Which best describes how a fetus exchanges gases while in the womb?

Gases are removed by the umbilical cord and taken to the uterus.
Gas exchange occurs at the lungs.
Gas exchange occurs through the placenta.
Gases diffuse out of the fetus directly into the uterus.

Answers

Answer 1

Answer:

C. Gas exchange occurs through the placenta.

Explanation:

The fetus is a developing baby in the womb or uterus. The fetus is incapable of performing certain life processes itself and hence, depends on the mother to do them. One of these processes is GAS EXCHANGE. Gas exchange occurs in the fetus via a structure called PLACENTA.

Placenta is a structure that forms in the uterus during pregnancy. It helps the developing fetus supply oxygen and nutrients from the mother and also remove wastes from the fetus back to the mother. The oxygen is taken into the fetus via the PLACENTA while the carbon dioxide (waste product of respiration) is removed via the PLACENTA. Hence, Gas exchange occurs through the placenta.


Related Questions

a change in an objects position is called​

Answers

Answer: are there any answer choices? If not I think MOTION

Explanation: hope that’s right, have a great day!! :)

What is the usable form of nitrogen that is found in the ground?

Answers

Nitrate

Hope this helps :))

The elements in the periodic table are not always represented by
the first one or two letters in their names. What are some examples of
this (list three)?

Answers

Unnillium (101)

Unnilbium (102)

Unniltrium (103)

Unnilquadium (104)

Unnilpentium (105)

Unnilhexium (106)

Unnilseptium (107)

Unniloctium (108)

Unnilennium (109)

Ununnillium (110)

When water is added to a mixture Na_2O_2(s) and S(s), a redox reaction occurs, as represented by the equation below.
2NaO_2(s) + 2 H_2O(l) rightarrow 4 NaOH (aq) + SO_2(aq) Delta H_298 degree = -610 kJ/mol_rxn; Delta S_298 degree = -73 J/(K mol_rxn)
Which of the following statements about the thermodynamic favorability of the reaction at 298 K is correct?
(A) It is thermodynamically unfavorable
(B) It is thermodynamically favorable and is driven by Delta S degree only.
(C) It is favorable and is driven by Delta H degree only.
(D) It is thermodynamically favorable and is driven by both Delta H degree and Delta S degree

Answers

Answer:

(C) It is favorable and is driven by ΔH° only.

Explanation:

Let's consider the following balanced equation.

2 Na₂O₂ + S + 2 H₂O → 4 NaOH + SO₂

To determine whether it will be favorable or not at 298 K, we need to calculate the standard Gibbs free energy (ΔG°).

If ΔG° < 0, the reaction will be favorable.If ΔG° > 0, the reaction will be unfavorable.

We can calculate ΔG° using the following expression.

ΔG° = ΔH° - T.ΔS°

As we can see from the expression above, the favorability will be driven if ΔH° < 0 and if ΔS° < 0. Since ΔH° = -610 kJ/mol and ΔS° = -73 J/K.mol, the favorability will be driven by ΔH°. Now, let's calculate the overall favorability.

ΔG° = ΔH° - T.ΔS°

ΔG° = -610 kJ/mol - 298 K.(-0.073 kJ/K.mol) = -588 kJ/mol

The reaction is favorable and is driven by ΔH° only.

Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.

Answers

Answer:

mass of sucrose = 17.115 grams

Explanation:

Given that:

mass = 2000 grams

molar mass of sucrose = 342.3 g/mol

2.5% of the sucrose soltion.

Let assume we are given 1 M of the sucrose solution;

2.5% of 1 M = 0.025 M

Molarity = ( mass/molar  mass )(1000/V)

mass = (0.025 * 342.3 * 2000)/(1000)

mass of sucrose = 17.115 grams

Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.

Answers

Answer:

50 g Sucrose

Explanation:

Step 1: Given data

Mass of solution: 2000 gConcentration of the solution: 2.5%

Step 2: Calculate the mass of sucrose needed to prepare the solution

The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:

2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose

"At constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature." This is -

Answers

Answer: B

Explanation:

According to Charle's law, at constant pressure the volume of a fixed mass of a ga is directly proportional to its absolute temperature.

At constant pressure, V∝T.

30. Which of the following atoms would form
a trivalent anion?
A. Aluminium
B. Oxygen
C. Lithium
D. Nitrogen​

Answers

Aluminium and Nitrogen!

I think the answer is D. nitrogen .

A or B or C or D, fassst plzzz

Answers

Answer:

a.option is the correct answer

It’s C because there are less frogs eating the insect so the insect amount increases and there are less snakes bc they don’t have a stable food source of frogs anymore

Solid lead acetate is slowly added to 75.0 mL of a 0.0492 M sodium sulfate solution. What is the concentration of lead ion required to just initiate precipitation?

Answers

Answer:

The concentration of lead ion required to just initiate precipitation is -[tex]2.37\times10^-^5 M[/tex]

Explanation:

Lets calculate -:

Solubility equilibrium -: [tex]PbI_2(s)[/tex] ⇄ [tex]Pb^2^+ (aq) + 2I^- (aq)[/tex]

Solubility product of [tex]PbI_2[/tex] ,[tex]Q=[Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex][I^-]^2_i_n_i_t_i_a_l[/tex] [tex]=9.8\times10^-^9[/tex]

Concentration of [tex]I^-[/tex][tex]=[KI]=0.0492M[/tex]

When the ionic product exceeds the solubility product , precipitation of salt takes place .

                                   [tex]Q_s_p\geq K_s_p[/tex]

        [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex][I^-]^2_i_n_i_t_i_a_l[/tex] [tex]\geq 9.8\times10^-^9[/tex]

      [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex]  [tex][0.0492]^2[/tex] [tex]\geq 9.8\times10^-^9[/tex]

                       [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq \frac{9.8\times10^-^9}{[0.0492]^2}[/tex]

                        [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq[/tex] [tex]\frac{9.8\times10^-^9}{2.42\times10^-^3}[/tex]

                        [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq[/tex] [tex]2.37\times10^-^5 M[/tex]

Thus , [tex]PbI_2[/tex] will start precipitating when [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex]   [tex]\geq 2.37\times10^-^5 M[/tex].    

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the temperature changed to:

(a) -5 ºC
(b) 95 ºF
(c) 1095 K

Answers

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: [tex]V_{1}[/tex] = 571 mL,       [tex]T_{1} = 26^{o}C[/tex]

(a) [tex]T_{2} = 5^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL[/tex]

(b) [tex]T_{2} = 95^{o}F[/tex]

Convert degree Fahrenheit into degree Cesius as follows.

[tex](1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL[/tex]

(c) [tex]T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL[/tex]

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes?
-Molecules in both the metal and the surrounding air will start moving at lower speeds. -Molecules in both the metal and the surrounding air will start moving at higher speeds. -The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
-The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Answers

Answer:

until the next harvest, and seed must be held for the next season's ... successful grain storage is the moisture content of the crop. ... or both. If ambient temperatures are low, then air alone may cool the ... allow some of the drying to take place naturally while the crop ... employed to cool grain that has been placed in storage.

1.the volume of air in a mountain bicycle tire is constant. the initial pressure and temperature are 3.14 atm and 26 degrees celsius.

a) as the bike is ridden friction with the road causes the tire to heat up. at what kelvin temperature will the gas in the tire have a pressure of 3.96 atm

b) explain why your answer makes sense at the particle level. use the words collisions, force, and frequency in your responde.

Answers

Answer:

Explanation:

Givens

P1 = 3.14 atm

T1 = 26 + 273 = 299

P2 = 3.96

T2 = ?

Equation

P1 / T1 = P2 / T2

Solution

3.14 / 299 = 3.96 / x                   Cross multiply

3.14 x = 299 * 3.96                     Divide by 3.14

x = 299*3.96 / 3.14

x = 1184.04/3.14

x = 377.08 oK                             Take off 273 to get the degrees Centigrade.

x = 104.08 oC

Part B

If you want the temperature to increase, the relationship is a direct  one. That means as the temperature goes up, the pressure will as well. So for a bicycle, it makes sense that the volume remains constant. That makes the formula above without volume because the volume would cancel out on both sides of the equation.

So as the pressure increases, the particles making up the air begin to respond by the molecules moving faster. Temperature really is the a measurement of how fast molecules are moving. So the momentum is increasing. When the particles hit something, it is with a much greater force and that increases the apparent pressure.

4. Eggs are present in the ovaries when people are born, and after they go
through puberty. *
OTrue
OFalse

Answers

The answer is true. Eggs remain in the body all throughout life cycle.

Molecular complexes in the cristae contain electron transport carriers that move _________ into the intermembrane space. The first electron transport carrier accepts an ________ from _________ . A second carrier accepts an ___________ from _________ . After the ________have travelled through the chain they are finally accepted by ________ and 2 __________ to produce water. Going from high to low concentration, _________ flow through ATP synthase like a water wheel to produce ~32 ________ molecules.

Answers

Answer:

a.) Hydrogen

b.) electron

c.) NADH⁺ + H⁺

d.) electron

e.) FADH₂

f.) electron

g.) hydrogen ions

h.) oxygen

i.) hydrogen ions

j.) ATP

Explanation:

Molecular complexes in the cristae contain electron transport carriers that move Hydrogen into the intermembrane space.

The first electron transport carrier accepts an electron from NADH⁺ + H⁺

A second carrier accepts an electron from FADH₂ .

After the electron have travelled through the chain they are finally accepted by hydrogen ions and oxygen to produce water.

Going from high to low concentration, hydrogen ions flow through ATP synthase like a water wheel to produce ~32 ATP molecules.

What type of a liquid will have a pH value equal to 12?


Basic


Neutral


Strong acid


Weak acid

Answers

Answer:

weak acid

Explanation:

Answer: Basic is correct!!!!!

Explanation:

One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) technique. As corn photosynthesizes, it concentrates the isotope carbon-13, whereas most other plants concentrate carbon-12. Over-reliance on corn consumption can then be correlated with certain diseases, because corn lacks the essential amino acid lysine. Archaeologists use a mass spectrometer to separate the C12 and C 13 isotopes in samples of humans remains. Suppose you use a velocity selector to obtain single ionized (missing one electron) atoms of speed 8.50 km/s and what to bend them within a uniform magnetic field in a semicircle of diameter 25.0 cm for the C12 . The measured masses of these isotopes are 1.99 × 10^-26 kg ( C12 ) and 2.16 × 10^-26 kg ( C13).

Required:
a. What strength of magnetic field is required? (b) What is the diameter of the 13C semicircle?
b. What is the separation of the C12 and C13 ions at the detector at the end of the semicircle? Is this distance large enough to be easily observed?

Answers

Answer:

a. i. 8.447 × 10⁻³ T ii.  27.14 cm

b. i. 2.14 cm ii. It is easily detectable.

Explanation:

a.

i. What strength of magnetic field is required?

Since the magnetic force F = Bqv equals the centripetal force F' = mv²/r on the C12 charge, we have

F = F'

Bqv = mv²/r

B = mv/re where B = strength of magnetic field, m = mass of C12 isotope = 1.99 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q = charge on C 12 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron)and r = radius of semicircle = 25.0 cm/2 = 12.5 cm = 12.5 × 10⁻² m

So,

B = mv/rq

B = 1.99 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (12.5 × 10⁻² m × 1.602 × 10⁻¹⁹ C)

B = 16.915 × 10⁻²³ kgm/s ÷ (20.025 × 10⁻²¹ mC)

B = 0.8447 × 10⁻² kg/sC)

B = 8.447 × 10⁻³ T

(ii) What is the diameter of the 13C semicircle?

Since the magnetic force F = Bq'v equals the centripetal force F' = mv²/r' on the C13 charge, we have

F = F'

Bq'v = mv²/r'

r' = mv/Be where r = radius of semicircle, B = strength of magnetic field = 8.447 × 10⁻³ T, m = mass of C12 isotope = 2.16 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q' = charge on C 13 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron) and  = d/2 = 12.5 cm = 12.5 × 10⁻² m

So, r' = mv/Be

r' = 2.16 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (8.447 × 10⁻³ T × 1.602 × 10⁻¹⁹ C)

r' = 18.36 × 10⁻²³ kgm/s ÷ 13.5321 × 10⁻²² TC)

r' = 1.357 × 10⁻¹ kgm/TC)

r' = 0.1357 m

r' = 13.57 cm

Since diameter d' = 2r', d' = 2(13.57 cm) = 27.14 cm

b.

i. What is the separation of the C12 and C13 ions at the detector at the end of the semicircle?

Since the diameter of the C12 isotope is 25.0 cm and that of the C 13 isotope is 27.14 cm, their separation at the end of the semicircle is 27.14 cm - 25.0 cm = 2.14 cm

ii. Is this distance large enough to be easily observed?

This distance of 2.14 cm easily detectable since it is in the centimeter range.

The line notation, Pt
| H2(g) | H (aq) || Cu2 (aq) | Cu(s),
indicates that
copper metal is a product of the cell reaction.
hydrogen gas (H2) is a product of the cell reaction.
Cu is the anode.
Pt is the cathode.

Answers

Answer:

copper metal is a product of the cell reaction.

Explanation:

In writing the line notation of a cell reaction, we ought to recall that the anode is placed at the left hand side of the notation while the cathode is placed at the right hand side of the notation.

If we look at the line notation shown in the question, we will realize that the Cu2+ (aq) | Cu(s) half cell is the cathode and that copper metal is the product of the reaction as shown by the notation.

a sample of mg(hco3)2 contains 1.8 moles of oxygen atom find the number of carbon atoms in the given sample


please solve fast very much urgent​

Answers

Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Chemical formula of the compound: Mg(HCO₃)₂Moles of oxygen atoms: 1.8 moles

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

In each pair of compounds, pick the one with the higher vapor pressure at a given temperature. Explain your reasoning.
a. CH4 or CH3CI
b. CH3CH2CH2OH or CH3OH
c. CH3OH or H2CO

Answers

Answer:

The answer is:

[tex]PART \ A: CH_4\\\\PART \ B: CH_30H\\\\PART \ C: H_2CO[/tex]

Explanation:

Parts A:

The vapor pressure is higher in [tex]CH_4[/tex] because it is non-polar, while [tex]CH_3Cl[/tex] is polar. [tex]CH_4[/tex] has a lower molar weight as well.

Part B:

Although hydrogen bonding is found in both commodities, the vapor pressure is higher because of the smaller molar mass of [tex]CH_30H[/tex].

Part C:

[tex]H_2CO[/tex] does not show hydrogen due to the increased vapor pressure

[tex]CH_3OH[/tex] bonding.

Question 6
4 pts
6) Chromium crystallizes in a body-centered cubic unit cell. If the length of an edge of the unit cell
is 289 pm, what is the density (in g/cm3) of chromium?
Show your work on a paper and upload it here.
Upload
Choose a File

Answers

Answer:

7.15g/cm³

Explanation:

To solve this question we must know that a body-centered cubic unit cell contains 2 atoms.

The volume of the unit cell is:

289pm = (289x10⁻¹²m)³ =

2.414x10⁻²⁹m³ * (1cm³ / 1x10⁻⁶m³) = 2.414x10⁻²³cm³

And the mass is -Molar mass Chromium = 51.9961g/mol:

2atoms * (1mol / 6.022x10²³atoms) * (51.9961g / mol) =

1.727x10⁻²²g

The density is:

1.727x10⁻²²g / 2.414x10⁻²³cm³ =

7.15g/cm³

The celestial bodies in space move about in predictable paths called blank . As a result, a planet is able to blank around the Sun. Other objects in the solar system also orbit the Sun. These objects include blank and comets.

Answers

Answer:

Gravity

Explanation:

All matter exerts a force, which is called , that pulls all other matter towards its center. The strength of the force depends on the mass of the object: the Sun has more gravity than Earth, which in turn has more gravity than an apple. Also, the force weakens with distance. Objects far from the Sun won’t be influenced by its gravity.

Civic participation is best described as the act of

avoiding harming other community members.
meeting one's legal responsibilities.
voting in every type of election.
going above and beyond one's legal duties.
Which is one of Edwin Hubble’s findings that supports the big bang theory?

Answers

Answer:

meeting ones legal responsibility

If a medicine ball in a gym has a mass of 4.0 Kg, what is its weight?

Answers

Answer:

Weight = 0.4

Explanation:

Given Information :

Mass = 4.0kg

Acceleration  due to gravity = 10 m/s

Weight= ?

[tex]Weight = \frac{mass}{acceleration\: due \:to \:gravity} \\\\W= \frac{4.0}{10} \\\\W= \frac{2}{5} \\\\W=0.4[/tex]

I NEED HELP PLS! Do the fossil finds in Antarctica support Wegener’s continental drift hypothesis? Explain your answer using examples of fossil finds. Your answer should include at least five complete sentences.

Answers

Answer:

There are many examples of fossils found on separate continents and nowhere else, suggesting the continents were once joined. If Continental Drift had not occurred, the alternative explanations would be: The species evolved independently on separate continents – contradicting Darwin's theory of evolution.

hope this helps you ☺️☺️

Zack has noticed a lot of changes in his body. He has gained muscle mass and started to grow facial hair. His voice is also getting deeper.

In which stage of development is he?

childhood
adolescence
early adulthood
late adulthood

Answers

Answer:

b

Explanation:

What is matter?
O A. Anything that has energy and motion
B. Anything that takes up space and has mass
C. Anything that can be seen
D. Anything that can be measured

Answers

the answer is would be B! :)

Answer:

B.Anything that takes up space and has mass


When liquid water freezes into solid ice in the freezer,

Answers

Answer:

What about it? I don't get the question

Sample A: 300 mL of 1M sodium chloride
Sample B: 145 mL of 1.5 M sodium chloride

Which sample contains the larger concentration of sodium chloride?

Answers

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

How many sigma bond and pi bond are present

Answers

Your question is not complete ! Please told me the compound name I hope I can give you answers,
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