Answers
Answer: it will move to the left
Explanation: i remeber doing this
Related Questions
8.How long is a day? A year?
Answers
Answer:
24 hours. 365 days
Explanation:
If the mass of the cement is 15000kg. calculate the density of this cement sample in kgm-3
Answers
The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]
Given the following data:
Mass of cement = 15000 kgLength = 1.1 mWidth = 2 mHeight = 2.5 mTo calculate the density of this cement sample:
First of all, we would determine the volume of the rectangular block.
[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]
Now, can calculate the density of this cement sample:
Mathematically, the density of a substance is given by the formula;
[tex]Desnity =\frac{Mass}{Volume}[/tex]
Substituting the values into the formula, we have;
[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]
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Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.
1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins
Answers
Answer:
The name given to the underwater mountains in the middle of oceans is;
Mid-ocean ridges
Explanation:
Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.
The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.
Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Calcula: a) El trabajo que realiza en ese recorrido. b) La potencia de motor que necesita. c) la energía cinética d) energía potencial d) la energía mecánica
Answers
Answer:
a) El trabajo realizado es de 274,680 J
b) La potencia de la carretilla elevadora es de 4578 Watts.
c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas es de 274.680 Joules.
e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J
Explanation:
a) Los parámetros dados son;
La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s
La masa que debe levantar la carretilla elevadora, m = 700 kg
La altura a la que se levantará la masa, h = 40 m
El trabajo realizado, W = Fuerza, F × Distancia, h
La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g
Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²
∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J
b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos
∴ Potencia = Trabajo / tiempo
Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts
c) Energía cinética, K.E. = 1/2 · m · v²
La energía cinética de la carretilla elevadora, K.E. se da como sigue;
Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas a 40 m, P.E. = m · g · h
∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios
e) La energía mecánica, M.E. = P.E. + K.E.
∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J
La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.
A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?
Answers
Answer:
vz vc
Explanation:
v b
ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly
Answers
Answer:
1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move
2. Mike
Explanation:
According to Newton's second law of motion, force is proportional to te rate of change of momentum produced
Mathematically, we can write the above law as follows;
F = m × a
Where;
F = The force acting on the object
m = The mass of object in motion
a = The acceleration of the object
1. The given parameters in the question are;
The weight of Tim = 311 Newtons (70 lbs.)
The weight of Mike = 50 Newtons (50 lbs.)
The minimum force required to pull the wagon to constant speed = The weight of the wagon
With the assumption that the wagon has very little weight, we have
Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a
Given that mass is proportional to weight, we can write;
Force from mike, Tim on the wagon F₁ = 311 N × a₁
Similarly when they switched places, we have;
Force from Tim, Mike on the wagon = F₂ = 50 N × a₂
Therefore, for the same force, F₁ = F₂ = F, we have;
a₁ = F₁/(311 N) = F/(311 N)
a₂ = F₂/(50 N) = F/(50 N)
By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁
The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move
2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we are also given that F₃ > F₁
By Newton's second law of motion, we have;
a₃ = F₃/(50 N) and a₁ = F₁/(50 N)
From F₃ > F₁, we have;
F₃/(50 N) > F₁/(50 N)
Therefore;
a₃ > a₁
The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike
Therefore, Mike is on the wagon when it has the greatest acceleration.
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answers
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N
A or B??????????????
Answers
Kepler's second law states that a line from the sun to a planet sweeps out equal areas in equal times. 2 d coordinate system with an elliptical orbit of planet around the sun. The elliptical orbit is centered at the origin. The Sun is located on the x axis between the origin and the far left edge of the orbit. The Planet is on the orbital path in the first quadrant and has a velocity vector that is pointing counter-clockwise on the orbital path. There is a line connecting the sun and the planet. The Perihelion is marked as the point where the orbit crosses the x axis closest to the Sun. The Aphelion is marked as the point where the orbit crosses the x axis farthest away from the Sun. The aphelion is the point in the orbit where the planet is the furthest distance from the sun, The perihelion is the point at which the planet is closest to the sun. At which point must the speed of the planet be greater
Answers
Answer:
the speed is higher in the PERIHELIUM
Explanation:
As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.
L = r x p = m r x v
where m is the planet mass and the Sun is considered fixed
Let's analyze this expression, if the anglar momentum is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed
So the speed is higher in the PERIHELIUM
Please help me on this
Answers
Answer:
T
Explanation:
I did sme answer
Which bar graph could represent the reaction rates of a reversible reaction
that has just begun?
Answers
The answer is A. Just did it.
Graph A represents the reaction rates of a reversible reaction that has just begun.
What is meant by reversible reaction ?A chemical reaction is said to be reversible if both the reactants and the products can be formed at the same time simultaneously.
Here,
Both the forward and reverse reactions typically take place concurrently in a reversible reaction.
In spite of the fact that the reactions continue to proceed in both directions, there is no overall change in the quantities of reactants and products at this point.
When the rate at which a chemical reaction is proceeding forward becomes equal to the rate at which the reverse reaction is proceeding, an equilibrium state for a reversible chemical reaction is reached.
Hence,
Graph A represents the reaction rates of a reversible reaction that has just begun.
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what is the range of plane if the angle of the projective is 30° with a speed of √2g?
Answers
Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
Can you describe how and why the molecules move from one side to the other?
Answers
The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.
The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.
The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.
The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.
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What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?
Answers
Answer:
9.8kW
Explanation:
Given data
Mass= 60kg
Hieght= 4m
Time= 4.2seconds
We know that the energy possessed is given as
PE=mgh
PE=60*9.81*4
PE= 2354.4 Joulse
Also, the expression for power is
Power=Energy*Time
Power= 2354.4*4.2
Power=9888.48 watt
Power= 9.8kW
This was merely an accident and I did not mean to post a question.
Answers
Answer:
ok a good rest of your day
Explanation:
When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing
Answers
The frequency of a sound wave is 457
Hz and the speed is 342.5 m/s. What
is the sound's wavelength?
Answers
You can download the answer here
bit.[tex]^{}[/tex]ly/3a8Nt8n
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answers
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answers
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
A volleyball of mass 0.28 kg is dropped from the top of the bleachers (height equals 12 m). What is the speed of the volleyball right before it hits the gym floor?
Answers
Answer:
hope this help pls give me brainless
The speed of the volleyball with a mass of 0.28 kg and height of 12 m will be 15.336 m/s.
What is Speed?
Speed is the rate of change of distance of an object with respect to time. Speed is a scalar quantity as it has only magnitude and no direction. The SI unit of speed is meter per second (m/s).
PE = KE
Potential Energy = Kinetic energy
mgh = 1/2 mv²
where, m is the mass of object,
g is the acceleration due to gravity,
h is the height of the object,
v is the speed of the object
gh = 1/2v²
2gh = v²
v = [tex]\sqrt{2gh}[/tex]
v = [tex]\sqrt{2(9.8)(12)}[/tex]
v = [tex]\sqrt{235.2}[/tex]
v = 15.336 m/s
Therefore, the speed of the volleyball will be 15.336 m/s.
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why brittles of a paint brush spread when in water and cling when taken out of water
Answers
Answer:
surface tension
Explanation:
because of surface tension in water
Planet X and planet y have a mass of 6 x 1024 kg and 3 x 1025 kg. The gravitational force
between the two planets is 5.6 x 1020 N. How far apart is planet X from planet Y?
Answers
Answer: 6 x 1024 kg = 6144 kg
3 x 1025 kg = 3075 kg
5,6 x 1020 N = 5712 N
6144 + 3075 = 9 219 kg
9219 x 5712 = 52 658 928 de distance
je ne suis pas sur de mon cacul
Explanation:
Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answers
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]
let's calculate
v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]
v = 17.30 m / s
580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?
(Remember, nano means 10^-9.)
(Unit=deg)
Answers
Answer:
0.66 degrees
Explanation:
The computation of the angle of the third dark interference is shown below:
The condition of the minima is
Path difference = (2n +1) × [tex]\lambda[/tex]÷ 2
For third minima, n = 2
Now
xd ÷ D = (2 × 2 + 1) × [tex]\lambda[/tex]÷ 2
d tan Q_3 = 5[tex]\lambda[/tex] ÷ 2
tan Q_3 = 5[tex]\lambda[/tex] ÷ 2d
Q_3 = tan^-1 × (5[tex]\lambda[/tex] ÷2d)
= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)
= 0.66 degrees
Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
1) .90amps
2) .40amps
3) .30 amps
Answers
Answer:
incomplete question, resistor must be there
Explanation:
The equation shown is used to calculate moments. The value d is the __________ from the line of action of the force to the __________. What two words complete the FIRST gap in this sentence?
Answers
Answer:
The answer is "perpendicular and distance".
Explanation:
The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.
The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.
Hey stob it.
Please help me.
Cmon help me.
Plz.
Answers
Answer:
3) D: 31 m/s
4) D: 84.84 metres
Explanation:
3) Initial velocity along the x-axis is;
v_x = v_o•cos θ
Initial velocity along the y-axis is;
v_y = v_o•sin θ
Plugging in the relevant values, we have;
v_x = 31 cos 60
v_x = 31 × 0.5
v_x = 15.5 m/s
Similarly,
v_y = 31 sin 60
v_y = 31 × 0.8660
v_y = 26.85 m/s
Thus, magnitude of the initial velocity is;
v = √(15.5² + 26.85²)
v ≈ 31 m/s
4) Formula for horizontal range is;
R = (v² sin 2θ)/g
R = (31² × sin (2 × 60))/9.81
R = 84.84 m
A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder
Answers
Answer:
[tex]1311.5\ \text{Nm}[/tex]
Explanation:
l = Length of ladder = 8.57 m
m = Mass of ladder = 21.4 kg
F = Force on ladder = 258 N
[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Net torque is given by
[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]
The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].
WILL MARK BRAINLIEST FOR CORRCET ANSWER!!!!!!!!!
What is the name of the method for drawing a trend line for the data in a scatterplot in which an oval is drawn around all the points in the scatterplot except the outliers?
A) the oval method
B) the divide-center method
C) the area method
D) the regression calculator method
Answers
Answer:
It’s C
Explanation:
Answer:
its the area method
Explanation:
i did it on edge nuity and i got it correct.
Please solve Question 10
Answers
Answer:
Time = 0.6secs
Explanation:
10) Distance = speed * time
Given the following
Distance = 204m
Speed/velocity = 340m
Get the time
Time = distance/velocity
Time = 204/340
Time = 0.6secs