The missing value so that the relation is still a function is {(3, 7), (0, −2), (1, −3), (−2, 1), (1, 4)} (option b)
In this case, let's first check if the given set is a function without the missing value. We can do this by checking if each input value appears only once in the set. If we look at the set {(3, 7), (0, −2), (−2, 1), (1, 4)}, we can see that each input value appears only once, which means that the set is a function.
Now, we need to determine which value can replace the missing value so that the set remains a function. Let's consider each option one by one.
If we replace the missing input value with 1, we get {(3, 7), (0, −2), (1, −3), (−2, 1), (1, 4)}. Here, we can see that each input value maps to a unique output value, which means that the set is still a function.
Therefore, option B is the correct answer.
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what is the solution for x+1*-4x+1
The solution to the product of the given equation is:
-4x² - 3x + 1
How to multiply linear equations?A linear equation is defined as an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant.
Thus, looking at the given equation, we have:
(x + 1) * (-4x + 1)
Expanding this gives:
-4x² - 4x + x + 1
-4x² - 3x + 1
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What is the principal that will grow to $5100 in two years,
eight months at 4.3% compounded semi-annually? The principal is
$=
The principal that will grow to $5,100 in two years, eight months at 4.3% compounded semi-annually is approximately $4,568.20.
To find the principal that will grow to $5,100 in two years and eight months at 4.3% compounded semi-annually, you can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = final amount ($5,100)
P = principal amount (what we're trying to find)
r = annual interest rate (4.3% or 0.043)
n = number of times interest is compounded per year (semi-annually, so 2)
t = time in years (2 years and 8 months or 2.67 years)
First, plug in the values:
$5,100 = P(1 + 0.043/2)^(2*2.67)
Next, solve for P:
P = $5,100 / (1 + 0.043/2)^(2*2.67)
P = $5,100 / (1.0215)^(5.34)
P = $5,100 / 1.11726707
P ≈ $4,568.20
The principal that will grow to $5,100 in two years, eight months at 4.3% compounded semi-annually is approximately $4,568.20.
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the lengths of full-grown scorpions of a certain variety have a mean of 1.96 inches and a standard deviation of 0.08 inch. assuming the distribution of the lengths has roughly the shape of a normal disribution, find the value above which we could expect the longest 20% of these scorpions.
We can expect the longest 20% of these scorpions to be above a length of approximately 2.0272 inches.
To find the value above which we could expect the longest 20% of these scorpions, we need to use the z-score formula. First, we need to find the z-score that corresponds to the 80th percentile, which is the complement of the top 20%. Using a standard normal distribution table or calculator, we find that the z-score corresponding to the 80th percentile is 0.84.
Next, we use the formula z = (x - mu) / sigma, where z is the z-score, x is the value we are trying to find, mu is the mean, and sigma is the standard deviation. We plug in the given values and solve for x:
0.84 = (x - 1.96) / 0.08
0.0672 = x - 1.96
x = 2.0272
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Andre, Lin, and Noah each designed and built a paper airplane. They launched each plane several times and recorded the distance of each flight in yards. Write the five-number summary for the data for each airplane. Then, calculate the interquartile range for each data set.
Answer:
Andre's: Min = 18, Q1 = 23.5, Median = 28.5, Q3 = 31.5, Max = 35, IQR = 8
Lin's: Min = 15, Q1 = 19, Median = 21.5, Q3 = 24, Max = 33, IQR = 5
Noah's: Min = 10, Q1 = 12.5, Median = 19, Q3 = 22.5, Max = 25, IQR = 10
Step-by-step explanation:
How many students were in the sample?
Responses
10
10
20
20
15
15
11
11
Answer:
The answer to your problem is, B. 20
Step-by-step explanation:
Well by looking at the graph we can tell that it is not labeled so we will go to our estimate which is on the left side
2 + 3 + 4 + 5 + 6 = 20
Which we can look at our options and see we have a 20.
Thus the answer to your problem is, B. 20
4. What are the median and mode of the
plant height data?
⬇️
Numbers:
13,14,15,17,17,17,19,20,21
Answer: 5
Step-by-step explanation:
Answer:17
Step-by-step explanation:
The median of this data set is 17, since if you cross one # off of both sides, you will eventually get to the middle fo the data set, pointing to 17.
The solution of the boundary value problem (D^2 +4^2)y=0,given that y(0) = 0 and y(phi/8) = 1. a) y = cos 4x, b) y = 3 sin 4x, c) y) = 4 sin 4x. d) y=sin 4x
The correct solution to the given boundary value problem (D^2 + 4^2)y = 0, with y(0) = 0 and y(phi/8) = 1, is d) y = sin 4x.
This can be found by using the value problem characteristic equation of the differential equation, which is r^2 + 16 = 0. Solving for r, we get r = +/- 4i. Therefore, the general solution is y(x) = c1 sin 4x + c2 cos 4x.
To find the values of c1 and c2, we use the boundary conditions. First, we have y(0) = 0, which gives c2 = 0. Then, we have y(phi/8) = 1, which gives c1 = 1/4. Thus, the final solution is y(x) = (1/4) sin 4x.
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The market price of a t-shirt is $15.00. It is discounted at 10% off. What is the selling price of the t-shirt?
(Enter your answer following the model, i.e. $01.01)
Answer: $13.5
Step-by-step explanation:
1. 15 x 10 =150
2. 150/100=1.5
3. 15.00 - 1.50= 13.5
5. A random variable X has the moment generating function 0.03 Mx(0) t< - log 0.97 1 -0.97e Name the probability distribution of X and specify its parameter(s). (b) Let Y = X1 + X2 + X3 where X1, X3,
Y follows a negative binomial distribution with parameters r = 3 and p = 0.97.
The moment generating function (MGF) of a random variable X is defined as Mx(t) = E(e^(tX)).
(a) The given MGF is 0.03 Mx(0) t< - log 0.97 1 -0.97e^(tX)
The MGF of the geometric distribution with parameter p is given by Mx(t) = E(e^(tX)) = Σ [p(1-p)^(k-1)]e^(tk), where the sum is taken over all non-negative integers k.
Comparing this with the given MGF, we can see that p = 0.97. Therefore, X follows a geometric distribution with parameter p = 0.97.
(b) Let Y = X1 + X2 + X3, where X1, X3, and X3 are independent and identically distributed geometric random variables with parameter p = 0.97.
The MGF of Y can be obtained as follows:
My(t) = E(e^(tY)) = E(e^(t(X1 + X2 + X3))) = E(e^(tX1) * e^(tX2) * e^(tX3))
= Mx(t)^3, since X1, X2, and X3 are independent and identically distributed with the same MGF
Substituting the given MGF of X, we get:
My(t) = (0.03 Mx(0) t< - log 0.97 1 -0.97e^(t))^3
Therefore, Y follows a negative binomial distribution with parameters r = 3 and p = 0.97.
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Show as much work as possible Simplify. 1. 3(5-7)
To show as much work as possible and simplify the expression 3(5-7), we first need to simplify the expression inside the parentheses. After simplification, we get the answer as -6.
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Let x^8+3x^4-4=p_1(x)p_2(x)...p_k(x) where each non-constant polynomial p_i(x) is monic with integer coefficients, and cannot be factored further over the integers. Compute p_1(1)+p_2(1)+...+p_k(1).
Answer: We can factor the given polynomial as follows:
x^8 + 3x^4 - 4 = (x^4 - 1)(x^4 + 4)
= (x^2 - 1)(x^2 + 1)(x^2 - 2x + 1)(x^2 + 2x + 1)
The four factors on the right-hand side are all monic polynomials with integer coefficients that cannot be factored further over the integers. Therefore, we have k = 4, and we can compute p_1(1) + p_2(1) + p_3(1) + p_4(1) as follows:
p_1(1) + p_2(1) + p_3(1) + p_4(1) = (1^2 - 1) + (1^2 + 1) + (1^2 - 2(1) + 1) + (1^2 + 2(1) + 1)
= 0 + 2 + 0 + 6
= 8
Therefore, p_1(1) + p_2(1) + p_3(1) + p_4(1) = 8.
Step-by-step explanation:
(0.70 * (1 - 0.10) = 0.70 * 0.9)
Answer:
The simplified result of the expression is 0.63.
Step-by-step explanation:
How to solve for A and Z?
The length of the missing sides of the two quadrilaterals are listed below:
a = 5z = 4.219How to find the missing lengths in quadrilaterals
In this problem we must determine the length of missing sides in two quadrilaterals, this can be done with the help of Pythagorean theorem and properties for special right triangles:
r = √(x² + y²)
45 - 90 - 45 right triangle
r = √2 · x = √2 · y
Where:
x, y - Legsr - HypotenuseNow we proceed to determine the missing sides for each case:
a = √[(6 - 3)² + 4²]
a = √(3² + 4²)
a = √25
a = 5
Case 2
z = √[(22 - 4√2 - 15)² + 4²]
z = √[(7 - 4√2)² + 4²]
z = 4.219
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Let a > 0 be real. Consider the complex function f(z) 1 + cos az 02 22 - Identify the order of all the poles of f(z) on the finite complex plane. Evaluate the residue of f(z) at these poles.
Hi! To answer your question, let's analyze the complex function f(z) given by f(z) = 1 + cos(az)/(z^2).
First, we need to identify the poles of the function. A pole occurs when the denominator of the function is zero. In this case, the poles are at z = 0. However, the order of the pole is determined by the number of times the denominator vanishes, which is given by the exponent of z in the denominator. Here, the exponent is 2, so the order of the pole is 2.
Now, let's find the residue of complex function f(z) at the pole z = 0. To do this, we can apply the residue formula for a second-order pole:
Res[f(z), z = 0] = lim (z -> 0) [(z^2 * (1 + cos(az)))/(z^2)]'
where ' denotes the first derivative with respect to z.
First, let's find the derivative:
d(1 + cos(az))/dz = -a * sin(az)
Now, substitute this back into the residue formula:
Res[f(z), z = 0] = lim (z -> 0) [z^2 * (-a * sin(az))]
Since sin(0) = 0, the limit evaluates to 0. Therefore, the residue of f(z) at the pole z = 0 is 0.
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Compound i street at what was an investment made that obtains $136. 85 in interest compounded quarterly on $320 over four years
Wait just ignore this.
Step-by-step explanation:
CI = p(r/100 + 1)^t - p
136.85 = 320(r/100 +1)^4 - 320
320(r/100 + 1)^4 = 456.85
(r/100 + 1)^4 = 456.85/320 = 1.42765625
(r/100+1) = 4th root of 1.42765625 = 1. 093089979
R/100 = 0.93089979
R = 93.0 %
following is the probability distribution of a random variable that represents the number of extracurricular activities a college freshman participates in.Part 1 Find the probability that a student participates in exactly two activities The probability that a student participates in exactly two activities is
The table, we cannot determine the probability of a student participating in exactly two activities.
The probability distribution table is not provided in the question, but assuming that it is a valid probability distribution, we can use it to find the probability that a student participates in exactly two activities.
Let X be the random variable representing the number of extracurricular activities a college freshman participates in, and let p(x) denote the probability of X taking the value x.
Then, we want to find p(2), the probability that a student participates in exactly two activities. This can be obtained from the probability distribution table.
Without the table, we cannot determine the probability of a student participating in exactly two activities.
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√175x²y³ simplify radical expression
Answer:
[tex] \sqrt{175 {x}^{2} {y}^{3} } = \sqrt{175} \sqrt{ {x}^{2} } \sqrt{ {y}^{3} } = \sqrt{25} \sqrt{ {x}^{2} } \sqrt{ {y}^{2} } \sqrt{7} \sqrt{y} = 5xy \sqrt{7y} [/tex]
Help please!! <3
Anything would be much appreciated!!
Answer:
a) It is not possible to find the mean because these are words, not numbers.
b) If we put these words in alphabetical order, we have:
blue, blue, green, purple, purple, purple, red, red
The median word here is purple.
c) It is possible to find the mode, which in this case is the word that appears the most times in this list. That word is purple, which appears three times.
Type the correct answer in the box. If necessary, use / for the fraction bar.
If a rectangular prism has a length, width, and height of centimeter, centimeter, and centimeter, respectively, then the volume of the prism is
cubic centimeter
For a rectangular prism with a length, width, and height of [tex] \frac{3}{8}[/tex] cm, [tex] \frac{5}{8}[/tex] cm and [tex] \frac{7}{8}[/tex] centimetre respectively. The volume of this rectangular prism is equals to 0.21 cm³.
Volume of a rectangular prism, can be calculated by multiply the length of the prism by the width of the prism by the height of the prism. That is Volume, V = length × width × height
It is expressed in cubic of measurement units like cm³, m³, feet³, etc. We have a rectangular prism with following dimensions, length of rectangular prism, L = [tex]\frac{3}{8}[/tex] cm
Height of rectangular prism, H = [tex] \frac{7}{8}[/tex] cm
width of rectangular prism, W = [tex] \frac{5}{8}[/tex] cm
Using the above volume formula of rectangular prism, Volume, V = L×H×W
Substitute all known values in above formula,
=> V = [tex] \frac{3}{8} \times \frac{5}{8} \times \frac{7}{8}[/tex]
= [tex] \frac{105}{8^{3} }[/tex]
= 0.21 cm³
Hence, required volume value is
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Complete question:
Type the correct answer in the box. If necessary, use / for the fraction bar.
If a rectangular prism has a length, width, and height of 3/8 centimeter, 5/8 centimeter, and 7/8 centimeter, respectively, then the volume of the prism is ____cubic centimeter.
It is estimated that 25% of all california adults are college graduates and that 31% of california adults are regular internet users. It is also estimated that 19% of California adults are both college graduates and regular internet users.
a. Among california adlts, what is the probability that a randomly chosen internet user is a college graduate? roud off to 2 decimal places.
b. What is the probability that a california adult is an internet user, given that he or her is a college graduate? round off to 2 decimal places.
The probability that a randomly chosen internet user is a college graduate is about 0.61, and the probability that a California adult is an internet user, given that he or she is a college graduate, is about 0.76.
Let A be the event that a California adult is a college graduate, and B be the event that a California adult is a regular internet user.
a. We want to find P(A|B), the probability that a randomly chosen internet user is a college graduate. We can use Bayes' theorem:
P(A|B) = P(B|A) * P(A) / P(B)
where P(B|A) is the probability that an college graduate is an internet user, which is given by P(B|A) = P(A and B) / P(A) = 0.19 / 0.25 = 0.76.
P(B) is the probability of being an internet user, which is given by:
P(B) = P(B and A) + P(B and not A) = 0.19 + 0.12 = 0.31
where P(B and not A) is the probability of being an internet user but not a college graduate, which is equal to P(B) - P(A and B) = 0.31 - 0.19 = 0.12.
Therefore, we have:
P(A|B) = 0.76 * 0.25 / 0.31 ≈ 0.61
b. We want to find P(B|A), the probability that a California adult is an internet user, given that he or she is a college graduate. Again, we can use Bayes' theorem:
P(B|A) = P(A|B) * P(B) / P(A)
where P(A) is the probability of being a college graduate, which is given by P(A) = 0.25.
We already know P(A|B) from part (a), and P(B) from the previous calculation.
Therefore, we have:
P(B|A) = 0.61 * 0.31 / 0.25 ≈ 0.76
So the probability that a randomly chosen internet user is a college graduate is about 0.61, and the probability that a California adult is an internet user, given that he or she is a college graduate, is about 0.76.
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A mountain road drops 5.2 m for every 22.5 m of the road. Calculate the angle at which the road is inclined to the horizontal. ſans: 13 m) 5. A ramp is inclined at 7° to the horizontal. John walks up a distance of 8.5 m on the ramp. How high is he above the ground? [ans: 1.0 m]
The height, which comes out to be approximately 1.0 m.
To calculate the angle at which the mountain road is inclined to the horizontal, we can use the tangent function from trigonometry. The tangent of an angle in a right triangle is the ratio of the opposite side length to the adjacent side length.
1. Set up a right triangle where the vertical drop (5.2 m) represents the opposite side and the horizontal distance (22.5 m) represents the adjacent side.
2. Use the tangent function to find the angle: tan(angle) = opposite / adjacent.
3. Plug in the values: tan(angle) = 5.2 / 22.5.
4. Solve for the angle by taking the inverse tangent (arctan or tan^(-1)): angle = arctan(5.2 / 22.5).
5. Calculate the angle, which comes out to be approximately 13°.
Now, let's address the ramp scenario.
To find the height John is above the ground after walking up the 8.5 m ramp inclined at 7° to the horizontal, we can use the sine function.
1. Set up a right triangle where the unknown height represents the opposite side and the ramp length (8.5 m) represents the hypotenuse.
2. Use the sine function to find the height: sin(angle) = opposite / hypotenuse.
3. Plug in the values: sin(7°) = height / 8.5.
4. Solve for the height: height = 8.5 * sin(7°).
5. Calculate the height, which comes out to be approximately 1.0 m.
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you are dealt one card from a standard 52-card deck. find the probability of being dealt an ace or a 8. group of answer choices
There are 4 aces and 4 nights in a standard 52-card deck. So, the total number of cards that can be considered as a successful outcome is 8. Therefore, the probability of being dealt an ace or an 8 is 8/52 or 2/13. To find the probability of being dealt an Ace or an 8, follow these steps:
1. Identify the total number of cards in the deck: There are 52 cards in a standard deck.
2. Determine the number of Aces and 8s in the deck: There are 4 Aces and 4 eights, totaling 8 cards (4 Aces + 4 eights).
3. Calculate the probability: Divide the number of desired outcomes (Aces and 8s) by the total number of cards in the deck.
Probability = (Number of Aces and 8s) / (Total number of cards)
Probability = 8 / 52
4. Simplify the fraction: 8/52 can be simplified to 2/13.
So, the probability of being dealt an Ace or an 8 from a standard 52-card deck is 2/13.
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you have a sample of 20 pieces of chocolate that are all of the same shape and size (5 pieces have peanuts, 5 pieces have almonds, 5 pieces have macadamia nuts, 5 pieces have no nuts). you weigh each of the 20 pieces of chocolate and get the following weights (in grams). you want to know if the weights across all types of chocolate are statistically significantly different from one another using a significance level of 0.05.
Determine if the weights across all types of chocolate are statistically significantly different from one another using a significance level of 0.05. To do this, we'll use an ANOVA (Analysis of Variance) test. Here are the steps to perform the test:
1. Organize the data: Group the weights of each type of chocolate (peanuts, almonds, macadamia nuts, and no nuts) separately.
2. Calculate the means: Find the mean weight for each group and the overall mean weight for all 20 pieces of chocolate.
3. Calculate the Sum of Squares Between (SSB) and Sum of Squares Within (SSW): SSB represents the variation between groups, and SSW represents the variation within each group.
4. Calculate the Mean Squares Between (MSB) and Mean Squares Within (MSW): Divide SSB by the degrees of freedom between groups (k-1, where k is the number of groups), and divide SSW by the degrees of freedom within groups (N-k, where N is the total number of samples).
5. Calculate the F statistic: Divide MSB by MSW.
6. Determine the critical F value: Using an F distribution table, find the critical F value corresponding to a significance level of 0.05 and the degrees of freedom between and within groups.
7. Compare the calculated F statistic to the critical F value: If the calculated F statistic is greater than the critical F value, the difference in weights across the types of chocolate is considered statistically significant.
If you follow these steps with the provided weight data, you'll be able to determine if the differences in chocolate weights are statistically significant at a 0.05 significance level.
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Suppose the sample space for a continuous random variable is 0 to 200. If
the area under the density graph for the variable from 0 to 50 is 0.25, then the
area under the density graph from 50 to 200 is 0.75.
OA. True
B. False
The three sides of a triangle have lengths of x units,
(x-4) units, and (x² - 2x - 5) units for some value of x greater than 4. What is the perimeter, in units, of the triangle?
Answer:
The perimeter is x² - 9 units-----------------------
The perimeter is the sum of three side lengths:
P = x + (x - 4) + (x² - 2x - 5) P = x + x - 4 + x² - 2x - 5P = x² - 9In the figure there are 5 equal rectangles and each of its sides is marked with a number as indicated in the drawing. Rectangles are placed without rotating or flipping in positions I, II, III, IV, and V in such a way that the sides that stick together in two rectangles have the same number. Which of the rectangles should go in position I?
The rectangle which should go in position I is rectangle A.
We are given that;
The rectangles A,B,C and D with numbers
Now,
To take the same the number of side
If we take A on 1 place
F will be on second place
And B will be on 4th place
Therefore, by algebra the answer will be rectangle A.
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(1 point) Determine whether the following series converges or diverges. (-1)n-1 (- n=1 Input C for convergence and D for divergence: Note: You have only one chance to enter your answer
The series ∑n-1 to ∞ [tex](-1)^{n-1} )/\frac{\sqrt(n}{n+5} }[/tex] is convergence (C).
The given series is:
∑n-1 to ∞ [tex](-1)^{n-1} )/\frac{\sqrt(n}{n+5} }[/tex]
To determine if the series converges or diverges, we can use the alternating series test. The alternating series test states that if a series has alternating terms that decrease in absolute value and converge to zero, then the series converges.
In this series, the terms alternate in sign and decrease in absolute value, since the denominator (n) increases as n increases. Also, as n approaches infinity, the term [tex](-1)^{n-1}[/tex]oscillates between 1 and -1, but does not converge to a specific value. However, the absolute value of the term 1/n approaches 0 as n approaches infinity.
Therefore, by the alternating series test, the given series converges. The answer is C (convergence).
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fill in the price and the total, marginal, and average revenue sendit earns when it rents 0, 1, 2, or 3 trucks during move-in week.
Renting 0 trucks the Marginal Revenue (MR) = Not applicable, and Average Revenue (AR) = Not applicable. Renting 1 truck the Marginal Revenue (MR) = $P (since it's the additional revenue gained from renting 1 truck), Average Revenue (AR) = Total Revenue / Quantity = P / 1 = $P.
Renting 2 trucks Marginal Revenue (MR) = ($2P - $P) = $P (since it's the additional revenue gained from renting the second truck), Average Revenue (AR) = Total Revenue / Quantity = 2P / 2 = $P. Renting 3 trucks Marginal Revenue (MR) = ($3P - $2P) = $P (since it's the additional revenue gained from renting the third truck), Average Revenue (AR) = Total Revenue / Quantity = 3P / 3 = $P.
To help you with your question, we need to know the rental price per truck and the costs associated with renting these trucks. Since this information is not provided, I will assume a rental price of P dollars per truck. Based on this assumption, we can calculate total, marginal, and average revenue for Sendit when renting 0, 1, 2, or 3 trucks during the move-in week.
1. Renting 0 trucks:
Total Revenue (TR) = 0 * P = $0
Marginal Revenue (MR) = Not applicable
Average Revenue (AR) = Not applicable
2. Renting 1 truck:
Total Revenue (TR) = 1 * P = $P
Marginal Revenue (MR) = $P (since it's the additional revenue gained from renting 1 truck)
Average Revenue (AR) = Total Revenue / Quantity = P / 1 = $P
3. Renting 2 trucks:
Total Revenue (TR) = 2 * P = $2P
Marginal Revenue (MR) = ($2P - $P) = $P (since it's the additional revenue gained from renting the second truck)
Average Revenue (AR) = Total Revenue / Quantity = 2P / 2 = $P
4. Renting 3 trucks:
Total Revenue (TR) = 3 * P = $3P
Marginal Revenue (MR) = ($3P - $2P) = $P (since it's the additional revenue gained from renting the third truck)
Average Revenue (AR) = Total Revenue / Quantity = 3P / 3 = $P
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Castel and Kali each improved their yards by planting rose bushes and geraniums. They brought their supplies from the same store. Castel spent $115 on 5 rose bushes and 12 geraniums. Kail spent $94 on 10 rose bushes and 8 geraniums.
(a) Write a system of equations that represents the scenario
(b) Solve the system to determine the cost of one rose bush and the cost of one geraniums.
a) The system of equations that represents the scenario is given as follows:
5x + 12y = 115.10x + 8y = 94.b) The costs are given as follows:
One bush: $2.6.One geranium: 8.5.How to define the system of equations?The variables for the system of equations are defined as follows:
Variable x: cost of a bush.Variable y: cost of a geranium;Castel spent $115 on 5 rose bushes and 12 geraniums, hence:
5x + 12y = 115.
Kail spent $94 on 10 rose bushes and 8 geraniums, hence:
10x + 8y = 94
Then the system is defined as follows:
5x + 12y = 115.10x + 8y = 94.Multiplying the first equation by 2 and subtracting by the second, we have that the value of y is obtained as follows:
24y - 8y = 230 - 94
16y = 136
y = 136/16
y = 8.5.
Then the value of x is obtained as follows:
5x + 12(8.5) = 115
x = (115 - 12 x 8.5)/5
x = 2.6.
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Question 5(Multiple Choice Worth 2 points)
(Properties of Operations MC)
What is an equivalent form of 15(p+ 4) - 12(2q + 4)?
15p24q+ 12
O15p -24q+8
60p-72q
-9pq
Answer:
15p - 24q +8
Step-by-step explanation: