exothermic ?
Answer:
exothermic
Explanation:
Which best explains the relationship between evaporation and temperature?
• A liquid evaporates slower at lower temperatures because the molecules are more spread apart and are not pushed
as easily from the liquid's surface.
O A liquid evaporates faster at lower temperatures becaus the attractions are decreased and more particles can
escape the surface of the liquid.
© A liquid evaporates slower at higher temperatures because the vapor pressure of the liquid is higher, SO fewer
molecules can escape the surface.
• A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome
attractions in the liquid.
Answer: D
Explanation:
liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.
Answer:
D. A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.
Explanation:
Correct on Edge 2022!!!
Good luck everyone, you got this! Have a great day!
it refers to the length of the entire path the object travelled
Answer:
Path length is the overall distance traveled following the path of where the object travel. ... Displacement is the distance from the starting point of the object to its final point irregardless where it travels.
Name the following alkene:
CH3CH = CHCH2CH3
A. 3-pentane
B. 2-pentene
C. 2-pentane
D. 3-pentene
Answer:
2-pentene
Explanation:
The name of the alkene is 2 pentene. The correct option is B, 2-pentene.
What is 2-pentene?Alkenes with the chemical formula [tex]C_5H_10[/tex] are known as pentene. Within its molecular structure, each has one double bond.
The given alkene [tex]CH_3CH = CHCH_2CH_3[/tex] is 2-pentene because the double bond is present in the second carbon and it's pentene because there are five carbons present.
Thus, the correct option is B. 2-pentene.
Learn more about 2-pentene
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Qualitatively explain the effect of changing concentration of Cu2+ on voltage using your experimental observations and the Keq values below. (No calculations are required).
(a) Cu^2+(aq) + 4NH3(aq) ⇄ [Cu(NH^3)4]^2+(aq) Keq = 1.2 x 10^12
(b) CuS(s) ⇄ Cu^2+(aq) + S^2-(aq) , Keq = 8.5 x 10^-45
Cu/Zn = 0.525 V
after 1 drop NH3: 0.505 V
after 2 drops NH3: 0.435 V
Cu/Zn = 0.510 V
after 1 drop Na2S: 0.452 V
after 2 drops Na2S: 0.393 V
How many molecules of sodium fluoride (NaF) are found in 7.2 moles of sodium fluoride?
Answer:
well please answer me it's question too after you get it
Explanation:
i am also stucked in that question
No. of molecules of any substance is one mole
= Avogadro's Number = (6.022 x 10^23)
So, no. of molecules in 7.2 moles of sodium fluoride
= 7.2 × (6.022 x 10^23)
= 4.33584^24
True or false: A skeleton equation in chemistry shows the relative amounts of all materials in the reaction
Answer:
false im pretty sure.
You dissolve 14 g of [tex]Mg(NO_{3} )_{2}[/tex] in water and dilute to 750 mL. What is the molarity of this solution?
Show your work
How many neutrons are in an atom of argon–40?
Answer:
22 neutrons
Explanation:
If so please sorry
When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands to 829 mL. What is the air pressure at this new altitude (in atm)?
Answer:
0.766atm
Explanation:
Boyles law
P1V1=P2V2
1×635=P2×829
P2=635/829
P2=0.766atm
What is the thermal efficiency of an engine that takes n moles of diatomic ideal gas through the cycle
Answer:
The thermal efficiency of an engine is [tex]0.15[/tex] that is 15%
Explanation:
Specific heat of a gas at constant volume is
[tex]C_{v}=\frac{fR}{2}[/tex]
here, [tex]f=[/tex]degree of freedom
[tex]R=[/tex]universal gas constant
Thermal efficiency of a cycle is
[tex]\frac{total workdone}{gross heat absorbed}[/tex]
Gross heat absorbed is amount of heat that absorbed.
ω[tex]=P_{o} V_{o}[/tex]
[tex]Q_{AB}=[/tex]Δ[tex]V_{AB}+[/tex]ω[tex]_{AB}[/tex][tex]=nC_{v}(T_{f}-T_{i} )[/tex]
[tex]=n\frac{f}{2}(RT_{f}-RT_{i} )[/tex][tex]=\frac{f}{2}(P_{o}V_{o} )[/tex]
[tex]Q_{BC}=n(\frac{f}{2}+1 )R(T_{f}-T_{i} )[/tex]
[tex]=(\frac{f}{2} +1)(4P_{o}V_{o}-2P_{o}V_{o} )[/tex]=[tex]=(\frac{f}{2}+1)2P_{o}V_{o}[/tex]
[tex]Q_{CD}=-ve and Q_{DA}=-ve[/tex] these 2 are not the part of gross heat
η[tex]=\frac{P_{o}V_{o} }{(\frac{3f}{2}+2 )(P_{o}V_{o})}[/tex]
[tex]=\frac{1}{(\frac{3f}{2}+2 )}[/tex]
For monoatomic gas [tex]f=3[/tex]
η[tex]=\frac{2}{13}[/tex]
[tex]=0.15[/tex]