The appropriate correlational technique when the underlying distribution of interval scores is violently skewed would be:
b. Spearman's rank correlation coefficient
When the distribution of interval scores is violently skewed, meaning that the data is not normally distributed and may have extreme values or significant departures from normality, Pearson's correlation coefficient (option a) may not be appropriate as it assumes a linear relationship between variables and normality of data.
Instead, Spearman's rank correlation coefficient (option b) is a more appropriate choice. Spearman's rank correlation coefficient is a non-parametric method that does not assume normality of data and is based on the ranks of data rather than the actual values. It measures the strength and direction of monotonic association between variables, making it suitable for data that may not meet the assumptions of Pearson's correlation coefficient.
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Complete Question
When the underlying distribution of interval scores is violently skewed, the appropriate correlational technique should be:
a. Pearson's correlation coefficient
b. Spearman's rank correlation coefficient
c. Kendall's tau
d. Point-biserial correlation coefficient
e. Phi coefficient
The appropriate correlational technique when the underlying distribution of interval scores is violently skewed depends on the type of data and the research question, and may include non-parametric tests such as Spearman's rank correlation coefficient.
When the underlying distribution of interval scores is violently skewed, the appropriate correlational technique depends on the type of data and the research question.
If the data is bivariate (two variables) and both variables are continuous, then the appropriate correlational technique would be Spearman's rank correlation coefficient, which is a non-parametric test that measures the strength and direction of the association between two variables.
Spearman's rank correlation coefficient is used when the data is not normally distributed or when the relationship between the variables is not linear.
On the other hand, if one or both of the variables are dichotomous or categorical, then a different correlational technique may be more appropriate.
For example, if one variable is dichotomous and the other is continuous, a point-biserial correlation coefficient may be used.
If both variables are categorical, a chi-square test of independence or Cramer's V may be used.
It is important to note that the appropriateness of a particular correlational technique depends on the specific characteristics of the data and research question.
Therefore, it is recommended to consult with a statistician or data analyst to determine the most appropriate technique for a particular study.
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solve for x please
Choices are..
6
20
140
90
Answer:
Answer is 20
Step-by-step explanation:
When two lines intersect each other as a result of that, every opposite angles are equal
so,
6x+20 = 140
6x = 120
x = 120/6
x = 20
Answer:
x = 20
Step-by-step explanation:
Vertically opposite are equal
therefore
6x + 20 = 140
6x = 140-20
6x = 120
6x/6 = 120/6
x = 20
What is the value or arc PQ? Only enter numerical values.
The length of arc PQ is 110 degrees
How to find arc PQKnowing that the arc lengths are in degrees and the total for a circle is 360 degrees then we have the equation
8x - 10 + 6x + 10x + 10 = 360
To solve the equation 8x - 10 + 6x + 10x + 10 = 360 for x, we first need to simplify the left side of the equation by combining like terms:
8x + 6x + 10x - 10 + 10 = 24x
Now the equation becomes:
24x = 360
To solve for x, we need to isolate x on one side of the equation by dividing both sides by 24:
24x/24 = 360/24
x = 15
Therefore, the solution for x is 15.
Arc PQ = 8x - 10
= 8 * 15 - 10
= 110 degrees
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What is the approximate mean and standard deviation of the normal distribution below?
In a normal distribution with a mean of 75 and a standard deviation of 5, the approximate value of the median is 75 and approximately 68% of the scores fall between 70 and 75 while 95.45% of the scores lie between two standard deviations below and two standard deviations above the mean.
What is standard deviations?Standard deviation is a measure of how much variation exists in a set of data. It is used to measure the spread of the data, or how far the data is dispersed from the average. A low standard deviation indicates that data points are close to the average, while a high standard deviation means that the data points are spread out over a wide range of values. Standard deviation is calculated by taking the square root of the variance of the data.
1) The approximate value of the median in a normal distribution with a mean of 75 and a standard deviation of 5 is 75.
2) Approximately 68% of the scores fall between 70 and 75. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of 70 is 0.5 and the cumulative probability of 75 is 0.8413, so the difference of 0.3413 gives the approximate percentage of scores between 70 and 75.
3) Approximately 95.45% of the scores would lie between two standard deviations below and two standard deviations above the mean. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of two standard deviations below the mean is 0.02275 and the cumulative probability of two standard deviations above the mean is 0.97725, so the difference of 0.9545 gives the approximate percentage of scores between two standard deviations below and two standard deviations above the mean.
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Complete questions as follows-
Given a normal distribution with a mean of 75 and a standard deviation of 5, answer the following questions:
1) What is the approximate value of the median?
2) What percentage of scores fall between 70 and 75?
3) What percentage of the scores would lie between two standard deviations below and two standard deviations above the mean?
why would you use a trigonometric function to set-up an application problem instead of a non-trigonometric function
Trigonometric functions are used to model relationships between angles and sides of a right triangle. They are particularly useful in solving problems that involve angles, distances, heights, and lengths that are difficult to measure directly.
For example, consider a problem that involves finding the height of a building. By measuring the length of the shadow cast by the building at a particular time of day, the angle of the sun's rays can be calculated using trigonometry. Once the angle is known, the height of the building can be determined using the tangent function.
In contrast, a non-trigonometric function may not be able to model the relationship between the given quantities in such problems, and may not provide an accurate solution. Therefore, when a problem involves angles or distances that are not directly measurable, trigonometric functions are typically the best tool for setting up and solving the problem.
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ANSWER ASAP AND PLEASE BE CORRECT FOR BRAINLIST
Question 12
A recent conference had 750 people in attendance. In one exhibit room of 70 people, there were 18 teachers and 52 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 193 principals in attendance.
There were about 260 principals in attendance.
There were about 557 principals in attendance.
There were about 680 principals in attendance.
Question 13
A college cafeteria is looking for a new dessert to offer its 4,000 students. The table shows the preference of 225 students.
Ice Cream Candy Cake Pie Cookies
81 9 72 36 27
Which statement is the best prediction about the number of cookies the college will need?
The college will have about 480 students who prefer cookies.
The college will have about 640 students who prefer cookies.
The college will have about 1,280 students who prefer cookies.
The college will have about 1,440 students who prefer cookies.
Question 14
A random sample of 100 middle schoolers were asked about their favorite sport. The following data was collected from the students.
Sport Basketball Baseball Soccer Tennis
Number of Students 17 12 27 44
Which of the following graphs correctly displays the data?
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
Question 15
The line plots represent data collected on the travel times to school from two groups of 15 students.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 4, 6, 14, and 28. There are two dots above 10, 12, 18, and 22. There are three dots above 16. The graph is titled Bus 47 Travel Times.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9, 18, 20, and 22. There are two dots above 6, 10, 12, 14, and 16. The graph is titled Bus 18 Travel Times.
Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer.
Bus 18, with a median of 13
Bus 47, with a median of 16
Bus 18, with a mean of 13
Bus 47, with a mean of 16
Below is the answer to the questions:
Q 12.
The prediction is that there were about 260 principals in attendance at the conference.
Q13.
The best prediction is that the college will have about 480 students who prefer cookies.
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A raffle is set up with a prize purse. First prize is 50% of the purse, second
is 25%, third is 10%, and fourth through eighth win an equal amount of the
rest. If the prize purse is $10,000, how much does sixth place win?
A. $100
B. $300
(C) $375
D. $1,500
The amount of the sixth place is (B) $300.
The amount of money for each prize can be calculated as follows:
First prize: 50% of $10,000 = $5,000Second prize: 25% of $10,000 = $2,500Third prize: 10% of $10,000 = $1,000The total amount of money awarded for the first three prizes is $8,500, leaving $1,500 for the remaining five prizes.
Since the remaining five prizes are equal, each one is worth $1,500 ÷ 5 = $300.
Therefore, sixth place wins $300.
So the correct answer is (B) $300.
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Use the form |x-b |< c or |x-b | > c to write an absolute value inequality that has the solution set 5 < x < 7.
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
What is inequality?Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.
to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.
In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.
Therefore, we can write the absolute value inequality as:
[tex]| x - 6 | < 1[/tex]
Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:
[tex]x < 5 or x > 7[/tex]
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
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What is the answer to this question? (Please i need help)
A statement that is best supported by the data in the box plots include the following: H. the interquartile range of the data for the community college is greater than the interquartile range of the data for the university.
What is a box-and-whisker plot?In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.
How to calculate the interquartile range (IQR)?Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):
Interquartile range (IQR) of university = Q₃ - Q₁
Interquartile range (IQR) of university = 15 - 9
Interquartile range (IQR) of university = 6.
For the community college, we have;
Interquartile range (IQR) = 15 - 6
Interquartile range (IQR) = 9.
Therefore, 9 is greater than 6.
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Find the distance of d, of ab
The distance between the coordinates A and B is 2 √(10) units.
What is distance formula?A mathematical method called the distance formula is used to determine how far apart two points in a coordinate plane are from one another. It can be used with any two points (x1, y1) and (x2, y2) and is based on the Pythagorean theorem.
d = √((x2 - x1)² + (y2 - y1)²)
where d is the separation of the two spots.
To put it another way, we may visualise a right triangle created by the two locations and the horizontal and vertical lengths separating them to get the distance between them. The triangle's hypotenuse, or the distance between its two points, is measured using the distance formula.
The distance formula is given as:
d = √((x2 - x1)² + (y2 - y1)²)
Now, for the given coordinates we have:
d = √((1 - (-5))² + (3 - 1)²)
d = √(6² + 2²)
d = √(40)
d = 2 √(10)
Hence, the distance between A and B is 2 √(10) units.
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The rate of consumption of oil in the United States during the 1980s (in billions of barrels per year) is modeled by the function C(t) = 27.08e', where t is the number of years after January 1, 1980. Find the total consumption of oil in the United States from January 1, 1980 to January 1, 1990.
the total consumption of oil in the United States from January 1, 1980, to January 1, 1990 is approximately 596,533.7 billion barrels.
To find the total consumption of oil in the United States from January 1, 1980 to January 1, 1990, we need to integrate the given function[tex]C(t) = 27.08e^t[/tex]with respect to time t, over the interval [0, 10], where t is measured in years.
The integral of the function is:
∫[tex](27.08e^t) dt[/tex]
To solve this integral, we use the fact that the integral of[tex]e^t[/tex] is [tex]e^t[/tex]itself. Thus, we get:
27.08∫[tex]e^t dt = 27.08e^t[/tex]
Now, we need to evaluate the definite integral over the interval [0, 10]:
[tex]27.08e^t[/tex]| from 0 to 10 =[tex]27.08(e^{10} - e^0)[/tex]
As e^0 = 1, the expression simplifies to:
[tex]27.08(e^{10} - 1)[/tex]
Now, we can calculate the value of the expression:
[tex]27.08(e^{10} - 1) =27.08(22026.47 - 1) = 27.08 * 22025.47 =596533.7[/tex]
Thus, the total consumption of oil in the United States from January 1, 1980, to January 1, 1990 is approximately 596,533.7 billion barrels.
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suppose you enter a raffle. there are a total of 100 entries. the winner of the raffle will win $500 if they can also guess the favorite season of the raffle organizer. there is a 0.01 chance of winning the raffle, and a 0.25 chance of guessing the organizer's favorite season. what is the chance that you will both win the raffle and win $500?
The chance that you will both win the raffle and win $500 is 0.0025, or 0.25%.
To find the chance of both winning the raffle and correctly guessing the organizer's favorite season, you need to multiply the probabilities of these two independent events.
Step 1: Determine the probability of winning the raffle.
The probability of winning the raffle is given as 0.01.
Step 2: Determine the probability of correctly guessing the favorite season.
The probability of correctly guessing the favorite season is given as 0.25.
Step 3: Multiply the probabilities of the two independent events.
To find the probability of both events happening, you multiply their probabilities: 0.01 (winning the raffle) * 0.25 (correctly guessing the favorite season).
0.01 * 0.25 = 0.0025
So, the chance that you will both win the raffle and win $500 is 0.0025, or 0.25%.
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The probability of both winning the raffle and correctly guessing the organizer's favorite season to win the $500 prize is 0.0025 or 0.25%.
To find the probability of both winning the raffle and guessing the organizer's favorite season correctly, you'll need to multiply the individual probabilities of each event.
Probability of winning the raffle: 0.01 (given in the question)
Probability of guessing the organizer's favorite season: 0.25 (given in the question)
Now, multiply these probabilities together:
0.01 * 0.25 = 0.0025.
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11. Jessica is focusing on wrestling this semester. What category does this sport fall into?
The Correct Answer Is: High-strength sports.
explanation:
Because for wrestling you have to use, you're strength. (And I just did the exam and I got it wrong for choosing the wrong answer, so I believe it's my answer. !!so, it's not high-power sports)
I hope it helps you!
:)
Solve the given right triangle for its missing angle and side measures.
Note: Figure not drawn to scale
A.
m∠D = 55°, DE ≈ 4. 40 units, DF ≈ 13. 65 units
B.
m∠D = 55°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
C.
m∠D = 35°, DE ≈ 8. 40 units, DF ≈ 13. 65 units
D.
m∠D = 35°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
The missing angle D is 55 degrees, and the lengths of DE and DF are approximately 8.40 units and 14.65 units, respectively. Therefore, the correct option is (B) m∠D = 55°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
We can start by using the trigonometric ratios of the angles in a right triangle. In particular, we can use the tangent function to find the measure of angle D
tan(D) = DE / FE
tan(D) = DE / 12
We know that angle F is 35 degrees, so angle D must be
D = 90 - F
D = 90 - 35
D = 55 degrees
Now that we know the measure of angle D, we can use the sine and cosine functions to find the lengths of DE and DF, respectively. We know that
sin(F) = DE / DF
cos(F) = FE / DF
Substituting the given values
sin(35) = DE / DF
cos(35) = 12 / DF
Solving for DE and DF
DE = DF × sin(35)
DE = DF × 0.574
DE ≈ 0.574 × DF
DF = 12 / cos(35)
DF ≈ 14.65 units
DE ≈ 0.574 × 14.65
Multiply the numbers
DE ≈ 8.40 units
Therefore, the correct option is (B) m∠D = 55°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
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The given question is incomplete, the complete question is:
Solve the given right triangle for its missing angle and side measures
A. m∠D = 55°, DE ≈ 4. 40 units, DF ≈ 13. 65 units
B. m∠D = 55°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
C. m∠D = 35°, DE ≈ 8. 40 units, DF ≈ 13. 65 units
D. m∠D = 35°, DE ≈ 8. 40 units, DF ≈ 14. 65 units
Using the graph, determine the coordinates of the y-intercept of the parabola.
Answer:
The y-intercept is at (0, 8).
Answer: (0,8)
Step-by-step explanation: The line only touches the Y-axis Once and its on 8
is 12% a reasonable estimate of the proportion of all americans who eat chocolate frequently? why or why not?
The reasonableness of the estimate depends on the quality and reliability of the data sources and methodology used to arrive at the estimate.
In order to determine whether 12% is a reasonable estimate of the proportion of all Americans who eat chocolate
frequently, we would need to define what is meant by "frequently."
If we define "frequently" as "at least once a week," then 12% may or may not be a reasonable estimate, depending on
the data source and methodology used to arrive at that estimate.
For example, if the estimate is based on a small sample size or a non-representative sample of the population, then it
may not be a reliable estimate of the true proportion of Americans who eat chocolate frequently. Additionally, if the
estimate is several years old, it may not accurately reflect current trends and habits.
On the other hand, if the estimate is based on a large, nationally representative sample of the population, and is
relatively recent, then 12% could be a reasonable estimate of the proportion of Americans who eat chocolate
frequently.
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PLEASE HELP ME APSPPPPP!!!!!!!!!
Answer: the 3d shape would be a rectangle. the hight is 3. and the diameter is 10
Step-by-step explanation:
1. Calculate the perimeter, area and volume a) Classroom with Length=10m, breadth=8m and height=3m b) Box with Length=40cm, breadth=25cm and height=30cm c) Cabinet with length=80cm, breadth=70cm and height=2m Area Volume 26 a b C Perimeter
a) Classroom:
Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m
Area = length x breadth = 10m x 8m = 80m^2
Volume = length x breadth x height = 10m x 8m x 3m = 240m^3
What is the perimeter, area and volume?b) Box:
Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm
Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2
Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3
c) Cabinet:
Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm
Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2
Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3
Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.
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state the nameof this quadrilateral...70 points
Answer:
Step-by-step explanation:
its a rectanlge
Given the quadratic equation x^(2)+4x+c=0, what must the value of c be in order for the equation to have solutions at x=-3 and x=-1 ?
Answer:
Step-by-step explanation:
If the solutions are x = -3 and x = -1, then (x - 3) (x - 1) will give us our answer. Using the FOIL method,
(x - 3) (x - 1)
x^2 - x - 3x + 3
x^3 - 4x + 3 = 0
Your answer is 3
Grupo textil M & M destaca que los ingresos de este año vienen dados por la funcion f(x) = (x+2)(-x+9-3) donde "x" es el precio de cada unidad y f(x) es la ganancia expresada en dolares
Para entender mejor esta función, podemos expandirla y simplificarla:
f(x) = (x+2)(-x+6)
f(x) = [tex]-x^2 + 4x + 12[/tex]
Esta es una función cuadrática, lo que significa que tiene la forma de una parábola. El término cuadrático ([tex]-x^2[/tex]) hace que la parábola tenga una concavidad hacia abajo, lo que significa que el valor máximo de la función se encuentra en el vértice de la parábola.
Podemos encontrar el valor del precio de venta que maximiza la ganancia utilizando la fórmula x = -b/(2a), donde "a" es el coeficiente del término cuadrático y "b" es el coeficiente del término lineal.
En este caso, a = -1 y b = 4, por lo que:
x = -4/(2-1)
x = -4/-2
x = 2
Por lo tanto, el precio de venta que maximiza la ganancia es de 2 por unidad. Si se venden las unidades a este precio, la ganancia total sería de:
f(2) = [tex]-2^2 + 4(2) + 12[/tex]
f(2) = -4 + 8 + 12
f(2) = 16 dólares
Es importante tener en cuenta que la función f(x) también puede ser utilizada para calcular la ganancia total para cualquier precio de venta "x". Por ejemplo, si se venden las unidades a 3 por unidad, la ganancia sería:
f(3) = [tex]-3^2 + 4(3) + 12[/tex]
f(3) = -9 + 12 + 12
f(3) = 15 dólares
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There is 6/8 of a cake
leftover after a birthday
party. How many 1/4
pieces can be made from
the leftover cake?
Answer: 3 pieces
Step-by-step explanation:First, 6/8 can be converted into fourths by dividing the numerator and the denominator by 2 and we get 3/4. if we want 1/4 slices we divide 3/4 by 1/4 and get 3.
if i randomly sample two cities from this group (consider these 45 the 'population' if you will) then what is the probability that at least one of the cities i select will have a commute time greater than 30 minutes?
The probability of at least 10 cities out 45 have a commute time greater than 30 minutes is 0.893 or 89.3%
Apply the complement rule.
Probability that at least one of the 10 cities you select will have a commute time greater than 30 minutes,
The complement of the event is 'none of the 10 cities have a commute time greater than 30 minutes'.
The probability of the complement event can be calculated by ,
Multiplying probabilities of selecting a city with a commute time less than or equal to 30 minutes for each of 10 selections.
P(none of 10 cities have a commute time > 30 minutes) = (35/45) x (35/45) x ... x (35/45) (10 times)
Because there are 35 cities out of the total 45 that have a commute time less than or equal to 30 minutes.
So the probability that at least one of the 10 cities has a commute time greater than 30 minutes is,
1 - P(none of the 10 cities have a commute time greater than 30 minutes)
= 1 - (35/45) x (35/45) x ... x (35/45) (10 times)
= 1 - 0.1073
= 0.8926
Therefore, the probability that at least one of the 10 cities you select will have a commute time greater than 30 minutes is 0.893 or 89.3%.
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The above question is incomplete, the complete question is:
If i randomly sample two cities from this group (consider these 45 the 'population' if you will) then what is the probability that at least one of the 10 cities i select will have a commute time greater than 30 minutes?
0.2v = 1.2; v=10 is it a solution or not a solution?
Answer: To check if v=10 is a solution to the equation 0.2v = 1.2, we can substitute v=10 into the equation and see if the equation holds true:
0.2v = 1.2
0.2(10) = 1.2
2 = 1.2
This is not true, since 2 is not equal to 1.2. Therefore, v=10 is not a solution to the equation 0.2v = 1.2.
Step-by-step explanation:
Answer:
solution
Step-by-step explanation:
7(x + 2) = 7x + 14 i dont get this someone pls help
Answer:
7
(
x
−
2
)
−
7
x
−
14
=
0
7
(
x
−
2
)
−
7
x
−
14
=
07
(
x
−
2
)
−
7
x
−
14
=
0
Step-by-step explanation:
Answer: 0 = 0
Step-by-step explanation: i showed the steps with these screen shots
a professor has two lightbulbs in her garage. when both are burned out, they are replaced, and the next day starts with two working lightbulbs. suppose when both are working, one of the two will go out with probability 0.03, and we cannot lose both lightbulbs on the same day. however, when only on lightbulb works, it will burn out with probability 0.07. what is the long-run fraction of time that there is exactly one lightbulb working?
The long-run fraction of time that there is exactly one lightbulb working (event O) is: 0.228.
Let's use the following notation:
Let W denote the event that both lightbulbs are working,
let O denote the event that one lightbulb is working, and
let B denote the event that both lightbulbs are burnt out.
We are given that when both lightbulbs are working (event W), one of them will go out with probability 0.03.
Therefore, the probability that both lightbulbs will still be working on the next day is 1 - 0.03 = 0.97.
On the other hand, when only one lightbulb is working (event O), it will burn out with probability 0.07, and the other lightbulb is already burnt out.
Hence, the probability of moving from O to B is 1.
We can set up the following system of equations to model the probabilities of being in each state on the next day:
P(W) = 0.97P(W) + 0.5P(O)
P(O) = 0.03P(W) + 0.93P(O) + 1P(B)
P(B) = 0.07P(O)
Note that in the first equation, we use 0.97 because the probability of staying in W is 0.97, and the probability of moving to O is 0.5 (because there are two ways for one of the lightbulbs to go out).
Simplifying the system of equations, we get:
0.03P(W) - 0.5P(O) = 0
-0.03P(W) + 0.07P(O) - 1P(B) = 0
0P(W) - 0.07P(O) + 1P(B) = 0
Solving for P(O), we get:
P(O) = 0.3P(W)
Substituting this into the second equation, we get:
-0.03P(W) + 0.07(0.3P(W)) - P(B) = 0
Simplifying, we get:
P(B) = 0.004P(W)
We also know that the sum of the probabilities of being in each state must be 1:
P(W) + P(O) + P(B) = 1
Substituting the expressions for P(O) and P(B), we get:
P(W) + 0.3P(W) + 0.004P(W) = 1
Solving for P(W), we get:
P(W) = 0.762
Therefore, the long-run fraction of time that there is exactly one lightbulb working (event O) is:
P(O) = 0.3P(W) = 0.228.
Approximately 22.8% of the time, there will be exactly one lightbulb working.
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Becca is construction triangle d e f using the following angles 50°, 65°, 65°,
what mistake did she make?
Becca made a mistake while constructing triangle DEF by using the angles 50°, 65°, and 65°. The mistake she made was violating the triangle inequality theorem.
According to the theorem, the sum of any two sides of a triangle must be greater than the third side. In other words, if we add the lengths of two sides of a triangle, it must be greater than the length of the third side.
Since Becca only used angles to construct the triangle, she did not consider the side lengths of the triangle. Therefore, there is a possibility that the triangle she constructed does not satisfy the triangle inequality theorem, and it may not be a valid triangle.
In order to ensure the triangle is valid, Becca needs to consider the side lengths while constructing the triangle. She could use trigonometric ratios or a ruler and protractor to measure the side lengths and angles accurately.
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Sam makes tote bags for a school fundraiser. The fixed costs for making the bags is $30. The cost of the materials for each bag is $8.50. Sam can spend less than a total of $200 on the tote bags. Write an inequality that can be used to determine b , the number of tote bags that can be made.
Find the exact value of sin a, given that cos a=-5/9 and a is in quadrant 3
Since cosine is negative and a is in quadrant III, we know that sine is positive. We can use the Pythagorean identity to solve for sine:
sin^2(a) + cos^2(a) = 1
sin^2(a) + (-5/9)^2 = 1
sin^2(a) = 1 - (-5/9)^2
sin^2(a) = 1 - 25/81
sin^2(a) = 56/81
Taking the square root of both sides:
sin(a) = ±sqrt(56/81)
Since a is in quadrant III, sin(a) is positive. Therefore:
sin(a) = sqrt(56/81) = (2/3)sqrt(14)
a company pays its employees an average of $5.25 per hour with a standard deviation of 60 cents. if the wages are approximately normally distributed: (a.) what percentage of the workers receive wages between $4.75 and $5.69 per hour? (b.) the highest 5% of the hourly wages are greater than what amount?
Using the standard normal distribution, we find that approximately 73.8% of workers receive wages between $4.75 and $5.69 per hour. Using the inverse of the standard normal distribution, we find that the highest 5% of hourly wages are greater than approximately $6.09.
Using a standard normal distribution table or calculator with a mean of 5.25 and a standard deviation of 0.60, we can find that approximately 79.42% of workers receive wages between $4.75 and $5.69 per hour.
Using a standard normal distribution table or calculator, we can find the z-score corresponding to the highest 5% of wages, which is approximately 1.645.
Then, we can solve for x in the equation z = (x - μ) / σ, where z is the z-score, μ is the mean of 5.25, and σ is the standard deviation of 0.60. This gives us x = zσ + μ, which is approximately $6.09 per hour. Therefore, the highest 5% of hourly wages are greater than $6.09 per hour.
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Which of the following combinations of side lengths would NOT form a triangle with vertices X, Y, and Z? A. XY = 11 mm , YZ = 12 mm , XZ = 18 mm B. XY = 16 mm , YZ = 12 mm , XZ = 23 mm C. XY = 16 mm , YZ = 17 mm , XZ = 18 mm D. XY = 11 mm , YZ = 12 mm , XZ = 28 mm
the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
How to solve the question?
To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
Let's check each option:
A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm
To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:
XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm
YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm
XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm
YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm
Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.
C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm
YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm
YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm
XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm
The first combination is less than the third side, so a triangle cannot be formed with these side lengths.
Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
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