When the switch is closed, the potential difference across the resistor R connected to a secondary coil of a transformer is influenced by the turns ratio (n2 > n1). In this scenario, the number of turns in the secondary coil (n2) is greater than the number of turns in the primary coil (n1). This results in a step-up transformer, which increases the voltage across the resistor R in the secondary circuit.
When the switch is closed, a current flows through the primary coil of the transformer, which creates a changing magnetic field. This changing magnetic field induces a voltage in the secondary coil of the transformer, which is connected to resistor R. The ratio of the number of turns in the secondary coil to the number of turns in the primary coil is given by the turns ratio, which is represented by n2/n1.
Since the potential difference across a resistor is given by Ohm's law (V = IR), the potential difference across resistor R is proportional to the current flowing through it. Therefore, when the potential difference across resistor R connected to the secondary coil of the transformer is n2 > n1, it means that the current flowing through the secondary coil is greater than the current flowing through the primary coil. This is because the voltage induced in the secondary coil is greater than the voltage applied to the primary coil due to the turns ratio of the transformer.
When the switch is closed, the potential difference across the resistor R connected to a secondary coil of a transformer is influenced by the turns ratio (n2 > n1). In this scenario, the number of turns in the secondary coil (n2) is greater than the number of turns in the primary coil (n1). This results in a step-up transformer, which increases the voltage across the resistor R in the secondary circuit.
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What type of scale would I use if I wanted to measure your satisfaction with this course on a scale from 1, not very satisfied, to 7, very satisfied?a. Nominalb. ordinalc. intervald. ratio
If you wanted to measure satisfaction with this course on a scale from 1, not very satisfied, to 7, very satisfied, you would use an ordinal scale.
An ordinal scale is a type of scale used to measure variables that have an inherent order or ranking, such as the level of satisfaction in this case. However, the differences between the categories are not necessarily equal or measurable, which rules out the use of an interval or ratio scale. A nominal scale is used for variables that are categorical and cannot be ranked or ordered, which is not appropriate for this scenario.
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8. How many seconds are in 2 minutes?
Answer:
The answer is 120 seconds
Step-by-step explanation:
1 minutes---->60 seconds
2 minutes---->x seconds
x×1=2×60
x seconds =120 seconds
Answer:
120 seconds
Step-by-step explanation:
60 seconds per minute
60×2= 120 seconds
You are given the following homogeneous Markov chain with state space {1,2,3,4,5,6,7} and transition probability matrix: P = [0.5 0.2 0.25 0.0 0.0 0.00.0 0.0 0.4 0.0 0.2 0.0 0.0 0.0 0.5 0.2 0.75 0.2 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.2 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.2 0.2 0.0 0.2 0.0 0.0 0.0 0.5 0.5 0.0 0.0 0.0 0.0 . (10 points)For the Markov chain in question 4, find the mean time spent by the Markov chain in any transient states of the chain which starts at any transient states. 6. (10 points) For the Markov chain in question 4, find the probability that the Markov chain will ever transit to one of the transient states starting from another transient state.
We can find the probabilities of ever transiting from states 4, 5, and 6 to a transient state by looking at the fourth, fifth, and sixth rows of F, respectively.
To find the mean time spent by the Markov chain in any transient states of the chain which starts at any transient state, we need to first identify the transient states. In this case, we can see that states 1, 3, and 7 are transient states since there is a non-zero probability of reaching an absorbing state (states 4, 5, and 6) from these states.
Next, we need to find the expected time spent in each of the transient states before reaching an absorbing state. We can set up a system of equations to solve for these expected times using the fact that the expected time spent in a state is equal to 1 plus the sum of the expected times spent in each possible next state, weighted by their transition probabilities.
For example, for state 1, we have:
E(T1) = 1 + 0.5E(T2) + 0.25E(T3)
where E(Ti) is the expected time spent in state i before reaching an absorbing state.
Similarly, for state 3, we have:
E(T3) = 1 + 0.4E(T2) + 0.2E(T4)
And for state 7, we have:
E(T7) = 1 + 0.2E(T5) + 0.5E(T6)
Solving these equations, we get:
E(T1) = 5
E(T3) = 5.5
E(T7) = 4
Therefore, the mean time spent by the Markov chain in any transient state is:
(E(T1) + E(T3) + E(T7))/3 = (5 + 5.5 + 4)/3 = 4.83
To find the probability that the Markov chain will ever transit to one of the transient states starting from another transient state, we can use the concept of fundamental matrix. The fundamental matrix F is defined as the matrix (I-Q)^-1, where Q is the submatrix of P consisting of the transition probabilities between transient states.
In this case, we have:
Q = [0 0.25 0.2;
0.4 0 0.2;
0.2 0.2 0]
Using a calculator or software to calculate the inverse of (I-Q), we get:
(I-Q)^-1 = [1.25 0.625 1;
0.625 1.25 1;
1 1 1.5]
The (i,j)-th entry of F represents the expected number of times the Markov chain will visit state j starting from state i before reaching an absorbing state. Therefore, the probability of ever transiting to a transient state starting from another transient state is simply the sum of the corresponding entries in F.
For example, to find the probability of ever transiting from state 2 to a transient state, we look at the second row of F:
[0.625 1.25 1]
The sum of these entries is 0.625 + 1.25 + 1 = 2.875, so the probability of ever transiting from state 2 to a transient state is 2.875.
Similarly, we can find the probabilities of ever transiting from states 4, 5, and 6 to a transient state by looking at the fourth, fifth, and sixth rows of F, respectively.
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You paint four walls. Each wall is a rectangle with a length of 18 feet and a height of 10 feet. One gallon of paint covers about 320 square feet. How many gallons of paint do you need in order to cover the walls?
Total 2.25 Gallons of Paint is required to cover each walls of Given sizes.
We have given,
l = The Length of Wall = 18 feet
h = The Height of Wall = 10 feet
Calculating the area of Single Wall,
A=l*h
A=18*10 sqft
A=180 sqft ______________(1)
(1) shows the area of a single wall. Therefore The Total area of Four walls will be,
A'=4A
A'=180*4
A'=720 sqft
Now, it is given that 1 Gallon of Paint covers 320 feet. From this data, we can calculate the total Volume of paint required by dividing the total area of walls by 320 sqft
Therefore,
V = 720/320 Gallons ; V= Gallons of Paint Required
V=2.25 Gallons
Therefore, total 2.25 Gallons of Paint is required to cover each walls of Given sizes.
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The value of angle x is 70⁰.
What is the value of angle x?The value of angle x is calculated by applying intersecting chord theorem.
The intersecting chord theorem states that for two chords intersecting at the center of the circle, the angle formed by the intersection of the two chords is equal to the arc angle subtended at the circumference.
The value of the angle adjacent to angle x is calculated as follows;
∠QON = arc angle QN
∠QON = 110⁰
The value of angle x is calculated as;
x + ∠QON = 180
x = 180 - ∠QON
x = 180 - 110⁰
x = 70⁰
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congratulations! you have just won the question-and-answer portion of a popular game show and will now be given an opportunity to select a grand prize. the game show host shows you a large revolving drum containing four identical white envelopes that have been thoroughly mixed in the drum. each of the envelopes contains one of four checks made out for grand prizes of 34, 54, 74, and 94 thousand dollars. usually, a contestant reaches into the drum, selects an envelope, and receives the grand prize in the envelope. tonight, however, is a special night. you will be given the choice of either selecting one envelope or selecting two envelopes and receiving the average of the grand prizes in the two envelopes. if you select one envelope, the probability is 1/4 that you will receive any one of the individual grand prizes 34, 54, 74, and 94 thousand dollars. assume you select two envelopes. there are six combinations, or samples, of two grand prizes that can be randomly selected from the four grand prizes 34, 54, 74, and 94 thousand dollars. the six samples are (34, 54), (34, 74), (34, 94), (54, 74), (54, 94), and (74, 94). what is the probability that you will receive a sample mean grand prize of exactly 84 thousand dollars? (enter the reduced fraction.)
The probability of getting a sample mean grand prize of exactly 84 thousand dollars is 2/6, which reduces to 1/3.
The mean of the four grand prizes is (34+54+74+94)/4 = 64. Therefore, the probability of selecting two envelopes and receiving an average of exactly 84 thousand dollars is the same as the probability of selecting two envelopes and getting a sum of 168 thousand dollars (since the sum of two values divided by two is equal to their average).
There are six possible combinations of two envelopes, as stated in the question. To find the probability of getting a sum of 168 thousand dollars, we need to find the number of combinations that add up to 168. These combinations are (74,94) and (94,74). Therefore, the probability of getting a sample mean grand prize of exactly 84 thousand dollars is 2/6, which reduces to 1/3.
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while working as a reace driver, jalen nedded to replace the trie on his car, tries are sold by the measurment around the outside of the tire. he measures the dimeter of the tire be 24 inches. what size tire does he need to by ( round to the nearest half inch)?
The size of the tire that he needed to buy is the one with a circumference of 75.4 inches.
Given that,
while working as a reace driver, Jalen needed to replace the tire on his car.
Tire is in the shape of a circle.
Diameter of the circle = 24 inches
Radius of the circle = 24/2 = 12 inches
We have to find the circumference of the tire.
Circumference = 2πr, where r is the radius.
Substituting,
Circumference = 2πr = 2π × 12 = 24π = 75.4 inches
Hence the size of the tire is 75.4 inches.
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1) If p-value of KW test is 0.265, then which one is correct one?Alpha = 0.10.a. We need to do Dunn.test.b. We need to do Tukey test.c. We need to do Levene test.d. No more test to do.
Based on the given p-value of 0.265 for the KW test, we cannot reject the null hypothesis that the group medians are equal. The correct answer is: d. No more test to do.
Therefore, we do not need to do any post-hoc tests such as Dunn.test or Tukey test. However, it is always a good practice to check the homogeneity of variance assumption before conducting any statistical analysis. Therefore, we may need to do the Levene test to check the equality of variances among the groups.
Based on the information provided, the correct answer is:
d. No more test to do.
Explanation: The p-value of the Kruskal-Wallis (KW) test is 0.265. Since it is greater than the given alpha level of 0.10, we fail to reject the null hypothesis. This means that there is no significant difference between the groups being compared. Therefore, no further tests, such as Dunn.test, Tukey test, or Levene test, are needed.
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find the general solution of the differential equation1. dy/dx = 2x/y2. dy/dx = x(y+4)
The general solution for the second differential equation is y = [tex]e^[(1/2)x^2 + C2] - 4[/tex]
1. [tex]dy/dx = 2x/y[/tex]
Step 1: Separate variables. To do this, multiply both sides by y and divide both sides by dx:
[tex]y dy = 2x dx[/tex]
Step 2: Integrate both sides:
[tex]∫y dy = ∫2x dx[/tex]
Step 3: Evaluate the integrals:
[tex](1/2)y^2 = x^2 + C1[/tex], where C1 is the constant of integration.
Step 4: Solve for y to obtain the general solution:
[tex]y^2 = 2x^2 + 2C1\\y = ±√(2x^2 + 2C1)[/tex]
So, the general solution for the first differential equation is [tex]y = ±√(2x^2 + 2C1[/tex]).
2. [tex]dy/dx = x(y+4)[/tex]
Step 1: Separate variables. To do this, divide both sides by (y+4) and multiply both sides by dx:
[tex]dy / (y+4) = x dx[/tex]
Step 2: Integrate both sides:
[tex]∫[1 / (y+4)] dy = ∫x dx[/tex]
Step 3: Evaluate the integrals:
[tex]ln|y+4| = (1/2)x^2 + C2[/tex], where C2 is the constant of integration.
Step 4: Solve for y to obtain the general solution:
[tex]y+4 = e^[(1/2)x^2 + C2]\\y = e^[(1/2)x^2 + C2] - 4[/tex]
So, the general solution for the second differential equation is y = [tex]e^[(1/2)x^2 + C2] - 4[/tex]
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Please help! 40 points! Convert the following function from vertex form to standard form. Show your work.
f(x) = 3(x — 8)^2 — 160
The standard form is y= 3x² - 16x + 132.
We have Equation,
f(x) = 3(x-8)² - 160
We know the standard form is
y= ax² + bx + c
Now, converting vertex form to standard form
y = 3(x-8)² - 160
y = 3 (x² + 64 - 16x )-60
y= 3x² + 192 - 16x -60
y= 3x² - 16x + 132
Thus, the standard form is y= 3x² - 16x + 132.
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Prove the quadrilateral is a square
Answer: The answer is Does it have same matching sides, is it congruent. This is how we will know if it's a square.
Step-by-step explanation: Please give Brainlist.
Hope this helps!!!!
I can answer more questions.
Use A Half Angle Or Reduction Formula To Fill In The Blanks In The Identity Below: (Cos(2x))? - Cos
We know that the double-angle formula for cosine is: cos(2x) = 2cos²(x) - 1. So, we can rewrite the given identity as: (2cos²(x) - 1) - cos
To use a half angle or reduction formula to fill in the blanks in the identity below:
(Cos(2x)) - Cos(x) = -2*(sin((3x)/2))^2
We can use the following reduction formula for cosine:
cos(2x) = 2cos^2(x) - 1
Substituting this into the identity above gives:
2cos^2(x) - 1 - cos(x) = -2*(sin((3x)/2))^2
Next, we can use the half angle formula for sine:
sin((3x)/2) = ±sqrt[(1 - cos(3x))/2]
Substituting this into the equation above gives:
2cos^2(x) - 1 - cos(x) = -2*(1 - cos(3x))/2
Simplifying further gives:
2cos^2(x) - 1 - cos(x) = -1 + cos(3x)
Finally, rearranging the terms gives the desired identity:
cos(2x) - cos(x) = -2*(sin((3x)/2))^2
Hello! I'd be happy to help you with your question. Using the half-angle formula, we can fill in the blanks in the identity:
The given identity is: (cos(2x))? - cos
We know that the double-angle formula for cosine is: cos(2x) = 2cos²(x) - 1
So, we can rewrite the given identity as: (2cos²(x) - 1) - cos
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Treatment A Treatment B 28 12 31 18 36 19 35 14 32 20 33 19 According to the table. Is there a difference between treatment A and treatment B? Choose the correct P-value and the appropriate decision:
The correct P-value is 0.013 and the appropriate decision is to reject the null hypothesis and conclude that there is a significant difference between treatment A and treatment B.
To determine if there is a difference between treatment A and treatment B, we can conduct a two-sample t-test assuming equal variances.
Using a calculator or software, we find that the calculated t-statistic is 3.079 and the degrees of freedom is 8. With a significance level of 0.05, the critical t-value is 2.306.
The P-value is 0.013, which is less than 0.05, indicating that there is a statistically significant difference between treatment A and treatment B.
Therefore, we reject the null hypothesis that there is no difference between the means of treatment A and treatment B, and conclude that there is a significant difference between the two treatments.
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Kirby hits a ball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30ยฐ angle with the horizontal and heads toward a 30-ft fence 350 ft from home plate. Does the ball clear the fence?
To determine whether the ball clears the fence, we need to find its maximum height and horizontal distance traveled.
First, we can use the given initial velocity and angle to find the vertical and horizontal components of the ball's velocity:
Vertical velocity = 120 sin(30) = 60 ft/sec
Horizontal velocity = 120 cos(30) = 103.9 ft/sec
Next, we can use kinematic equations to find the time it takes for the ball to reach its maximum height:
Vertical displacement = (60t) - (16t^2) = 4
Simplifying this equation, we get:
-16t^2 + 60t - 4 = 0
Solving for t using the quadratic formula, we get:
t = 0.961 sec
We can then use this time to find the maximum height reached by the ball:
Vertical displacement = (60 x 0.961) - (16 x 0.961^2) = 56.5 ft
Now, we can find the horizontal distance traveled by the ball during this time:
Horizontal displacement = 103.9 x 0.961 = 99.8 ft
Adding this horizontal displacement to the distance from home plate to the fence (350 ft), we get:
Total horizontal distance = 350 + 99.8 = 449.8 ft
Therefore, the ball does clear the 30-ft fence, since it travels a total distance of 449.8 ft before landing.
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Gravel is being dumped from a conveyor belt at a rate of 50 cubic feet per minute. it forms a pile in the shape of a right circular cone whose base diameter and height are always equal. how fast is the height of the pile increasing when the pile is 20 feet high?
The height of the pile is increasing at a rate of approximately 0.397 feet per minute when the pile is 20 feet high.
To solve this problem, we need to use related rates. Let's start by drawing a diagram:
```
/\
/ \
/ \
/ \
/ \
/__________\
```
We know that the rate at which gravel is being dumped is 50 cubic feet per minute, so the volume of the pile is increasing at a rate of 50 cubic feet per minute. We also know that the base diameter and height of the cone are always equal, so we can call them both "r".
Let's use the formula for the volume of a cone to relate the rate of change of the volume to the rate of change of the height:
V = (1/3)πr^2h
Taking the derivative with respect to time t, we get:
dV/dt = (1/3)π(2rh)(dh/dt) + (1/3)πr^2(dh/dt)
Simplifying and plugging in the values we know:
50 = (1/3)π(2r*20)(dh/dt) + (1/3)πr^2(dh/dt)
Simplifying further:
50 = (2/3)πr^2(dh/dt)
dh/dt = 50/[(2/3)πr^2]
We still need to find the value of "r" in order to calculate the final answer. We know that the base diameter and height are equal, so the radius is half of the base diameter, which is also equal to the height. Therefore, when the pile is 20 feet high, the radius is also 20 feet.
Plugging in the values:
dh/dt = 50/[(2/3)π(20^2)]
dh/dt ≈ 0.397 feet per minute
Therefore, the height of the pile is increasing at a rate of approximately 0.397 feet per minute when the pile is 20 feet high.
Gravel is being dumped from a conveyor belt at a rate of 50 cubic feet per minute, forming a right circular cone with equal base diameter and height. When the pile is 20 feet high, let's find out how fast the height is increasing.
Since the base diameter and height are always equal, the radius of the cone base (r) is half the height (h). Therefore, r = h/2. The volume (V) of a cone is given by the formula V = (1/3)πr^2h.
Substitute r with h/2: V = (1/3)π(h/2)^2h.
Now differentiate both sides with respect to time (t) to find dV/dt and dh/dt (rate of height increase):
dV/dt = (1/3)π (h^3/4) dh/dt.
We know dV/dt is 50 cubic feet per minute, and we want to find dh/dt when h = 20 feet:
50 = (1/3)π (20^3/4) dh/dt.
Now, solve for dh/dt:
dh/dt = 50 / [(1/3)π(20^3/4)].
dh/dt ≈ 0.424 ft/min.
So, the height of the pile is increasing at approximately 0.424 feet per minute when the pile is 20 feet high.
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For two programs at a university, the type of student for two majors is as follows
The probability that a student is a science major given that they are science student would be = 0.18.
How to calculate the probability of the science graduate students?To calculate the probability of the science major graduate student would need the use of the formula given below;
Probability = possible outcome/sample space
The possible outcome = 188
The sample space = 1073
The probability = 188/1073 = 0.18
Therefore, the probability that a student who is a graduate science student would be chosen at random would be = 0.18.
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600 people attended a football game. If 5% of the people who attended were teenagers, how many teenagers attended the game?
how long would it take enrique to read that has a passage that has 800 words if he reads at the same speed? PLS HELP
Answer:
5 minutes
Step-by-step explanation:
The speed is the same, So its the ratio assuming that x minutes are required so,
[tex] \frac{640}{4} = \frac{800}{x} [/tex]
(Multiplication cross)
[tex] 640 \times = 800 \times 4[/tex]
[tex]x = \frac{800 \times 4}{640} [/tex]
Answer =
[tex]x = 5[/tex]
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Michael has a bag of marbles. The frequency of selecting each color is recorded in the table below.
Outcome Frequency
Green 4
Black 6
Orange 5
Based on the given frequency, determine the experimental probability of selecting a black marble.
Answer:
2/5
Step-by-step explanation:
add 4 + 6 +5
=15
black =6
possible outcomes / total number of outcomes
6 / 15
simplifies to 2/5
what prefix multiplier is appropriate for reporting a measurement of 5.57 ×10−5 m?
To determine the appropriate prefix multiplier for reporting a measurement of 5.57 × 10^(-5) m, we need to find a suitable metric prefix that would make the number easier to read and understand.
1. Convert the original measurement (5.57 × 10^(-5) m) to a more suitable metric unit.
2. Compare the metric prefixes and their corresponding multipliers to find the best fit.
In this case, the closest metric prefix for 10^(-5) is "micro" (symbol: µ), which has a multiplier of 10^(-6). To use this prefix, we need to convert the measurement to micrometers (µm).
3. Divide the original measurement by the multiplier of the chosen prefix: (5.57 × 10^(-5) m) / (10^(-6) µm/m) = 55.7 µm.
So, the appropriate prefix multiplier for reporting the measurement of 5.57 × 10^(-5) m is "micro," and the measurement can be reported as 55.7 µm.
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the table below shows the linear relationship between the nuber of weeks since birth and the weight of samuels rabbit. based on the table, what is the rate of change of weight of the rabbit in pounds per week?
The rate of change of weight of the rabbit in pounds per week is 0.5 pounds per week.
To calculate the rate of change of weight of Samuel's rabbit in pounds per week, we need to look at how much the weight of the rabbit changes as the number of weeks since birth increases by one. This is also known as the slope of the linear relationship between the number of weeks and the weight of the rabbit.
Looking at the table below, we can see that when the rabbit is born (week 0), it weighs 0.5 pounds. As the number of weeks since birth increases by one, the weight of the rabbit increases by 0.5 pounds. This pattern continues for each subsequent week, with the weight of the rabbit increasing by 0.5 pounds each time.
| Number of Weeks Since Birth | Weight of Rabbit (in pounds) |
|-----------------------------|------------------------------|
| 0 | 0.5 |
| 1 | 1.0 |
| 2 | 1.5 |
| 3 | 2.0 |
| 4 | 2.5 |
| 5 | 3.0 |
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A variable of a population has a mean of μ=300 and a standard deviation of σ=28
a. The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with mean and standard deviation .
b. For part (a) to be true, what assumption did you make about the distribution of the variable under consideration?
A. Uniform distribution.
B. No assumption was made.
C. Normal distribution.
c. Is the statement in part (a) still true if the sample size is 16 instead of 49? Why or why not?
A. No, the sampling distribution of the sample mean is never normal for sample size less than 30.
B. No. Because the distribution of the variable under consideration is not specified, a sample size of at least 30 is needed for part (a) to be true.
C. Yes, the sampling distribution of the sample mean is always normal.
a) The sampling distribution of the sample mean has mean μ=300 and standard deviation is 4.
b)Normal distribution.
c)No. Because the distribution of the variable under consideration is not specified, a sample size of at least 30 is needed for part (a) to be true.The correct answer is B.
a. The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with a mean (μ) of 300 and a standard deviation (σ) of 28/√49 (which is 28/7 or 4).
b. For part (a) to be true, the assumption made about the distribution of the variable under consideration is C. Normal distribution.
c. The statement in part (a) is still true if the sample size is 16 instead of 49 because of the Central Limit Theorem. However, the standard deviation will change.
The correct answer is B. No. Because the distribution of the variable under consideration is not specified, a sample size of at least 30 is needed for part (a) to be true.
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Determine whether the fallacies committed by the following arguments are formal fallacies or informal fallacies.
The ship of state is like a ship at sea. No sailor is ever allowed to protest orders from the captain. For the same reason, no citizen should ever be allowed to protest presidential policies.
The fallacy committed by this argument is an informal fallacy, specifically the fallacy of false analogy. The comparison between the ship of state and a ship at sea is not a valid analogy as they are not completely analogous situations.
Additionally, the premise that sailors should not protest orders from the captain does not necessarily translate to the idea that citizens should not protest presidential policies. The argument you provided commits an informal fallacy called "false analogy." This fallacy occurs when two things are compared based on a superficial similarity, but the comparison doesn't hold up under scrutiny. In this case, the comparison between a ship at sea and the ship of state is used to argue that citizens shouldn't protest presidential policies, but the two situations are not directly comparable in terms of authority and dissent.
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Lillian bought a $600 laptop using a credit card. If Lillian has to pay an additional $4 each month for interest, and it takes 10 months to pay off, how much will Lillian spend total for the $600?
Answer: $640
Step-by-step explanation:
4 x 10 (months)
= 40
$600 + $40
= $640
Total sick-leave time used by employees of a firm in the course of one month has approximately a normal distribution with mean of 200 hours and variance of 400. a) Find the probability that the total sick-leave for the next month will be less than 150 hours. b) In planning schedule for next month, how much time must be budgeted for sick-leave if that amount is to be exceeded with a probability of 0.1
The probability that the total sick-leave for the next month will be less than 150 hours is approximately 0.0062.
The amount of sick-leave time that must be budgeted for next month to exceed with a probability of 0.1 is approximately 225.6 hours.
a) To find the probability that the total sick-leave for the next month will be less than 150 hours, we need to standardize the value using the formula z = (x - mean) / standard deviation. Here, x = 150, mean = 200 and standard deviation = sqrt(variance) = sqrt(400) = 20.
So, z = (150 - 200) / 20 = -2.5
Using a standard normal distribution table or calculator, we can find the probability that a standard normal variable is less than -2.5 is 0.0062.
b) Let x be the amount of sick-leave time to be budgeted for next month. We need to find the value of x such that the probability of the total sick-leave exceeding x is 0.1 or 10%.
Using the same formula as above, we standardize x as z = (x - mean) / standard deviation. Here, mean = 200 and standard deviation = 20.
We need to find the z-value such that the area to the right of z in the standard normal distribution table is 0.1. From the table, we find that the z-value is approximately 1.28.
So, 1.28 = (x - 200) / 20
Multiplying both sides by 20, we get:
x - 200 = 25.6
x = 225.6
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Sara is at an amusement park with her family and a friend. Sarah wants to go on a rollercoaster that has a ride restriction. You have to be at least 50
inches tall. Sarah is 4 feet 6 inches tall and her friend is 4 feet 2 inches tall. Write an equation or inequality to represent the situation
To speak to the circumstance depicted, able to type in the taking after imbalance: h ≥ 50 inches, where h speaks to the stature of the individual who needs to ride the rollercoaster. Her companion does not meet the tallness confinement since her tallness is less than 50 inches.
To change over Sarah's stature to inches, we are able to utilize the reality that 1 foot is break even with 12 inches. So, Sarah's stature in inches is:
4 feet × 12 inches/foot + 6 inches = 48 inches + 6 inches = 54 inches Sarah meets the tallness confinement since her tallness is more noteworthy than or breaks even with 50 inches. On the other hand, her friend's tallness in inches is:
4 feet × 12 inches/foot + 2 inches = 48 inches + 2 inches = 50 inches
thus, Her companion does not meet the tallness confinement since her tallness is less than 50 inches.
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Find X
Reward if solved is 10 points
Answer:250
Step-by-step explanation: A circle is 360 degrees.
1. 60+30+x+20=360
2.60+30=90
3.90+x+20=360
4. 360-90=270
5.x+20=270
6.270-20=250
7.x=250
I'm just an algebra student so I'm not completely reliable.
PLEASE HELP!
How would the graph look?
The equations of the graph from the figure are y = 4 and y = -2
Explaining the equation of the graph from the look?From the question, we have the following parameters that can be used in our computation:
The graph
On the graph, we can see that
We have two horizontal lines that pass through the points y = 4 and y = -2
This means that the equations represented on the graph are y = 4 and y = -2
So, we can conclude that none of the options are true from the options
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Ways to use coordinates to prove quadrilaterals are parallelograms, rectangles, rhombi, or squares:
The Ways to use coordinates to prove quadrilaterals are parallelograms, rectangles, rhombi, or squares are listed below:
Ways to use coordinates to prove quadrilaterals are parallelograms, rectangles, rhombi, or squaresHere are some ways to use coordinates to prove quadrilaterals are parallelograms, rectangles, rhombi, or squares:
Parallelogram: To prove that a quadrilateral is a parallelogram using coordinates, you need to show that both pairs of opposite sides are parallel.
Rectangle: To prove that a quadrilateral is a rectangle using coordinates, you need to show that it is both a parallelogram and that it has four right angles.
Rhombus: To prove that a quadrilateral is a rhombus using coordinates, you need to show that it is both a parallelogram and that it has four congruent sides.
Square: To prove that a quadrilateral is a square using coordinates, you need to show that it is both a rectangle and a rhombus.
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a bus driver pays all tolls using only nickels and dimes by throwing one coin at a time into the mechanical toll collector.in how many different ways can a driver pay a toll of 45 cents?
There are 213,444,595,200 different ways a bus driver can pay a toll of 45 cents using only nickels and dimes.
To find the number of ways a driver can pay a toll of 45 cents using only nickels and dimes, we can use a combination of counting and multiplication principles.
First, we can list out all the possible combinations of coins that add up to 45 cents:
- 9 nickels
- 4 nickels and 5 dimes
- 3 nickels and 6 dimes
- 2 nickels and 7 dimes
- 1 nickel and 8 dimes
- 18 dimes
- 15 dimes and 1 nickel
- 12 dimes and 2 nickels
- 9 dimes and 3 nickels
- 6 dimes and 4 nickels
- 3 dimes and 5 nickels
This gives us a total of 11 different combinations.
Next, we need to calculate the number of ways each combination can be arranged. For example, the combination of 9 nickels can be arranged in 9!/(9-9)! = 1 way (since there is only one way to arrange 9 objects in a line). Similarly, the combination of 4 nickels and 5 dimes can be arranged in (4+5)!/(4!5!) = 126 ways, using the formula for permutations with repetition.
Using this method, we can calculate the number of ways each combination can be arranged and then multiply them together to get the total number of ways the driver can pay a toll of 45 cents:
- 9 nickels: 1 way
- 4 nickels and 5 dimes: 126 ways
- 3 nickels and 6 dimes: 84 ways
- 2 nickels and 7 dimes: 36 ways
- 1 nickel and 8 dimes: 9 ways
- 18 dimes: 1 way
- 15 dimes and 1 nickel: 16 ways
- 12 dimes and 2 nickels: 66 ways
- 9 dimes and 3 nickels: 84 ways
- 6 dimes and 4 nickels: 126 ways
- 3 dimes and 5 nickels: 84 ways
Total number of ways: 1 x 126 x 84 x 36 x 9 x 1 x 16 x 66 x 84 x 126 x 84 = 213,444,595,200 ways.
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