Which bond(s) shown are double bonds?

Answer:

Your answer is c :)

Explanation:

Answer:

2ohms

Explanation:

the net resistance is given by

1/R=1/R1 +1/R2,we are supposed to find R

thus by making R the subject ....

R=R1•R2/R1+R2

R=3•6/3+6

R=18/9 =2Ohms

Answer:

D all of the above

Explanation:

electricity moves easily through all of them and none of them prevent the flow of electricity

Answer:

m=1800kg

1800000g×10N/kg

18000000N force is required to life the car

Answer:

The two moments must be the same:

p1=p2

m1v1=m2v2

v2=(m1v1)/m2

v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s

Answer:

1000J

Explanation:

According to the law of calorimetry;

Heat lost by cold substance = Heat gained by hot substance

If 1000 J of heat energy is lost from a piece of hot metal,

heat lost by hot substance = 1000J

Since we are to determine how much energy is gained by the water, using the law

Heat lost by hot metal = heat gained by the water

Hence heat gained by the water = 1000J

Answer:

Yes.

Explanation:

Yes Light has inertia, since inertia is in units of mass.

Answer:

Electricity ⚡️

Explanation:

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  [tex]\frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}[/tex]

On substituting the values, we get

⇒  [tex]\frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}[/tex]

On taking L.C.M, we get

⇒  [tex]\frac{1}{R_{net}} =\frac{2+1}{6}[/tex]

⇒  [tex]\frac{1}{R_{net}} =\frac{3}{6}[/tex]

⇒  [tex]\frac{1}{R_{net}} =\frac{1}{2}[/tex]

On applying cross-multiplication, we get

⇒ [tex]R_{net}=2 \Omega[/tex]

Answer:

the first one stationary charge

first oneeeeeeeeeeeeeeeeeeee

Answer:

a) v = 18.86 m / s, b)  h = 8.85 m

Explanation:

a) For this exercise we can use the conservation of energy relations.

Starting point. Like the compressed spring

          Em₀ = K_e + U = ½ k x² + m g x

the zero of the datum is placed at the point of the uncompressed spring

Final point. With the spring if compress

           Em_f = K = ½ m v²

how energy is conserved

          Em₀ = Em_f

          ½ k x² + m g x = ½ m v²

           v² = [tex]\frac{k}{m}[/tex]  x² + 2gx

let's reduce the magnitudes to the SI system

          m = 500 g = 0.500 kg

          x = -45 cm = -0.45 m

the negative sign is because the distance in below zero of the reference frame

let's calculate

           v² = [tex]\frac{900}{0.500}[/tex]  0.45² + 2 9.8 (- 0.45)

           v = √355.68

           v = 18.86 m / s

b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops

           Em_f = U = m g h

           Em₀ = Em_f

            ½ k x²2 + m g x = m g h

            h = ½  [tex]\frac{k}{g}[/tex]   x² + x

let's calculate

           h = [tex]\frac{1}{2} \ \frac{900}{9.8 } \ 0.45^2[/tex] - 0.45

           h = 8.85 m

measured from the point where the spring is uncompressed

Answer:

The sun.

Explanation:

The sun has the most gravitational pull.

Answer:

Philip Gbeho

Explanation:

Answer:

1.Contact because its a contact force

2 Contact because when the car is stopping it is coming in to contact with the ground.

3 non Contact because magnets don't need to have contact they pull

4 non Contact because its not a contact force

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

Answer:

I₁ = I₂ = I₃ = 12 A

Explanation:

Since the resistors are connected in parallel across a battery. Hence, the voltage across each of them will be the same, which will be equal to the voltage of the power supply. Since each resistor has the same resistance of 5 Ω. Therefore. the current across each resistor will also be the same. We can easily calculate these current values by the use of Ohm's Law, as follows:

[tex]V = IR\\I_{1}=I_{2}=I_{3}=\frac{V}{R} \\\\I_{1}=I_{2}=I_{3}=\frac{9\ Volt}{5 \Omega}\\\\[/tex]

I₁ = I₂ = I₃ = 12 A

Answer:

W = 3.15 · 10⁶ J  

Explanation:

We know that power is calculated using the formula:

We can derive a formula for work using this formula by multiplying t to both sides of the equation.

Let's convert 15 kW to W.

Let's convert 3.5 min to s.

Substitute these values into the formula for work and solve for W.

This is the amount of work done by a 15 kW engine in 3.5 minutes.

Answer: iDc im in 3grade

Explanation:sorry

Answer:

7i, 5j, 0k

Explanation:

Add up the two vectors.

Add

i+i       1+6  = 7i

j+j       2+3 = 5j

k+k    -2+2 = 0k

therefore A+B = (7i, 5j, 0k)

Hello,

Light is an electromagnetic wave, its speed is maximum in space and almost in the air where interactions have almost no effect. In other non-opaque media, light is subject to several phenomena: refraction and reflection. Part of the incident ray will be reflected in the same medium while the other part will be refracted in the new medium with a lower speed. In general, the medium influences the speed, and therefore the wavelength.  

Answer:

Workdone = 0.025 Joules

Explanation:

Given the following data;

Workdone = 2J

Extension = 42 - 24 = 18 cm to meters = 18/100 = 0.18m

The workdone to stretch a string is given by the formula;

Workdone = ½ke²

Where;

k is the constant of elasticity.

e is the extension of the string.

We would solve for string constant, k;

2 = ½*k*0.18²

2 = ½*k*0.0324

Cross-multiplying, we have;

4 = 0.0324k

k = 4/0.0324

k = 123.46 N/m

a. To find the workdone when e = 32, 34.

Extension = 34 - 32 = 2 to meters = 2/100 = 0.02m

Workdone = ½*123.46*0.02²

Workdone = 61.73 * 0.0004

Workdone = 0.025 Joules

Therefore, the amount of work (in J) needed to stretch the spring from 32 cm to 34 cm is 0.67.

Answer:

Your ans is B)

Explanation:

Hope its right

if wrong firgive me

Answer:

The correct answer is "12 rad/s"

Explanation:

The given values are,

Mass of rod,

M = 140 g

i.e.,

   = 0.14 kg

Length,

L = 57 cm

i.e.,

  = 0.57 m

Mass of beads,

M = 30 g

i.e.,

   = 0.03 kg

Angular speed,

r = 11 cm

i.e.,

 = 0.11 m

Now,

The inertia of rods will be:

=  [tex]\frac{1}{12}ML ^2[/tex]

On substituting the values, we get

=  [tex]\frac{1}{12}\times 0.14\times (0.57)^2[/tex]

=  [tex]0.0037905 \ kg-m^2[/tex]

The inertia of beads will be:

=  [tex]mr^2[/tex]

On substituting the values, we get

=  [tex]0.03\times (0.11)^2[/tex]

=  [tex]0.000726 \ kg-m^2[/tex]

The total inertia will be:

=  [tex]Inertia \ of \ rods+Inertia \ of \ beads[/tex]

=  [tex]0.0037905 + 0.000726[/tex]

=  [tex]0.0045165 \ kg-m^2[/tex]

now,

The angular speed of the system will be:

⇒ [tex]L_1w_1=L_2w_2[/tex]

On substituting the values in the above equation, we get

⇒ [tex]0.0045165\times 23 = (0.0037905 + (0.03\times 0.285^2)\times 2 )\times w_2[/tex]

⇒ [tex]0.1038795 = 0.0037905 + (0.00243675\times 2 )\times w_2[/tex]

⇒             [tex]w_2 = 12 \ rad/s[/tex]

Answer:b yuh

Explanation:

Yuh

Answer:

A) 80 cm³

B) 0.75 dm³

Explanation:

I hope this help❤️

x-component is V·cos(angle)

y-component is V·sin(angle)

When the angle is 45°, its sin and cos are both 1/2·√2 .

Vx = 20·√2 = 28.28 m/s

Vy = 20·√2 = 28.28 m/s