Which algebraic expression represents the phrase below?
five times the sum of a number and eleven, divided by three times the sum of the number and eight
5(x + 11) + 3(x + 8)
5x+11
3X+8
5(X+11)
3(x+8)
5x + 11 + 3x + 8

Answer:

(-1,0), (0,3) and (2,2.25)

Step-by-step explanation:

The qualitative graph is as follows:

A(-1,0) ------> B(0,3) ------> C(2,2.25)

Hence, slope = (2.25 - 0)/(2 - (-1)) = 2.25/3

∴ slope = 0.75

Except for the option graph on a coordinate plane, a line with a positive slope goes through points (negative 1, 0) and (0, 3), all the graph is qualitative. Options B, C, and D are correct.

The kind of graph that shows the quality curve such as decreasing and increasing events, is called a qualitative graph or curve.

Here,
1. On a coordinate plane, a line with a positive slope goes through points (negative 1, 0) and (0, 3), since this graph does not represent any data as well as also constantly increasing between two points so it is not a qualitative graph.

Similarly,
Graphs B, C, and D have an increasing and decreasing order, so all are qualitative graphs.

Thus, except for graph A all the graphs are qualitative graphs.

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Answer: square 105

Step-by-step explanation: Confirming answer

A radical expression is an expression containing a square root, mostly a square root.

The value of √3.√5.√7 in radical form is √105.

A radical expression is an expression containing a square root, mostly a square root.

We have,

√3.√5.√7

We can multiply the numbers together.

= √(3 x 5 x 7 )

= √(15 x 7)

= √105

Thus the value of √3.√5.√7 in radical form is  √105.

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Answer:

49

Step-by-step explanation:

[tex]3x^2+5x-2 = 0[/tex]

Apply discriminant formula : [tex]D = b^2- 4ac[/tex]

[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]

[tex]D = b^2- 4ac[/tex]

Plug in the values for a, b, and c.

[tex]D = 5^2- 4(3)(-2)[/tex]

Evaluate.

[tex]D = 25- 12(-2)[/tex]

[tex]D = 25- - 24[/tex]

[tex]D=25+24[/tex]

[tex]D=49[/tex]

Answer:

49

Step-by-step explanation:

3x²+5x-2 = 0

This is in the form

ax^2 + bx + c=0

a=3  b=5  c = -2

The discriminant is

b^2 -4ac

5^2 -4(3) (-2)

25 + 24

49

The discriminant is 49

Answer:

144 codes are possible

Step-by-step explanation:

Okay for the first digit, we shall be selecting one out of 3,4,5,6.

Meaning we are selecting one out of four choices

The number of ways this can be done is 4C1 ways = 4 ways

For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways

And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices

So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes

Answer:

[tex]\boxed{x=7, \: x=-13}[/tex]

Step-by-step explanation:

[tex]|3x+9|= 30[/tex]

Solve for absolute value.

There are two possibilities.

One possibility:

[tex]3x+9=30\\3x=21\\x=7[/tex]

Second possibility:

[tex]3x+9=-30\\3x=-39\\x=-13[/tex]

Answer:

Step-by-step explanation:

f(x) = 3x + 2

To find f(5) substitute 5 into f(x)

That's

f(5) = 3(5) + 2

= 15 + 2

= 17

Hope this helps you

Answer:

17

Step-by-step explanation:

You just plug 5 into the equation

f(5)= 3(5)+2

=15+2

=17

Hope this helped! :)

Answer:

C

Step-by-step explanation:

1:draw a very simple Cartesian plane for the graph

2:label the quadrants 1-4 from top right round to bottom right as 4

3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

Snaphcat logo is symmetrical and it is also reflective symmetry.

Answer:

rectangular prism

Step-by-step explanation:

check by rotating the shape in images

Explanation:

We'll use the tangent ratio to connect the opposite and adjacent sides with the reference angle

tan(angle) = opposite/adjacent

tan(A) = 14/7

Then use the arctangent function (aka inverse tangent) to fully isolate A

A = arctan(14/7)

A = 63.4349 degrees approximately; make sure your calculator is in degree mode

Round this to the nearest whole number to get 63.

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

Answer:

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8)  = 83.9≅ 84 percentage

Step-by-step explanation:

Step(i):-

Mean of the Population = 8.3 points

Standard deviation of the Population = 0.5 points

Let 'X' be the random variable in normal distribution

Let X = 6.8

[tex]Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3[/tex]

Let X = 8.8

[tex]Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1[/tex]

The probability that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = P(-3≤Z≤1)

                     = P(Z≤1)- P(Z≤-3)

                    =  0.5 + A(1) - ( 0.5 -A(-3))

                   = A(1) + A(3)       (∵A(-3)=A(3)

                  =  0.3413 +0.4986    (∵ From Normal table)

                 = 0.8399

Conclusion:-

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8)  = 83.9≅ 84 percentage

Answer:

CE = 100°

Step-by-step explanation:

Using the cofunction identity

sin x = cos(90 - x)

Given x = 20°, then 90° - 20° = 70° thus

CE - 30 = 70° ( add 30 to both sides )

CE = 100°

Thus

sin20° = cos(100 - 30)° = cos70°

Answer:

CE = 100

have a nice day!

Step-by-step explanation:

Answer:

6c1;   [tex]Area = 81.12m^2[/tex]

6cii:  See Explanation

Step-by-step explanation:

Given

[tex]A = 3p^2[/tex]

[tex]0 \leq p \leq 6[/tex]

Where A represents Area and P represents Width

Required

Solve 6c

Please note that because you only need 6c, I'll solve using calculations;

Solving 6ci:

Area of the cage, when width is 5.2m

Substitute 5.2m for p in[tex]A = 3p^2[/tex]

[tex]A = 3 * 5.2m^2[/tex]

[tex]A = 3 * 27.04m^2[/tex]

[tex]A = 81.12m^2[/tex]

Hence, the area of the cage is 81.12m²

Solving 6cii:

Area of the cage, when width is 40m

From the range of value of p:   [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p

However, if the range is extended; the value of Area is as follows;

Substitute 40m for p

[tex]A = 3 * 40m^2[/tex]

[tex]A = 3 * 1600m^2[/tex]

[tex]A = 4,800m^2[/tex]

Answer:

x = -7/9; y = 4/3.

Step-by-step explanation:

I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.

If you add the two...

(6x + 3x) + (2y + (-2y)) = (-2 + (-5))

9x + 0 = -7

9x = -7

x = -7/9

6(-7/9) + 2y = -2

-42/9 + 2y = -18/9

2y = 24/9

y = 24/18

y = 12/9

y = 4/3

Hope this helps!

Answer:

6/35

Step-by-step explanation:

add ¹/7+¹/5 =12/35

divide 12/35 by 2

=6/35

1) Identify the sample used in the study: B) The sample is the responses of the volunteers in the study

2)  What is the​ sample's population: B) The population is collected of the response of all individuals who completed the math test

3) Which part of the study represents the descriptive branch of​ statistics:

individuals who are not sleep deprived will be more likely to answer math questions correctly than individuals who are sleep deprived.

hope i helpd

-lvr

Answer:

17

Step-by-step explanation:

3m-(m + 5)

Distribute the minus sign

3m -m -5

Combine like terms

2m -5

Let m =11

2*11 -5

22-5

17

Answer:

[tex]17[/tex]

Step-by-step explanation:

[tex]3m-(m + 5)[/tex]

[tex]m= 11[/tex]

Plug m as 11 in the expression.

[tex]3(11)-(11+5)[/tex]

Evaluate.

[tex]33-16[/tex]

[tex]=17[/tex]

Answer:

A=3244.8 dollars

Step-by-step explanation:

A=p(1+r)^t

A=3000(1+0.04)^2

A=3244.8 dollars

Answer:   [tex]\dfrac{27}{65}[/tex]

Step-by-step explanation:

There are 130 students.

There are 58 boys --> 72 girls

A) 49 chose football: 27 are girls --> 22 are boys

B) 72 girls: 24 chose running, 27 chose football --> 21 girls chose tennis

C) 27 students chose tennis: 21 are girls --> 6 are boys.

D) 58 boys: 22 chose football, 6 chose tennis --> 30 boys chose running.

[tex]\large\boxed{\begin{array}{l|cc||c}&\underline{Boys}&\underline{Girls}&\underline{Total}\\Football&22&27&49\\Tennis&6&21&27\\\underline{Running}&\underline{\quad 30\quad}&\underline{\quad 24\quad}&\underline{\quad 54\quad}\\Total&58&72&130\end{array}}[/tex]

Total running = 30 boys + 24 girls = 54

Total students = 130

[tex]\dfrac{\text{Total running}}{\text{Total students}}=\dfrac{54}{130}\quad \rightarrow \large\boxed{\dfrac{27}{65}}[/tex]

Answer:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).

Step-by-step explanation:

distance formula

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

We want the distance, d, from points (-2, 0) and (2, 0) to be 14.

Point (-2, 0):

[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

Point (2, 0):

[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

We have a system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

Since the right sides of both equations are equal, we set the left sides equal.

[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]

Square both sides:

[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]

Square the binomials and combine like terms.

[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]

[tex] 4x = -4x [/tex]

[tex] 8x = 0 [/tex]

[tex] x = 0 [/tex]

Now we substitute x = 0 in the first equation of the system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{4 + y^2} = 14 [/tex]

Square both sides.

[tex] y^2 + 4 = 196 [/tex]

[tex] y^2 = 192 [/tex]

[tex] y = \pm \sqrt{192} [/tex]

[tex] y = \pm \sqrt{64 \times 3} [/tex]

[tex] y = \pm 8\sqrt{3} [/tex]

The points are:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex]

Answer:

You are m + 1 years old.

Step-by-step explanation:

Let's say that you are x years old, and Mack is m years old.

x = 1/2( two plus twice m)

x = 1/2(2 + 2m)

x = 1 + m

x = m + 1

Hope this helps!

Answer:

1) 24Z^2 - 177.

2) 16d^2 - 32d.

6) 30x - 24.

7) 6q - 4.

Step-by-step explanation:

1) 3(8Z^2 - 52 - 7)

= 3(8Z^2 - 59)

= 24Z^2 - 177

2) 8d(2d - 4)

= (8d * 2d) - (8d * 4)

= 16d^2 - 32d

6) 6(5x - 4)

= (6 * 5x) - (6 * 4)

= 30x - 24

7) Already simplified. 6q - 4.

Hope this helps!

Answer:

-x^2 +2x +8

Step-by-step explanation:

f(x) = 2x + 1

g(x) = x^2 – 7,

(f – g)(x) = 2x +1 - ( x^2 -7)

Distribute the minus sign

             = 2x+1 - x^2 +7

Combine like terms

             = -x^2 +2x +8

Answer:

its not true. Answer is (f + g)(x) = x2 + 2x - 6

Step-by-step explanation:

Trust me. Good luck.

Answer:

Step-by-step explanation:

Vertex of f is (-1, -4) so its range is limited to y≥-4

|x+1| is always ≥0 therefore -|x+1| is always ≤0 {4 is insignificant to this - slope doesn't mean in range} so its range is limited to y≤0

Answer:

D

Step-by-step explanation:

i just took the test

Answer:

4 liters

Step-by-step explanation:

Let's assume that the side lengths of the cubical block are 2 inches.

This means that one of the sides area is 4 in².

Multiplying this by 6 (for there are 6 sides) gets us 24 in².

So one liter of paint covers 24 in².

Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.

So the area of one side is 16 in².

Multiplying this by 6 (as there are 6 sides) gets us 96 in².

To find how many liters of paint this will take, we divide 96 by 24.

[tex]96\div24=4[/tex]

So 4 liters of paint will be needed for the second cubical block.

Hope this helped!

Answer:

The vertex of the graph moves to a point twice as far from the y-axis.

Step-by-step explanation:

How does the graph of y = a(x – h)2 + k change if the value of h is doubled?

The vertex of the graph moves to a point twice as far from the x-axis.

because the role of h is to indicate the distance of the vertex from the y-axis.

The vertex of the graph moves to a point half as far from the x-axis.

The vertex of the graph moves to a point half as far from the y-axis.

Transformation involves changing the position of a function.

When h is doubled in [tex]\mathbf{y = a(x - h)^2 + k}[/tex], the vertex of the graph moves to a point twice as far from the y-axis.

The function is given as:

[tex]\mathbf{y = a(x - h)^2 + k}[/tex]

When the value of h is doubled, the new function becomes:

[tex]\mathbf{y' = a(x - 2h)^2 + k}[/tex]

Rewrite as:

[tex]\mathbf{y' = a(x - h- h)^2 + k}[/tex]

The above equation means that:

Function y will be translated to the right by h units

Assume the vertex is:

[tex]\mathbf{Vertex = (2,5)}[/tex]

The new vertex will be:

[tex]\mathbf{Vertex = (4,5)}[/tex]

Comparing the vertices, it means that:

The new function will have its vertex twice as far from the y-axis

Hence, option (b) is correct.

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Answer:

explanation

Step-by-step explanation:

the reason for your statement is just your explanation of why you think that.