Which chemical equation is unbalanced?
A). C+O,, CO,
B). Sr t+ O2 2SFO
C). 6H, + 30, 6H,O
D). H, +H, +O,-→ H,0 + H,O

Answers

Answer 1

Answer:

The options in this question are unclear, the clear options are as follows:

A. C + O2 → CO2

B. Sr + O2 → 2SrO

C. 6H2 + 3O2 → 6H2O

D. H2 + H2 + O2 → H2O + H2O

The answer is B

Explanation:

A balanced chemical equation is that equation in which atoms of each elements in the reaction are of equal number on both sides of the equation (product and reactant). To balance a chemical equation, coefficients are used.

In this question, four chemical equations are given as follows:

- C + O2 → CO2

In this equation, atoms of carbon (1) and oxygen (2) are the same on both sides, hence, it is BALANCED.

- Sr + O2 → 2SrO

In this equation, Sr has 1 atom on the reactant side but 2 atoms on the product side. Hence, it is UNBALANCED. The balanced equation will be: 2Sr + O2 → 2SrO

- 6H2 + 3O2 → 6H2O

In this equation, atoms of hydrogen (12) and oxygen (6) are the same on both sides, hence, it is BALANCED.

- H2 + H2 + O2 → H2O + H2O

In this equation, atoms of hydrogen (4) and oxygen (2) are the same on both sides, hence, it is BALANCED.


Related Questions

You are working in the lab and spill some acid on the counter. Because you don't want to get into trouble, you decide to clean it up by yourself. What would be best to reduce the acidity of the spill?

Answers

Answer:

By adding baking soda

Explanation:

The best way to reduce the acidity of the spill would be to add some amount of baking soda to the spill and then clean it up with a towel or any other appropriate item.

Baking soda is made up of sodium bicarbonate and has the capacity to react with acid to produce a salt and carbonic acid. The carbonic acid readily decomposes to produce carbon dioxide and water. For example, sodium bicarbonate reacts with hydrochloric acid according to the equation below:

  [tex]NaHCO_3 + HCl --> NaCl + H_2CO3[/tex]

   [tex]H_2CO_3 --> H_2O + CO_2[/tex]

One would expect the addition of a base to the spilled acid to work in a way as to neutralize the acid but bases are also corrosive and only a stoichiometrically balanced quantity would completely neutralize the acid. Thus, the quantity might not easily be determinable and one can end up doing more harm than good.

Hence, the best option is to add baking soda to the spilled acid to reduce its acidity before cleaning it off.

Pls help, science 8th grade question, #11 thx :)

Answers

D, KOH is a concentrated Base and HCL is an acid. D is the only one that has these two.

What type of charge do ionic compounds have

Answers

Answer:neutral

Explanation:ionic compounds is between a cation and anion so they cancel eachother out

PLEASE HELP!! PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP

CHEMJSTRY!! LONE PAIRS WILL GIVE BRAINLIEST IF CORRECT!

Answers

Answer:

T

Explanation:

T is what you are looking for

Consider the following data:

HfCo2 = -393.5 kj/mol
HfH20 = -241.82 kj/mol
Hfc2h6 = -84.68 kj/mol

Using these data, calculate Delta HRXN
for this chemical reaction. Round to the nearest whole number.

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Answers

Answer:

if you ask yahoo answers it will tell you

Explanation:

hope i helped

Answer:

-2856

-792

endothermic, exothermix, exothermic, endothermic

no

Explanation:

The weight loss of an aluminum alloy corroding in a solution of hydrochloric acid was observed to be 0.250 g/cm2 after an 8 h immersion period [13]. What is the corresponding anodic current density in milliamperes per square centimeter, assuming that all the corrosion is due to the following anodic half-cell reaction:

Answers

This question is incomplete, the complete question is;

The weight loss of an aluminum alloy corroding in a solution of hydrochloric acid was observed to be 0.250 g/cm² after an 8 h immersion period [13]. What is the corresponding anodic current density in milliamperes per square centimeter, assuming that all the corrosion is due to the following anodic half-cell reaction:

Al → Al³⁺ + 3e⁻

The atomic weight is 58.7 g/mol

Answer:

Current density in milliamperes per square centimeter is 45.81 mA/cm²

Explanation:

Given the data in the question;

we know that Faradays law of electrolysis states that;

amount of substance produced at each electrode is directly proportional to the quantity of charge flowing through the cell.

so

m = ( Q/F) (M/z)

where m is the mass of substance liberated at an electrode( 0.250 g/cm²)

Q is the total electric charge passed through the substance

F is Faradays constant (96,500 C/mol)

M is the molar mass of the substance( 58.7 g/mol )  and Z is the number of electrons transferred(3)

Also

we know that; Q = It

where I is current and t is time( 8hrs × 60 × 60 = 28800 sec )

we substitute  Q = It  into our equation'

we have;

m = ( It/F) (M/z)

m = ItM / Fz

mFz = ItM

I = mFz / tM

so we substitute

I = [0.250 g/cm² × 96,500 C/mol × 3] / [ 28800 × 58.7 g/mol]

I = 72375 /  1690560

I = 0.04581 A/cm²

we know that; 1 ampere = 1000 milliampere

so

I = 0.04581 × 1000

I = 45.81 mA/cm²

Therefore, current density in milliamperes per square centimeter is 45.81 mA/cm²

A 558 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After this purification was completed the product crystals were dried and analyzed. The purification procedure produced 185 mg of fluorene and 144 mg of benzoic acid. Calculate the percent composition of this mixture.

Answers

Answer:

See explanation

Explanation:

Mass of mixture of  fluorene and benzoic acid = 558 mg

Mass of pure fluorene  after purification = 185 mg of fluorene

Mass of pure  benzoic acid after purification = 144 mg of benzoic acid

Percentage of fluorene int he mixture = 185mg/558mg * 100 = 33.15 %

Percentage of benzoic acid in the mixture = 144mg/558mg * 100 = 25.81 %

Percentage of impurities = 100% - [33.15 + 25.81]

Percentage of impurities = 100 - 58.96

Percentage of impurities = 41.04 %

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