Answer:
1927
Explanation:
Answer:
1971 is the year
In c please
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used-times.
b was used - times.
c was used - times .... ...and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array|
| Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]:
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
Describing How to Insert a Subdatasheet
Use the drop-down menus to complete the steps for inserting a subdatasheet.
1. Open a table in Design view.
2. Click the
v tab, and in the Records group, click
3. In the drop-down menu, select Subdatasheet.
4. In the Insert Subdatasheet dialog box, select the table you want and click
5. If there is no relationship between the tables, you can
one.
Ve
Answer:
1. Home
2. More
4. Ok
5. Create
Explanation:
Answer:
1. insert
2. smartart
3. OK
4. close
Explanation:
In numerical methods, one source of error occurs when we use an approximation for a mathematical expression that would otherwise be too costly to compute in terms of run-time or memory resources. One routine example is the approximation of infinite series by a finite series that mostly captures the important behavior of the infinite series.
In this problem you will implement an approximation to the exp(x) as represented by the following infinite series,
exp(x) = Infinity n= 0 xn/xn!
Your approximation will be a truncated finite series with N + 1 terms,
exp(x, N) = Infinityn n = 0 xn/xn!
For the first part of this problem, you are given a random real number x and will investigate how well a finite series expansion for exp(x) approximates the infinite series.
Compute exp(x) using a finite series approximation with N E [0, 9] N (i.e. is an integer).
Save the 10 floating point values from your approximation in a numpy array named exp_approx. exp_approx should be of shape (10,) and should be ordered with increasing N (i.e. the first entry of exp_approx should correspond to exp(x, N) when N = 0 and the last entry when N = 9).
Answer:
The function in Python is as follows:
import math
import numpy as np
def exp(x):
mylist = []
for n in range(10):
num = (x**n)/(math.factorial(n))
mylist.append([num])
exp_approx = np.asarray(mylist)
sum = 0
for num in exp_approx:
sum+=num
return sum
Explanation:
The imports the python math module
import math
The imports the python numpy module
import numpy as np
The function begins here
def exp(x):
This creates an empty list
mylist = []
This iterates from 0 to 9
for n in range(10):
This calculates each term of the series
num = (x**n)/(math.factorial(n))
This appends the term to list, mylist
mylist.append([num])
This appends all elements of mylist to numpy array, exp_approx
exp_approx = np.asarray(mylist)
This initializes the sum of the series to 0
sum = 0
This iterates through exp_approx
for num in exp_approx:
This adds all terms of the series
sum+=num
This returns the calculated sum
return sum
PLEASE HELP ME ASAP
Which of the following is NOT an example of a metasearch engine?
Answer:
Where is the choices mate?
Yo I need to know where to find a ps4 for free or a very cheap price please
The Internet is written in a "language" called
O Usenet
O package switching
O HTTP
O ARPANET
Answer:
HTTP
Explanation:
I hope it helps u.
Mark Me as brainlist answer
Answer quick plzzz I only have 2 hours
Answer:
option 2
Explanation:
Answer:
B. Kathy performs tasks common to the Engineering and Technology pathway and Sean and Joan perform tasks common to the Science and Math pathway.
free pass if you want it.
Answer:
yuh
Explanation:
Answer:
thank youuuu!
Explanation:
have a great day!!
How I did it. Part 4
Answer:
What are you asking for in this problem?
Explanation:
c Write a program that simulates a magic square using 3 one dimensional parallel arrays of integer type. Each one the arrays corresponds to a row of the magic square. The program asks the user to enter the values of the magic square row by row and informs the user if the grid is a magic square or not. flowchart
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
Write a Java program named Problem 3 that prompts the user to enter two integers, a start value and end value ( you may assume that the start value is less than the end value). As output, the program is to display the odd values from the start value to the end value. For example, if the user enters 2 and 14, the output would be 3, 5, 7, 9, 11, 13 and if the user enters 14 and 3, the output would be 3, 5, 7, 9, 11, 13.
Answer:
hope this helps
Explanation:
import java.util.Scanner;
public class Problem3 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter start value: ");
int start = in.nextInt();
System.out.print("Enter end value: ");
int end = in.nextInt();
if (start > end) {
int temp = start;
start = end;
end = temp;
}
for (int i = start; i <= end; i++) {
if (i % 2 == 1) {
System.out.print(i);
if (i == end || i + 1 == end) {
System.out.println();
} else {
System.out.print(", ");
}
}
}
}
}
Davos has been reading about encryption recently. He begins to wonder how anything can be secure if everyone is using the same set of algorithms. After all, anyone using the same algorithm would be able to decrypt anything that had been encrypted using that algorithm. Which of the following helps make the data unusable by anyone else using that same encryption scheme without having this information?
a. Algorithm
b. Cipher
c. Key
d. Block
Answer:
The correct answer is B. Cipher.
Explanation:
Cipher is a system of reversible transformations that depends on some secret parameter, called key, and is designed to ensure the secrecy of transmitted information.
The cipher can be a combination of conventional characters or an algorithm for converting ordinary numbers and letters. The process of making a message secret with a cipher is called encryption. An important parameter of any cipher is the key - a parameter of the cryptographic algorithm, which ensures the selection of one transformation from the set of transformations possible for this algorithm. In modern cryptography, it is assumed that all the secrecy of a cryptographic algorithm is concentrated in the key.
Explain the IT vendor selection and management processes
Answer:
The vendor management process includes a number of different activities, such as: Selecting vendors. The vendor selection process includes researching and sourcing suitable vendors and seeking quotes via requests for quotation (RFQs) and requests for proposal (RFPs), as well as shortlisting and selecting vendors. hope it helps
Plz hurry it’s timed
Your assignment is to write an assembly language program which read a string and print it in uppercase. This program asks the user to enter a string which is subsequently displayed in uppercase. It is important to first ensure that string to be converted is in the a-z range. The program does not recognize any space, symbols or any kind of punctuation marks. Any time the user enters any of this character the program is going to repeatedly ask for the valid string.
An example execution of your program could be:
Please enter your string: 1winter
Invalid Entry!
Please enter your string: summer
Your capitalized string:SUMMER
Answer:
try this
Explanation:
MSG1 DB 10,13,'enter any string:-$'
MSG2 DB 10,13,'converted string is:-$'
P1 LABEL BYTE
M1 DB 0FFH
L1 DB?
P11 DB 0FFH DUP<'$'>
DATA ENDS
DISPLAY MARCO MSG
MOV AH,9
LEA DX,MSG
INT 21H
ENDM
CODE SEGMENT
ASSUME CS: CODE,DS:DATA
START:
MOV AX,DATA
MOV DS,AX
DISPLAY MSG1
LEA DX,P1
MOV AH,0AH
INT 21H
DISPLAY MSG2
LEA SI,P1
MOV CL,L1
MOV CH,0
CHECK:
CMP[SI],61H
JB DONE
CMP[SI],5BH
UPR: SUB[SI],20H
DONE: INC SI
LOOP CHECK
DISPLAY P11
MOV AH,4CH
INT 21H
CODE ENDS
END START
What is the problem with paying only your minimum credit card balance each month?
A. It lowers your credit score
B. You have to pay interest
C. The bank will cancel your credit card
D. All of the above
Answer:b
Explanation:
Answer: The answer is B.
Explanation: While yes it is important to make at least the minimum payment, its not ideal to carry a balance from month to month (You'll rack up interest charges). And risk falling into debt. Therefore, the answer is B.
Hope this helps!
Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of 10 times the sum of two random numbers is equal to 10, you win, else you loose. You will need to get your own method getRandom(int n) that generates a random number, see below (you can modify it as needed), a loop, and IF statement in the loop that checks if a sum of two random numbers is 10 or not.
Please start your program as follows, similar to what we did in class:
import java.util.Random;
public class UseRandom{
//your method getRandom() is here below, n is a range for a random number from 0 to n
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}
//code continues here, don't forget your main() method inside the class, and making your own object in main() using "new" keyword.
Answer:
Explanation:
The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"
import java.util.Random;
class Brainly {
public static void main(String[] args) {
UseRandom useRandom = new UseRandom();
boolean youWin = false;
for (int x = 0; x<10; x++) {
int num1 = useRandom.getRandom(6);
int num2 = useRandom.getRandom(6);
if ((num1 + num2) == 10) {
System.out.println("Number 1: " + num1);
System.out.println("Number 2: " + num2);
System.out.println("You Win");
youWin = true;
break;
}
}
if (youWin == false) {
System.out.println("You Lose");
}
}
}
class UseRandom{
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}}
Does anybody have the full answer sheet for Cisco Packet Tracer 11.10.1 (Design and implement a vlsm addressing scheme)? Will give brainliest!
Answer:
Red font color or Gray highlights indicate text that appears ... In this lab, you will design a VLSM addressing scheme given a network ... You have been asked to design, implement, and test addressing ...
Explanation: