Which choice correctly compares the two numbers? A) 2.41 > 2.37 B) 2.75 < 2.24 9 2.75 > 3.24 D) 3.48 < 2.47​

Since the price of the ribbon is 17 cents per yards, the number of yards of ribbon Ann bought is 27 yards.

She has 15 dollars in her debit card.

She bought bulk ribbons at a craft store.

The price of the ribbon is 17 cents per yards. Therefore,

17 cents = 0.17 dollars

Hence,

Amount debited from her account  = 15  - 10.41 = $4.59

Therefore, she spent a total of $4.59 .

The yards of ribbon bought = 4.59 / 0.17

The yards of ribbon bought = 27

Therefore, Ann bought 27 yards of bulk ribbon.

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Answer:

Below in bold.

Step-by-step explanation:

y = -4x2 + 8x - 13

Divide first 2 terms by -4:-

y = -4(x^2 - 2x) - 13

Convert to vertex form by completing the square:

y = -4[(x - 1)^2 - 1] - 13

y = -4(x - 1)^2 + 4 - 13

y = -4(x - 1)^2 - 9     <---------- Vertex form

y =  a(x -  j)^2 + k       <---------- General form with vertex = (j, k).

So comparing, we see that the vertex is   (1, -9).

Answer:

Step-by-step explanation:

Ratio of length : width = 4 : 7

Length = 4x

Width = 7x

Longer side = 31.5 in

⇒ 7x = 31.5

Divide both sides by 7

x = 31.5/7

x = 4.5

length = 4x

           = 4*4.5

         l = 18 in

width =  31.5

       w = 31.5 in

[tex]\boxed{ \text {Perimeter of rectangle }= 2*l + 2*w}[/tex]

                                      = 2*18 + 2*31.5

                                      = 36 +  63

                                      = 99 in

[tex]\boxed{ \text{Area of rectangle = l*w}}[/tex]

                             = 18*31.5

                             =  567 in²

Answer: Its 1,110

Step-by-step explanation:

Answer:

The elapsed time is 2 hours and 5 minutes. Example 4. The movie started at 7:30 pm and ended at 10:20 pm. 

Step-by-step explanation:

Elapsed time is the amount of time that has passed between two events. You can calculate the elapsed time by figuring out the difference between the start and stop time.Here is an elapsed time problem.Soccer practice begins at 3:15 p.m. and ends at 4:45 p.m. Determine how long soccer practice lasts.To solve this problem, set up a subtraction problem that could be used to find the number of hours and minutes that pass between those two times.Subtract the starting time from the stopping time. Remember that both times represent the number of hours and minutes past noon. 

5 : 40 PM

Explanation:

   11 : 05 P.M

(-)  5 : 25

--------------

5 : 40 PM

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Answer:

The answer is the 3rd option

t = 0.06c

Answer:

t = 0.06c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Scale factor = 4 : 500

                    = 1 : 125

Let the length of hall in her plan = x cm

1 : 125 = x : 1050

[tex]\sf \dfrac{1}{125}=\dfrac{x}{1050}[/tex]

Cross multiply,

1*1050 = x*125

[tex]\sf x =\dfrac{1050}{125}[/tex]

x = 8.4 cm

The length of the hall in her plan = 8.4 cm

Answer:

Step-by-step explanation:

The area of a rectangle is length x width.

Given:

length = 175.23m

width = 67.5m

Area = 175.23m x 67.5m = 11828.025[tex]m^{2}[/tex]

Answer: [tex]\frac{4}{7}[/tex]

Step-by-step explanation:

P(a) or P(b) = P(a) + P(b)

This means that the probability of a or b is the same of the probability of a plus b

So let's see the probability of a, selecting a professor

[tex]\frac{12}{12+6+9+8} \\\\\frac{12}{35}[/tex]

We won't simplify just yet so that addition will be easier later

Now let's see the probability of selecting b, an instructor

[tex]\frac{8}{12+6+9+8} \\\\\frac{8}{35}[/tex]

Now add the 2 probabilities together

[tex]\frac{12}{35} +\frac{8}{35} =\frac{20}{35}[/tex]

Simplify.

[tex]\frac{20}{35} =\frac{4}{7}[/tex]

Answer:B

Step-by-step explanation:the slope is 1/4, and it crosses the y axis at -2.

Answer:

30,000

Step-by-step explanation:

150 x 200

Explanation:

To find the area you need to multiply the two numbers. Therefore, giving you your correct awswer.

Answer:

The first x=4       y=8

Step-by-step explanation:

2x-5 = y-5

x+1 = y-3

  Multiply the second by -2(to eliminate x)

  2x-5 =y-5

 -2x-2= -2y+6

      ADD BOTH

-7 = -y+1

y=8

            PLUG y

x+1 =y-3

x+1 =8-3

x+1=5

x=4

Answer:   1/2 x 1 = 1/2

                 1/3 x 3 = 1  

Step-by-step explanation: 100% Sure! :D

The weight of the third heaviest among the four dogs is 2 kg.

An equation is an expression that shows the relationship between two or more numbers and variables.

The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.

Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.

29 + 28 + 2 + 1 = 60 kg

The weight of the third heaviest among the four dogs is 2 kg.

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Answer:

x³/3 - x² + C

Step-by-step explanation:

∫ x² - 2x + 8 dx

= x³/3 - x² + C

when finding the derivative, you need to take the power plus 1 then divide by the power x^(2+1)/(2+1) = x³/3

the same goes for 2x and the 2/2 is 1 so you would get x²

since you are finding the derivative for x and 8 is a constant it equals zero.

when integrating you always need to add C at the end and C stands for a constant. The only time you do not add C is when the integral goes from one constant to the next.

Example: [tex]\int\limits^1_0 {x^2 - 3x +9} \, dx[/tex] like this...

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

Answer:

30 pesos

Step-by-step explanation:

Given

Solving

Answer:

Karen= 35 messages

Lamar= 25 messages

John= 100 messages

Step-by-step explanation:

[tex]\textcolor{steelblue}{\text{\textcircled{1} Define the variables}}[/tex]

Let the number of messages Karen, Lamar and John send be K, L and J messages respectively.

[tex]\textcolor{steelblue}{\text{\textcircled{2} Form equations with given information}}[/tex]

K +L +J= 160 -----(1)

J= 4L -----(2)

L= K -10 -----(3)

[tex]\textcolor{steelblue}{\text{\textcircled{3} Solve by substitution}}[/tex]

Substitute (3) into (2):

J= 4(K -10)

J= 4K -40 -----(4)

Substitute (3) and (4) into (1):

K +(K -10) +(4K -40)= 160

Simplify:

6K -50= 160

6K= 160 +50

6K= 210

Divide both sides by 6:

K= 210 ÷6

K= 35

Substitute K= 35 into (3):

L= 35 -10

L= 25

Substitute L= 25 into (2):

J= 4(25)

J= 100

[tex]\textcolor{steelblue}{\text{\textcircled{4} Concluding statement}}[/tex]

Thus Karen, Lamar and John sent 35, 25 and 100 messages respectively.

The figure given in the image is a cuboid which have 3 sides, with Length, breadth and height, it's basically a 3-D shape, so here for volume of the cuboid, we can just multiply all the sides and we will be just done then after writing the SI unit of volume against it

[tex]{:\implies \quad \sf So,\:\: Volume=4\dfrac{2}{5}\times 10\times 3}[/tex]

[tex]{:\implies \quad \sf Volume=\bigg(\dfrac{20+2}{5}\bigg)\times 10\times 3}[/tex]

[tex]{:\implies \quad \sf Volume=\dfrac{22}{5}\times 10\times 3}[/tex]

[tex]{:\implies \quad \sf Volume=22\times 2\times 3}[/tex]

[tex]{:\implies \quad \sf Volume=44\times 3=\boxed{\bf{132\:\: m^{3}}}}[/tex]

Answer:

tkm

Step-by-step explanation:

First T the middle k and at last m

Rewrite 2 1/8 as 17/8

Now subtract:

17/8 - 6/8 = 11/8 = 1 3/8

answer : 1 3/8 miles left

Answer:

150 miles

Step-by-step explanation:

speed = 120 km per hour

1 mile = 1.6 km

speed = 120 km per hr

divide 120 with 1.6 to get in miles=120/1.6

= 75 miles per hour

speed = 75 miles per hour

So, in 1 hr, it can travel 75 miles

the distance traveled by car in 2 hours = 75 * 2 = 150

Result : Speed = 75 miles per hour , distance = 150 miles

Answer:

-9

Step-by-step explanation:

225 ÷ -25 = -9

Answer:

The answer to the problem is 4 1/2

Answer:

9/2

Step-by-step explanation:

the answer is 9/2 or 4.5,

the solution for that I have attached below

Using the normal distribution and the central limit theorem, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

Item a:

The mean and the standard error are given by:

[tex]\mu = p = 0.22[/tex]

[tex]s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338[/tex]

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is one subtracted by the p-value of Z when X = 0.25, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.25 - 0.22}{0.0338}[/tex]

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15, hence:

X = 0.2:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.2 - 0.22}{0.0338}[/tex]

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.15 - 0.22}{0.0338}[/tex]

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

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Answer:

Step-by-step explanation:

Final Answer: 19.5%

The total percentage 19.5% increase in the investor's stock account

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given:

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $5900 and his stock in Company B was worth $1850.

The total worth is $5900 + $1850 = $7750

The stock in Company A has increased 20% since last year.

So,

20% of 5900,

= 20 x 5900 /100

= $1180

And the stock in Company B has increased 18%.

So,

18% of 1850,

= 18 x 1850/100

= $333

The total increased amount,

= $333 + $1180

= $1513

The increased percentage,

1513 = n x 7750/100

n = 1513 x 100/7750

n = 19.522

n = 19.5% to the nearest tenth.

Therefore, 19.5% is the required percentage.

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With the frequecy distribution shown in the 50 cities of pakistan,

= highest value - lowest value

= 26.5 - 8.5

= 18

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

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The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let x represent the number of students in the class, hence:

x ≤ 6(4)

x ≤ 24

If each team has at least 2 students:

x ≥ 6(2)

x ≥ 12 and x ≤ 24

The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

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19.99 + 15= 34.99

40-34.99 = 12.51

Jenny received $5.01 change.