which algorithm involves getting the next unsorted number and doing comparisons to see where it should go into a sorted sublist?

In order to write formulae that give the evolution of the concentrations in terms of the extent of reaction, we need to use the stoichiometry of the reaction and the initial concentrations of the reactants.

Let's consider a generic reaction of the form:

a A + b B ⟶ c C + d D

where A and B are the reactants, C and D are the products, and a, b, c, and d are the stoichiometric coefficients. The extent of reaction, denoted by ξ, represents the amount of reaction that has occurred and is related to the change in the concentrations of the reactants and products by the stoichiometry of the reaction:

Δ[A] = -aξ

Δ[B] = -bξ

Δ[C] = cξ

Δ[D] = dξ

where Δ[X] is the change in concentration of species X. Using these relationships, we can write the evolution of the concentrations in terms of the extent of reaction as follows:

[A] = [A]0 - aξ

[B] = [B]0 - bξ

[C] = cξ

[D] = dξ

where [X]0 is the initial concentration of species X. These formulae give the concentrations of the reactants and products as a function of the extent of reaction ξ. Note that the concentrations of the reactants decrease as the reaction proceeds, while the concentrations of the products increase.

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The correct answer is D. The flux of F across C is the sum of the components of F orthogonal or normal to C at each point of C.

The flux of a two-dimensional vector field F across a smooth oriented curve C represents the amount of the field that passes through the curve. In this context, the correct answer is: D. The flux of F across C is the sum of the components of F orthogonal or normal to C at each point of C. This means that the flux is calculated by considering the components of the vector field that are perpendicular to the curve at each point along C. By summing these orthogonal components, we can determine the overall quantity of the field that passes through the curve.

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Answer:

A

Step-by-step explanation:

[tex]\lim_{x \to -2} \frac{x^{2}-4 }{x+2} \\\lim_{x \to -2} \frac{(x+2)(x-2)}{x+2}\\ \lim_{x \to -2} x-2\\= -4[/tex]

Answer:

First answer choice

[tex]- 4[/tex]

Step-by-step explanation:

[tex]\lim _{x\to \:-2}\left(\dfrac{x^2-4}{x+2}\right)\\\\\\\mathrm{Simplify}\:\dfrac{x^2-4}{x+2}\\\\\\\mathrm{Factor}\:x^2-4:\quad (x + 2)(x - 2)\\\\\lim _{x\to \:-2}\left(\dfrac{x^2-4}{x+2}\right) \\\\= \lim _{x\to \:-2}\left(\dfrac{x+2)(x-2)}{x+2}\right)[/tex]

The x+2 common factor cancels out

[tex]= \lim _{x\to \:-2}\left(x-2\right)\\\\\text{Plug in the value x= -2}\\\\= -2 - 2\\= -4[/tex]

Answer:

x = 0 and x = 4/3

Step 1:  First, we must find the derivative of f(x), noted by f'(x)

When you have a polynomial in the form x^n, we take the derivative of each polynomial using the following formula:

[tex]f'(x)=nx^n^-^1[/tex]

This means that the exponent becomes a coefficient and we subtract from the exponent.

We can do take the derivatives of x^3 and -2x^2 separately and combine them at the end:

x^3:

[tex]x^3\\3x^3^-^1\\3x^2[/tex]

-2x^2

[tex]-2x^2\\-2(2x^2^-^1)\\-4x[/tex]

Thus, f'(x) is 3x^2 - 4x

Step 2:  Critical points are found when f'(x) = 0 or when f'(x) = undefined.  There are no values for x which would make 3x^2 - 4x undefined, so we can set the function equal to 0 and solving will give us our critical points

We see that we can factor out x from 3x^2 - 4x to get

x(3x - 4) = 0

Now, we can set the two expressions equal to 0 to solve for x:

Setting x equal to 0:

x = 0

Setting 3x - 4 equal to 0:

3x - 4 = 0

3x = 4

x = 4/3

Therefore, the two critical points of the function are x = 0 and x = 4/3

The individual events of drawing and eating two red pieces of candy in a row from a bag are dependent. The probability of the second event is influenced by the outcome of the first event, since one red candy has already been removed from the bag.

The probability of drawing a red candy from the bag on the first attempt is 6/37. Once the first red candy has been drawn and eaten, there are now 5 red candies left in the bag out of 36 total candies. Therefore, the probability of drawing and eating a second red candy from the bag is now 5/36.

The probability of the combined event of drawing and eating two red candies in a row can be found by multiplying the probability of the first event by the probability of the second event, since the events are dependent:

P(drawing and eating two red candies in a row) = P(drawing a red candy on the first attempt) x P(drawing a red candy on the second attempt, given that a red candy was drawn on the first attempt)

P(drawing and eating two red candies in a row) = (6/37) x (5/36)

P(drawing and eating two red candies in a row) = 5/222

Therefore, the probability of drawing and eating two red candies in a row from the bag is 5/222 or approximately 0.0226.

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The partial derivative of z with respect to s is $\frac{\partial z}{\partial s} = \frac{\partial f}{\partial x} r^3 + \frac{\partial f}{\partial y} 2re^{2s}$

The partial derivative of z with respect to s can be found using the chain rule of differentiation as follows:

$\frac{\partial z}{\partial s} = \frac{\partial z}{\partial x} \frac{\partial x}{\partial s} + \frac{\partial z}{\partial y} \frac{\partial y}{\partial s}$

Given that $x = r^3s$ and $y = re^{2s}$, we have:

$\frac{\partial x}{\partial s} = r^3$ and $\frac{\partial y}{\partial s} = 2re^{2s}$

Taking partial derivatives of z with respect to x and y:

$\frac{\partial z}{\partial x} = \frac{\partial f}{\partial x}$ and $\frac{\partial z}{\partial y} = \frac{\partial f}{\partial y}$

Hence, the partial derivative of z with respect to s is:

$\frac{\partial z}{\partial s} = \frac{\partial f}{\partial x} r^3 + \frac{\partial f}{\partial y} 2re^{2s}$

where $\frac{\partial f}{\partial x}$ and $\frac{\partial f}{\partial y}$ are the partial derivatives of f with respect to x and y, respectively.

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(a) G = N; addition

To show that G = N (the set of natural numbers) under addition is a group, we need to verify the four group axioms:

Closure: For any a, b in N, a + b is also in N.

Associativity: For any a, b, c in N, (a + b) + c = a + (b + c).

Identity element: There exists an element 0 in N such that for any a in N, a + 0 = a.

Inverse element: For any a in N, there exists an element -a in N such that a + (-a) = 0.

Closure and associativity hold for addition on N, so we only need to verify the identity and inverse elements.

Identity element: The only possible identity element is 0, since adding any natural number to 0 gives that number. Thus, 0 is the identity element of (N, +).

Inverse element: For any a in N, there is no element -a in N such that a + (-a) = 0. Therefore, G = N under addition is not a group, because the inverse element axiom fails.

(b) G = R; a · b = a + b + 1

To show that G = R (the set of real numbers) under the given operation is a group, we need to verify the four group axioms:

Closure: For any a, b in R, a + b + 1 is also in R.

Associativity: For any a, b, c in R, (a + b + 1) + c = a + (b + c) + 1.

Identity element: There exists an element e in R such that for any a in R, a + e + 1 = a. Solving for e, we get e = -1, so -1 is the identity element of (R, ·).

Inverse element: For any a in R, there exists an element b in R such that a · b = e. Solving for b, we get b = -a - 2. Thus, for any a in R, -a - 2 is the inverse element of a.

Therefore, G = R under the given operation is a group.

(c) G = {16, 12, 8, 4}; multiplication in Z20

To show that G under multiplication modulo 20 is a group, we need to verify the four group axioms:

Closure: For any a, b in G, ab mod 20 is also in G.

Associativity: For any a, b, c in G, (ab)c mod 20 = a(bc) mod 20.

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Answer:

There only one real root, which is 8-

-8 × -8 × -8 = -512

Hope this helps :)
Pls brainliest...

Answer: I think there is 1 : -8

Step-by-step explanation: It's because you're CUBE rooting a negative number, so the answer has to be negative, resulting in only 1 answer, as opposed to if you were square rooting.

Georgia's average speed expressed in meter per seconds is 4m/s

To find the average speed in meters per second, we need to convert the distance and time to the appropriate units.

Converting distance from kilometers to meters :

1km = 1000m

2.4 km = (2.4 × 1000) = 2400 m

Converting time from minutes to seconds ;

1 minute = 60 seconds

10 minutes = (60 × 10) = 600 seconds

The average speed can be calculated using the formula:

Average speed = distance / time

Average speed = 2400/60 = 4

Therefore, Georgia's average speed is 4 meters per second.

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Answer:

$8000 in federal loans and $16000 in private bank loans.

Step-by-step explanation:

x + 16000 = 24000

x = 8000

y = 16000

The solution to Laplace's equation for the bottom side of the plate is u(x, y) = ∑[n=1 to ∞] 4/(nπ sinh(nπ)) [1 - cos(nπ)] sinh(nπ(T-y)/T) sin(nπx/T)

Let's start with the left side of the plate, where u(0, y) = 1. Since this is a constant potential, the solution to Laplace's equation is simply u(x, y) = 1.

Next, let's consider the right side of the plate, where u(TT, y) = 1. Again, the solution to Laplace's equation is u(x, y) = 1.

Moving on to the top side of the plate, where u(x, 0) = 0. We can use separation of variables to find the solution to Laplace's equation in terms of a Fourier series:

u(x, y) = ∑[n=1 to ∞] Bn sin(nπx/T) [tex]e^{-n\pi y/T}[/tex]

where T is the length of the side, and Bn are constants that depend on the boundary conditions. Since u(x, 0) = 0, we have:

Bn = 2/T ∫[0 to T] 0 sin(nπx/T) dx = 0

Therefore, the solution to Laplace's equation for the top side of the plate is:

u(x, y) = 0

Finally, let's consider the bottom side of the plate, where u(x, 7) = 1. Using separation of variables again, we find:

u(x, y) = ∑[n=1 to ∞] An sinh(nπ(T-y)/T) sin(nπx/T)

where An are constants that depend on the boundary conditions. Since u(x, 7) = 1, we have:

An = 2/ sinh(nπ) ∫[0 to T] sin(nπx/T) dx

Using trigonometric identities, we can evaluate this integral and obtain:

An = 4/(nπ sinh(nπ)) [1 - cos(nπ)]

Now, we can add these four solutions together to obtain the solution for the entire plate:

u(x, y) = 1 + ∑[n=1 to ∞] 4/(nπ sinh(nπ)) [1 - cos(nπ)] sinh(nπ(T-y)/T) sin(nπx/T)

This is the solution to Laplace's equation for a square plate with the given boundary conditions.

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The correct answer is E) Both A and C are true. In summary, the line integral jĚ.dr of a smooth, positive function f of two variables, where F = Vf, is positive for all smooth paths C and positive for all closed smooth paths C.

Explanation:

The line integral jĚ.dr represents the work done by the vector field F on a particle that moves along the path C. In this case, since F = Vf, we have jĚ.dr = VfĚ.dr. By the fundamental theorem of calculus for line integrals, we have:

jĚ.dr = VfĚ.dr = f(P) - f(Q)

where P and Q are the endpoints of the path C. Since f is positive everywhere, we have f(P) > f(Q), which implies that jĚ.dr is positive for all smooth paths C.

Moreover, since f is positive everywhere, we have f(P) > f(Q) for any two points P and Q on a closed path C. Therefore, jĚ.dr is positive for any closed smooth path C. This means that the vector field F is "circulation-preserving", meaning that the work done by F on a particle that moves around a closed loop is always positive.

In conclusion, both A and C are true, as jĚ.dr is positive for all smooth paths C and positive for all closed smooth paths C.

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Answer:

38.2 ft

Step-by-step explanation:

The ladder, the ground, and the wall make a right triangle.

The wall is the opposite leg to the 63° angle.

The ladder is the hypotenuse.

Let x = length of the hypotenuse.

sin Θ = opp/hyp

sin 63° = 34 ft / x

x × sin 63° = 34 ft

x = 34 ft / sin 63°

x = 38.2 ft

Answer: Around 2.46 cm.

Step-by-step explanation:

The volume for a cylinder is volume = πr^2 x h

Substitute the variables
158 = 3.14 x r^2 x 8.3

Simplify the right side (multiple 3.14 x 8.3) to get 158 = r^2 x 26.062

Divide both sides by 26.062 to get approximately 6.06 = r^2

To get rid of the exponent, take the square root of 6.06, which is around 2.46.

The Maclaurin series for f(x) is:[tex]f(x) = 1 - 6x + 36x^2 - 216x^3 + ...[/tex]

The associated radius of convergence for this Maclaurin series is infinite, which means the series converges for all values of x.

The Maclaurin series for the function [tex]f(x) = ( {e}^{-6x} )[/tex] can be found using the definition of a Maclaurin series. The Maclaurin series represents a function as an infinite sum of terms, each term being a derivative of the function evaluated at x = 0, multiplied by a power of x divided by the factorial of the power.

To find the Maclaurin series for f(x),

we need to compute the derivatives of f(x) at x = 0.

Taking the derivatives of [tex]f(x) = ( {e}^{-6x} )[/tex]

we get:[tex]f'(x) ={ -6e}^{-6x} [/tex]

[tex]f''(x) = {36e}^{-6x} [/tex]

[tex]f'''(x) ={ -216e}^{-6x} [/tex]...

Evaluating these derivatives at x = 0,

we find:[tex]f(0) = e^0

= 1[/tex]f'(0)

= -6f''(0)

= 36f'''(0)

= -216...

Using these values,

the Maclaurin series for f(x) is:

[tex]f(x) = 1 - 6x + 36x^2 - 216x^3 + ...[/tex]

The associated radius of convergence for this Maclaurin series is infinite, which means the series converges for all values of x. This is because the exponential function [tex] {e}^{-6x} [/tex]converges for all real numbers x, and the series expansion captures the behavior of the function within that range.

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The equivalent integral is ∫ba∫0g(x)∫0k(x,z)f(x,y,z)h(x,z)dydzdx.

To obtain the equivalent integral, we need to rewrite the original integral limits and order of integration.

Starting from the innermost integral, we have ∫x=0^(z) f(x,y,z)dy, where y varies from 0 to z.

Moving to the second integral, we now have ∫z=1^(0) ∫x=0^(z) f(x,y,z)dydx, where z varies from 1 to 0 and x varies from 0 to z.

Finally, for the outermost integral, we have ∫z=1^(0) ∫x=0^(z) ∫y=0^(z) f(x,y,z)dydxdz, where z varies from 1 to 0, x varies from 0 to z, and y varies from 0 to z.

To obtain the equivalent integral in the desired order, we can change the limits of integration and rewrite the integrand as follows:

∫z=0^(b) ∫x=0^(g(z)) ∫y=0^(k(x,z)) h(x,z)f(x,y,z)dydzdx.

Finally, we can rearrange the order of integration to obtain the equivalent integral:

∫ba∫0g(x)∫0k(x,z)f(x,y,z)h(x,z)dydzdx.

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The lateral surface area of the triangular prism is 128 square centimeters. The correct answer would be an option (G) 128 cm².

Given, we have dimension are:

side length of base  = 6 cm, 5 cm, and 5 cm

height = 8 cm

Lateral surface area = (a+b+c)h

Substitute the values and we get

Lateral surface area = (6+5+5)8

Lateral surface area = 16 × 8

Lateral surface area = 128 cm².

Hence, the lateral surface area of the triangular prism is 128 square centimeters.

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The missing figure has been attached below.

The correct options are:-

Option B: Translation of 1 unit right

Option F: Vertical stretch by a factor of 2

Translation is a type of transformation in mathematics that involves moving a shape or object without changing its size, shape or orientation.

This is done by sliding the object along a straight line in a particular direction, such as up, down, left or right.

Based on the given information, the transformations that were applied to the red graph to obtain the blue graph are:

A translation of 1 unit right (Option B).

A vertical stretch by a factor of 2 (Option F).

Therefore, the correct options are:

Translation of 1 unit right?

Vertical stretch by a factor of 2.

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Answer:

60

Explanation:

triangles are supposed to add up to 180 on the inside

you have a right angle which equals 90

and the other angle is 30

90+30 is 120

180-120 is 60

X=60

The probability that 3 out of 8 of them entered a profession closely related to their college major is equal to 0.1239.

Sample size of college graduates = 300

Randomly selected subjects = 8

Using the binomial probability formula,

P(X = x) = ⁿCₓ × pˣ × (1 - p)ⁿ⁻ˣ

where X is the number of subjects who entered a profession closely related to their college major,

n is the sample size,

x is the number of successes entered a profession closely related to their college major,

p is the probability of success = 0.60

and ⁿCₓ is the binomial coefficient.

ⁿCₓ = n! / (x! × (n - x)!)

Plugging in the values, we get,

P(X = 3) = (⁸C₃) × 0.60³ × (1 - 0.60)⁸⁻³

Using a calculator ,

⁸C₃ = 56

0.60³ = 0.216

(1 - 0.60)⁸⁻³ = 0.01024

Plugging these values in,

P(X = 3) = 56 × 0.216 × 0.01024

Simplifying it,

P(X = 3) = 0.1239

Therefore, the probability that exactly 3 of the 8 selected subjects entered a profession closely related to their college major is approximately 0.1239

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The inverse of the matrix A is:

| -5  2 |

|   3 -1 |

To find the inverse of a matrix using row reduction, we can use the following algorithm:

1. Write the matrix A next to the identity matrix I, separated by a vertical line to obtain the augmented matrix [A|I].

2. Apply row operations to transform the left side of the augmented matrix into the identity matrix I. Perform the same row operations on the right side of the augmented matrix to obtain the inverse matrix A^-1.

3. If the left side of the augmented matrix cannot be transformed into I, then A does not have an inverse.

Let's apply this algorithm to find the inverse of the matrix A:

```

| 1  2 |

| 3  5 |

```

We first write the augmented matrix [A|I]:

```

| 1  2 | 1  0 |

| 3  5 | 0  1 |

```

Next, we perform row operations to transform the left side of the augmented matrix into I:

R2 - 3R1 -> R2

```

| 1  2 | 1   0 |

| 0 -1 | -3  1 |

```

-R2 -> R2

```

| 1  2 | 1    0 |

| 0  1 | 3   -1 |

```

-2R2 + R1 -> R1

```

| 1  0 | -5   2 |

| 0  1 | 3   -1 |

```

We have now transformed the left side of the augmented matrix into I, so the right side is the inverse matrix:

```

| -5  2 |

|  3 -1 |

```

Therefore, the inverse of the matrix A is:

```

| -5  2 |

|   3 -1 |

```

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Answer:

--------------------------

Using the pair (10, 460) on the graph find the speed per hour:

Find the distance after 13 hours:

The matching choice is D.

The explicit rule for the geometric sequence 3, 12, 48,... is:

f(n) = [tex]3 \times 4^{(n-1)[/tex]. B.

The explicit rule for the geometric sequence 3, 12, 48,... need to determine the common ratio, r.

We can do this by dividing any term by the previous term:

r = 12/3

= 48/12

= 4

Now that we know the common ratio can use the formula for the nth term of a geometric sequence:

[tex]a_n[/tex] = [tex]a_1 \times r^{(n-1)[/tex]

where:

[tex]a_n[/tex] is the nth term

[tex]a_1[/tex] is the first term (3 in this case)

r is the common ratio (4 in this case)

n is the term number

Substituting these values into the formula, we get:

[tex]a_n[/tex] = [tex]3 \times 4^{(n-1)[/tex]

So, the explicit rule for the geometric sequence 3, 12, 48,... is:

f(n) = [tex]3 \times 4^{(n-1)[/tex]

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The histograms number II have mean larger than median.

Histograms are a type of graphical representation of data that are used to show the frequency distribution of continuous data. They are constructed by dividing the data range into intervals or bins, and then counting the number of observations that fall into each bin.

The height of each bar in the histogram represents the frequency of the data that falls within that bin. Histograms are commonly used in statistics to visually explore the distribution of a dataset, and to identify patterns or outliers.

They can also be used to check the assumptions of statistical models, such as normality assumptions, and to compare the distribution of data across different groups or categories.

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To write the given expression as a single integral, we can apply the linearity property of integration, which states that the integral of the sum of two functions is equal to the sum of their integrals.

Using this property, we get:

a^2 f(x) dx - 5 + 3 f(x) dx / 2 - (-3 f(x) dx / 5)

Now, we can simplify each term by multiplying and dividing by appropriate constants to get a common denominator of 10:

= (2a^2 f(x) - 50) / 10 + (15 f(x) - 6 f(x)) / 10 + (30 f(x) - (-3) f(x)) / 10

= (2a^2 f(x) + 9 f(x) + 33 f(x) - 50) / 10

= (2a^2 + 42) / 10

Therefore, the given expression can be written as the single integral:

∫ [(2a^2 f(x) + 9 f(x) + 33 f(x) - 50) / 10] dx

which simplifies to:

(2a^2 + 42) / 10 ∫ f(x) dx

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The surface area of the given prism is 386 square inches.

To find the surface area of a prism, we need to find the area of all its faces and add them up.

The given prism has a rectangular base with dimensions of 7 inches by 15 inches, and a height of 4 inches.

The two rectangular faces (front and back) have dimensions of 7 inches by 4 inches,

so each has an area of 7 x 4 = 28 square inches.

The two rectangular faces (sides) have dimensions of 15 inches by 4 inches,

so each has an area of 15 x 4 = 60 square inches.

The top and bottom faces are both rectangles with dimensions of 7 inches by 15 inches,

so each has an area of 7 x 15 = 105 square inches.

Therefore, the total surface area of the prism is:

2(28 sq in) + 2(60 sq in) + 2(105 sq in) = 56 sq in + 120 sq in + 210 sq in

                                                               = 386 sq in.

So, the surface area of the given prism is 386 square inches.

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The force of friction is equal to the centripetal force, which is given by the formula Fc = mv²/r, where m is the mass of the worker, v is the speed of the worker, and r is the radius of the circle. After plugging in the values, we get a force of friction of 55.97 N.

The problem requires us to calculate the force of friction necessary to keep the merry-go-round worker from falling off the platform. To solve this problem, we need to use the concept of centripetal force. Centripetal force is the force required to keep an object moving in a circular path. In this case, the force of friction is acting as the centripetal force to keep the worker moving in a circular path.

We are given the mass of the worker, which is 65 kg, and her speed, which is 4.1 m/s. We also know that the worker is standing 5.3 meters away from the center of the merry-go-round. To calculate the force of friction, we can use the formula for centripetal force, which is Fc = mv²/r, where Fc is the centripetal force, m is the mass of the worker, v is the speed of the worker, and r is the radius of the circle.

After substituting the given values, we get:

Fc = (65 kg)(4.1 m/s)²/5.3 m

Fc = 55.97 N

Therefore, the force of friction required to keep the worker from falling off the platform is 55.97 N.

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The correct expressions are:

B. 5² × 5³ >[tex]5^5[/tex]

C. 3² × [tex]3^5 < 3^8[/tex]

Let's evaluate each expression:

A. 4³ × [tex]4^4 = 4^{12[/tex]

Simplifying the left side: [tex]4^3 \times 4^4 = 4^{(3+4) }= 4^7[/tex]

Comparing with the right side: [tex]4^7[/tex]≠ [tex]4^{12[/tex]

Therefore, expression A is not true.

B. 5² × 5³ > [tex]5^5[/tex]

Simplifying the left side: [tex]5^2 \times 5^3 = 5^{(2+3)} = 5^5[/tex]

Comparing with the right side: [tex]5^5 = 5^5[/tex]

Therefore, expression B is true.

C. 3² × [tex]3^5 < 3^8[/tex]

Simplifying the left side: [tex]3^2 \times 3^5 = 3^{(2+5) }= 3^7[/tex]

Comparing with the right side: [tex]3^7 < 3^8[/tex]

Therefore, expression C is true.

D. 5² × [tex]5^4 = 5^8[/tex]

Simplifying the left side: [tex]5^2 \times 5^4 = 5^{(2+4) }= 5^6[/tex]

Comparing with the right side: [tex]5^6[/tex] ≠ [tex]5^8[/tex]

Therefore, expression D is not true.

In conclusion, the correct expressions are:

B. 5² × 5³ >[tex]5^5[/tex]

C. 3² × [tex]3^5 < 3^8[/tex]

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Answer:

-infinity < x < infinity

Step-by-step explanation:

it has none.

Isotopes are creation of a chemical element with specific properties. They are different nuclear species (or nuclides) of the same element.

They are generated by the same atomic number (number of protons in their nuclei) and their position in the periodic table (and hence belong to the same chemical element), but they are different in nucleon numbers (mass numbers) due to different numbers of neutrons in their nuclei.

The periodic table is considered a space which comprises a table of the chemical elements which are arranged in order of atomic number, generally in rows, so that elements with similar atomic structure appear in vertical columns.
It is globally used in chemistry, physics, and other sciences, and is generally seen as an icon of chemistry. The periodic table is sub divided into four blocks, reflecting the filling of electrons into types of subshell. Here, the table columns are referred as groups, and the rows are referred as periods.
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